db3b_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	91	85.2	^(91-85.2)²⁄ _85.2	0.395
Pink Flowers	56	68.2	^(56-68.2)²⁄ _68.2	2.182
White Flowers	20	13.7	^(20-13.7)²⁄ _13.7	2.897
(sum) χ² =				5.474

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

295d_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	26	22.0	^(26-22.0)²⁄ _22.0	0.727
Pink Flowers	18	25.6	^(18-25.6)²⁄ _25.6	2.256
White Flowers	11	7.4	^(11-7.4)²⁄ _7.4	1.751
(sum) χ² =				4.735

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

3d2c_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	85	97.7	^(85-97.7)²⁄ _97.7	1.651
Pink Flowers	271	246.6	^{(271-246.6)²}⁄ _246.6	2.414
White Flowers	143	155.6	^{(143-155.6)²}⁄ _155.6	1.020
(sum) χ² =				5.085

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

ae01_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	117	104.7	^{(117-104.7)²}⁄ _104.7	1.445
Pink Flowers	223	248.2	^{(223-248.2)²}⁄ _248.2	2.559
White Flowers	159	147.1	^{(159-147.1)²}⁄ _147.1	0.963
(sum) χ² =				4.966

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

df75_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	32	25.2	^(32-25.2)²⁄ _25.2	1.835
Pink Flowers	54	67.1	^(54-67.1)²⁄ _67.1	2.558
White Flowers	51	44.7	^(51-44.7)²⁄ _44.7	0.888
(sum) χ² =				5.280

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

a771_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	28	24.6	^(28-24.6)²⁄ _24.6	0.470
Pink Flowers	15	22.3	^(15-22.3)²⁄ _22.3	2.390
White Flowers	9	5.0	^(9-5.0)²⁄ _5.0	3.200
(sum) χ² =				6.060

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

d9c0_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	272	281.4	^{(272-281.4)²}⁄ _281.4	0.314
Pink Flowers	206	187.4	^{(206-187.4)²}⁄ _187.4	1.846
White Flowers	22	31.2	^(22-31.2)²⁄ _31.2	2.713
(sum) χ² =				4.873

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8c2d_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	97	109.3	^(97-109.3)²⁄ _109.3	1.384
Pink Flowers	274	248.9	^{(274-248.9)²}⁄ _248.9	2.531
White Flowers	129	141.8	^{(129-141.8)²}⁄ _141.8	1.155
(sum) χ² =				5.071

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

1d69_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	133	145.1	^{(133-145.1)²}⁄ _145.1	1.009
Pink Flowers	273	248.5	^{(273-248.5)²}⁄ _248.5	2.415
White Flowers	94	106.4	^(94-106.4)²⁄ _106.4	1.445
(sum) χ² =				4.870

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

53e3_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	184	172.3	^{(184-172.3)²}⁄ _172.3	0.794
Pink Flowers	218	242.4	^{(218-242.4)²}⁄ _242.4	2.456
White Flowers	97	85.3	^(97-85.3)²⁄ _85.3	1.605
(sum) χ² =				4.855

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

c032_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	229	239.9	^{(229-239.9)²}⁄ _239.9	0.495
Pink Flowers	234	212.9	^{(234-212.9)²}⁄ _212.9	2.091
White Flowers	37	47.2	^(37-47.2)²⁄ _47.2	2.204
(sum) χ² =				4.791

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

2712_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	70	65.5	^(70-65.5)²⁄ _65.5	0.309
Pink Flowers	32	40.3	^(32-40.3)²⁄ _40.3	1.709
White Flowers	10	6.2	^(10-6.2)²⁄ _6.2	2.329
(sum) χ² =				4.348

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

b01f_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	100	112.3	^{(100-112.3)²}⁄ _112.3	1.347
Pink Flowers	274	249.3	^{(274-249.3)²}⁄ _249.3	2.447
White Flowers	126	138.3	^{(126-138.3)²}⁄ _138.3	1.094
(sum) χ² =				4.888

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

bf1d_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	54	48.3	^(54-48.3)²⁄ _48.3	0.673
Pink Flowers	41	51.8	^(41-51.8)²⁄ _51.8	2.252
White Flowers	19	13.9	^(19-13.9)²⁄ _13.9	1.871
(sum) χ² =				4.796

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9341_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	44	39.7	^(44-39.7)²⁄ _39.7	0.466
Pink Flowers	26	34.0	^(26-34.0)²⁄ _34.0	1.882
White Flowers	12	7.3	^(12-7.3)²⁄ _7.3	3.026
(sum) χ² =				5.374

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

9444_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	27	22.8	^(27-22.8)²⁄ _22.8	0.774
Pink Flowers	22	30.8	^(22-30.8)²⁄ _30.8	2.514
White Flowers	15	10.4	^(15-10.4)²⁄ _10.4	2.035
(sum) χ² =				5.323

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.60 and q=0.40. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

33dc_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	89	101.2	^(89-101.2)²⁄ _101.2	1.471
Pink Flowers	272	247.5	^{(272-247.5)²}⁄ _247.5	2.425
White Flowers	139	151.3	^{(139-151.3)²}⁄ _151.3	1.000
(sum) χ² =				4.896

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

2e35_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	70	64.4	^(70-64.4)²⁄ _64.4	0.487
Pink Flowers	53	65.1	^(53-65.1)²⁄ _65.1	2.249
White Flowers	22	16.5	^(22-16.5)²⁄ _16.5	1.833
(sum) χ² =				4.569

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

1238_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	15	11.2	^(15-11.2)²⁄ _11.2	1.289
Pink Flowers	19	27.7	^(19-27.7)²⁄ _27.7	2.732
White Flowers	21	17.1	^(21-17.1)²⁄ _17.1	0.889
(sum) χ² =				4.911

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

4615_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	49	44.3	^(49-44.3)²⁄ _44.3	0.499
Pink Flowers	31	40.5	^(31-40.5)²⁄ _40.5	2.228
White Flowers	14	9.2	^(14-9.2)²⁄ _9.2	2.504
(sum) χ² =				5.231

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

d5e6_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	33	26.6	^(33-26.6)²⁄ _26.6	1.540
Pink Flowers	55	68.4	^(55-68.4)²⁄ _68.4	2.625
White Flowers	50	44.0	^(50-44.0)²⁄ _44.0	0.818
(sum) χ² =				4.983

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

1a4c_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	141	128.6	^{(141-128.6)²}⁄ _128.6	1.196
Pink Flowers	225	249.9	^{(225-249.9)²}⁄ _249.9	2.481
White Flowers	134	121.5	^{(134-121.5)²}⁄ _121.5	1.286
(sum) χ² =				4.963

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

190f_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	49	42.8	^(49-42.8)²⁄ _42.8	0.898
Pink Flowers	45	56.5	^(45-56.5)²⁄ _56.5	2.341
White Flowers	25	18.7	^(25-18.7)²⁄ _18.7	2.122
(sum) χ² =				5.361

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.60 and q=0.40. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

7745_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	146	158.0	^{(146-158.0)²}⁄ _158.0	0.911
Pink Flowers	271	246.1	^{(271-246.1)²}⁄ _246.1	2.519
White Flowers	84	95.9	^(84-95.9)²⁄ _95.9	1.477
(sum) χ² =				4.907

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

f8d9_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	263	253.0	^{(263-253.0)²}⁄ _253.0	0.395
Pink Flowers	185	205.3	^{(185-205.3)²}⁄ _205.3	2.007
White Flowers	52	41.7	^(52-41.7)²⁄ _41.7	2.544
(sum) χ² =				4.947

