MC

de8b_67ca

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 150 137.4 (150-137.4)2⁄ 137.4 1.155
 Pink Flowers 224 249.4 (224-249.4)2⁄ 249.4 2.587
 White Flowers 126 113.2 (126-113.2)2⁄ 113.2 1.447
(sum) χ2 =  5.190

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

00dc_c73f

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 179 166.4 (179-166.4)2⁄ 166.4 0.954
 Pink Flowers 220 244.1 (220-244.1)2⁄ 244.1 2.379
 White Flowers 102 89.5 (102-89.5)2⁄ 89.5 1.746
(sum) χ2 =  5.079

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

63c6_ba65

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 129 116.4 (129-116.4)2⁄ 116.4 1.364
 Pink Flowers 225 249.7 (225-249.7)2⁄ 249.7 2.443
 White Flowers 146 133.9 (146-133.9)2⁄ 133.9 1.093
(sum) χ2 =  4.901

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

d454_b4da

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 40 35.5 (40-35.5)2⁄ 35.5 0.570
 Pink Flowers 25 33.6 (25-33.6)2⁄ 33.6 2.201
 White Flowers 12 7.9 (12-7.9)2⁄ 7.9 2.128
(sum) χ2 =  4.899

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.68 and q=0.32. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

f942_dbd3

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 34 30.8 (34-30.8)2⁄ 30.8 0.332
 Pink Flowers 14 19.9 (14-19.9)2⁄ 19.9 1.749
 White Flowers 6 3.2 (6-3.2)2⁄ 3.2 2.450
(sum) χ2 =  4.532

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

8024_91de

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 62 55.3 (62-55.3)2⁄ 55.3 0.812
 Pink Flowers 58 71.0 (58-71.0)2⁄ 71.0 2.380
 White Flowers 29 22.8 (29-22.8)2⁄ 22.8 1.686
(sum) χ2 =  4.878

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

4b66_42da

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 191 202.5 (191-202.5)2⁄ 202.5 0.653
 Pink Flowers 255 231.4 (255-231.4)2⁄ 231.4 2.407
 White Flowers 55 66.1 (55-66.1)2⁄ 66.1 1.864
(sum) χ2 =  4.924

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

efbb_3b39

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 75 69.3 (75-69.3)2⁄ 69.3 0.469
 Pink Flowers 44 54.8 (44-54.8)2⁄ 54.8 2.128
 White Flowers 16 10.8 (16-10.8)2⁄ 10.8 2.504
(sum) χ2 =  5.101

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

2197_4df2

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 96 89.6 (96-89.6)2⁄ 89.6 0.457
 Pink Flowers 63 75.5 (63-75.5)2⁄ 75.5 2.070
 White Flowers 22 15.9 (22-15.9)2⁄ 15.9 2.340
(sum) χ2 =  4.867

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

f611_81fe

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 270 279.5 (270-279.5)2⁄ 279.5 0.323
 Pink Flowers 208 188.6 (208-188.6)2⁄ 188.6 1.996
 White Flowers 22 31.8 (22-31.8)2⁄ 31.8 3.020
(sum) χ2 =  5.339

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

79e4_66fe

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 134 146.3 (134-146.3)2⁄ 146.3 1.034
 Pink Flowers 273 248.3 (273-248.3)2⁄ 248.3 2.457
 White Flowers 93 105.4 (93-105.4)2⁄ 105.4 1.459
(sum) χ2 =  4.950

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

6613_524d

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 62 53.6 (62-53.6)2⁄ 53.6 1.316
 Pink Flowers 105 122.0 (105-122.0)2⁄ 122.0 2.369
 White Flowers 78 69.4 (78-69.4)2⁄ 69.4 1.066
(sum) χ2 =  4.751

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

71db_2dc7

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 238 227.0 (238-227.0)2⁄ 227.0 0.533
 Pink Flowers 198 219.8 (198-219.8)2⁄ 219.8 2.162
 White Flowers 64 53.2 (64-53.2)2⁄ 53.2 2.192
(sum) χ2 =  4.888

