MC

ec5b_1daa

GenotypeOutcome
CC Lethal, does not survive
CcIvory
ccYolk

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the ivory phenotype and cc produces the yolk phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the yolk phenotype?

1/4 × 96 = 24 offspring Incorrect 1/3 × 96 = 32 offspring Correct 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Incorrect 3/4 × 96 = 72 offspring Incorrect MC

913e_1daa

GenotypeOutcome
CC Lethal, does not survive
CcGloomy
ccKnotted

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the gloomy phenotype and cc produces the knotted phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Before considering survival, assume the cross produces 96 offspring.
How many would you expect to have the lethal CC genotype?

1/4 × 96 = 24 offspring Correct 1/3 × 96 = 32 offspring Incorrect 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Incorrect 3/4 × 96 = 72 offspring Incorrect MC

2955_1daa

GenotypeOutcome
CC Lethal, does not survive
CcIcy
ccKidney

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the icy phenotype and cc produces the kidney phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the icy phenotype?

1/4 × 96 = 24 offspring Incorrect 1/3 × 96 = 32 offspring Incorrect 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Correct 3/4 × 96 = 72 offspring Incorrect MC

6667_2ffe

GenotypeOutcome
CC Lethal, does not survive
CcZippy
ccMushy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the zippy phenotype and cc produces the mushy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 48 surviving offspring.
How many of the surviving offspring do you expect to have the mushy phenotype?

1/3 × 48 = 16 offspring Correct 1/2 × 48 = 24 offspring Incorrect 2/3 × 48 = 32 offspring Incorrect 3/4 × 48 = 36 offspring Incorrect 1 × 48 = 48 offspring Incorrect MC

411c_14d7

GenotypeOutcome
CC Lethal, does not survive
CcUncut
ccFuzzy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the uncut phenotype and cc produces the fuzzy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 48 surviving offspring.
How many of the surviving offspring do you expect to have the uncut phenotype?

1/4 × 48 = 12 offspring Incorrect 1/3 × 48 = 16 offspring Incorrect 1/2 × 48 = 24 offspring Incorrect 2/3 × 48 = 32 offspring Correct 3/4 × 48 = 36 offspring Incorrect MC

fb2d_d4d7

GenotypeOutcome
CC Lethal, does not survive
CcToxic
ccVacuolex

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the toxic phenotype and cc produces the vacuolex phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the vacuolex phenotype?

0 × 96 = 0 offspring Incorrect 1/4 × 96 = 24 offspring Incorrect 1/3 × 96 = 32 offspring Correct 2/3 × 96 = 64 offspring Incorrect 1 × 96 = 96 offspring Incorrect MC

f01a_d193

GenotypeOutcome
CC Lethal, does not survive
CcMilitant
ccZippy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the militant phenotype and cc produces the zippy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
Before considering survival, assume the cross produces 120 offspring.
How many would you expect to survive with the zippy phenotype?

1/3 × 120 = 40 offspring Incorrect 1/2 × 120 = 60 offspring Correct 2/3 × 120 = 80 offspring Incorrect 3/4 × 120 = 90 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

401b_bf7a

GenotypeOutcome
CC Lethal, does not survive
CcHorsey
ccNerdy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the horsey phenotype and cc produces the nerdy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the nerdy phenotype?

1/4 × 120 = 30 offspring Incorrect 1/3 × 120 = 40 offspring Correct 1/2 × 120 = 60 offspring Incorrect 2/3 × 120 = 80 offspring Incorrect 3/4 × 120 = 90 offspring Incorrect MC

2b8c_9263

GenotypeOutcome
CC Lethal, does not survive
CcBubbly
ccUncut

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the bubbly phenotype and cc produces the uncut phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the uncut phenotype?

0 × 96 = 0 offspring Incorrect 1/3 × 96 = 32 offspring Correct 2/3 × 96 = 64 offspring Incorrect 3/4 × 96 = 72 offspring Incorrect 1 × 96 = 96 offspring Incorrect MC

6163_b8df

GenotypeOutcome
CC Lethal, does not survive
CcArtsy
ccFuzzy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the artsy phenotype and cc produces the fuzzy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
The cross produces 72 surviving offspring.
How many of the surviving offspring do you expect to have the artsy phenotype?