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

1ace_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	59	53.4	^(59-53.4)²⁄ _53.4	0.587
Pink Flowers	46	57.9	^(46-57.9)²⁄ _57.9	2.446
White Flowers	21	15.7	^(21-15.7)²⁄ _15.7	1.789
(sum) χ² =				4.822

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

4755_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	195	183.3	^{(195-183.3)²}⁄ _183.3	0.747
Pink Flowers	215	238.9	^{(215-238.9)²}⁄ _238.9	2.391
White Flowers	90	77.8	^(90-77.8)²⁄ _77.8	1.913
(sum) χ² =				5.051

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

26fe_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	182	169.7	^{(182-169.7)²}⁄ _169.7	0.892
Pink Flowers	219	243.2	^{(219-243.2)²}⁄ _243.2	2.408
White Flowers	99	87.1	^(99-87.1)²⁄ _87.1	1.626
(sum) χ² =				4.925

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

b0ed_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	225	235.3	^{(225-235.3)²}⁄ _235.3	0.451
Pink Flowers	237	215.4	^{(237-215.4)²}⁄ _215.4	2.166
White Flowers	39	49.3	^(39-49.3)²⁄ _49.3	2.152
(sum) χ² =				4.769

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

1998_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	313	304.8	^{(313-304.8)²}⁄ _304.8	0.221
Pink Flowers	154	171.2	^{(154-171.2)²}⁄ _171.2	1.728
White Flowers	33	24.0	^(33-24.0)²⁄ _24.0	3.375
(sum) χ² =				5.324

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

788d_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	14	10.3	^(14-10.3)²⁄ _10.3	1.329
Pink Flowers	20	28.3	^(20-28.3)²⁄ _28.3	2.434
White Flowers	24	19.4	^(24-19.4)²⁄ _19.4	1.091
(sum) χ² =				4.854

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

fe0a_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	217	205.5	^{(217-205.5)²}⁄ _205.5	0.644
Pink Flowers	207	230.1	^{(207-230.1)²}⁄ _230.1	2.319
White Flowers	76	64.4	^(76-64.4)²⁄ _64.4	2.089
(sum) χ² =				5.052

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ed1a_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	111	98.9	^(111-98.9)²⁄ _98.9	1.480
Pink Flowers	222	247.0	^{(222-247.0)²}⁄ _247.0	2.530
White Flowers	166	154.1	^{(166-154.1)²}⁄ _154.1	0.919
(sum) χ² =				4.930

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4189_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	119	112.4	^{(119-112.4)²}⁄ _112.4	0.388
Pink Flowers	78	91.8	^(78-91.8)²⁄ _91.8	2.075
White Flowers	26	18.8	^(26-18.8)²⁄ _18.8	2.757
(sum) χ² =				5.220

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

b6fc_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	78	72.8	^(78-72.8)²⁄ _72.8	0.371
Pink Flowers	49	60.6	^(49-60.6)²⁄ _60.6	2.220
White Flowers	18	12.6	^(18-12.6)²⁄ _12.6	2.314
(sum) χ² =				4.906

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

da5c_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	153	165.5	^{(153-165.5)²}⁄ _165.5	0.944
Pink Flowers	269	244.3	^{(269-244.3)²}⁄ _244.3	2.497
White Flowers	78	90.1	^(78-90.1)²⁄ _90.1	1.625
(sum) χ² =				5.066

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

31f9_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	23	17.6	^(23-17.6)²⁄ _17.6	1.657
Pink Flowers	31	41.2	^(31-41.2)²⁄ _41.2	2.525
White Flowers	29	24.2	^(29-24.2)²⁄ _24.2	0.952
(sum) χ² =				5.134

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

2e6b_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	39	31.8	^(39-31.8)²⁄ _31.8	1.630
Pink Flowers	77	92.3	^(77-92.3)²⁄ _92.3	2.536
White Flowers	74	66.9	^(74-66.9)²⁄ _66.9	0.754
(sum) χ² =				4.920

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0242_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	23	17.2	^(23-17.2)²⁄ _17.2	1.956
Pink Flowers	37	47.7	^(37-47.7)²⁄ _47.7	2.400
White Flowers	38	33.1	^(38-33.1)²⁄ _33.1	0.725
(sum) χ² =				5.081

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

bd09_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	29	22.7	^(29-22.7)²⁄ _22.7	1.748
Pink Flowers	52	64.9	^(52-64.9)²⁄ _64.9	2.564
White Flowers	53	46.4	^(53-46.4)²⁄ _46.4	0.939
(sum) χ² =				5.251

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

edd0_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	27	22.2	^(27-22.2)²⁄ _22.2	1.038
Pink Flowers	31	41.5	^(31-41.5)²⁄ _41.5	2.657
White Flowers	24	19.4	^(24-19.4)²⁄ _19.4	1.091
(sum) χ² =				4.785

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

db5a_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	83	78.3	^(83-78.3)²⁄ _78.3	0.282
Pink Flowers	43	53.6	^(43-53.6)²⁄ _53.6	2.096
White Flowers	14	9.2	^(14-9.2)²⁄ _9.2	2.504
(sum) χ² =				4.883

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

45c6_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	89	82.5	^(89-82.5)²⁄ _82.5	0.512
Pink Flowers	67	80.7	^(67-80.7)²⁄ _80.7	2.326
White Flowers	26	19.7	^(26-19.7)²⁄ _19.7	2.015
(sum) χ² =				4.853

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

198d_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	131	118.7	^{(131-118.7)²}⁄ _118.7	1.275
Pink Flowers	225	249.8	^{(225-249.8)²}⁄ _249.8	2.462
White Flowers	144	131.5	^{(144-131.5)²}⁄ _131.5	1.188
(sum) χ² =				4.925

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

6466_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	263	252.8	^{(263-252.8)²}⁄ _252.8	0.412
Pink Flowers	185	205.5	^{(185-205.5)²}⁄ _205.5	2.045
White Flowers	52	41.7	^(52-41.7)²⁄ _41.7	2.544
(sum) χ² =				5.001

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

4048_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	202	190.2	^{(202-190.2)²}⁄ _190.2	0.732
Pink Flowers	213	236.4	^{(213-236.4)²}⁄ _236.4	2.316
White Flowers	85	73.5	^(85-73.5)²⁄ _73.5	1.799
(sum) χ² =				4.848

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d146_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	35	30.5	^(35-30.5)²⁄ _30.5	0.664
Pink Flowers	22	30.7	^(22-30.7)²⁄ _30.7	2.465
White Flowers	12	7.7	^(12-7.7)²⁄ _7.7	2.401
(sum) χ² =				5.531

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

3ec0_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	57	49.1	^(57-49.1)²⁄ _49.1	1.271
Pink Flowers	80	96.0	^(80-96.0)²⁄ _96.0	2.667
White Flowers	55	46.9	^(55-46.9)²⁄ _46.9	1.399
(sum) χ² =				5.337

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

ee1a_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	263	272.9	^{(263-272.9)²}⁄ _272.9	0.359
Pink Flowers	212	193.0	^{(212-193.0)²}⁄ _193.0	1.870
White Flowers	24	34.1	^(24-34.1)²⁄ _34.1	2.991
(sum) χ² =				5.221

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8b55_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	196	183.8	^{(196-183.8)²}⁄ _183.8	0.810
Pink Flowers	215	238.7	^{(215-238.7)²}⁄ _238.7	2.353
White Flowers	89	77.5	^(89-77.5)²⁄ _77.5	1.706
(sum) χ² =				4.869

