MC

a03d_1f80

Phenotype Diversity in Hybrid Cross

Mikaela and Sam are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Mikaela genotypeAabbCCDd 
Sam genotypeAABbCcDd 
(a) Mikaela gametes     
(b) Sam gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

5ac2_1f80

Phenotype Diversity in Hybrid Cross

Rulaa and Het are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Rulaa genotypeAABbccDd 
Het genotypeAabbCcDD 
(a) Rulaa gametes     
(b) Het gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

5016_1f80

Phenotype Diversity in Hybrid Cross

Emaad and Mudrika are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Emaad genotypeAABbCCDd 
Mudrika genotypeaabbCcdd 
(a) Emaad gametes     
(b) Mudrika gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

e1f6_1f80

Phenotype Diversity in Hybrid Cross

Aye and Salume are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Aye genotypeaaBbCcDD 
Salume genotypeAaBbCcdd 
(a) Aye gametes     
(b) Salume gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

6676_1f80

Phenotype Diversity in Hybrid Cross

Shal and Kenza are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Shal genotypeAAbbccDd 
Kenza genotypeaaBbCcdd 
(a) Shal gametes     
(b) Kenza gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

c57f_1f80

Phenotype Diversity in Hybrid Cross

Brenda and Silver are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Brenda genotypeAaBbCcDd 
Silver genotypeAABbccDd 
(a) Brenda gametes     
(b) Silver gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

38fd_1f80

Phenotype Diversity in Hybrid Cross

Rafiaa and Jake are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Rafiaa genotypeaaBbCcDd 
Jake genotypeAaBbCCDd 
(a) Rafiaa gametes     
(b) Jake gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

b13c_319e

Phenotype Diversity in Hybrid Cross

Jane and Mit are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jane genotypeAaBbCcDd 
Mit genotypeAaBbccdd 
(a) Jane gametes     
(b) Mit gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct MC

44a5_1f80

Phenotype Diversity in Hybrid Cross

Tricia and Firdose are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Tricia genotypeaaBBCcDd 
Firdose genotypeAaBbCcDd 
(a) Tricia gametes     
(b) Firdose gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

d1b2_1f80

Phenotype Diversity in Hybrid Cross

Pravalika and Dan are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Pravalika genotypeAaBBccDd 
Dan genotypeaaBbCcDD 
(a) Pravalika gametes     
(b) Dan gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

3e37_1f80

Phenotype Diversity in Hybrid Cross

Deanna and Vibhuti are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Deanna genotypeaaBBCcDd 
Vibhuti genotypeaaBBCcDd 
(a) Deanna gametes     
(b) Vibhuti gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

f2f8_319e

Phenotype Diversity in Hybrid Cross

Alishah and Serene are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Alishah genotypeaaBbCcDd 
Serene genotypeAaBbccDd 
(a) Alishah gametes     
(b) Serene gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct MC

517b_1f80

Phenotype Diversity in Hybrid Cross

Medard and Anjali are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Medard genotypeAaBbCcDd 
Anjali genotypeAABbCcDd 
(a) Medard gametes     
(b) Anjali gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

2c8d_319e

Phenotype Diversity in Hybrid Cross

Agnes and Isabel are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Agnes genotypeAaBbCcdd 
Isabel genotypeAaBbCcDd 
(a) Agnes gametes     
(b) Isabel gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct MC

84dd_1f80

Phenotype Diversity in Hybrid Cross

Nihar and Dishank are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Nihar genotypeAaBbCcdd 
Dishank genotypeAABbCcDd 
(a) Nihar gametes     
(b) Dishank gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

a613_1f80

Phenotype Diversity in Hybrid Cross

Mackenzye and Leonardo are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Mackenzye genotypeAABBccDd 
Leonardo genotypeAaBbCcDd 
(a) Mackenzye gametes     
(b) Leonardo gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

f6ce_319e

Phenotype Diversity in Hybrid Cross

Jayasurya and Marta are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jayasurya genotypeAabbCcdd 
Marta genotypeaaBbccDd 
(a) Jayasurya gametes     
(b) Marta gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct MC

70b4_1f80

Phenotype Diversity in Hybrid Cross

Marta and Miraj are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Marta genotypeAABbCcdd 
Miraj genotypeAaBbCcDD 
(a) Marta gametes     
(b) Miraj gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

