MC

e1ba_fe12

Genotype Diversity in Hybrid Cross

Mary and Rebecca are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Mary genotypeAabbCcDD 
Rebecca genotypeaaBbCcDD 
(a) Mary gametes     
(b) Rebecca gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

a52f_3280

Genotype Diversity in Hybrid Cross

Ravikumar and Xavier are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Ravikumar genotypeaaBBCCDd 
Xavier genotypeaaBBCcDd 
(a) Ravikumar gametes     
(b) Xavier gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Correct 23   = 8 (i.e. 3 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

df22_e57f

Genotype Diversity in Hybrid Cross

Jocelyn and Lupe are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jocelyn genotypeaaBbCcDd 
Lupe genotypeaaBbCCDd 
(a) Jocelyn gametes     
(b) Lupe gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

78fc_6444

Genotype Diversity in Hybrid Cross

Vanessa and Toni are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Vanessa genotypeAaBbCcDd 
Toni genotypeaaBbCcDd 
(a) Vanessa gametes     
(b) Toni gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Correct 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

0752_ecef

Genotype Diversity in Hybrid Cross

Silvana and Marta are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Silvana genotypeaaBbCcDd 
Marta genotypeAABbccdd 
(a) Silvana gametes     
(b) Marta gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

71c8_6cc7

Genotype Diversity in Hybrid Cross

Antonia and Namrah are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Antonia genotypeAABBCcdd 
Namrah genotypeAaBbccDd 
(a) Antonia gametes     
(b) Namrah gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

c6b9_e1f9

Genotype Diversity in Hybrid Cross

Praveena and Amanda are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Praveena genotypeAAbbccDd 
Amanda genotypeAABbCCdd 
(a) Praveena gametes     
(b) Amanda gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

7f3d_204c

Genotype Diversity in Hybrid Cross

Nivedha and Aysun are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Nivedha genotypeaaBbCcDD 
Aysun genotypeAaBBCcdd 
(a) Nivedha gametes     
(b) Aysun gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

4a84_a96a

Genotype Diversity in Hybrid Cross

Itzel and Megan are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Itzel genotypeAaBBCCDd 
Megan genotypeAabbCCDd 
(a) Itzel gametes     
(b) Megan gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Correct 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

66a1_b04b

Genotype Diversity in Hybrid Cross

Rudmine and Sunya are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Rudmine genotypeAaBbCCdd 
Sunya genotypeAaBbCCDD 
(a) Rudmine gametes     
(b) Sunya gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

16ee_6cc7

Genotype Diversity in Hybrid Cross

Ramon and Mackenzye are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Ramon genotypeaaBbCcDD 
Mackenzye genotypeAabbccDd 
(a) Ramon gametes     
(b) Mackenzye gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

5bc4_1865

Genotype Diversity in Hybrid Cross

Abbey and Perla are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Abbey genotypeAaBBCcDd 
Perla genotypeAaBbCcDD 
(a) Abbey gametes     
(b) Perla gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct MC

3473_80f4

Genotype Diversity in Hybrid Cross

Misbah and Alona are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Misbah genotypeAaBbccdd 
Alona genotypeAabbCcdd 
(a) Misbah gametes     
(b) Alona gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

70a0_d07e

Genotype Diversity in Hybrid Cross

Mehul and Riddhi are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Mehul genotypeAaBbCcDd 
Riddhi genotypeAaBbCcdd 
(a) Mehul gametes     
(b) Riddhi gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Correct 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

31a6_bd8e

Genotype Diversity in Hybrid Cross

Anupam and Nur are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Anupam genotypeAaBBCCDD 
Nur genotypeAaBBCCDd 
(a) Anupam gametes     
(b) Nur gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Correct 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

d2f9_6cc7

Genotype Diversity in Hybrid Cross

Dulce and Monika are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Dulce genotypeaaBbccDd 
Monika genotypeAabbCcdd 
(a) Dulce gametes     
(b) Monika gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

4dfc_f99c

Genotype Diversity in Hybrid Cross

Kirstin and Kayla are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Kirstin genotypeAABbCcDd 
Kayla genotypeAaBBCCDd 
(a) Kirstin gametes     
(b) Kayla gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Correct 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

9ec5_6b70

Genotype Diversity in Hybrid Cross

Haneef and Yamini are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Haneef genotypeaaBbCCDd 
Yamini genotypeaaBBCcDd 
(a) Haneef gametes     
(b) Yamini gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect MC