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

215f_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	23	18.8	^(23-18.8)²⁄ _18.8	0.938
Pink Flowers	16	23.7	^(16-23.7)²⁄ _23.7	2.502
White Flowers	11	7.5	^(11-7.5)²⁄ _7.5	1.633
(sum) χ² =				5.073

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

0c29_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	190	201.2	^{(190-201.2)²}⁄ _201.2	0.623
Pink Flowers	255	231.9	^{(255-231.9)²}⁄ _231.9	2.301
White Flowers	55	66.8	^(55-66.8)²⁄ _66.8	2.084
(sum) χ² =				5.009

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

505d_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	61	57.0	^(61-57.0)²⁄ _57.0	0.281
Pink Flowers	27	35.5	^(27-35.5)²⁄ _35.5	2.035
White Flowers	10	5.5	^(10-5.5)²⁄ _5.5	3.682
(sum) χ² =				5.998

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

938b_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	145	133.8	^{(145-133.8)²}⁄ _133.8	0.938
Pink Flowers	170	191.6	^{(170-191.6)²}⁄ _191.6	2.435
White Flowers	79	68.6	^(79-68.6)²⁄ _68.6	1.577
(sum) χ² =				4.949

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

ec37_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	132	120.0	^{(132-120.0)²}⁄ _120.0	1.200
Pink Flowers	225	249.9	^{(225-249.9)²}⁄ _249.9	2.481
White Flowers	143	130.1	^{(143-130.1)²}⁄ _130.1	1.279
(sum) χ² =				4.960

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

e8be_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	151	163.4	^{(151-163.4)²}⁄ _163.4	0.941
Pink Flowers	269	244.9	^{(269-244.9)²}⁄ _244.9	2.372
White Flowers	79	91.7	^(79-91.7)²⁄ _91.7	1.759
(sum) χ² =				5.072

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.57 and q=0.43. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4c86_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	30	24.7	^(30-24.7)²⁄ _24.7	1.137
Pink Flowers	39	50.5	^(39-50.5)²⁄ _50.5	2.619
White Flowers	31	25.8	^(31-25.8)²⁄ _25.8	1.048
(sum) χ² =				4.804

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3074_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	24	18.9	^(24-18.9)²⁄ _18.9	1.376
Pink Flowers	38	49.2	^(38-49.2)²⁄ _49.2	2.550
White Flowers	37	31.9	^(37-31.9)²⁄ _31.9	0.815
(sum) χ² =				4.741

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0dce_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	41	35.3	^(41-35.3)²⁄ _35.3	0.920
Pink Flowers	35	45.8	^(35-45.8)²⁄ _45.8	2.547
White Flowers	20	14.9	^(20-14.9)²⁄ _14.9	1.746
(sum) χ² =				5.213

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

cc1d_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	181	169.1	^{(181-169.1)²}⁄ _169.1	0.837
Pink Flowers	219	243.3	^{(219-243.3)²}⁄ _243.3	2.427
White Flowers	100	87.5	^(100-87.5)²⁄ _87.5	1.786
(sum) χ² =				5.050

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4250_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	84	96.2	^(84-96.2)²⁄ _96.2	1.547
Pink Flowers	271	246.2	^{(271-246.2)²}⁄ _246.2	2.498
White Flowers	145	157.5	^{(145-157.5)²}⁄ _157.5	0.992
(sum) χ² =				5.037

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

1a86_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	97	84.4	^(97-84.4)²⁄ _84.4	1.881
Pink Flowers	218	242.1	^{(218-242.1)²}⁄ _242.1	2.399
White Flowers	186	173.5	^{(186-173.5)²}⁄ _173.5	0.901
(sum) χ² =				5.181

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

116c_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	209	220.5	^{(209-220.5)²}⁄ _220.5	0.600
Pink Flowers	245	223.1	^{(245-223.1)²}⁄ _223.1	2.150
White Flowers	45	56.4	^(45-56.4)²⁄ _56.4	2.304
(sum) χ² =				5.054

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

8b8c_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	296	286.9	^{(296-286.9)²}⁄ _286.9	0.289
Pink Flowers	165	183.7	^{(165-183.7)²}⁄ _183.7	1.904
White Flowers	39	29.4	^(39-29.4)²⁄ _29.4	3.135
(sum) χ² =				5.327

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

49b0_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	109	121.3	^{(109-121.3)²}⁄ _121.3	1.247
Pink Flowers	275	249.9	^{(275-249.9)²}⁄ _249.9	2.521
White Flowers	116	128.7	^{(116-128.7)²}⁄ _128.7	1.253
(sum) χ² =				5.022

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

3c2f_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	118	130.0	^{(118-130.0)²}⁄ _130.0	1.108
Pink Flowers	275	249.9	^{(275-249.9)²}⁄ _249.9	2.521
White Flowers	108	120.1	^{(108-120.1)²}⁄ _120.1	1.219
(sum) χ² =				4.848

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

e27d_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	40	35.4	^(40-35.4)²⁄ _35.4	0.598
Pink Flowers	30	39.5	^(30-39.5)²⁄ _39.5	2.285
White Flowers	16	11.0	^(16-11.0)²⁄ _11.0	2.273
(sum) χ² =				5.155

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

e96e_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	21	15.7	^(21-15.7)²⁄ _15.7	1.789
Pink Flowers	32	41.7	^(32-41.7)²⁄ _41.7	2.256
White Flowers	33	27.6	^(33-27.6)²⁄ _27.6	1.057
(sum) χ² =				5.102

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

59e8_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	36	31.6	^(36-31.6)²⁄ _31.6	0.613
Pink Flowers	30	39.2	^(30-39.2)²⁄ _39.2	2.159
White Flowers	17	12.2	^(17-12.2)²⁄ _12.2	1.889
(sum) χ² =				4.660

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

25e9_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	224	213.6	^{(224-213.6)²}⁄ _213.6	0.506
Pink Flowers	183	203.8	^{(183-203.8)²}⁄ _203.8	2.123
White Flowers	59	48.6	^(59-48.6)²⁄ _48.6	2.226
(sum) χ² =				4.855

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.68 and q=0.32. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

7857_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	199	187.3	^{(199-187.3)²}⁄ _187.3	0.731
Pink Flowers	214	237.5	^{(214-237.5)²}⁄ _237.5	2.325
White Flowers	87	75.3	^(87-75.3)²⁄ _75.3	1.818
(sum) χ² =				4.874

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9764_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	21	16.6	^(21-16.6)²⁄ _16.6	1.166
Pink Flowers	27	36.9	^(27-36.9)²⁄ _36.9	2.656
White Flowers	25	20.5	^(25-20.5)²⁄ _20.5	0.988
(sum) χ² =				4.810

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

4bcb_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	24	19.8	^(24-19.8)²⁄ _19.8	0.891
Pink Flowers	24	32.7	^(24-32.7)²⁄ _32.7	2.315
White Flowers	18	13.5	^(18-13.5)²⁄ _13.5	1.500
(sum) χ² =				4.706

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

bea1_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	88	100.5	^(88-100.5)²⁄ _100.5	1.555
Pink Flowers	272	247.3	^{(272-247.3)²}⁄ _247.3	2.467
White Flowers	140	152.1	^{(140-152.1)²}⁄ _152.1	0.963
(sum) χ² =				4.984

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0804_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	32	26.6	^(32-26.6)²⁄ _26.6	1.096
Pink Flowers	43	55.0	^(43-55.0)²⁄ _55.0	2.618
White Flowers	34	28.4	^(34-28.4)²⁄ _28.4	1.104
(sum) χ² =				4.819