990d_1f80

Phenotype Diversity in Hybrid Cross

Jane and Alex are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jane genotypeaabbccDd 
Alex genotypeaaBbCcDD 
(a) Jane gametes     
(b) Alex gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

fda7_319e

Phenotype Diversity in Hybrid Cross

Rutuja and Travis are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Rutuja genotypeAabbccDd 
Travis genotypeAaBbCcdd 
(a) Rutuja gametes     
(b) Travis gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct MC

69cd_1f80

Phenotype Diversity in Hybrid Cross

Firdose and Sierra are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Firdose genotypeAaBbccDD 
Sierra genotypeAabbccDd 
(a) Firdose gametes     
(b) Sierra gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

1094_1f80

Phenotype Diversity in Hybrid Cross

Yuritzy and Leila are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Yuritzy genotypeAaBBCcDd 
Leila genotypeAaBbCCDd 
(a) Yuritzy gametes     
(b) Leila gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

9963_1f80

Phenotype Diversity in Hybrid Cross

Arinola and Kirk are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Arinola genotypeAaBBccDd 
Kirk genotypeAaBbCcDd 
(a) Arinola gametes     
(b) Kirk gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

b7f4_1f80

Phenotype Diversity in Hybrid Cross

Henry and Salman are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Henry genotypeAABbCcDd 
Salman genotypeAabbCcDd 
(a) Henry gametes     
(b) Salman gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

80e8_1f80

Phenotype Diversity in Hybrid Cross

Alishah and Shahd are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Alishah genotypeAABbCCDd 
Shahd genotypeAaBbccdd 
(a) Alishah gametes     
(b) Shahd gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

06bc_1f80

Phenotype Diversity in Hybrid Cross

Stefany and Jasmin are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Stefany genotypeAaBbccdd 
Jasmin genotypeAaBBCcDD 
(a) Stefany gametes     
(b) Jasmin gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

6f10_1f80

Phenotype Diversity in Hybrid Cross

Jullisa and Aye are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jullisa genotypeaaBBCcDD 
Aye genotypeAaBbccdd 
(a) Jullisa gametes     
(b) Aye gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

51b1_1f80

Phenotype Diversity in Hybrid Cross

Simranjit and Eunbi are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Simranjit genotypeAabbccDD 
Eunbi genotypeAaBbCcDd 
(a) Simranjit gametes     
(b) Eunbi gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

fcbb_1f80

Phenotype Diversity in Hybrid Cross

Richa and Danny are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Richa genotypeAaBbccDD 
Danny genotypeaaBBCcDd 
(a) Richa gametes     
(b) Danny gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

2694_1f80

Phenotype Diversity in Hybrid Cross

Hilary and Shaheryar are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Hilary genotypeAABbCcDD 
Shaheryar genotypeaaBbCcdd 
(a) Hilary gametes     
(b) Shaheryar gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

2a32_1f80

Phenotype Diversity in Hybrid Cross

Daisy and Felipe are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Daisy genotypeAABbccDd 
Felipe genotypeaaBBCcDd 
(a) Daisy gametes     
(b) Felipe gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

3f0c_1f80

Phenotype Diversity in Hybrid Cross

Naba and Jazzmyne are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Naba genotypeAaBBCcDd 
Jazzmyne genotypeaaBbccDd 
(a) Naba gametes     
(b) Jazzmyne gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

5d78_1f80

Phenotype Diversity in Hybrid Cross

Nicole and Brittnie are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Nicole genotypeAABbCcDd 
Brittnie genotypeAabbCcdd 
(a) Nicole gametes     
(b) Brittnie gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

6b9c_1f80

Phenotype Diversity in Hybrid Cross

Shaheryar and Mireya are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Shaheryar genotypeAaBbCcDd 
Mireya genotypeAaBbCCDd 
(a) Shaheryar gametes     
(b) Mireya gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

342a_1f80

Phenotype Diversity in Hybrid Cross

Robert and Ashur are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Robert genotypeAaBBCcDd 
Ashur genotypeAabbCcDd 
(a) Robert gametes     
(b) Ashur gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

0f61_1f80

Phenotype Diversity in Hybrid Cross

Stefany and Alina are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Stefany genotypeAaBbccdd 
Alina genotypeAaBBCcDd 
(a) Stefany gametes     
(b) Alina gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

003a_1f80

Phenotype Diversity in Hybrid Cross

Najmeh and Shubham are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Najmeh genotypeAaBbccDd 
Shubham genotypeAabbCCdd 
(a) Najmeh gametes     
(b) Shubham gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