1/4 × 72 = 18 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 1/2 × 72 = 36 offspring Correct 2/3 × 72 = 48 offspring Incorrect 1 × 72 = 72 offspring Incorrect MC

82fe_739b

GenotypeOutcome
CC Lethal, does not survive
CcQuacky
ccGooey

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the quacky phenotype and cc produces the gooey phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Before considering survival, assume the cross produces 120 offspring.
How many would you expect to survive with the gooey phenotype?

1/4 × 120 = 30 offspring Correct 1/3 × 120 = 40 offspring Incorrect 2/3 × 120 = 80 offspring Incorrect 3/4 × 120 = 90 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

ac58_2c8c

GenotypeOutcome
CC Lethal, does not survive
CcJerky
ccXanthic

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the jerky phenotype and cc produces the xanthic phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
Before considering survival, assume the cross produces 72 offspring.
How many would you expect to survive with the jerky phenotype?

0 × 72 = 0 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 1/2 × 72 = 36 offspring Correct 2/3 × 72 = 48 offspring Incorrect 1 × 72 = 72 offspring Incorrect MC

caab_52b2

GenotypeOutcome
CC Lethal, does not survive
CcMilitant
ccDoubled

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the militant phenotype and cc produces the doubled phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
What fraction of all offspring will survive?

1/3, 33.3% Incorrect 1/2, 50% Incorrect 2/3, 66.7% Incorrect 3/4, 75% Correct All, 100% Incorrect MC

2e38_4856

GenotypeOutcome
CC Lethal, does not survive
CcFuzzy
ccVacuolex

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the fuzzy phenotype and cc produces the vacuolex phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
Before considering survival, assume the cross produces 72 offspring.
How many would you expect to survive with the fuzzy phenotype?

0 × 72 = 0 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 1/2 × 72 = 36 offspring Correct 2/3 × 72 = 48 offspring Incorrect 3/4 × 72 = 54 offspring Incorrect MC

43a4_e5fe

GenotypeOutcome
CC Lethal, does not survive
CcEery
ccFuzzy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the eery phenotype and cc produces the fuzzy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Of the offspring that survive, what fraction will have the fuzzy phenotype?

1/4, 25% Incorrect 1/3, 33.3% Correct 1/2, 50% Incorrect 2/3, 66.7% Incorrect 3/4, 75% Incorrect MC

b9ed_52b2

GenotypeOutcome
CC Lethal, does not survive
CcYolk
ccIvory

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the yolk phenotype and cc produces the ivory phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
What fraction of all offspring will survive?

1/3, 33.3% Incorrect 1/2, 50% Incorrect 2/3, 66.7% Incorrect 3/4, 75% Incorrect All, 100% Correct MC

f274_5fb0

GenotypeOutcome
CC Lethal, does not survive
CcRusty
ccBumpy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the rusty phenotype and cc produces the bumpy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 72 surviving offspring.
How many of the surviving offspring do you expect to have the bumpy phenotype?

1/3 × 72 = 24 offspring Correct 1/2 × 72 = 36 offspring Incorrect 2/3 × 72 = 48 offspring Incorrect 3/4 × 72 = 54 offspring Incorrect 1 × 72 = 72 offspring Incorrect MC

4e31_5d90

GenotypeOutcome
CC Lethal, does not survive
CcYucky
ccGooey

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the yucky phenotype and cc produces the gooey phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Before considering survival, assume the cross produces 48 offspring.
How many would you expect to survive with the yucky phenotype?

1/4 × 48 = 12 offspring Incorrect 1/3 × 48 = 16 offspring Incorrect 1/2 × 48 = 24 offspring Correct 2/3 × 48 = 32 offspring Incorrect 1 × 48 = 48 offspring Incorrect MC

951a_2ffe

GenotypeOutcome
CC Lethal, does not survive
CcPebble
ccHairy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the pebble phenotype and cc produces the hairy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 48 surviving offspring.
How many of the surviving offspring do you expect to have the hairy phenotype?

1/3 × 48 = 16 offspring Correct 1/2 × 48 = 24 offspring Incorrect 2/3 × 48 = 32 offspring Incorrect 3/4 × 48 = 36 offspring Incorrect 1 × 48 = 48 offspring Incorrect MC

5240_d193

GenotypeOutcome
CC Lethal, does not survive
CcFuzzy
ccNerdy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the fuzzy phenotype and cc produces the nerdy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the fuzzy phenotype?

1/3 × 120 = 40 offspring Incorrect 1/2 × 120 = 60 offspring Incorrect 2/3 × 120 = 80 offspring Correct 3/4 × 120 = 90 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

13a3_af0e

GenotypeOutcome
CC Lethal, does not survive
CcFuzzy
ccWebbed

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the fuzzy phenotype and cc produces the webbed phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
Of the offspring that survive, what fraction will have the webbed phenotype?

None, 0% Incorrect 1/3, 33.3% Incorrect 1/2, 50% Correct 2/3, 66.7% Incorrect All, 100% Incorrect MC

d6b9_52b2

GenotypeOutcome
CC Lethal, does not survive
CcDewy
ccQuacky

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the dewy phenotype and cc produces the quacky phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Of the offspring that survive, what fraction will have the quacky phenotype?

1/3, 33.3% Correct 1/2, 50% Incorrect 2/3, 66.7% Incorrect 3/4, 75% Incorrect All, 100% Incorrect MC

a3eb_b8df

GenotypeOutcome
CC Lethal, does not survive
CcKnotted
ccZippy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the knotted phenotype and cc produces the zippy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Before considering survival, assume the cross produces 72 offspring.
How many would you expect to survive with the knotted phenotype?

1/4 × 72 = 18 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 1/2 × 72 = 36 offspring Correct 2/3 × 72 = 48 offspring Incorrect 1 × 72 = 72 offspring Incorrect MC

e926_579a

GenotypeOutcome
CC Lethal, does not survive
CcFuzzy
ccQuilt

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the fuzzy phenotype and cc produces the quilt phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the fuzzy phenotype?

1/4 × 96 = 24 offspring Incorrect 1/3 × 96 = 32 offspring Incorrect 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Correct 1 × 96 = 96 offspring Incorrect MC

c022_032f

GenotypeOutcome
CC Lethal, does not survive
CcFuzzy
ccStringy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the fuzzy phenotype and cc produces the stringy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the stringy phenotype?

0 × 120 = 0 offspring Incorrect 1/4 × 120 = 30 offspring Incorrect 1/3 × 120 = 40 offspring Correct 2/3 × 120 = 80 offspring Incorrect 3/4 × 120 = 90 offspring Incorrect MC

c87a_7eaa

GenotypeOutcome
CC Lethal, does not survive
CcWaxy
ccUgly

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the waxy phenotype and cc produces the ugly phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
What ratio do you expect among the offspring that survive?
waxy : ugly

1 to 2 Incorrect 1 to 1 Incorrect 3 to 2 Incorrect 2 to 1 Correct 3 to 1 Incorrect MC

f714_af85

GenotypeOutcome
CC Lethal, does not survive
CcJeweled
ccMilitant

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the jeweled phenotype and cc produces the militant phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
What fraction of all offspring would have the lethal CC genotype?

None, 0% Correct 1/3, 33.3% Incorrect 1/2, 50% Incorrect 2/3, 66.7% Incorrect 3/4, 75% Incorrect MC

9768_b209

GenotypeOutcome
CC Lethal, does not survive
CcTipsy
ccWaxy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the tipsy phenotype and cc produces the waxy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the waxy phenotype?

0 × 120 = 0 offspring Incorrect 1/4 × 120 = 30 offspring Incorrect 1/3 × 120 = 40 offspring Correct 1/2 × 120 = 60 offspring Incorrect 2/3 × 120 = 80 offspring Incorrect MC

b0d6_ca08

GenotypeOutcome
CC Lethal, does not survive
CcKnotted
ccLavender

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the knotted phenotype and cc produces the lavender phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the lavender phenotype?

0 × 96 = 0 offspring Incorrect 1/4 × 96 = 24 offspring Incorrect 1/3 × 96 = 32 offspring Correct 2/3 × 96 = 64 offspring Incorrect 3/4 × 96 = 72 offspring Incorrect MC

46d5_070d

GenotypeOutcome
CC Lethal, does not survive
CcToxic
ccGloomy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the toxic phenotype and cc produces the gloomy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 48 surviving offspring.
How many of the surviving offspring do you expect to have the toxic phenotype?

0 × 48 = 0 offspring Incorrect 1/3 × 48 = 16 offspring Incorrect 1/2 × 48 = 24 offspring Incorrect 2/3 × 48 = 32 offspring Correct 1 × 48 = 48 offspring Incorrect MC

0dc5_d193

GenotypeOutcome
CC Lethal, does not survive
CcXanthic
ccBumpy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the xanthic phenotype and cc produces the bumpy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the xanthic phenotype?

1/3 × 120 = 40 offspring Incorrect 1/2 × 120 = 60 offspring Incorrect 2/3 × 120 = 80 offspring Correct 3/4 × 120 = 90 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

563c_df36

GenotypeOutcome
CC Lethal, does not survive
CcAmber
ccZippy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the amber phenotype and cc produces the zippy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
Before considering survival, assume the cross produces 48 offspring.
How many would you expect to have the lethal CC genotype?

0 × 48 = 0 offspring Correct 1/4 × 48 = 12 offspring Incorrect 1/3 × 48 = 16 offspring Incorrect 2/3 × 48 = 32 offspring Incorrect 3/4 × 48 = 36 offspring Incorrect MC

dca4_8872

GenotypeOutcome
CC Lethal, does not survive
CcQuacky
ccNerdy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the quacky phenotype and cc produces the nerdy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 72 surviving offspring.
How many of the surviving offspring do you expect to have the quacky phenotype?

0 × 72 = 0 offspring Incorrect 1/4 × 72 = 18 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 2/3 × 72 = 48 offspring Correct 1 × 72 = 72 offspring Incorrect MC

1eb5_110c

GenotypeOutcome
CC Lethal, does not survive
CcSpicy
ccKidney

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the spicy phenotype and cc produces the kidney phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
Before considering survival, assume the cross produces 96 offspring.
How many would you expect to survive with the kidney phenotype?

0 × 96 = 0 offspring Incorrect 1/3 × 96 = 32 offspring Incorrect 1/2 × 96 = 48 offspring Correct 2/3 × 96 = 64 offspring Incorrect 1 × 96 = 96 offspring Incorrect MC

c19c_b8df

GenotypeOutcome
CC Lethal, does not survive
CcIcy
ccWaxy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the icy phenotype and cc produces the waxy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 72 surviving offspring.
How many of the surviving offspring do you expect to have the icy phenotype?

1/4 × 72 = 18 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 1/2 × 72 = 36 offspring Incorrect 2/3 × 72 = 48 offspring Correct 1 × 72 = 72 offspring Incorrect MC

805f_5d90

GenotypeOutcome
CC Lethal, does not survive
CcTipsy
ccLeafy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the tipsy phenotype and cc produces the leafy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 48 surviving offspring.
How many of the surviving offspring do you expect to have the tipsy phenotype?

1/4 × 48 = 12 offspring Incorrect 1/3 × 48 = 16 offspring Incorrect 1/2 × 48 = 24 offspring Incorrect 2/3 × 48 = 32 offspring Correct 1 × 48 = 48 offspring Incorrect MC

c747_59bf

GenotypeOutcome
CC Lethal, does not survive
CcPrickly
ccChummy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the prickly phenotype and cc produces the chummy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the chummy phenotype?

0 × 96 = 0 offspring Incorrect 1/3 × 96 = 32 offspring Correct 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Incorrect 3/4 × 96 = 72 offspring Incorrect MC

3036_3d80

GenotypeOutcome
CC Lethal, does not survive
CcLavender
ccFuzzy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the lavender phenotype and cc produces the fuzzy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
What fraction of all offspring will survive with the lavender phenotype?

1/4, 25% Incorrect 1/3, 33.3% Incorrect 1/2, 50% Correct 2/3, 66.7% Incorrect All, 100% Incorrect MC

e355_d193

GenotypeOutcome
CC Lethal, does not survive
CcXanthic
ccPrickly

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the xanthic phenotype and cc produces the prickly phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the xanthic phenotype?

1/3 × 120 = 40 offspring Incorrect 1/2 × 120 = 60 offspring Correct 2/3 × 120 = 80 offspring Incorrect 3/4 × 120 = 90 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

0a37_f6ef

GenotypeOutcome
CC Lethal, does not survive
CcJeweled
ccIvory

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the jeweled phenotype and cc produces the ivory phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 72 surviving offspring.
How many of the surviving offspring do you expect to have the jeweled phenotype?

1/4 × 72 = 18 offspring Incorrect 1/3 × 72 = 24 offspring Incorrect 1/2 × 72 = 36 offspring Incorrect 2/3 × 72 = 48 offspring Correct 3/4 × 72 = 54 offspring Incorrect MC

1133_fa98

GenotypeOutcome
CC Lethal, does not survive
CcAmber
ccFuzzy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the amber phenotype and cc produces the fuzzy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Before considering survival, assume the cross produces 120 offspring.
How many would you expect to have the lethal CC genotype?