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

ed7f_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	8934	8864.3	^{(8934-8864.3)²}⁄ _8864.3	0.548
Pink Flowers	8585	8724.1	^{(8585-8724.1)²}⁄ _8724.1	2.218
White Flowers	2216	2146.5	^{(2216-2146.5)²}⁄ _2146.5	2.250
(sum) χ² =				5.016

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d1bd_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	110	97.7	^(110-97.7)²⁄ _97.7	1.549
Pink Flowers	222	246.6	^{(222-246.6)²}⁄ _246.6	2.454
White Flowers	168	155.7	^{(168-155.7)²}⁄ _155.7	0.972
(sum) χ² =				4.974

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8fe5_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	56	50.7	^(56-50.7)²⁄ _50.7	0.554
Pink Flowers	43	54.6	^(43-54.6)²⁄ _54.6	2.464
White Flowers	20	14.7	^(20-14.7)²⁄ _14.7	1.911
(sum) χ² =				4.929

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

30e4_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	43	37.9	^(43-37.9)²⁄ _37.9	0.686
Pink Flowers	33	42.9	^(33-42.9)²⁄ _42.9	2.285
White Flowers	17	12.2	^(17-12.2)²⁄ _12.2	1.889
(sum) χ² =				4.859

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c5ef_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	87	80.7	^(87-80.7)²⁄ _80.7	0.492
Pink Flowers	55	67.3	^(55-67.3)²⁄ _67.3	2.248
White Flowers	20	14.0	^(20-14.0)²⁄ _14.0	2.571
(sum) χ² =				5.311

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

4dd4_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	32	25.2	^(32-25.2)²⁄ _25.2	1.835
Pink Flowers	53	65.4	^(53-65.4)²⁄ _65.4	2.351
White Flowers	49	42.5	^(49-42.5)²⁄ _42.5	0.994
(sum) χ² =				5.180

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

dd3c_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	40	33.2	^(40-33.2)²⁄ _33.2	1.393
Pink Flowers	59	72.8	^(59-72.8)²⁄ _72.8	2.616
White Flowers	47	40.0	^(47-40.0)²⁄ _40.0	1.225
(sum) χ² =				5.234

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

5ea0_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	9160	9056.6	^{(9160-9056.6)²}⁄ _9056.6	1.181
Pink Flowers	17023	17230.2	^{(17023-17230.2)²}⁄ _17230.2	2.492
White Flowers	8299	8195.2	^{(8299-8195.2)²}⁄ _8195.2	1.315
(sum) χ² =				4.987

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

832b_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	190	201.6	^{(190-201.6)²}⁄ _201.6	0.667
Pink Flowers	255	231.8	^{(255-231.8)²}⁄ _231.8	2.322
White Flowers	55	66.6	^(55-66.6)²⁄ _66.6	2.020
(sum) χ² =				5.010

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

193c_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	251	240.7	^{(251-240.7)²}⁄ _240.7	0.441
Pink Flowers	191	212.5	^{(191-212.5)²}⁄ _212.5	2.175
White Flowers	58	46.9	^(58-46.9)²⁄ _46.9	2.627
(sum) χ² =				5.243

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

8fa1_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	2266	2238.5	^{(2266-2238.5)²}⁄ _2238.5	0.338
Pink Flowers	1516	1570.9	^{(1516-1570.9)²}⁄ _1570.9	1.919
White Flowers	303	275.6	^{(303-275.6)²}⁄ _275.6	2.724
(sum) χ² =				4.981

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

bf44_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	38	32.0	^(38-32.0)²⁄ _32.0	1.125
Pink Flowers	49	61.5	^(49-61.5)²⁄ _61.5	2.541
White Flowers	36	29.5	^(36-29.5)²⁄ _29.5	1.432
(sum) χ² =				5.098

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

2288_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	111	123.3	^{(111-123.3)²}⁄ _123.3	1.227
Pink Flowers	275	250.0	^{(275-250.0)²}⁄ _250.0	2.500
White Flowers	114	126.7	^{(114-126.7)²}⁄ _126.7	1.273
(sum) χ² =				5.000

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

705b_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	197	185.6	^{(197-185.6)²}⁄ _185.6	0.700
Pink Flowers	214	238.1	^{(214-238.1)²}⁄ _238.1	2.439
White Flowers	88	76.4	^(88-76.4)²⁄ _76.4	1.761
(sum) χ² =				4.901

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

37e4_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	121	133.0	^{(121-133.0)²}⁄ _133.0	1.083
Pink Flowers	275	249.8	^{(275-249.8)²}⁄ _249.8	2.542
White Flowers	105	117.2	^{(105-117.2)²}⁄ _117.2	1.270
(sum) χ² =				4.895

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

e776_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	155	143.0	^{(155-143.0)²}⁄ _143.0	1.007
Pink Flowers	224	248.8	^{(224-248.8)²}⁄ _248.8	2.472
White Flowers	121	108.2	^{(121-108.2)²}⁄ _108.2	1.514
(sum) χ² =				4.993

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

d802_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	271	260.8	^{(271-260.8)²}⁄ _260.8	0.399
Pink Flowers	181	200.6	^{(181-200.6)²}⁄ _200.6	1.915
White Flowers	49	38.6	^(49-38.6)²⁄ _38.6	2.802
(sum) χ² =				5.116

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

4a08_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	42	35.7	^(42-35.7)²⁄ _35.7	1.112
Pink Flowers	46	57.9	^(46-57.9)²⁄ _57.9	2.446
White Flowers	29	23.5	^(29-23.5)²⁄ _23.5	1.287
(sum) χ² =				4.845

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

5a63_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	85	78.5	^(85-78.5)²⁄ _78.5	0.538
Pink Flowers	58	69.9	^(58-69.9)²⁄ _69.9	2.026
White Flowers	22	15.6	^(22-15.6)²⁄ _15.6	2.626
(sum) χ² =				5.190

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

309b_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	25	21.4	^(25-21.4)²⁄ _21.4	0.606
Pink Flowers	17	24.5	^(17-24.5)²⁄ _24.5	2.296
White Flowers	11	7.0	^(11-7.0)²⁄ _7.0	2.286
(sum) χ² =				5.187

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

ad41_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	80	75.0	^(80-75.0)²⁄ _75.0	0.333
Pink Flowers	46	56.4	^(46-56.4)²⁄ _56.4	1.918
White Flowers	16	10.6	^(16-10.6)²⁄ _10.6	2.751
(sum) χ² =				5.002

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

6d20_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	28	22.1	^(28-22.1)²⁄ _22.1	1.575
Pink Flowers	37	47.4	^(37-47.4)²⁄ _47.4	2.282
White Flowers	31	25.4	^(31-25.4)²⁄ _25.4	1.235
(sum) χ² =				5.092

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

2c39_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	142	154.8	^{(142-154.8)²}⁄ _154.8	1.058
Pink Flowers	271	246.8	^{(271-246.8)²}⁄ _246.8	2.373
White Flowers	86	98.4	^(86-98.4)²⁄ _98.4	1.563
(sum) χ² =				4.994

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

a684_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	288	297.1	^{(288-297.1)²}⁄ _297.1	0.279
Pink Flowers	194	176.7	^{(194-176.7)²}⁄ _176.7	1.694
White Flowers	17	26.3	^(17-26.3)²⁄ _26.3	3.289
(sum) χ² =				5.261

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

9385_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	94	89.5	^(94-89.5)²⁄ _89.5	0.226
Pink Flowers	42	51.2	^(42-51.2)²⁄ _51.2	1.653
White Flowers	12	7.3	^(12-7.3)²⁄ _7.3	3.026
(sum) χ² =				4.905