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

ae1f_dbd3

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 40 34.7 (40-34.7)2⁄ 34.7 0.810
 Pink Flowers 33 43.0 (33-43.0)2⁄ 43.0 2.326
 White Flowers 18 13.3 (18-13.3)2⁄ 13.3 1.661
(sum) χ2 =  4.796

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

cd29_2dc7

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 47 40.5 (47-40.5)2⁄ 40.5 1.043
 Pink Flowers 52 64.1 (52-64.1)2⁄ 64.1 2.284
 White Flowers 32 25.4 (32-25.4)2⁄ 25.4 1.715
(sum) χ2 =  5.042

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

5c35_3034

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 59 54.6 (59-54.6)2⁄ 54.6 0.355
 Pink Flowers 34 43.7 (34-43.7)2⁄ 43.7 2.153
 White Flowers 13 8.8 (13-8.8)2⁄ 8.8 2.005
(sum) χ2 =  4.512

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

71ce_9910

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 52 44.7 (52-44.7)2⁄ 44.7 1.192
 Pink Flowers 68 82.9 (68-82.9)2⁄ 82.9 2.678
 White Flowers 46 38.5 (46-38.5)2⁄ 38.5 1.461
(sum) χ2 =  5.331

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

30e6_524d

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 179 191.1 (179-191.1)2⁄ 191.1 0.766
 Pink Flowers 260 236.0 (260-236.0)2⁄ 236.0 2.441
 White Flowers 61 72.9 (61-72.9)2⁄ 72.9 1.943
(sum) χ2 =  5.149

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

7e45_91de

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 48 42.8 (48-42.8)2⁄ 42.8 0.632
 Pink Flowers 38 49.1 (38-49.1)2⁄ 49.1 2.509
 White Flowers 19 14.1 (19-14.1)2⁄ 14.1 1.703
(sum) χ2 =  4.844

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

5aae_4df2

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 75 66.2 (75-66.2)2⁄ 66.2 1.170
 Pink Flowers 114 132.0 (114-132.0)2⁄ 132.0 2.455
 White Flowers 75 65.8 (75-65.8)2⁄ 65.8 1.286
(sum) χ2 =  4.911

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

5ea1_481c

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 4382 4341.5 (4382-4341.5)2⁄ 4341.5 0.378
 Pink Flowers 3166 3245.9 (3166-3245.9)2⁄ 3245.9 1.967
 White Flowers 647 606.7 (647-606.7)2⁄ 606.7 2.677
(sum) χ2 =  5.022

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

bac9_6034

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 202 190.1 (202-190.1)2⁄ 190.1 0.745
 Pink Flowers 213 236.4 (213-236.4)2⁄ 236.4 2.316
 White Flowers 85 73.5 (85-73.5)2⁄ 73.5 1.799
(sum) χ2 =  4.860

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

244f_0222

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 38 32.3 (38-32.3)2⁄ 32.3 1.006
 Pink Flowers 46 57.8 (46-57.8)2⁄ 57.8 2.409
 White Flowers 32 25.9 (32-25.9)2⁄ 25.9 1.437
(sum) χ2 =  4.852

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

528c_ba65

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 119 113.5 (119-113.5)2⁄ 113.5 0.267
 Pink Flowers 54 64.4 (54-64.4)2⁄ 64.4 1.680
 White Flowers 14 9.1 (14-9.1)2⁄ 9.1 2.638
(sum) χ2 =  4.584

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

425b_67ca

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 100 87.9 (100-87.9)2⁄ 87.9 1.666
 Pink Flowers 219 243.5 (219-243.5)2⁄ 243.5 2.465
 White Flowers 181 168.6 (181-168.6)2⁄ 168.6 0.912
(sum) χ2 =  5.043