22db_1f80

Phenotype Diversity in Hybrid Cross

Melissa and Ibrahim are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Melissa genotypeAabbCCdd 
Ibrahim genotypeaaBbCCDd 
(a) Melissa gametes     
(b) Ibrahim gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

e26d_1f80

Phenotype Diversity in Hybrid Cross

Doha and Norhan are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Doha genotypeAABbccdd 
Norhan genotypeAaBbCcDd 
(a) Doha gametes     
(b) Norhan gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

a802_1f80

Phenotype Diversity in Hybrid Cross

Phylicia and Sejal are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Phylicia genotypeAABbccdd 
Sejal genotypeAabbCCDd 
(a) Phylicia gametes     
(b) Sejal gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

e388_1f80

Phenotype Diversity in Hybrid Cross

Pravalika and Jas are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Pravalika genotypeAaBbCCDd 
Jas genotypeAaBbccDd 
(a) Pravalika gametes     
(b) Jas gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

26bd_1f80

Phenotype Diversity in Hybrid Cross

Rusul and Matthew are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Rusul genotypeAaBbccDd 
Matthew genotypeAaBbCCDd 
(a) Rusul gametes     
(b) Matthew gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

450a_1f80

Phenotype Diversity in Hybrid Cross

Nate and Maricarmen are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Nate genotypeaaBbccDd 
Maricarmen genotypeAaBbCcDD 
(a) Nate gametes     
(b) Maricarmen gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

7eec_1f80

Phenotype Diversity in Hybrid Cross

Jagoda and Mary are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Jagoda genotypeAabbCcDD 
Mary genotypeAabbCcDd 
(a) Jagoda gametes     
(b) Mary gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

cdba_1f80

Phenotype Diversity in Hybrid Cross

Sydney and Marianne are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Sydney genotypeAABBCcDd 
Marianne genotypeAAbbccDd 
(a) Sydney gametes     
(b) Marianne gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

6d56_1f80

Phenotype Diversity in Hybrid Cross

Lisa and Krystyna are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Lisa genotypeAABbccdd 
Krystyna genotypeAaBBCcDd 
(a) Lisa gametes     
(b) Krystyna gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

bbde_1f80

Phenotype Diversity in Hybrid Cross

Ava and Silver are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Ava genotypeaaBbCcDd 
Silver genotypeaabbccDd 
(a) Ava gametes     
(b) Silver gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

8bb8_1f80

Phenotype Diversity in Hybrid Cross

Erick and Alex are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Erick genotypeaaBbCCDd 
Alex genotypeaabbCCDd 
(a) Erick gametes     
(b) Alex gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Correct 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

5481_1f80

Phenotype Diversity in Hybrid Cross

Sonia and Alex are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Sonia genotypeAabbCcdd 
Alex genotypeaaBbCcDD 
(a) Sonia gametes     
(b) Alex gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Correct 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect MC

80bd_319e

Phenotype Diversity in Hybrid Cross

Abram and Vikram are crossed. Use their genotypes to determine the number of different phenotypes possible in their offspring. An uppercase letter represents a dominant allele; a lowercase letter represents a recessive allele.

Hint: At each gene, Aa × Aa and Aa × aa can produce two phenotypes. All other crosses produce one phenotype. Multiply the counts across all genes.

Assume complete dominance and the principle of independent assortment for all genes.

Given these principles, how many unique PHENOTYPES could result from a hybrid cross between the following individuals?

Use the blank table to organize your work. For each gene, enter the number of possibilities, then multiply across the row to find the total.

Work in order: (a) and (b) count the different gametes each person can produce; (c) give the Punnett square dimensions (rows × columns) and total number of cells; then count the different offspring outcomes in the remaining row(s). You do not need to draw the full Punnett square.

Fill in the white cells and shaded TOTAL cells. Use your final total to select the answer below.

Genes →ABCDTOTAL
Abram genotypeAaBbCcDd 
Vikram genotypeaabbCcDd 
(a) Abram gametes     
(b) Vikram gametes     
(c) Punnett square size→ 
(d) Number of cross genotypes     
(e) Number of cross phenotypes     
22   = 4 (i.e. 2 genes with two forms) Incorrect 2 × 3   = 6 (i.e. 1 gene with two forms and 1 gene with three forms) Incorrect 23   = 8 (i.e. 3 genes with two forms) Incorrect 22 × 3   = 12 (i.e. 2 genes with two forms and 1 gene with three forms) Incorrect 24   = 16 (i.e. 4 genes with two forms) Correct