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

c758_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	62	58.1	^(62-58.1)²⁄ _58.1	0.262
Pink Flowers	24	30.8	^(24-30.8)²⁄ _30.8	1.501
White Flowers	8	4.1	^(8-4.1)²⁄ _4.1	3.710
(sum) χ² =				5.473

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

a41f_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	174	186.1	^{(174-186.1)²}⁄ _186.1	0.787
Pink Flowers	262	237.9	^{(262-237.9)²}⁄ _237.9	2.441
White Flowers	64	76.0	^(64-76.0)²⁄ _76.0	1.895
(sum) χ² =				5.123

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

2ed0_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	66	60.4	^(66-60.4)²⁄ _60.4	0.519
Pink Flowers	47	58.4	^(47-58.4)²⁄ _58.4	2.225
White Flowers	20	14.1	^(20-14.1)²⁄ _14.1	2.469
(sum) χ² =				5.213

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

3c2a_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	36	32.9	^(36-32.9)²⁄ _32.9	0.292
Pink Flowers	15	21.6	^(15-21.6)²⁄ _21.6	2.017
White Flowers	7	3.5	^(7-3.5)²⁄ _3.5	3.500
(sum) χ² =				5.809

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

fb42_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	104	91.3	^(104-91.3)²⁄ _91.3	1.767
Pink Flowers	220	244.7	^{(220-244.7)²}⁄ _244.7	2.493
White Flowers	176	163.9	^{(176-163.9)²}⁄ _163.9	0.893
(sum) χ² =				5.153

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

dbcc_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	270	259.5	^{(270-259.5)²}⁄ _259.5	0.425
Pink Flowers	181	201.4	^{(181-201.4)²}⁄ _201.4	2.066
White Flowers	49	39.1	^(49-39.1)²⁄ _39.1	2.507
(sum) χ² =				4.998

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

9265_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	199	186.9	^{(199-186.9)²}⁄ _186.9	0.783
Pink Flowers	214	237.6	^{(214-237.6)²}⁄ _237.6	2.344
White Flowers	87	75.5	^(87-75.5)²⁄ _75.5	1.752
(sum) χ² =				4.879

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

37b5_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	108	120.1	^{(108-120.1)²}⁄ _120.1	1.219
Pink Flowers	275	249.9	^{(275-249.9)²}⁄ _249.9	2.521
White Flowers	117	130.0	^{(117-130.0)²}⁄ _130.0	1.300
(sum) χ² =				5.040

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

fc47_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	45	41.8	^(45-41.8)²⁄ _41.8	0.245
Pink Flowers	21	28.4	^(21-28.4)²⁄ _28.4	1.928
White Flowers	8	4.8	^(8-4.8)²⁄ _4.8	2.133
(sum) χ² =				4.306

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

746e_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	278	287.0	^{(278-287.0)²}⁄ _287.0	0.282
Pink Flowers	202	183.6	^{(202-183.6)²}⁄ _183.6	1.844
White Flowers	20	29.4	^(20-29.4)²⁄ _29.4	3.005
(sum) χ² =				5.132

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

bb9c_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	152	163.9	^{(152-163.9)²}⁄ _163.9	0.864
Pink Flowers	269	244.7	^{(269-244.7)²}⁄ _244.7	2.413
White Flowers	79	91.4	^(79-91.4)²⁄ _91.4	1.682
(sum) χ² =				4.959

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.57 and q=0.43. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

b0d8_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	293	283.4	^{(293-283.4)²}⁄ _283.4	0.325
Pink Flowers	167	186.1	^{(167-186.1)²}⁄ _186.1	1.960
White Flowers	40	30.5	^(40-30.5)²⁄ _30.5	2.959
(sum) χ² =				5.245

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9990_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	163	175.3	^{(163-175.3)²}⁄ _175.3	0.863
Pink Flowers	266	241.5	^{(266-241.5)²}⁄ _241.5	2.486
White Flowers	71	83.2	^(71-83.2)²⁄ _83.2	1.789
(sum) χ² =				5.137

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f479_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	42	36.7	^(42-36.7)²⁄ _36.7	0.765
Pink Flowers	41	51.9	^(41-51.9)²⁄ _51.9	2.289
White Flowers	24	18.4	^(24-18.4)²⁄ _18.4	1.704
(sum) χ² =				4.759

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

c018_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	60	51.2	^(60-51.2)²⁄ _51.2	1.512
Pink Flowers	107	124.8	^{(107-124.8)²}⁄ _124.8	2.539
White Flowers	85	76.0	^(85-76.0)²⁄ _76.0	1.066
(sum) χ² =				5.117

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

1180_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	110	103.9	^{(110-103.9)²}⁄ _103.9	0.358
Pink Flowers	57	68.0	^(57-68.0)²⁄ _68.0	1.779
White Flowers	17	11.1	^(17-11.1)²⁄ _11.1	3.136
(sum) χ² =				5.274

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

c6c5_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	104	99.9	^(104-99.9)²⁄ _99.9	0.168
Pink Flowers	42	51.5	^(42-51.5)²⁄ _51.5	1.752
White Flowers	11	6.6	^(11-6.6)²⁄ _6.6	2.933
(sum) χ² =				4.854

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

01ab_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	61	55.8	^(61-55.8)²⁄ _55.8	0.485
Pink Flowers	37	47.2	^(37-47.2)²⁄ _47.2	2.204
White Flowers	15	10.0	^(15-10.0)²⁄ _10.0	2.500
(sum) χ² =				5.189

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cb5d_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	47	41.0	^(47-41.0)²⁄ _41.0	0.878
Pink Flowers	48	60.0	^(48-60.0)²⁄ _60.0	2.400
White Flowers	28	22.0	^(28-22.0)²⁄ _22.0	1.636
(sum) χ² =				4.914

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

2373_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	16	11.8	^(16-11.8)²⁄ _11.8	1.495
Pink Flowers	21	29.6	^(21-29.6)²⁄ _29.6	2.499
White Flowers	23	18.6	^(23-18.6)²⁄ _18.6	1.041
(sum) χ² =				5.034

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cb20_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	141	128.2	^{(141-128.2)²}⁄ _128.2	1.278
Pink Flowers	225	250.0	^{(225-250.0)²}⁄ _250.0	2.500
White Flowers	134	121.9	^{(134-121.9)²}⁄ _121.9	1.201
(sum) χ² =				4.979

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

6ccb_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	226	214.4	^{(226-214.4)²}⁄ _214.4	0.628
Pink Flowers	203	226.0	^{(203-226.0)²}⁄ _226.0	2.341
White Flowers	71	59.6	^(71-59.6)²⁄ _59.6	2.181
(sum) χ² =				5.149

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

f27b_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	36	31.3	^(36-31.3)²⁄ _31.3	0.706
Pink Flowers	25	33.6	^(25-33.6)²⁄ _33.6	2.201
White Flowers	13	9.0	^(13-9.0)²⁄ _9.0	1.778
(sum) χ² =				4.685

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4140_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	94	106.0	^(94-106.0)²⁄ _106.0	1.358
Pink Flowers	273	248.4	^{(273-248.4)²}⁄ _248.4	2.436
White Flowers	133	145.6	^{(133-145.6)²}⁄ _145.6	1.090
(sum) χ² =				4.885

