MC
a03d_1f80
Mikaela and Sam are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Mikaela genotype | Aa | bb | CC | Dd | |
| Sam genotype | AA | Bb | Cc | Dd | |
| (a) Mikaela gametes | |||||
| (b) Sam gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
5ac2_1f80
Rulaa and Het are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Rulaa genotype | AA | Bb | cc | Dd | |
| Het genotype | Aa | bb | Cc | DD | |
| (a) Rulaa gametes | |||||
| (b) Het gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
5016_1f80
Emaad and Mudrika are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Emaad genotype | AA | Bb | CC | Dd | |
| Mudrika genotype | aa | bb | Cc | dd | |
| (a) Emaad gametes | |||||
| (b) Mudrika gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
e1f6_1f80
Aye and Salume are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Aye genotype | aa | Bb | Cc | DD | |
| Salume genotype | Aa | Bb | Cc | dd | |
| (a) Aye gametes | |||||
| (b) Salume gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
6676_1f80
Shal and Kenza are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Shal genotype | AA | bb | cc | Dd | |
| Kenza genotype | aa | Bb | Cc | dd | |
| (a) Shal gametes | |||||
| (b) Kenza gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
c57f_1f80
Brenda and Silver are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Brenda genotype | Aa | Bb | Cc | Dd | |
| Silver genotype | AA | Bb | cc | Dd | |
| (a) Brenda gametes | |||||
| (b) Silver gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
38fd_1f80
Rafiaa and Jake are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Rafiaa genotype | aa | Bb | Cc | Dd | |
| Jake genotype | Aa | Bb | CC | Dd | |
| (a) Rafiaa gametes | |||||
| (b) Jake gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
b13c_319e
Jane and Mit are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Jane genotype | Aa | Bb | Cc | Dd | |
| Mit genotype | Aa | Bb | cc | dd | |
| (a) Jane gametes | |||||
| (b) Mit gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
44a5_1f80
Tricia and Firdose are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Tricia genotype | aa | BB | Cc | Dd | |
| Firdose genotype | Aa | Bb | Cc | Dd | |
| (a) Tricia gametes | |||||
| (b) Firdose gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
d1b2_1f80
Pravalika and Dan are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Pravalika genotype | Aa | BB | cc | Dd | |
| Dan genotype | aa | Bb | Cc | DD | |
| (a) Pravalika gametes | |||||
| (b) Dan gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
3e37_1f80
Deanna and Vibhuti are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Deanna genotype | aa | BB | Cc | Dd | |
| Vibhuti genotype | aa | BB | Cc | Dd | |
| (a) Deanna gametes | |||||
| (b) Vibhuti gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
f2f8_319e
Alishah and Serene are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Alishah genotype | aa | Bb | Cc | Dd | |
| Serene genotype | Aa | Bb | cc | Dd | |
| (a) Alishah gametes | |||||
| (b) Serene gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
517b_1f80
Medard and Anjali are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Medard genotype | Aa | Bb | Cc | Dd | |
| Anjali genotype | AA | Bb | Cc | Dd | |
| (a) Medard gametes | |||||
| (b) Anjali gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
2c8d_319e
Agnes and Isabel are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Agnes genotype | Aa | Bb | Cc | dd | |
| Isabel genotype | Aa | Bb | Cc | Dd | |
| (a) Agnes gametes | |||||
| (b) Isabel gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
84dd_1f80
Nihar and Dishank are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Nihar genotype | Aa | Bb | Cc | dd | |
| Dishank genotype | AA | Bb | Cc | Dd | |
| (a) Nihar gametes | |||||
| (b) Dishank gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
a613_1f80
Mackenzye and Leonardo are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Mackenzye genotype | AA | BB | cc | Dd | |
| Leonardo genotype | Aa | Bb | Cc | Dd | |
| (a) Mackenzye gametes | |||||
| (b) Leonardo gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
f6ce_319e
Jayasurya and Marta are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Jayasurya genotype | Aa | bb | Cc | dd | |
| Marta genotype | aa | Bb | cc | Dd | |
| (a) Jayasurya gametes | |||||
| (b) Marta gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
70b4_1f80
Marta and Miraj are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Marta genotype | AA | Bb | Cc | dd | |