1/4 × 120 = 30 offspring Correct 1/3 × 120 = 40 offspring Incorrect 1/2 × 120 = 60 offspring Incorrect 2/3 × 120 = 80 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

d116_110c

GenotypeOutcome
CC Lethal, does not survive
CcHairy
ccZippy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the hairy phenotype and cc produces the zippy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the hairy phenotype?

0 × 96 = 0 offspring Incorrect 1/3 × 96 = 32 offspring Incorrect 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Correct 1 × 96 = 96 offspring Incorrect MC

07b8_a7b7

GenotypeOutcome
CC Lethal, does not survive
CcToxic
ccKnotted

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the toxic phenotype and cc produces the knotted phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 48 surviving offspring.
How many of the surviving offspring do you expect to have the knotted phenotype?

0 × 48 = 0 offspring Incorrect 1/3 × 48 = 16 offspring Correct 1/2 × 48 = 24 offspring Incorrect 2/3 × 48 = 32 offspring Incorrect 3/4 × 48 = 36 offspring Incorrect MC

07f3_5cfa

GenotypeOutcome
CC Lethal, does not survive
CcKnotted
ccWebbed

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the knotted phenotype and cc produces the webbed phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Of the offspring that survive, what fraction will have the knotted phenotype?

None, 0% Incorrect 1/4, 25% Incorrect 1/3, 33.3% Incorrect 2/3, 66.7% Correct All, 100% Incorrect MC

5dbb_110c

GenotypeOutcome
CC Lethal, does not survive
CcDewy
ccSpicy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the dewy phenotype and cc produces the spicy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 96 surviving offspring.
How many of the surviving offspring do you expect to have the spicy phenotype?

0 × 96 = 0 offspring Incorrect 1/3 × 96 = 32 offspring Correct 1/2 × 96 = 48 offspring Incorrect 2/3 × 96 = 64 offspring Incorrect 1 × 96 = 96 offspring Incorrect MC

a3b1_973d

GenotypeOutcome
CC Lethal, does not survive
CcBubbly
ccClumpy

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the bubbly phenotype and cc produces the clumpy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Before considering survival, assume the cross produces 72 offspring.
How many would you expect to have the lethal CC genotype?

0 × 72 = 0 offspring Incorrect 1/4 × 72 = 18 offspring Correct 1/3 × 72 = 24 offspring Incorrect 2/3 × 72 = 48 offspring Incorrect 3/4 × 72 = 54 offspring Incorrect MC

4426_006a

GenotypeOutcome
CC Lethal, does not survive
CcBumpy
ccChummy

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the bumpy phenotype and cc produces the chummy phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the chummy phenotype?

0 × 120 = 0 offspring Incorrect 1/4 × 120 = 30 offspring Incorrect 1/3 × 120 = 40 offspring Correct 2/3 × 120 = 80 offspring Incorrect 1 × 120 = 120 offspring Incorrect MC

2190_bbf1

GenotypeOutcome
CC Lethal, does not survive
CcValley
ccQuacky

For a hypothetical fruit fly trait, C is dominant to c, so C_ produces the valley phenotype and cc produces the quacky phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
Of the offspring that survive, what fraction will have the quacky phenotype?

None, 0% Incorrect 1/3, 33.3% Correct 2/3, 66.7% Incorrect 3/4, 75% Incorrect All, 100% Incorrect MC

143d_7eaa

GenotypeOutcome
CC Lethal, does not survive
CcStringy
ccDoubled

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the stringy phenotype and cc produces the doubled phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: cc.
What ratio do you expect among the offspring that survive?
stringy : doubled

1 to 2 Incorrect 1 to 1 Correct 3 to 2 Incorrect 2 to 1 Incorrect 3 to 1 Incorrect MC

2341_fa98

GenotypeOutcome
CC Lethal, does not survive
CcWebbed
ccAmber

For a hypothetical budding yeast trait, C is dominant to c, so C_ produces the webbed phenotype and cc produces the amber phenotype. However, CC is lethal and those offspring do not survive.

Parent 1: Cc × Parent 2: Cc.
The cross produces 120 surviving offspring.
How many of the surviving offspring do you expect to have the webbed phenotype?

1/4 × 120 = 30 offspring Incorrect 1/3 × 120 = 40 offspring Incorrect 1/2 × 120 = 60 offspring Incorrect 2/3 × 120 = 80 offspring Correct 1 × 120 = 120 offspring Incorrect