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

dd7f_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	125	137.4	^{(125-137.4)²}⁄ _137.4	1.119
Pink Flowers	274	249.4	^{(274-249.4)²}⁄ _249.4	2.426
White Flowers	101	113.1	^{(101-113.1)²}⁄ _113.1	1.295
(sum) χ² =				4.840

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

d660_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	41	37.5	^(41-37.5)²⁄ _37.5	0.327
Pink Flowers	16	22.2	^(16-22.2)²⁄ _22.2	1.732
White Flowers	6	3.3	^(6-3.3)²⁄ _3.3	2.209
(sum) χ² =				4.267

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

5fc0_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	236	246.0	^{(236-246.0)²}⁄ _246.0	0.407
Pink Flowers	230	209.4	^{(230-209.4)²}⁄ _209.4	2.027
White Flowers	34	44.6	^(34-44.6)²⁄ _44.6	2.519
(sum) χ² =				4.952

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

e183_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	20	14.8	^(20-14.8)²⁄ _14.8	1.827
Pink Flowers	27	37.0	^(27-37.0)²⁄ _37.0	2.703
White Flowers	28	23.2	^(28-23.2)²⁄ _23.2	0.993
(sum) χ² =				5.523

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

7ae4_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	20	14.7	^(20-14.7)²⁄ _14.7	1.911
Pink Flowers	28	37.9	^(28-37.9)²⁄ _37.9	2.586
White Flowers	29	24.5	^(29-24.5)²⁄ _24.5	0.827
(sum) χ² =				5.323

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

25ca_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	299	289.9	^{(299-289.9)²}⁄ _289.9	0.286
Pink Flowers	163	181.6	^{(163-181.6)²}⁄ _181.6	1.905
White Flowers	38	28.4	^(38-28.4)²⁄ _28.4	3.245
(sum) χ² =				5.436

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f95a_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	121	108.4	^{(121-108.4)²}⁄ _108.4	1.465
Pink Flowers	224	248.8	^{(224-248.8)²}⁄ _248.8	2.472
White Flowers	155	142.8	^{(155-142.8)²}⁄ _142.8	1.042
(sum) χ² =				4.979

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

387d_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	12	8.0	^(12-8.0)²⁄ _8.0	2.000
Pink Flowers	16	24.0	^(16-24.0)²⁄ _24.0	2.667
White Flowers	22	18.0	^(22-18.0)²⁄ _18.0	0.889
(sum) χ² =				5.556

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.40 and q=0.60. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

2971_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	33	30.8	^(33-30.8)²⁄ _30.8	0.157
Pink Flowers	12	16.9	^(12-16.9)²⁄ _16.9	1.421
White Flowers	5	2.3	^(5-2.3)²⁄ _2.3	3.170
(sum) χ² =				4.747

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

db59_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	43	36.0	^(43-36.0)²⁄ _36.0	1.361
Pink Flowers	61	74.5	^(61-74.5)²⁄ _74.5	2.446
White Flowers	45	38.6	^(45-38.6)²⁄ _38.6	1.061
(sum) χ² =				4.869

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

beb3_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	236	221.2	^{(236-221.2)²}⁄ _221.2	0.990
Pink Flowers	324	353.5	^{(324-353.5)²}⁄ _353.5	2.462
White Flowers	156	141.3	^{(156-141.3)²}⁄ _141.3	1.529
(sum) χ² =				4.981

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f815_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	98	85.6	^(98-85.6)²⁄ _85.6	1.796
Pink Flowers	218	242.6	^{(218-242.6)²}⁄ _242.6	2.494
White Flowers	184	171.8	^{(184-171.8)²}⁄ _171.8	0.866
(sum) χ² =				5.157

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

d8ef_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	166	178.4	^{(166-178.4)²}⁄ _178.4	0.862
Pink Flowers	265	240.5	^{(265-240.5)²}⁄ _240.5	2.496
White Flowers	69	81.1	^(69-81.1)²⁄ _81.1	1.805
(sum) χ² =				5.163

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.60 and q=0.40. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8274_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	93	81.3	^(93-81.3)²⁄ _81.3	1.684
Pink Flowers	217	240.7	^{(217-240.7)²}⁄ _240.7	2.334
White Flowers	190	178.0	^{(190-178.0)²}⁄ _178.0	0.809
(sum) χ² =				4.826

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.40 and q=0.60. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

a237_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	196	207.9	^{(196-207.9)²}⁄ _207.9	0.681
Pink Flowers	252	229.0	^{(252-229.0)²}⁄ _229.0	2.310
White Flowers	52	63.1	^(52-63.1)²⁄ _63.1	1.953
(sum) χ² =				4.944

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

33aa_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	159	170.7	^{(159-170.7)²}⁄ _170.7	0.802
Pink Flowers	267	242.9	^{(267-242.9)²}⁄ _242.9	2.391
White Flowers	74	86.4	^(74-86.4)²⁄ _86.4	1.780
(sum) χ² =				4.973

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

900a_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	143	155.8	^{(143-155.8)²}⁄ _155.8	1.052
Pink Flowers	271	246.6	^{(271-246.6)²}⁄ _246.6	2.414
White Flowers	85	97.6	^(85-97.6)²⁄ _97.6	1.627
(sum) χ² =				5.093

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

1bfe_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	189	200.7	^{(189-200.7)²}⁄ _200.7	0.682
Pink Flowers	255	232.2	^{(255-232.2)²}⁄ _232.2	2.239
White Flowers	56	67.2	^(56-67.2)²⁄ _67.2	1.867
(sum) χ² =				4.787

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

6726_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	37	30.6	^(37-30.6)²⁄ _30.6	1.339
Pink Flowers	50	63.0	^(50-63.0)²⁄ _63.0	2.683
White Flowers	39	32.4	^(39-32.4)²⁄ _32.4	1.344
(sum) χ² =				5.366

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

1fdf_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	97	85.1	^(97-85.1)²⁄ _85.1	1.664
Pink Flowers	218	242.4	^{(218-242.4)²}⁄ _242.4	2.456
White Flowers	185	172.5	^{(185-172.5)²}⁄ _172.5	0.906
(sum) χ² =				5.026

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

75dc_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	90	84.0	^(90-84.0)²⁄ _84.0	0.429
Pink Flowers	55	66.7	^(55-66.7)²⁄ _66.7	2.052
White Flowers	19	13.3	^(19-13.3)²⁄ _13.3	2.443
(sum) χ² =				4.924

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

188b_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	48	42.3	^(48-42.3)²⁄ _42.3	0.768
Pink Flowers	40	50.6	^(40-50.6)²⁄ _50.6	2.221
White Flowers	21	15.1	^(21-15.1)²⁄ _15.1	2.305
(sum) χ² =				5.294

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

8542_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	109	103.1	^{(109-103.1)²}⁄ _103.1	0.338
Pink Flowers	57	68.5	^(57-68.5)²⁄ _68.5	1.931
White Flowers	17	11.4	^(17-11.4)²⁄ _11.4	2.751
(sum) χ² =				5.019

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f603_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	65	59.2	^(65-59.2)²⁄ _59.2	0.568
Pink Flowers	43	54.3	^(43-54.3)²⁄ _54.3	2.352
White Flowers	18	12.5	^(18-12.5)²⁄ _12.5	2.420
(sum) χ² =				5.340

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

88d1_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	166	153.3	^{(166-153.3)²}⁄ _153.3	1.052
Pink Flowers	222	247.1	^{(222-247.1)²}⁄ _247.1	2.550
White Flowers	112	99.6	^(112-99.6)²⁄ _99.6	1.544
(sum) χ² =				5.146