5542_948e

Genotype Diversity in Hybrid Cross

Valbhi and kushil are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Valbhi genotypeAabbCcDd 
kushil genotypeAABbCcdd 
(a) Valbhi gametes     
(b) kushil gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Correct 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

78eb_6cc7

Genotype Diversity in Hybrid Cross

Rosanna and Karen are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Rosanna genotypeaaBbCcDD 
Karen genotypeAaBBccDd 
(a) Rosanna gametes     
(b) Karen gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

1fe7_2acf

Genotype Diversity in Hybrid Cross

Yoana and Hasena are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Yoana genotypeAaBbCcDd 
Hasena genotypeAaBbCcDd 
(a) Yoana gametes     
(b) Hasena gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
32   = 9 (i.e. 2 genes with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect 34   = 81 (i.e. 4 genes with three forms) Correct MC

9395_57cb

Genotype Diversity in Hybrid Cross

Abram and Jamie are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Abram genotypeAaBbCcDd 
Jamie genotypeAAbbCcDd 
(a) Abram gametes     
(b) Jamie gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

797a_3459

Genotype Diversity in Hybrid Cross

Husna and Rory are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Husna genotypeaaBbCCDd 
Rory genotypeAaBbCcDd 
(a) Husna gametes     
(b) Rory gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
23   = 8 (i.e. 3 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

265f_d4f6

Genotype Diversity in Hybrid Cross

Abdul and Nathickshi are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Abdul genotypeAabbccDd 
Nathickshi genotypeAabbCCDD 
(a) Abdul gametes     
(b) Nathickshi gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Correct 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect MC

369d_1a9b

Genotype Diversity in Hybrid Cross

Harika and Rachel are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Harika genotypeAabbCcdd 
Rachel genotypeAaBbccDd 
(a) Harika gametes     
(b) Rachel gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Correct 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

0088_17b9

Genotype Diversity in Hybrid Cross

Salman and Sthefani are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Salman genotypeaaBBCCDd 
Sthefani genotypeAaBBCcdd 
(a) Salman gametes     
(b) Sthefani gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

3fdb_d25a

Genotype Diversity in Hybrid Cross

Hiedy and Mackenzye are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Hiedy genotypeAaBBCcDD 
Mackenzye genotypeAaBbCcDD 
(a) Hiedy gametes     
(b) Mackenzye gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Correct 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

b2f6_d20e

Genotype Diversity in Hybrid Cross

Nina and Ivanna are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Nina genotypeaaBbCcdd 
Ivanna genotypeAaBBCcDD 
(a) Nina gametes     
(b) Ivanna gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

e0e0_e043

Genotype Diversity in Hybrid Cross

Tom and Naheda are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Tom genotypeaaBbCcdd 
Naheda genotypeAABbCcDD 
(a) Tom gametes     
(b) Naheda gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Correct 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

d6f4_8abc

Genotype Diversity in Hybrid Cross

Clinton and Jenna are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Clinton genotypeAABbccDd 
Jenna genotypeAABbCcDd 
(a) Clinton gametes     
(b) Jenna gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Correct 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

d2bd_9de8

Genotype Diversity in Hybrid Cross

Hilda and Nyah are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Hilda genotypeAaBbCCDd 
Nyah genotypeAaBbCcDd 
(a) Hilda gametes     
(b) Nyah gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Correct 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

e1df_46a9

Genotype Diversity in Hybrid Cross

Yamini and Tania are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Yamini genotypeAaBBccDd 
Tania genotypeAaBBCcdd 
(a) Yamini gametes     
(b) Tania gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect MC

9b3a_0a9d

Genotype Diversity in Hybrid Cross

Aditi and Safi are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Aditi genotypeaabbccDd 
Safi genotypeaabbCcDd 
(a) Aditi gametes     
(b) Safi gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Correct 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

d9a1_c90e

Genotype Diversity in Hybrid Cross

Amtul and Ryan are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Amtul genotypeAaBbCcDd 
Ryan genotypeAaBbCCdd 
(a) Amtul gametes     
(b) Ryan gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct MC

40b8_8632

Genotype Diversity in Hybrid Cross

Suchi and Katya are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Suchi genotypeAabbCcdd 
Katya genotypeAaBbCcDd 
(a) Suchi gametes     
(b) Katya gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
32   = 9 (i.e. 2 genes with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

bf2b_d20e

Genotype Diversity in Hybrid Cross

Shal and Tempie are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Shal genotypeAaBbCCDD 
Tempie genotypeaaBbccDd 
(a) Shal gametes     
(b) Tempie gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

cb34_205d

Genotype Diversity in Hybrid Cross

Jeanette and Aashi are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jeanette genotypeAabbCCDd 
Aashi genotypeAabbCCDd 
(a) Jeanette gametes     
(b) Aashi gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

1ac6_0f3c

Genotype Diversity in Hybrid Cross

Mackenzye and Praveena are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Mackenzye genotypeAaBbCCDd 
Praveena genotypeAAbbCCDd 
(a) Mackenzye gametes     
(b) Praveena gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

b541_03b9

Genotype Diversity in Hybrid Cross

Michael and Jamie are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Michael genotypeAabbCcDd 
Jamie genotypeAABbCcDd 
(a) Michael gametes     
(b) Jamie gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct MC

b22a_78e7

Genotype Diversity in Hybrid Cross

Suchi and Ethan are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Suchi genotypeAabbccDd 
Ethan genotypeaaBbCCDD 
(a) Suchi gametes     
(b) Ethan gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect MC

46dc_3920

Genotype Diversity in Hybrid Cross

Cory and Urszula are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Cory genotypeaaBbCcDd 
Urszula genotypeaaBbccdd 
(a) Cory gametes     
(b) Urszula gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect 2 × 33   = 54 (i.e. 1 gene with two forms and 3 genes with three forms) Incorrect MC

0ce9_ec44

Genotype Diversity in Hybrid Cross

Abdul and Courtney are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Abdul genotypeaabbCcDd 
Courtney genotypeAaBbCcDd 
(a) Abdul gametes     
(b) Courtney gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct MC

f432_7e5f

Genotype Diversity in Hybrid Cross

Daisy and Genesis are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Daisy genotypeAaBbCcDd 
Genesis genotypeAaBbccDD 
(a) Daisy gametes     
(b) Genesis gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct MC

8d8b_fd83

Genotype Diversity in Hybrid Cross

Katherine and Mikaela are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Katherine genotypeAaBbCcDd 
Mikaela genotypeAaBBCCDd 
(a) Katherine gametes     
(b) Mikaela gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct 34   = 81 (i.e. 4 genes with three forms) Incorrect MC

d85d_fc76

Genotype Diversity in Hybrid Cross

Selena and Kathryn are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Selena genotypeAAbbCcdd 
Kathryn genotypeAabbCcdd 
(a) Selena gametes     
(b) Kathryn gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Correct 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect MC

f483_c90e

Genotype Diversity in Hybrid Cross

Salume and Erick are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Salume genotypeAaBBCcDD 
Erick genotypeAaBBccdd 
(a) Salume gametes     
(b) Erick gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Correct 32   = 9 (i.e. 2 genes with three forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Incorrect MC

d97f_1c4b

Genotype Diversity in Hybrid Cross

Conor and Dima are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Conor genotypeAABbCcDd 
Dima genotypeAaBbccDd 
(a) Conor gametes     
(b) Dima gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect 22 × 32   = 36 (i.e. 2 genes with two forms and 2 genes with three forms) Correct MC

b391_48cb

Genotype Diversity in Hybrid Cross

Isaac and Adria are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Isaac genotypeAAbbCcDd 
Adria genotypeAabbCCDd 
(a) Isaac gametes     
(b) Adria gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
23   = 8 (i.e. 3 genes with two forms) Incorrect 32   = 9 (i.e. 2 genes with three forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect MC

aa22_81ba

Genotype Diversity in Hybrid Cross

Mikhail and Abbey are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Mikhail genotypeAAbbCcdd 
Abbey genotypeAaBbCcdd 
(a) Mikhail gametes     
(b) Abbey gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Correct 24   = 16 (i.e. 4 genes with two forms) Incorrect 33   = 27 (i.e. 3 genes with three forms) Incorrect MC

8a6f_76ae

Genotype Diversity in Hybrid Cross

Brenda and Miguel are crossed. Use their genotypes to determine the number of different genotypes possible in their offspring.

Assume that all genes sort independently and display complete dominance.

Hint: For each gene pair from the parents, you can get 1, 2, or 3 unique genotypes.
This is based on the combinations: homozygous x homozygous (1), homozygous x heterozygous (2), and heterozygous x heterozygous (3).

Considering the principle of independent assortment, how many unique GENOTYPES could be produced in a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Brenda genotypeaaBBCcDD 
Miguel genotypeAABbccDD 
(a) Brenda gametes     
(b) Miguel gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Incorrect 2 × 32   = 18 (i.e. 1 gene with two forms and 2 genes with three forms) Incorrect 23 × 3   = 24 (i.e. 3 genes with two forms and 1 gene with three forms) Incorrect