| Miraj genotype | Aa | Bb | Cc | DD | |
| (a) Marta gametes | |||||
| (b) Miraj gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
990d_1f80
Jane and Alex are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Jane genotype | aa | bb | cc | Dd | |
| Alex genotype | aa | Bb | Cc | DD | |
| (a) Jane gametes | |||||
| (b) Alex gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
fda7_319e
Rutuja and Travis are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Rutuja genotype | Aa | bb | cc | Dd | |
| Travis genotype | Aa | Bb | Cc | dd | |
| (a) Rutuja gametes | |||||
| (b) Travis gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
69cd_1f80
Firdose and Sierra are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Firdose genotype | Aa | Bb | cc | DD | |
| Sierra genotype | Aa | bb | cc | Dd | |
| (a) Firdose gametes | |||||
| (b) Sierra gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
1094_1f80
Yuritzy and Leila are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Yuritzy genotype | Aa | BB | Cc | Dd | |
| Leila genotype | Aa | Bb | CC | Dd | |
| (a) Yuritzy gametes | |||||
| (b) Leila gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
9963_1f80
Arinola and Kirk are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Arinola genotype | Aa | BB | cc | Dd | |
| Kirk genotype | Aa | Bb | Cc | Dd | |
| (a) Arinola gametes | |||||
| (b) Kirk gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
b7f4_1f80
Henry and Salman are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Henry genotype | AA | Bb | Cc | Dd | |
| Salman genotype | Aa | bb | Cc | Dd | |
| (a) Henry gametes | |||||
| (b) Salman gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
80e8_1f80
Alishah and Shahd are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Alishah genotype | AA | Bb | CC | Dd | |
| Shahd genotype | Aa | Bb | cc | dd | |
| (a) Alishah gametes | |||||
| (b) Shahd gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
06bc_1f80
Stefany and Jasmin are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Stefany genotype | Aa | Bb | cc | dd | |
| Jasmin genotype | Aa | BB | Cc | DD | |
| (a) Stefany gametes | |||||
| (b) Jasmin gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
6f10_1f80
Jullisa and Aye are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Jullisa genotype | aa | BB | Cc | DD | |
| Aye genotype | Aa | Bb | cc | dd | |
| (a) Jullisa gametes | |||||
| (b) Aye gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
51b1_1f80
Simranjit and Eunbi are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Simranjit genotype | Aa | bb | cc | DD | |
| Eunbi genotype | Aa | Bb | Cc | Dd | |
| (a) Simranjit gametes | |||||
| (b) Eunbi gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
fcbb_1f80
Richa and Danny are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Richa genotype | Aa | Bb | cc | DD | |
| Danny genotype | aa | BB | Cc | Dd | |
| (a) Richa gametes | |||||
| (b) Danny gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
2694_1f80
Hilary and Shaheryar are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Hilary genotype | AA | Bb | Cc | DD | |
| Shaheryar genotype | aa | Bb | Cc | dd | |
| (a) Hilary gametes | |||||
| (b) Shaheryar gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
2a32_1f80
Daisy and Felipe are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Daisy genotype | AA | Bb | cc | Dd | |
| Felipe genotype | aa | BB | Cc | Dd | |
| (a) Daisy gametes | |||||
| (b) Felipe gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
3f0c_1f80
Naba and Jazzmyne are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Naba genotype | Aa | BB | Cc | Dd | |
| Jazzmyne genotype | aa | Bb | cc | Dd | |
| (a) Naba gametes | |||||
| (b) Jazzmyne gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
5d78_1f80
Nicole and Brittnie are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Nicole genotype | AA | Bb | Cc | Dd | |
| Brittnie genotype | Aa | bb | Cc | dd | |
| (a) Nicole gametes | |||||
| (b) Brittnie gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
6b9c_1f80
Shaheryar and Mireya are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Shaheryar genotype | Aa | Bb | Cc | Dd | |
| Mireya genotype | Aa | Bb | CC | Dd | |
| (a) Shaheryar gametes | |||||
| (b) Mireya gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
342a_1f80
Robert and Ashur are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Robert genotype | Aa | BB | Cc | Dd | |
| Ashur genotype | Aa | bb | Cc | Dd | |