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

32ed_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	19	13.8	^(19-13.8)²⁄ _13.8	1.959
Pink Flowers	28	37.2	^(28-37.2)²⁄ _37.2	2.275
White Flowers	30	25.0	^(30-25.0)²⁄ _25.0	1.000
(sum) χ² =				5.235

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

bc71_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	299	307.3	^{(299-307.3)²}⁄ _307.3	0.224
Pink Flowers	186	169.3	^{(186-169.3)²}⁄ _169.3	1.647
White Flowers	15	23.3	^(15-23.3)²⁄ _23.3	2.957
(sum) χ² =				4.828

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

7edb_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	72	84.3	^(72-84.3)²⁄ _84.3	1.795
Pink Flowers	266	242.0	^{(266-242.0)²}⁄ _242.0	2.380
White Flowers	162	173.6	^{(162-173.6)²}⁄ _173.6	0.775
(sum) χ² =				4.950

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

cfe2_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	298	306.4	^{(298-306.4)²}⁄ _306.4	0.230
Pink Flowers	187	170.0	^{(187-170.0)²}⁄ _170.0	1.700
White Flowers	15	23.6	^(15-23.6)²⁄ _23.6	3.134
(sum) χ² =				5.064

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cb5c_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	84	78.4	^(84-78.4)²⁄ _78.4	0.400
Pink Flowers	54	65.8	^(54-65.8)²⁄ _65.8	2.116
White Flowers	20	13.8	^(20-13.8)²⁄ _13.8	2.786
(sum) χ² =				5.302

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f522_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	31	26.0	^(31-26.0)²⁄ _26.0	0.962
Pink Flowers	29	39.2	^(29-39.2)²⁄ _39.2	2.654
White Flowers	20	14.8	^(20-14.8)²⁄ _14.8	1.827
(sum) χ² =				5.443

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.57 and q=0.43. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4c23_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	76	72.3	^(76-72.3)²⁄ _72.3	0.189
Pink Flowers	31	38.6	^(31-38.6)²⁄ _38.6	1.496
White Flowers	9	5.1	^(9-5.1)²⁄ _5.1	2.982
(sum) χ² =				4.668

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

5851_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	115	109.8	^{(115-109.8)²}⁄ _109.8	0.246
Pink Flowers	59	70.0	^(59-70.0)²⁄ _70.0	1.729
White Flowers	17	11.2	^(17-11.2)²⁄ _11.2	3.004
(sum) χ² =				4.978

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

fba9_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	213	223.6	^{(213-223.6)²}⁄ _223.6	0.503
Pink Flowers	244	221.5	^{(244-221.5)²}⁄ _221.5	2.286
White Flowers	44	54.9	^(44-54.9)²⁄ _54.9	2.164
(sum) χ² =				4.952

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d1e2_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	201	189.5	^{(201-189.5)²}⁄ _189.5	0.698
Pink Flowers	213	236.6	^{(213-236.6)²}⁄ _236.6	2.354
White Flowers	86	73.9	^(86-73.9)²⁄ _73.9	1.981
(sum) χ² =				5.033

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

6434_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	327	318.7	^{(327-318.7)²}⁄ _318.7	0.216
Pink Flowers	145	161.0	^{(145-161.0)²}⁄ _161.0	1.590
White Flowers	28	20.3	^(28-20.3)²⁄ _20.3	2.921
(sum) χ² =				4.727

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

0562_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	22	16.7	^(22-16.7)²⁄ _16.7	1.682
Pink Flowers	30	40.2	^(30-40.2)²⁄ _40.2	2.588
White Flowers	29	24.1	^(29-24.1)²⁄ _24.1	0.996
(sum) χ² =				5.266

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

1f06_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	174	185.6	^{(174-185.6)²}⁄ _185.6	0.725
Pink Flowers	262	238.1	^{(262-238.1)²}⁄ _238.1	2.399
White Flowers	64	76.4	^(64-76.4)²⁄ _76.4	2.013
(sum) χ² =				5.137

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c1f6_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	113	125.7	^{(113-125.7)²}⁄ _125.7	1.283
Pink Flowers	275	250.0	^{(275-250.0)²}⁄ _250.0	2.500
White Flowers	112	124.3	^{(112-124.3)²}⁄ _124.3	1.217
(sum) χ² =				5.000

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

22ae_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	49	44.7	^(49-44.7)²⁄ _44.7	0.414
Pink Flowers	24	32.4	^(24-32.4)²⁄ _32.4	2.178
White Flowers	10	5.9	^(10-5.9)²⁄ _5.9	2.849
(sum) χ² =				5.441

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

ae3d_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	367	353.5	^{(367-353.5)²}⁄ _353.5	0.516
Pink Flowers	298	324.2	^{(298-324.2)²}⁄ _324.2	2.117
White Flowers	88	74.3	^(88-74.3)²⁄ _74.3	2.526
(sum) χ² =				5.159

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

8293_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	68	62.2	^(68-62.2)²⁄ _62.2	0.541
Pink Flowers	55	67.5	^(55-67.5)²⁄ _67.5	2.315
White Flowers	24	18.3	^(24-18.3)²⁄ _18.3	1.775
(sum) χ² =				4.631

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

74f2_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	158	145.1	^{(158-145.1)²}⁄ _145.1	1.147
Pink Flowers	224	248.5	^{(224-248.5)²}⁄ _248.5	2.415
White Flowers	119	106.4	^{(119-106.4)²}⁄ _106.4	1.492
(sum) χ² =				5.054

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

8d0a_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	234	222.4	^{(234-222.4)²}⁄ _222.4	0.605
Pink Flowers	200	222.1	^{(200-222.1)²}⁄ _222.1	2.199
White Flowers	67	55.5	^(67-55.5)²⁄ _55.5	2.383
(sum) χ² =				5.187

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

8e05_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	16	11.3	^(16-11.3)²⁄ _11.3	1.955
Pink Flowers	22	31.2	^(22-31.2)²⁄ _31.2	2.713
White Flowers	26	21.5	^(26-21.5)²⁄ _21.5	0.942
(sum) χ² =				5.610

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

d83f_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	259	248.5	^{(259-248.5)²}⁄ _248.5	0.444
Pink Flowers	187	208.0	^{(187-208.0)²}⁄ _208.0	2.120
White Flowers	54	43.5	^(54-43.5)²⁄ _43.5	2.534
(sum) χ² =				5.098

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

70fc_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	51	47.3	^(51-47.3)²⁄ _47.3	0.289
Pink Flowers	20	26.9	^(20-26.9)²⁄ _26.9	1.770
White Flowers	7	3.8	^(7-3.8)²⁄ _3.8	2.695
(sum) χ² =				4.754

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

6742_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	157	145.0	^{(157-145.0)²}⁄ _145.0	0.993
Pink Flowers	224	248.5	^{(224-248.5)²}⁄ _248.5	2.415
White Flowers	119	106.5	^{(119-106.5)²}⁄ _106.5	1.467
(sum) χ² =				4.876

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c27d_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	227	237.5	^{(227-237.5)²}⁄ _237.5	0.464
Pink Flowers	236	214.2	^{(236-214.2)²}⁄ _214.2	2.219
White Flowers	38	48.3	^(38-48.3)²⁄ _48.3	2.196
(sum) χ² =				4.879

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4b50_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	58	54.4	^(58-54.4)²⁄ _54.4	0.238
Pink Flowers	22	28.8	^(22-28.8)²⁄ _28.8	1.606
White Flowers	7	3.8	^(7-3.8)²⁄ _3.8	2.695
(sum) χ² =				4.539