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

4a80_30a8

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 40 33.0 (40-33.0)2⁄ 33.0 1.485
 Pink Flowers 74 88.6 (74-88.6)2⁄ 88.6 2.406
 White Flowers 67 59.5 (67-59.5)2⁄ 59.5 0.945
(sum) χ2 =  4.836

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

e1c9_66fe

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 46 39.1 (46-39.1)2⁄ 39.1 1.218
 Pink Flowers 58 71.4 (58-71.4)2⁄ 71.4 2.515
 White Flowers 39 32.6 (39-32.6)2⁄ 32.6 1.256
(sum) χ2 =  4.989

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

7dd6_ab06

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 20 15.3 (20-15.3)2⁄ 15.3 1.444
 Pink Flowers 32 42.4 (32-42.4)2⁄ 42.4 2.551
 White Flowers 34 29.4 (34-29.4)2⁄ 29.4 0.720
(sum) χ2 =  4.714

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

f1ba_0940

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 115 102.4 (115-102.4)2⁄ 102.4 1.550
 Pink Flowers 223 247.8 (223-247.8)2⁄ 247.8 2.482
 White Flowers 162 149.8 (162-149.8)2⁄ 149.8 0.994
(sum) χ2 =  5.026

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

06ef_b10b

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 69 80.9 (69-80.9)2⁄ 80.9 1.750
 Pink Flowers 264 240.4 (264-240.4)2⁄ 240.4 2.317
 White Flowers 167 178.7 (167-178.7)2⁄ 178.7 0.766
(sum) χ2 =  4.833

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.40 and q=0.60. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

08d6_ba65

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 258 247.1 (258-247.1)2⁄ 247.1 0.481
 Pink Flowers 188 208.8 (188-208.8)2⁄ 208.8 2.072
 White Flowers 55 44.1 (55-44.1)2⁄ 44.1 2.694
(sum) χ2 =  5.247

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

633c_ba65

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 262 271.6 (262-271.6)2⁄ 271.6 0.339
 Pink Flowers 213 193.8 (213-193.8)2⁄ 193.8 1.902
 White Flowers 25 34.6 (25-34.6)2⁄ 34.6 2.664
(sum) χ2 =  4.905

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

7e5b_6034

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 16 11.4 (16-11.4)2⁄ 11.4 1.856
 Pink Flowers 19 27.7 (19-27.7)2⁄ 27.7 2.732
 White Flowers 21 16.8 (21-16.8)2⁄ 16.8 1.050
(sum) χ2 =  5.639

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

fd7e_66fe

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 42 38.7 (42-38.7)2⁄ 38.7 0.281
 Pink Flowers 18 25.2 (18-25.2)2⁄ 25.2 2.057
 White Flowers 8 4.1 (8-4.1)2⁄ 4.1 3.710
(sum) χ2 =  6.048

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

1f71_9910

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 58 52.2 (58-52.2)2⁄ 52.2 0.644
 Pink Flowers 43 54.6 (43-54.6)2⁄ 54.6 2.464
 White Flowers 20 14.3 (20-14.3)2⁄ 14.3 2.272
(sum) χ2 =  5.381

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

4f9b_3b39

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 160 172.4 (160-172.4)2⁄ 172.4 0.892
 Pink Flowers 267 242.4 (267-242.4)2⁄ 242.4 2.497
 White Flowers 73 85.2 (73-85.2)2⁄ 85.2 1.747
(sum) χ2 =  5.135

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

7b22_4df2

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 103 91.1 (103-91.1)2⁄ 91.1 1.554
 Pink Flowers 220 244.6 (220-244.6)2⁄ 244.6 2.474
 White Flowers 177 164.3 (177-164.3)2⁄ 164.3 0.982
(sum) χ2 =  5.010

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

6557_0222

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 19 14.4 (19-14.4)2⁄ 14.4 1.469
 Pink Flowers 29 38.2 (29-38.2)2⁄ 38.2 2.216
 White Flowers 30 25.3 (30-25.3)2⁄ 25.3 0.873
(sum) χ2 =  4.558