| (a) Robert gametes | |||||
| (b) Ashur gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
0f61_1f80
Stefany and Alina are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Stefany genotype | Aa | Bb | cc | dd | |
| Alina genotype | Aa | BB | Cc | Dd | |
| (a) Stefany gametes | |||||
| (b) Alina gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
003a_1f80
Najmeh and Shubham are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Najmeh genotype | Aa | Bb | cc | Dd | |
| Shubham genotype | Aa | bb | CC | dd | |
| (a) Najmeh gametes | |||||
| (b) Shubham gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
22db_1f80
Melissa and Ibrahim are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Melissa genotype | Aa | bb | CC | dd | |
| Ibrahim genotype | aa | Bb | CC | Dd | |
| (a) Melissa gametes | |||||
| (b) Ibrahim gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
e26d_1f80
Doha and Norhan are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Doha genotype | AA | Bb | cc | dd | |
| Norhan genotype | Aa | Bb | Cc | Dd | |
| (a) Doha gametes | |||||
| (b) Norhan gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
a802_1f80
Phylicia and Sejal are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Phylicia genotype | AA | Bb | cc | dd | |
| Sejal genotype | Aa | bb | CC | Dd | |
| (a) Phylicia gametes | |||||
| (b) Sejal gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
e388_1f80
Pravalika and Jas are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Pravalika genotype | Aa | Bb | CC | Dd | |
| Jas genotype | Aa | Bb | cc | Dd | |
| (a) Pravalika gametes | |||||
| (b) Jas gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
26bd_1f80
Rusul and Matthew are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Rusul genotype | Aa | Bb | cc | Dd | |
| Matthew genotype | Aa | Bb | CC | Dd | |
| (a) Rusul gametes | |||||
| (b) Matthew gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
450a_1f80
Nate and Maricarmen are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Nate genotype | aa | Bb | cc | Dd | |
| Maricarmen genotype | Aa | Bb | Cc | DD | |
| (a) Nate gametes | |||||
| (b) Maricarmen gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
7eec_1f80
Jagoda and Mary are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Jagoda genotype | Aa | bb | Cc | DD | |
| Mary genotype | Aa | bb | Cc | Dd | |
| (a) Jagoda gametes | |||||
| (b) Mary gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
cdba_1f80
Sydney and Marianne are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Sydney genotype | AA | BB | Cc | Dd | |
| Marianne genotype | AA | bb | cc | Dd | |
| (a) Sydney gametes | |||||
| (b) Marianne gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
6d56_1f80
Lisa and Krystyna are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Lisa genotype | AA | Bb | cc | dd | |
| Krystyna genotype | Aa | BB | Cc | Dd | |
| (a) Lisa gametes | |||||
| (b) Krystyna gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
bbde_1f80
Ava and Silver are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Ava genotype | aa | Bb | Cc | Dd | |
| Silver genotype | aa | bb | cc | Dd | |
| (a) Ava gametes | |||||
| (b) Silver gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
8bb8_1f80
Erick and Alex are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Erick genotype | aa | Bb | CC | Dd | |
| Alex genotype | aa | bb | CC | Dd | |
| (a) Erick gametes | |||||
| (b) Alex gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
5481_1f80
Sonia and Alex are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Sonia genotype | Aa | bb | Cc | dd | |
| Alex genotype | aa | Bb | Cc | DD | |
| (a) Sonia gametes | |||||
| (b) Alex gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||
80bd_319e
Abram and Vikram are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.
Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.
Assume complete dominance and the principle of independent assortment for all genes.
Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?
Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.
Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.
Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.
| Genes → | A | B | C | D | TOTAL |
|---|---|---|---|---|---|
| Abram genotype | Aa | Bb | Cc | Dd | |
| Vikram genotype | aa | bb | Cc | Dd | |
| (a) Abram gametes | |||||
| (b) Vikram gametes | |||||
| (c) Punnett square size | → | ||||
| (d) Number of cross genotypes | |||||
| (e) Number of cross phenotypes | |||||