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

0b33_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	183	171.1	^{(183-171.1)²}⁄ _171.1	0.828
Pink Flowers	219	242.8	^{(219-242.8)²}⁄ _242.8	2.333
White Flowers	98	86.1	^(98-86.1)²⁄ _86.1	1.645
(sum) χ² =				4.805

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

7241_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	42	38.8	^(42-38.8)²⁄ _38.8	0.264
Pink Flowers	18	25.1	^(18-25.1)²⁄ _25.1	2.008
White Flowers	7	4.1	^(7-4.1)²⁄ _4.1	2.051
(sum) χ² =				4.324

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cb5d_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	100	112.7	^{(100-112.7)²}⁄ _112.7	1.431
Pink Flowers	274	249.4	^{(274-249.4)²}⁄ _249.4	2.426
White Flowers	125	138.0	^{(125-138.0)²}⁄ _138.0	1.225
(sum) χ² =				5.082

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f824_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	205	216.2	^{(205-216.2)²}⁄ _216.2	0.580
Pink Flowers	248	225.2	^{(248-225.2)²}⁄ _225.2	2.308
White Flowers	47	58.6	^(47-58.6)²⁄ _58.6	2.296
(sum) χ² =				5.185

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9f21_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	181	168.9	^{(181-168.9)²}⁄ _168.9	0.867
Pink Flowers	219	243.4	^{(219-243.4)²}⁄ _243.4	2.446
White Flowers	100	87.7	^(100-87.7)²⁄ _87.7	1.725
(sum) χ² =				5.038

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

d71a_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	38	33.4	^(38-33.4)²⁄ _33.4	0.634
Pink Flowers	31	41.0	^(31-41.0)²⁄ _41.0	2.439
White Flowers	18	12.6	^(18-12.6)²⁄ _12.6	2.314
(sum) χ² =				5.387

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

7d5a_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	96	84.4	^(96-84.4)²⁄ _84.4	1.594
Pink Flowers	218	242.0	^{(218-242.0)²}⁄ _242.0	2.380
White Flowers	186	173.6	^{(186-173.6)²}⁄ _173.6	0.886
(sum) χ² =				4.860

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f945_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	91	86.4	^(91-86.4)²⁄ _86.4	0.245
Pink Flowers	43	52.6	^(43-52.6)²⁄ _52.6	1.752
White Flowers	13	8.0	^(13-8.0)²⁄ _8.0	3.125
(sum) χ² =				5.122

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

7cb9_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	339	320.4	^{(339-320.4)²}⁄ _320.4	1.080
Pink Flowers	498	534.1	^{(498-534.1)²}⁄ _534.1	2.440
White Flowers	241	222.5	^{(241-222.5)²}⁄ _222.5	1.538
(sum) χ² =				5.058

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

cb9a_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	30	27.0	^(30-27.0)²⁄ _27.0	0.333
Pink Flowers	13	19.5	^(13-19.5)²⁄ _19.5	2.167
White Flowers	7	3.5	^(7-3.5)²⁄ _3.5	3.500
(sum) χ² =				6.000

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

19ac_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	37	30.3	^(37-30.3)²⁄ _30.3	1.482
Pink Flowers	63	76.9	^(63-76.9)²⁄ _76.9	2.512
White Flowers	56	48.8	^(56-48.8)²⁄ _48.8	1.062
(sum) χ² =				5.056

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

858e_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	260	269.6	^{(260-269.6)²}⁄ _269.6	0.342
Pink Flowers	215	195.1	^{(215-195.1)²}⁄ _195.1	2.030
White Flowers	26	35.3	^(26-35.3)²⁄ _35.3	2.450
(sum) χ² =				4.822

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f1dd_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	68	61.2	^(68-61.2)²⁄ _61.2	0.756
Pink Flowers	63	76.1	^(63-76.1)²⁄ _76.1	2.255
White Flowers	30	23.7	^(30-23.7)²⁄ _23.7	1.675
(sum) χ² =				4.685

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

a31e_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	155	142.4	^{(155-142.4)²}⁄ _142.4	1.115
Pink Flowers	224	248.9	^{(224-248.9)²}⁄ _248.9	2.491
White Flowers	121	108.7	^{(121-108.7)²}⁄ _108.7	1.392
(sum) χ² =				4.998

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d376_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	117	105.8	^{(117-105.8)²}⁄ _105.8	1.186
Pink Flowers	175	197.3	^{(175-197.3)²}⁄ _197.3	2.520
White Flowers	103	91.9	^(103-91.9)²⁄ _91.9	1.341
(sum) χ² =				5.047

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cd83_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	65	57.0	^(65-57.0)²⁄ _57.0	1.123
Pink Flowers	82	97.4	^(82-97.4)²⁄ _97.4	2.435
White Flowers	49	41.6	^(49-41.6)²⁄ _41.6	1.316
(sum) χ² =				4.874

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

0517_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	151	136.0	^{(151-136.0)²}⁄ _136.0	1.654
Pink Flowers	347	376.9	^{(347-376.9)²}⁄ _376.9	2.372
White Flowers	276	261.0	^{(276-261.0)²}⁄ _261.0	0.862
(sum) χ² =				4.888

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8306_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	3201	3157.0	^{(3201-3157.0)²}⁄ _3157.0	0.613
Pink Flowers	3367	3456.1	^{(3367-3456.1)²}⁄ _3456.1	2.297
White Flowers	990	945.9	^{(990-945.9)²}⁄ _945.9	2.056
(sum) χ² =				4.966

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

0a04_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	288	297.1	^{(288-297.1)²}⁄ _297.1	0.279
Pink Flowers	194	176.6	^{(194-176.6)²}⁄ _176.6	1.714
White Flowers	17	26.2	^(17-26.2)²⁄ _26.2	3.231
(sum) χ² =				5.224

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f44b_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	217	205.8	^{(217-205.8)²}⁄ _205.8	0.610
Pink Flowers	207	230.0	^{(207-230.0)²}⁄ _230.0	2.300
White Flowers	76	64.3	^(76-64.3)²⁄ _64.3	2.129
(sum) χ² =				5.038

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

dd0b_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	104	93.0	^(104-93.0)²⁄ _93.0	1.301
Pink Flowers	178	200.7	^{(178-200.7)²}⁄ _200.7	2.567
White Flowers	119	108.3	^{(119-108.3)²}⁄ _108.3	1.057
(sum) χ² =				4.926

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3849_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	274	283.7	^{(274-283.7)²}⁄ _283.7	0.332
Pink Flowers	204	185.9	^{(204-185.9)²}⁄ _185.9	1.762
White Flowers	21	30.5	^(21-30.5)²⁄ _30.5	2.959
(sum) χ² =				5.053

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ca4c_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	124	118.4	^{(124-118.4)²}⁄ _118.4	0.265
Pink Flowers	54	64.8	^(54-64.8)²⁄ _64.8	1.800
White Flowers	14	8.9	^(14-8.9)²⁄ _8.9	2.922
(sum) χ² =				4.987

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

256e_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	230	240.9	^{(230-240.9)²}⁄ _240.9	0.493
Pink Flowers	234	212.3	^{(234-212.3)²}⁄ _212.3	2.218
White Flowers	36	46.8	^(36-46.8)²⁄ _46.8	2.492
(sum) χ² =				5.204

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

e30a_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	17	12.5	^(17-12.5)²⁄ _12.5	1.620
Pink Flowers	26	35.0	^(26-35.0)²⁄ _35.0	2.314
White Flowers	29	24.6	^(29-24.6)²⁄ _24.6	0.787
(sum) χ² =				4.721

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.