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

28cf_dbd3

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 66 62.5 (66-62.5)2⁄ 62.5 0.196
 Pink Flowers 27 34.7 (27-34.7)2⁄ 34.7 1.709
 White Flowers 9 4.8 (9-4.8)2⁄ 4.8 3.675
(sum) χ2 =  5.580

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

cabf_ab06

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 166 153.7 (166-153.7)2⁄ 153.7 0.984
 Pink Flowers 222 247.0 (222-247.0)2⁄ 247.0 2.530
 White Flowers 112 99.3 (112-99.3)2⁄ 99.3 1.624
(sum) χ2 =  5.139

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

5771_481c

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 46 40.8 (46-40.8)2⁄ 40.8 0.663
 Pink Flowers 35 44.9 (35-44.9)2⁄ 44.9 2.183
 White Flowers 17 12.4 (17-12.4)2⁄ 12.4 1.706
(sum) χ2 =  4.552

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

ebf0_81fe

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 42 36.0 (42-36.0)2⁄ 36.0 1.000
 Pink Flowers 54 66.4 (54-66.4)2⁄ 66.4 2.316
 White Flowers 37 30.6 (37-30.6)2⁄ 30.6 1.339
(sum) χ2 =  4.654

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

ef40_81fe

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 325 316.5 (325-316.5)2⁄ 316.5 0.228
 Pink Flowers 146 162.6 (146-162.6)2⁄ 162.6 1.695
 White Flowers 29 20.9 (29-20.9)2⁄ 20.9 3.139
(sum) χ2 =  5.062

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

51ed_af1c

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 255 264.7 (255-264.7)2⁄ 264.7 0.355
 Pink Flowers 218 198.2 (218-198.2)2⁄ 198.2 1.978
 White Flowers 27 37.1 (27-37.1)2⁄ 37.1 2.750
(sum) χ2 =  5.083

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

0454_4df2

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 157 168.8 (157-168.8)2⁄ 168.8 0.825
 Pink Flowers 268 243.4 (268-243.4)2⁄ 243.4 2.486
 White Flowers 76 87.8 (76-87.8)2⁄ 87.8 1.586
(sum) χ2 =  4.897

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

cefe_67ca

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 38 34.8 (38-34.8)2⁄ 34.8 0.294
 Pink Flowers 14 19.4 (14-19.4)2⁄ 19.4 1.503
 White Flowers 6 2.7 (6-2.7)2⁄ 2.7 4.033
(sum) χ2 =  5.831

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

cf2d_4df2

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 225 213.8 (225-213.8)2⁄ 213.8 0.587
 Pink Flowers 204 226.3 (204-226.3)2⁄ 226.3 2.197
 White Flowers 71 59.9 (71-59.9)2⁄ 59.9 2.057
(sum) χ2 =  4.841

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

8fd6_ab06

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 161 148.4 (161-148.4)2⁄ 148.4 1.070
 Pink Flowers 223 248.0 (223-248.0)2⁄ 248.0 2.520
 White Flowers 116 103.6 (116-103.6)2⁄ 103.6 1.484
(sum) χ2 =  5.074

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

2142_dbd3

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 31 24.4 (31-24.4)2⁄ 24.4 1.785
 Pink Flowers 55 67.7 (55-67.7)2⁄ 67.7 2.382
 White Flowers 53 46.9 (53-46.9)2⁄ 46.9 0.793
(sum) χ2 =  4.961

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

1d47_67ca

Table of Chi-Squared (χ2) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Observed Expected Calculation Statistic
 Red Flowers 214 202.0 (214-202.0)2⁄ 202.0 0.713
 Pink Flowers 208 231.6 (208-231.6)2⁄ 231.6 2.405
 White Flowers 78 66.4 (78-66.4)2⁄ 66.4 2.027
(sum) χ2 =  5.144

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ2) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ2) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ2) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ2) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ2) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect