a685_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	28	22.7	^(28-22.7)²⁄ _22.7	1.237
Pink Flowers	38	48.9	^(38-48.9)²⁄ _48.9	2.430
White Flowers	32	26.4	^(32-26.4)²⁄ _26.4	1.188
(sum) χ² =				4.855

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

3dd0_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	60	54.2	^(60-54.2)²⁄ _54.2	0.621
Pink Flowers	51	63.3	^(51-63.3)²⁄ _63.3	2.390
White Flowers	25	18.5	^(25-18.5)²⁄ _18.5	2.284
(sum) χ² =				5.294

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

6e35_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	130	124.9	^{(130-124.9)²}⁄ _124.9	0.208
Pink Flowers	55	65.5	^(55-65.5)²⁄ _65.5	1.683
White Flowers	14	8.6	^(14-8.6)²⁄ _8.6	3.391
(sum) χ² =				5.282

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

2119_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	210	221.4	^{(210-221.4)²}⁄ _221.4	0.587
Pink Flowers	245	222.6	^{(245-222.6)²}⁄ _222.6	2.254
White Flowers	45	56.0	^(45-56.0)²⁄ _56.0	2.161
(sum) χ² =				5.002

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

cb4c_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	52	47.7	^(52-47.7)²⁄ _47.7	0.388
Pink Flowers	25	33.4	^(25-33.4)²⁄ _33.4	2.113
White Flowers	10	5.9	^(10-5.9)²⁄ _5.9	2.849
(sum) χ² =				5.349

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9c1b_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	110	98.0	^(110-98.0)²⁄ _98.0	1.469
Pink Flowers	222	246.7	^{(222-246.7)²}⁄ _246.7	2.473
White Flowers	168	155.3	^{(168-155.3)²}⁄ _155.3	1.039
(sum) χ² =				4.981

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.44 and q=0.56. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

9371_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	113	125.3	^{(113-125.3)²}⁄ _125.3	1.207
Pink Flowers	275	250.0	^{(275-250.0)²}⁄ _250.0	2.500
White Flowers	112	124.7	^{(112-124.7)²}⁄ _124.7	1.293
(sum) χ² =				5.001

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9ecc_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	108	101.7	^{(108-101.7)²}⁄ _101.7	0.390
Pink Flowers	63	74.6	^(63-74.6)²⁄ _74.6	1.804
White Flowers	20	13.7	^(20-13.7)²⁄ _13.7	2.897
(sum) χ² =				5.091

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

2e90_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	1809	1788.0	^{(1809-1788.0)²}⁄ _1788.0	0.247
Pink Flowers	997	1039.8	^{(997-1039.8)²}⁄ _1039.8	1.762
White Flowers	172	151.2	^{(172-151.2)²}⁄ _151.2	2.861
(sum) χ² =				4.870

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

0d53_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	76	69.7	^(76-69.7)²⁄ _69.7	0.569
Pink Flowers	51	62.3	^(51-62.3)²⁄ _62.3	2.050
White Flowers	20	13.9	^(20-13.9)²⁄ _13.9	2.677
(sum) χ² =				5.296

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

7374_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	28	21.9	^(28-21.9)²⁄ _21.9	1.699
Pink Flowers	49	61.2	^(49-61.2)²⁄ _61.2	2.432
White Flowers	49	42.9	^(49-42.9)²⁄ _42.9	0.867
(sum) χ² =				4.998

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

08e4_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	103	97.9	^(103-97.9)²⁄ _97.9	0.266
Pink Flowers	53	63.7	^(53-63.7)²⁄ _63.7	1.797
White Flowers	16	10.4	^(16-10.4)²⁄ _10.4	3.015
(sum) χ² =				5.078

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

dbcc_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	59	52.0	^(59-52.0)²⁄ _52.0	0.942
Pink Flowers	60	73.2	^(60-73.2)²⁄ _73.2	2.380
White Flowers	32	25.8	^(32-25.8)²⁄ _25.8	1.490
(sum) χ² =				4.813

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

92e9_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	237	225.9	^{(237-225.9)²}⁄ _225.9	0.545
Pink Flowers	198	220.3	^{(198-220.3)²}⁄ _220.3	2.257
White Flowers	65	53.7	^(65-53.7)²⁄ _53.7	2.378
(sum) χ² =				5.181

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c902_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	229	218.2	^{(229-218.2)²}⁄ _218.2	0.535
Pink Flowers	202	224.2	^{(202-224.2)²}⁄ _224.2	2.198
White Flowers	69	57.6	^(69-57.6)²⁄ _57.6	2.256
(sum) χ² =				4.989

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

1085_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	9181	9099.4	^{(9181-9099.4)²}⁄ _9099.4	0.732
Pink Flowers	11044	11207.0	^{(11044-11207.0)²}⁄ _11207.0	2.371
White Flowers	3532	3450.7	^{(3532-3450.7)²}⁄ _3450.7	1.915
(sum) χ² =				5.018

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

be02_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	5492	5437.9	^{(5492-5437.9)²}⁄ _5437.9	0.538
Pink Flowers	5149	5256.1	^{(5149-5256.1)²}⁄ _5256.1	2.182
White Flowers	1324	1270.1	^{(1324-1270.1)²}⁄ _1270.1	2.287
(sum) χ² =				5.008

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

3f40_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	74	85.8	^(74-85.8)²⁄ _85.8	1.623
Pink Flowers	267	242.6	^{(267-242.6)²}⁄ _242.6	2.454
White Flowers	159	171.6	^{(159-171.6)²}⁄ _171.6	0.925
(sum) χ² =				5.002

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

f76d_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	290	280.3	^{(290-280.3)²}⁄ _280.3	0.336
Pink Flowers	169	188.1	^{(169-188.1)²}⁄ _188.1	1.939
White Flowers	41	31.6	^(41-31.6)²⁄ _31.6	2.796
(sum) χ² =				5.071

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

61df_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	36	30.5	^(36-30.5)²⁄ _30.5	0.992
Pink Flowers	46	58.0	^(46-58.0)²⁄ _58.0	2.483
White Flowers	34	27.6	^(34-27.6)²⁄ _27.6	1.484
(sum) χ² =				4.959

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

f52d_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	137	149.6	^{(137-149.6)²}⁄ _149.6	1.061
Pink Flowers	273	247.8	^{(273-247.8)²}⁄ _247.8	2.563
White Flowers	90	102.6	^(90-102.6)²⁄ _102.6	1.547
(sum) χ² =				5.171

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9749_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	199	187.0	^{(199-187.0)²}⁄ _187.0	0.770
Pink Flowers	214	237.5	^{(214-237.5)²}⁄ _237.5	2.325
White Flowers	87	75.4	^(87-75.4)²⁄ _75.4	1.785
(sum) χ² =				4.880

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

2255_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	203	190.8	^{(203-190.8)²}⁄ _190.8	0.780
Pink Flowers	213	236.2	^{(213-236.2)²}⁄ _236.2	2.279
White Flowers	85	73.1	^(85-73.1)²⁄ _73.1	1.937
(sum) χ² =				4.996

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

434a_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	130	142.8	^{(130-142.8)²}⁄ _142.8	1.147
Pink Flowers	274	248.8	^{(274-248.8)²}⁄ _248.8	2.552
White Flowers	96	108.4	^(96-108.4)²⁄ _108.4	1.418
(sum) χ² =				5.118

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

5a75_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	169	157.0	^{(169-157.0)²}⁄ _157.0	0.917
Pink Flowers	222	246.3	^{(222-246.3)²}⁄ _246.3	2.397
White Flowers	109	96.6	^(109-96.6)²⁄ _96.6	1.592
(sum) χ² =				4.906

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c0db_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	22	18.5	^(22-18.5)²⁄ _18.5	0.662
Pink Flowers	18	26.2	^(18-26.2)²⁄ _26.2	2.566
White Flowers	13	9.3	^(13-9.3)²⁄ _9.3	1.472
(sum) χ² =				4.701

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

21a6_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	33	25.9	^(33-25.9)²⁄ _25.9	1.946
Pink Flowers	61	74.5	^(61-74.5)²⁄ _74.5	2.446
White Flowers	60	53.6	^(60-53.6)²⁄ _53.6	0.764
(sum) χ² =				5.157

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

53ea_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	267	256.6	^{(267-256.6)²}⁄ _256.6	0.422
Pink Flowers	183	203.2	^{(183-203.2)²}⁄ _203.2	2.008
White Flowers	50	40.2	^(50-40.2)²⁄ _40.2	2.389
(sum) χ² =				4.819

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3d8a_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	25	21.6	^(25-21.6)²⁄ _21.6	0.535
Pink Flowers	16	23.8	^(16-23.8)²⁄ _23.8	2.556
White Flowers	10	6.6	^(10-6.6)²⁄ _6.6	1.752
(sum) χ² =				4.843

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

a5a5_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	26	22.1	^(26-22.1)²⁄ _22.1	0.688
Pink Flowers	17	24.3	^(17-24.3)²⁄ _24.3	2.193
White Flowers	10	6.7	^(10-6.7)²⁄ _6.7	1.625
(sum) χ² =				4.507

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

68e8_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	26	22.7	^(26-22.7)²⁄ _22.7	0.480
Pink Flowers	15	22.0	^(15-22.0)²⁄ _22.0	2.227
White Flowers	9	5.3	^(9-5.3)²⁄ _5.3	2.583
(sum) χ² =				5.290

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

583c_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	173	160.6	^{(173-160.6)²}⁄ _160.6	0.957
Pink Flowers	221	245.5	^{(221-245.5)²}⁄ _245.5	2.445
White Flowers	106	93.8	^(106-93.8)²⁄ _93.8	1.587
(sum) χ² =				4.989

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.57 and q=0.43. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

78e3_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	284	274.2	^{(284-274.2)²}⁄ _274.2	0.350
Pink Flowers	173	192.1	^{(173-192.1)²}⁄ _192.1	1.899
White Flowers	43	33.7	^(43-33.7)²⁄ _33.7	2.566
(sum) χ² =				4.816

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

6f1a_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	247	236.2	^{(247-236.2)²}⁄ _236.2	0.494
Pink Flowers	193	214.9	^{(193-214.9)²}⁄ _214.9	2.232
White Flowers	60	48.9	^(60-48.9)²⁄ _48.9	2.520
(sum) χ² =				5.245

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

0045_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	19	14.4	^(19-14.4)²⁄ _14.4	1.469
Pink Flowers	25	34.2	^(25-34.2)²⁄ _34.2	2.475
White Flowers	25	20.4	^(25-20.4)²⁄ _20.4	1.037
(sum) χ² =				4.982

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

eedf_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	251	261.4	^{(251-261.4)²}⁄ _261.4	0.414
Pink Flowers	220	200.2	^{(220-200.2)²}⁄ _200.2	1.958
White Flowers	28	38.3	^(28-38.3)²⁄ _38.3	2.770
(sum) χ² =				5.142

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

273a_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	129	116.8	^{(129-116.8)²}⁄ _116.8	1.274
Pink Flowers	225	249.7	^{(225-249.7)²}⁄ _249.7	2.443
White Flowers	146	133.5	^{(146-133.5)²}⁄ _133.5	1.170
(sum) χ² =				4.888

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

87d7_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	34	29.7	^(34-29.7)²⁄ _29.7	0.623
Pink Flowers	28	37.5	^(28-37.5)²⁄ _37.5	2.407
White Flowers	17	11.8	^(17-11.8)²⁄ _11.8	2.292
(sum) χ² =				5.321

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

16f6_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	35	31.6	^(35-31.6)²⁄ _31.6	0.366
Pink Flowers	14	20.2	^(14-20.2)²⁄ _20.2	1.903
White Flowers	6	3.2	^(6-3.2)²⁄ _3.2	2.450
(sum) χ² =				4.719

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f19f_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	116	103.9	^{(116-103.9)²}⁄ _103.9	1.409
Pink Flowers	223	248.0	^{(223-248.0)²}⁄ _248.0	2.520
White Flowers	160	148.1	^{(160-148.1)²}⁄ _148.1	0.956
(sum) χ² =				4.885

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

00bf_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	524	509.1	^{(524-509.1)²}⁄ _509.1	0.436
Pink Flowers	379	407.4	^{(379-407.4)²}⁄ _407.4	1.980
White Flowers	96	81.5	^(96-81.5)²⁄ _81.5	2.580
(sum) χ² =				4.996

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d410_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	197	185.0	^{(197-185.0)²}⁄ _185.0	0.778
Pink Flowers	214	238.3	^{(214-238.3)²}⁄ _238.3	2.478
White Flowers	89	76.7	^(89-76.7)²⁄ _76.7	1.972
(sum) χ² =				5.229

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

454f_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	168	155.8	^{(168-155.8)²}⁄ _155.8	0.955
Pink Flowers	222	246.6	^{(222-246.6)²}⁄ _246.6	2.454
White Flowers	110	97.6	^(110-97.6)²⁄ _97.6	1.575
(sum) χ² =				4.985

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

403a_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	88	79.9	^(88-79.9)²⁄ _79.9	0.821
Pink Flowers	89	105.4	^(89-105.4)²⁄ _105.4	2.552
White Flowers	43	34.8	^(43-34.8)²⁄ _34.8	1.932
(sum) χ² =				5.305

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.60 and q=0.40. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0436_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	312	303.0	^{(312-303.0)²}⁄ _303.0	0.267
Pink Flowers	155	172.4	^{(155-172.4)²}⁄ _172.4	1.756
White Flowers	33	24.5	^(33-24.5)²⁄ _24.5	2.949
(sum) χ² =				4.972

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

981d_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	45	39.0	^(45-39.0)²⁄ _39.0	0.923
Pink Flowers	53	65.5	^(53-65.5)²⁄ _65.5	2.385
White Flowers	34	27.5	^(34-27.5)²⁄ _27.5	1.536
(sum) χ² =				4.845

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

1bae_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	226	215.2	^{(226-215.2)²}⁄ _215.2	0.542
Pink Flowers	203	225.6	^{(203-225.6)²}⁄ _225.6	2.264
White Flowers	70	59.1	^(70-59.1)²⁄ _59.1	2.010
(sum) χ² =				4.816

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

7000_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	18	13.0	^(18-13.0)²⁄ _13.0	1.923
Pink Flowers	25	34.3	^(25-34.3)²⁄ _34.3	2.522
White Flowers	27	22.7	^(27-22.7)²⁄ _22.7	0.815
(sum) χ² =				5.259

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

36e2_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	298	306.2	^{(298-306.2)²}⁄ _306.2	0.220
Pink Flowers	187	170.2	^{(187-170.2)²}⁄ _170.2	1.658
White Flowers	15	23.7	^(15-23.7)²⁄ _23.7	3.194
(sum) χ² =				5.072

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9602_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	58	49.9	^(58-49.9)²⁄ _49.9	1.315
Pink Flowers	78	92.9	^(78-92.9)²⁄ _92.9	2.390
White Flowers	51	43.2	^(51-43.2)²⁄ _43.2	1.408
(sum) χ² =				5.113

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

8556_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	35	29.3	^(35-29.3)²⁄ _29.3	1.109
Pink Flowers	35	45.2	^(35-45.2)²⁄ _45.2	2.302
White Flowers	23	17.5	^(23-17.5)²⁄ _17.5	1.729
(sum) χ² =				5.139

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

ec3b_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	107	119.2	^{(107-119.2)²}⁄ _119.2	1.249
Pink Flowers	275	249.9	^{(275-249.9)²}⁄ _249.9	2.521
White Flowers	118	130.9	^{(118-130.9)²}⁄ _130.9	1.271
(sum) χ² =				5.041

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

d0f7_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	174	161.5	^{(174-161.5)²}⁄ _161.5	0.967
Pink Flowers	221	245.3	^{(221-245.3)²}⁄ _245.3	2.407
White Flowers	105	93.2	^(105-93.2)²⁄ _93.2	1.494
(sum) χ² =				4.869

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.57 and q=0.43. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

2fd0_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	269	259.1	^{(269-259.1)²}⁄ _259.1	0.378
Pink Flowers	182	201.7	^{(182-201.7)²}⁄ _201.7	1.924
White Flowers	49	39.3	^(49-39.3)²⁄ _39.3	2.394
(sum) χ² =				4.697

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

31fa_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	103	90.3	^(103-90.3)²⁄ _90.3	1.786
Pink Flowers	220	244.4	^{(220-244.4)²}⁄ _244.4	2.436
White Flowers	177	165.3	^{(177-165.3)²}⁄ _165.3	0.828
(sum) χ² =				5.050

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0622_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	26	22.8	^(26-22.8)²⁄ _22.8	0.449
Pink Flowers	15	21.9	^(15-21.9)²⁄ _21.9	2.174
White Flowers	9	5.3	^(9-5.3)²⁄ _5.3	2.583
(sum) χ² =				5.206

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.68 and q=0.32. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

1d52_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	67	63.3	^(67-63.3)²⁄ _63.3	0.216
Pink Flowers	26	33.3	^(26-33.3)²⁄ _33.3	1.600
White Flowers	8	4.4	^(8-4.4)²⁄ _4.4	2.945
(sum) χ² =				4.762

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f1aa_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	130	124.2	^{(130-124.2)²}⁄ _124.2	0.271
Pink Flowers	70	82.9	^(70-82.9)²⁄ _82.9	2.007
White Flowers	20	13.8	^(20-13.8)²⁄ _13.8	2.786
(sum) χ² =				5.064

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

a28c_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	39	35.2	^(39-35.2)²⁄ _35.2	0.410
Pink Flowers	22	29.6	^(22-29.6)²⁄ _29.6	1.951
White Flowers	10	6.2	^(10-6.2)²⁄ _6.2	2.329
(sum) χ² =				4.691

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

04e8_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	35	28.0	^(35-28.0)²⁄ _28.0	1.750
Pink Flowers	66	79.5	^(66-79.5)²⁄ _79.5	2.292
White Flowers	63	56.4	^(63-56.4)²⁄ _56.4	0.772
(sum) χ² =				4.815

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3383_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	58	53.3	^(58-53.3)²⁄ _53.3	0.414
Pink Flowers	37	46.5	^(37-46.5)²⁄ _46.5	1.941
White Flowers	15	10.1	^(15-10.1)²⁄ _10.1	2.377
(sum) χ² =				4.733

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9ad9_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	302	293.5	^{(302-293.5)²}⁄ _293.5	0.246
Pink Flowers	161	179.1	^{(161-179.1)²}⁄ _179.1	1.829
White Flowers	36	27.3	^(36-27.3)²⁄ _27.3	2.773
(sum) χ² =				4.848

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4664_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	108	102.3	^{(108-102.3)²}⁄ _102.3	0.318
Pink Flowers	54	65.3	^(54-65.3)²⁄ _65.3	1.955
White Flowers	16	10.4	^(16-10.4)²⁄ _10.4	3.015
(sum) χ² =				5.288

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

4543_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	315	306.1	^{(315-306.1)²}⁄ _306.1	0.259
Pink Flowers	153	170.2	^{(153-170.2)²}⁄ _170.2	1.738
White Flowers	32	23.7	^(32-23.7)²⁄ _23.7	2.907
(sum) χ² =				4.904

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

d9bb_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	153	140.9	^{(153-140.9)²}⁄ _140.9	1.039
Pink Flowers	224	249.0	^{(224-249.0)²}⁄ _249.0	2.510
White Flowers	122	110.0	^{(122-110.0)²}⁄ _110.0	1.309
(sum) χ² =				4.858

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

fb79_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	37	33.0	^(37-33.0)²⁄ _33.0	0.485
Pink Flowers	18	25.2	^(18-25.2)²⁄ _25.2	2.057
White Flowers	8	4.8	^(8-4.8)²⁄ _4.8	2.133
(sum) χ² =				4.675

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

a9b2_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	109	104.0	^{(109-104.0)²}⁄ _104.0	0.240
Pink Flowers	53	63.4	^(53-63.4)²⁄ _63.4	1.706
White Flowers	15	9.6	^(15-9.6)²⁄ _9.6	3.038
(sum) χ² =				4.984

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f702_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	54	49.9	^(54-49.9)²⁄ _49.9	0.337
Pink Flowers	26	33.5	^(26-33.5)²⁄ _33.5	1.679
White Flowers	10	5.6	^(10-5.6)²⁄ _5.6	3.457
(sum) χ² =				5.473

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f838_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	16	11.2	^(16-11.2)²⁄ _11.2	2.057
Pink Flowers	22	31.1	^(22-31.1)²⁄ _31.1	2.663
White Flowers	26	21.7	^(26-21.7)²⁄ _21.7	0.852
(sum) χ² =				5.572

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

34e4_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	324	316.1	^{(324-316.1)²}⁄ _316.1	0.197
Pink Flowers	147	162.9	^{(147-162.9)²}⁄ _162.9	1.552
White Flowers	29	21.0	^(29-21.0)²⁄ _21.0	3.048
(sum) χ² =				4.797

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cc7c_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	295	286.0	^{(295-286.0)²}⁄ _286.0	0.283
Pink Flowers	166	184.3	^{(166-184.3)²}⁄ _184.3	1.817
White Flowers	39	29.7	^(39-29.7)²⁄ _29.7	2.912
(sum) χ² =				5.012

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c27d_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	227	237.5	^{(227-237.5)²}⁄ _237.5	0.464
Pink Flowers	236	214.2	^{(236-214.2)²}⁄ _214.2	2.219
White Flowers	38	48.3	^(38-48.3)²⁄ _48.3	2.196
(sum) χ² =				4.879

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8169_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	226	216.1	^{(226-216.1)²}⁄ _216.1	0.454
Pink Flowers	166	185.9	^{(166-185.9)²}⁄ _185.9	2.130
White Flowers	50	40.0	^(50-40.0)²⁄ _40.0	2.500
(sum) χ² =				5.084

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

0898_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	68	63.1	^(68-63.1)²⁄ _63.1	0.381
Pink Flowers	44	55.0	^(44-55.0)²⁄ _55.0	2.200
White Flowers	17	12.0	^(17-12.0)²⁄ _12.0	2.083
(sum) χ² =				4.664

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

bc8c_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	41	37.1	^(41-37.1)²⁄ _37.1	0.410
Pink Flowers	25	33.4	^(25-33.4)²⁄ _33.4	2.113
White Flowers	12	7.5	^(12-7.5)²⁄ _7.5	2.700
(sum) χ² =				5.223

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

911c_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	219	229.7	^{(219-229.7)²}⁄ _229.7	0.498
Pink Flowers	240	218.4	^{(240-218.4)²}⁄ _218.4	2.136
White Flowers	41	51.9	^(41-51.9)²⁄ _51.9	2.289
(sum) χ² =				4.924

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.68 and q=0.32. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

e151_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	304	295.6	^{(304-295.6)²}⁄ _295.6	0.239
Pink Flowers	160	177.7	^{(160-177.7)²}⁄ _177.7	1.763
White Flowers	36	26.7	^(36-26.7)²⁄ _26.7	3.239
(sum) χ² =				5.241

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

b56e_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	98	110.7	^(98-110.7)²⁄ _110.7	1.457
Pink Flowers	274	249.1	^{(274-249.1)²}⁄ _249.1	2.489
White Flowers	128	140.2	^{(128-140.2)²}⁄ _140.2	1.062
(sum) χ² =				5.008

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

bc28_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	172	183.6	^{(172-183.6)²}⁄ _183.6	0.733
Pink Flowers	263	238.8	^{(263-238.8)²}⁄ _238.8	2.452
White Flowers	66	77.7	^(66-77.7)²⁄ _77.7	1.762
(sum) χ² =				4.947

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

bc46_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	33	27.3	^(33-27.3)²⁄ _27.3	1.190
Pink Flowers	37	47.8	^(37-47.8)²⁄ _47.8	2.440
White Flowers	26	20.9	^(26-20.9)²⁄ _20.9	1.244
(sum) χ² =				4.875

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

d3c7_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	266	275.5	^{(266-275.5)²}⁄ _275.5	0.328
Pink Flowers	210	191.3	^{(210-191.3)²}⁄ _191.3	1.828
White Flowers	24	33.2	^(24-33.2)²⁄ _33.2	2.549
(sum) χ² =				4.705

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

c9a1_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	201	189.0	^{(201-189.0)²}⁄ _189.0	0.762
Pink Flowers	213	236.8	^{(213-236.8)²}⁄ _236.8	2.392
White Flowers	86	74.2	^(86-74.2)²⁄ _74.2	1.877
(sum) χ² =				5.031

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

6eab_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	30	24.3	^(30-24.3)²⁄ _24.3	1.337
Pink Flowers	46	58.5	^(46-58.5)²⁄ _58.5	2.671
White Flowers	41	35.2	^(41-35.2)²⁄ _35.2	0.956
(sum) χ² =				4.964

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

471b_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	41	33.4	^(41-33.4)²⁄ _33.4	1.729
Pink Flowers	80	95.4	^(80-95.4)²⁄ _95.4	2.486
White Flowers	76	68.2	^(76-68.2)²⁄ _68.2	0.892
(sum) χ² =				5.107

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

2522_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	16	11.9	^(16-11.9)²⁄ _11.9	1.413
Pink Flowers	24	33.5	^(24-33.5)²⁄ _33.5	2.694
White Flowers	28	23.6	^(28-23.6)²⁄ _23.6	0.820
(sum) χ² =				4.927

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

e4ff_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	23040	22953.2	^{(23040-22953.2)²}⁄ _22953.2	0.328
Pink Flowers	15754	15928.4	^{(15754-15928.4)²}⁄ _15928.4	1.910
White Flowers	2851	2763.4	^{(2851-2763.4)²}⁄ _2763.4	2.777
(sum) χ² =				5.015

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

b0d8_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	293	283.4	^{(293-283.4)²}⁄ _283.4	0.325
Pink Flowers	167	186.1	^{(167-186.1)²}⁄ _186.1	1.960
White Flowers	40	30.5	^(40-30.5)²⁄ _30.5	2.959
(sum) χ² =				5.245

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

dfc0_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	156	140.7	^{(156-140.7)²}⁄ _140.7	1.664
Pink Flowers	361	391.7	^{(361-391.7)²}⁄ _391.7	2.406
White Flowers	288	272.6	^{(288-272.6)²}⁄ _272.6	0.870
(sum) χ² =				4.940

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

9da1_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	108	102.4	^{(108-102.4)²}⁄ _102.4	0.306
Pink Flowers	53	63.7	^(53-63.7)²⁄ _63.7	1.797
White Flowers	15	9.9	^(15-9.9)²⁄ _9.9	2.627
(sum) χ² =				4.731

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

bb64_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	113	100.9	^{(113-100.9)²}⁄ _100.9	1.451
Pink Flowers	223	247.4	^{(223-247.4)²}⁄ _247.4	2.406
White Flowers	164	151.7	^{(164-151.7)²}⁄ _151.7	0.997
(sum) χ² =				4.855

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

b895_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	40	34.4	^(40-34.4)²⁄ _34.4	0.912
Pink Flowers	44	55.3	^(44-55.3)²⁄ _55.3	2.309
White Flowers	28	22.3	^(28-22.3)²⁄ _22.3	1.457
(sum) χ² =				4.678

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

0184_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	65	56.9	^(65-56.9)²⁄ _56.9	1.153
Pink Flowers	87	102.7	^(87-102.7)²⁄ _102.7	2.400
White Flowers	54	46.4	^(54-46.4)²⁄ _46.4	1.245
(sum) χ² =				4.798

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

bbe9_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	183	194.4	^{(183-194.4)²}⁄ _194.4	0.669
Pink Flowers	258	234.7	^{(258-234.7)²}⁄ _234.7	2.313
White Flowers	59	70.9	^(59-70.9)²⁄ _70.9	1.997
(sum) χ² =				4.979

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d8bb_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	139	126.8	^{(139-126.8)²}⁄ _126.8	1.174
Pink Flowers	225	250.0	^{(225-250.0)²}⁄ _250.0	2.500
White Flowers	136	123.2	^{(136-123.2)²}⁄ _123.2	1.330
(sum) χ² =				5.004

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ca27_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	79	90.8	^(79-90.8)²⁄ _90.8	1.533
Pink Flowers	269	244.6	^{(269-244.6)²}⁄ _244.6	2.434
White Flowers	152	164.6	^{(152-164.6)²}⁄ _164.6	0.965
(sum) χ² =				4.932

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

09c9_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	59	51.0	^(59-51.0)²⁄ _51.0	1.255
Pink Flowers	77	92.3	^(77-92.3)²⁄ _92.3	2.536
White Flowers	49	41.7	^(49-41.7)²⁄ _41.7	1.278
(sum) χ² =				5.069

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

4a29_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	47	40.8	^(47-40.8)²⁄ _40.8	0.942
Pink Flowers	52	64.6	^(52-64.6)²⁄ _64.6	2.458
White Flowers	32	25.6	^(32-25.6)²⁄ _25.6	1.600
(sum) χ² =				5.000

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

0bbb_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	32	29.0	^(32-29.0)²⁄ _29.0	0.310
Pink Flowers	16	22.6	^(16-22.6)²⁄ _22.6	1.927
White Flowers	8	4.4	^(8-4.4)²⁄ _4.4	2.945
(sum) χ² =				5.183

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

592b_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	223	233.7	^{(223-233.7)²}⁄ _233.7	0.490
Pink Flowers	238	216.3	^{(238-216.3)²}⁄ _216.3	2.177
White Flowers	39	50.0	^(39-50.0)²⁄ _50.0	2.420
(sum) χ² =				5.087

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.68 and q=0.32. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

5969_ab06

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	28	22.4	^(28-22.4)²⁄ _22.4	1.400
Pink Flowers	40	51.3	^(40-51.3)²⁄ _51.3	2.489
White Flowers	35	29.3	^(35-29.3)²⁄ _29.3	1.109
(sum) χ² =				4.998

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3a82_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	148	135.5	^{(148-135.5)²}⁄ _135.5	1.153
Pink Flowers	225	249.6	^{(225-249.6)²}⁄ _249.6	2.425
White Flowers	127	115.0	^{(127-115.0)²}⁄ _115.0	1.252
(sum) χ² =				4.830

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

61b1_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	81	77.0	^(81-77.0)²⁄ _77.0	0.208
Pink Flowers	36	44.6	^(36-44.6)²⁄ _44.6	1.658
White Flowers	11	6.5	^(11-6.5)²⁄ _6.5	3.115
(sum) χ² =				4.981

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

9b07_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	97	85.0	^(97-85.0)²⁄ _85.0	1.694
Pink Flowers	218	242.3	^{(218-242.3)²}⁄ _242.3	2.437
White Flowers	185	172.7	^{(185-172.7)²}⁄ _172.7	0.876
(sum) χ² =				5.007

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

30e6_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	179	191.1	^{(179-191.1)²}⁄ _191.1	0.766
Pink Flowers	260	236.0	^{(260-236.0)²}⁄ _236.0	2.441
White Flowers	61	72.9	^(61-72.9)²⁄ _72.9	1.943
(sum) χ² =				5.149

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

66e7_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	26	22.3	^(26-22.3)²⁄ _22.3	0.614
Pink Flowers	19	27.3	^(19-27.3)²⁄ _27.3	2.523
White Flowers	12	8.4	^(12-8.4)²⁄ _8.4	1.543
(sum) χ² =				4.680

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

883e_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	89	84.3	^(89-84.3)²⁄ _84.3	0.262
Pink Flowers	45	55.5	^(45-55.5)²⁄ _55.5	1.986
White Flowers	14	9.1	^(14-9.1)²⁄ _9.1	2.638
(sum) χ² =				4.887

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

9cd9_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	17	12.5	^(17-12.5)²⁄ _12.5	1.620
Pink Flowers	28	37.1	^(28-37.1)²⁄ _37.1	2.232
White Flowers	32	27.4	^(32-27.4)²⁄ _27.4	0.772
(sum) χ² =				4.624

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.40 and q=0.60. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

1130_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	221	205.8	^{(221-205.8)²}⁄ _205.8	1.123
Pink Flowers	359	390.2	^{(359-390.2)²}⁄ _390.2	2.495
White Flowers	201	185.0	^{(201-185.0)²}⁄ _185.0	1.384
(sum) χ² =				5.001

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

5d4f_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	109	98.6	^(109-98.6)²⁄ _98.6	1.097
Pink Flowers	168	189.9	^{(168-189.9)²}⁄ _189.9	2.526
White Flowers	102	91.5	^(102-91.5)²⁄ _91.5	1.205
(sum) χ² =				4.827

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

9873_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	62	56.8	^(62-56.8)²⁄ _56.8	0.476
Pink Flowers	36	45.9	^(36-45.9)²⁄ _45.9	2.135
White Flowers	14	9.3	^(14-9.3)²⁄ _9.3	2.375
(sum) χ² =				4.987

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

1117_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	21	16.2	^(21-16.2)²⁄ _16.2	1.422
Pink Flowers	29	38.7	^(29-38.7)²⁄ _38.7	2.431
White Flowers	28	23.1	^(28-23.1)²⁄ _23.1	1.039
(sum) χ² =				4.893

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

6e43_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	42	35.4	^(42-35.4)²⁄ _35.4	1.231
Pink Flowers	59	72.0	^(59-72.0)²⁄ _72.0	2.347
White Flowers	43	36.6	^(43-36.6)²⁄ _36.6	1.119
(sum) χ² =				4.697

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

e3af_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	207	195.5	^{(207-195.5)²}⁄ _195.5	0.676
Pink Flowers	211	234.3	^{(211-234.3)²}⁄ _234.3	2.317
White Flowers	82	70.2	^(82-70.2)²⁄ _70.2	1.983
(sum) χ² =				4.977

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

8a1d_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	33	26.0	^(33-26.0)²⁄ _26.0	1.885
Pink Flowers	62	75.4	^(62-75.4)²⁄ _75.4	2.381
White Flowers	61	54.7	^(61-54.7)²⁄ _54.7	0.726
(sum) χ² =				4.992

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

bb6f_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	66	58.6	^(66-58.6)²⁄ _58.6	0.934
Pink Flowers	69	83.0	^(69-83.0)²⁄ _83.0	2.361
White Flowers	37	29.4	^(37-29.4)²⁄ _29.4	1.965
(sum) χ² =				5.261

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3705_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	130	117.2	^{(130-117.2)²}⁄ _117.2	1.398
Pink Flowers	225	249.7	^{(225-249.7)²}⁄ _249.7	2.443
White Flowers	146	133.0	^{(146-133.0)²}⁄ _133.0	1.271
(sum) χ² =				5.112

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

b381_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	101	113.4	^{(101-113.4)²}⁄ _113.4	1.356
Pink Flowers	274	249.4	^{(274-249.4)²}⁄ _249.4	2.426
White Flowers	125	137.2	^{(125-137.2)²}⁄ _137.2	1.085
(sum) χ² =				4.867

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f844_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	235	223.7	^{(235-223.7)²}⁄ _223.7	0.571
Pink Flowers	199	221.5	^{(199-221.5)²}⁄ _221.5	2.286
White Flowers	66	54.8	^(66-54.8)²⁄ _54.8	2.289
(sum) χ² =				5.145

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

23d7_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	46	42.0	^(46-42.0)²⁄ _42.0	0.381
Pink Flowers	29	37.6	^(29-37.6)²⁄ _37.6	1.967
White Flowers	13	8.4	^(13-8.4)²⁄ _8.4	2.519
(sum) χ² =				4.867

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

1664_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	46	40.5	^(46-40.5)²⁄ _40.5	0.747
Pink Flowers	41	52.5	^(41-52.5)²⁄ _52.5	2.519
White Flowers	23	17.0	^(23-17.0)²⁄ _17.0	2.118
(sum) χ² =				5.384

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

076e_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	128	140.5	^{(128-140.5)²}⁄ _140.5	1.112
Pink Flowers	274	249.1	^{(274-249.1)²}⁄ _249.1	2.489
White Flowers	98	110.4	^(98-110.4)²⁄ _110.4	1.393
(sum) χ² =				4.994

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.53 and q=0.47. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

9494_c73f

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	242	252.2	^{(242-252.2)²}⁄ _252.2	0.413
Pink Flowers	226	205.8	^{(226-205.8)²}⁄ _205.8	1.983
White Flowers	32	42.0	^(32-42.0)²⁄ _42.0	2.381
(sum) χ² =				4.776

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c085_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	44	40.1	^(44-40.1)²⁄ _40.1	0.379
Pink Flowers	20	27.2	^(20-27.2)²⁄ _27.2	1.906
White Flowers	8	4.6	^(8-4.6)²⁄ _4.6	2.513
(sum) χ² =				4.798

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d36a_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	549	521.1	^{(549-521.1)²}⁄ _521.1	1.494
Pink Flowers	1235	1291.6	^{(1235-1291.6)²}⁄ _1291.6	2.480
White Flowers	829	800.4	^{(829-800.4)²}⁄ _800.4	1.022
(sum) χ² =				4.996

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

876d_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	36	31.0	^(36-31.0)²⁄ _31.0	0.806
Pink Flowers	31	41.3	^(31-41.3)²⁄ _41.3	2.569
White Flowers	19	13.7	^(19-13.7)²⁄ _13.7	2.050
(sum) χ² =				5.426

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.60 and q=0.40. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

90b3_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	96	108.3	^(96-108.3)²⁄ _108.3	1.397
Pink Flowers	274	248.8	^{(274-248.8)²}⁄ _248.8	2.552
White Flowers	131	143.0	^{(131-143.0)²}⁄ _143.0	1.007
(sum) χ² =				4.956

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

1980_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	162	149.7	^{(162-149.7)²}⁄ _149.7	1.011
Pink Flowers	223	247.8	^{(223-247.8)²}⁄ _247.8	2.482
White Flowers	115	102.5	^{(115-102.5)²}⁄ _102.5	1.524
(sum) χ² =				5.017

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.55 and q=0.45. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

7eac_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	277	285.8	^{(277-285.8)²}⁄ _285.8	0.271
Pink Flowers	203	184.5	^{(203-184.5)²}⁄ _184.5	1.855
White Flowers	21	29.8	^(21-29.8)²⁄ _29.8	2.599
(sum) χ² =				4.725

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

5ad6_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	36	30.3	^(36-30.3)²⁄ _30.3	1.072
Pink Flowers	34	45.0	^(34-45.0)²⁄ _45.0	2.689
White Flowers	22	16.7	^(22-16.7)²⁄ _16.7	1.682
(sum) χ² =				5.443

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.57 and q=0.43. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

5d40_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	99	86.7	^(99-86.7)²⁄ _86.7	1.745
Pink Flowers	219	243.0	^{(219-243.0)²}⁄ _243.0	2.370
White Flowers	182	170.3	^{(182-170.3)²}⁄ _170.3	0.804
(sum) χ² =				4.919

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

a009_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	5344	5262.4	^{(5344-5262.4)²}⁄ _5262.4	1.265
Pink Flowers	10631	10795.8	^{(10631-10795.8)²}⁄ _10795.8	2.516
White Flowers	5619	5536.9	^{(5619-5536.9)²}⁄ _5536.9	1.217
(sum) χ² =				4.998

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

5133_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	27	22.1	^(27-22.1)²⁄ _22.1	1.086
Pink Flowers	35	46.0	^(35-46.0)²⁄ _46.0	2.630
White Flowers	29	23.9	^(29-23.9)²⁄ _23.9	1.088
(sum) χ² =				4.805

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

e8d6_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	110	122.4	^{(110-122.4)²}⁄ _122.4	1.256
Pink Flowers	275	250.0	^{(275-250.0)²}⁄ _250.0	2.500
White Flowers	115	127.6	^{(115-127.6)²}⁄ _127.6	1.244
(sum) χ² =				5.000

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

ccd9_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	80	74.6	^(80-74.6)²⁄ _74.6	0.391
Pink Flowers	53	64.5	^(53-64.5)²⁄ _64.5	2.050
White Flowers	20	13.9	^(20-13.9)²⁄ _13.9	2.677
(sum) χ² =				5.118

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0b41_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	41	34.0	^(41-34.0)²⁄ _34.0	1.441
Pink Flowers	77	91.9	^(77-91.9)²⁄ _91.9	2.416
White Flowers	70	62.1	^(70-62.1)²⁄ _62.1	1.005
(sum) χ² =				4.862

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.43 and q=0.57. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3bd6_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	140	127.2	^{(140-127.2)²}⁄ _127.2	1.288
Pink Flowers	225	250.0	^{(225-250.0)²}⁄ _250.0	2.500
White Flowers	135	122.9	^{(135-122.9)²}⁄ _122.9	1.191
(sum) χ² =				4.979

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

46d7_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	234	223.3	^{(234-223.3)²}⁄ _223.3	0.513
Pink Flowers	200	221.7	^{(200-221.7)²}⁄ _221.7	2.124
White Flowers	66	55.0	^(66-55.0)²⁄ _55.0	2.200
(sum) χ² =				4.837

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.67 and q=0.33. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

1e4f_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	148	135.9	^{(148-135.9)²}⁄ _135.9	1.077
Pink Flowers	225	249.5	^{(225-249.5)²}⁄ _249.5	2.406
White Flowers	127	114.5	^{(127-114.5)²}⁄ _114.5	1.365
(sum) χ² =				4.848

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

b8c7_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	204	192.5	^{(204-192.5)²}⁄ _192.5	0.687
Pink Flowers	212	235.5	^{(212-235.5)²}⁄ _235.5	2.345
White Flowers	84	72.0	^(84-72.0)²⁄ _72.0	2.000
(sum) χ² =				5.032

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.62 and q=0.38. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

e5e9_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	173	157.0	^{(173-157.0)²}⁄ _157.0	1.631
Pink Flowers	414	446.9	^{(414-446.9)²}⁄ _446.9	2.422
White Flowers	335	318.1	^{(335-318.1)²}⁄ _318.1	0.898
(sum) χ² =				4.950

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

cc6e_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	20	15.0	^(20-15.0)²⁄ _15.0	1.667
Pink Flowers	26	35.3	^(26-35.3)²⁄ _35.3	2.450
White Flowers	25	20.8	^(25-20.8)²⁄ _20.8	0.848
(sum) χ² =				4.965

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

65e8_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	234	244.5	^{(234-244.5)²}⁄ _244.5	0.451
Pink Flowers	231	210.3	^{(231-210.3)²}⁄ _210.3	2.038
White Flowers	35	45.2	^(35-45.2)²⁄ _45.2	2.302
(sum) χ² =				4.790

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

8f66_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	62	55.4	^(62-55.4)²⁄ _55.4	0.786
Pink Flowers	64	77.5	^(64-77.5)²⁄ _77.5	2.352
White Flowers	34	27.1	^(34-27.1)²⁄ _27.1	1.757
(sum) χ² =				4.895

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.59 and q=0.41. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

53a1_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	48	40.7	^(48-40.7)²⁄ _40.7	1.309
Pink Flowers	74	88.8	^(74-88.8)²⁄ _88.8	2.467
White Flowers	56	48.5	^(56-48.5)²⁄ _48.5	1.160
(sum) χ² =				4.936

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.48 and q=0.52. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

2e96_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	155	167.5	^{(155-167.5)²}⁄ _167.5	0.933
Pink Flowers	268	243.8	^{(268-243.8)²}⁄ _243.8	2.402
White Flowers	77	88.7	^(77-88.7)²⁄ _88.7	1.543
(sum) χ² =				4.878

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.58 and q=0.42. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

ff67_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	287	277.9	^{(287-277.9)²}⁄ _277.9	0.298
Pink Flowers	171	189.7	^{(171-189.7)²}⁄ _189.7	1.843
White Flowers	42	32.4	^(42-32.4)²⁄ _32.4	2.844
(sum) χ² =				4.986

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

35e2_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	122	109.8	^{(122-109.8)²}⁄ _109.8	1.356
Pink Flowers	224	249.0	^{(224-249.0)²}⁄ _249.0	2.510
White Flowers	154	141.2	^{(154-141.2)²}⁄ _141.2	1.160
(sum) χ² =				5.026

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.47 and q=0.53. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

dcb9_9910

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	37	33.5	^(37-33.5)²⁄ _33.5	0.366
Pink Flowers	18	25.6	^(18-25.6)²⁄ _25.6	2.256
White Flowers	8	4.9	^(8-4.9)²⁄ _4.9	1.961
(sum) χ² =				4.583

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

f4b4_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	82	75.8	^(82-75.8)²⁄ _75.8	0.507
Pink Flowers	64	76.7	^(64-76.7)²⁄ _76.7	2.103
White Flowers	26	19.4	^(26-19.4)²⁄ _19.4	2.245
(sum) χ² =				4.855

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

5fbf_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	300	308.3	^{(300-308.3)²}⁄ _308.3	0.223
Pink Flowers	185	168.6	^{(185-168.6)²}⁄ _168.6	1.595
White Flowers	15	23.1	^(15-23.1)²⁄ _23.1	2.840
(sum) χ² =				4.659

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

4933_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	72	68.2	^(72-68.2)²⁄ _68.2	0.212
Pink Flowers	32	39.9	^(32-39.9)²⁄ _39.9	1.564
White Flowers	10	5.9	^(10-5.9)²⁄ _5.9	2.849
(sum) χ² =				4.625

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.77 and q=0.23. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

c5b1_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	288	278.4	^{(288-278.4)²}⁄ _278.4	0.331
Pink Flowers	170	189.4	^{(170-189.4)²}⁄ _189.4	1.987
White Flowers	42	32.2	^(42-32.2)²⁄ _32.2	2.983
(sum) χ² =				5.301

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

5660_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	266	276.0	^{(266-276.0)²}⁄ _276.0	0.362
Pink Flowers	210	191.0	^{(210-191.0)²}⁄ _191.0	1.890
White Flowers	23	33.0	^(23-33.0)²⁄ _33.0	3.030
(sum) χ² =				5.283

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

f9f1_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	209	220.6	^{(209-220.6)²}⁄ _220.6	0.610
Pink Flowers	245	223.0	^{(245-223.0)²}⁄ _223.0	2.170
White Flowers	45	56.4	^(45-56.4)²⁄ _56.4	2.304
(sum) χ² =				5.085

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.66 and q=0.34. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

2a93_524d

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	9263	9205.2	^{(9263-9205.2)²}⁄ _9205.2	0.363
Pink Flowers	6738	6854.7	^{(6738-6854.7)²}⁄ _6854.7	1.987
White Flowers	1334	1276.1	^{(1334-1276.1)²}⁄ _1276.1	2.627
(sum) χ² =				4.977

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

41b5_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	131	118.7	^{(131-118.7)²}⁄ _118.7	1.275
Pink Flowers	225	249.8	^{(225-249.8)²}⁄ _249.8	2.462
White Flowers	144	131.4	^{(144-131.4)²}⁄ _131.4	1.208
(sum) χ² =				4.945

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0575_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	134	121.4	^{(134-121.4)²}⁄ _121.4	1.308
Pink Flowers	225	249.9	^{(225-249.9)²}⁄ _249.9	2.481
White Flowers	141	128.7	^{(141-128.7)²}⁄ _128.7	1.176
(sum) χ² =				4.964

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.49 and q=0.51. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

a5e9_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	106	100.7	^{(106-100.7)²}⁄ _100.7	0.279
Pink Flowers	53	64.1	^(53-64.1)²⁄ _64.1	1.922
White Flowers	16	10.2	^(16-10.2)²⁄ _10.2	3.298
(sum) χ² =				5.499

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

b39f_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	944	927.7	^{(944-927.7)²}⁄ _927.7	0.286
Pink Flowers	564	597.2	^{(564-597.2)²}⁄ _597.2	1.846
White Flowers	113	96.1	^(113-96.1)²⁄ _96.1	2.972
(sum) χ² =				5.104

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ac42_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	308	315.8	^{(308-315.8)²}⁄ _315.8	0.193
Pink Flowers	179	163.1	^{(179-163.1)²}⁄ _163.1	1.550
White Flowers	13	21.1	^(13-21.1)²⁄ _21.1	3.109
(sum) χ² =				4.852

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.79 and q=0.21. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

2438_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	214	202.6	^{(214-202.6)²}⁄ _202.6	0.641
Pink Flowers	208	231.4	^{(208-231.4)²}⁄ _231.4	2.366
White Flowers	78	66.1	^(78-66.1)²⁄ _66.1	2.142
(sum) χ² =				5.150

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

528e_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	113	100.4	^{(113-100.4)²}⁄ _100.4	1.581
Pink Flowers	223	247.3	^{(223-247.3)²}⁄ _247.3	2.388
White Flowers	165	152.3	^{(165-152.3)²}⁄ _152.3	1.059
(sum) χ² =				5.028

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

e99f_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	46	43.4	^(46-43.4)²⁄ _43.4	0.156
Pink Flowers	16	21.8	^(16-21.8)²⁄ _21.8	1.543
White Flowers	6	2.7	^(6-2.7)²⁄ _2.7	4.033
(sum) χ² =				5.732

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

fa88_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	35	32.1	^(35-32.1)²⁄ _32.1	0.262
Pink Flowers	13	18.3	^(13-18.3)²⁄ _18.3	1.535
White Flowers	5	2.6	^(5-2.6)²⁄ _2.6	2.215
(sum) χ² =				4.012

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

b6d5_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	50	44.8	^(50-44.8)²⁄ _44.8	0.604
Pink Flowers	32	41.5	^(32-41.5)²⁄ _41.5	2.175
White Flowers	14	9.6	^(14-9.6)²⁄ _9.6	2.017
(sum) χ² =				4.795

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.68 and q=0.32. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

cf68_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	121	133.0	^{(121-133.0)²}⁄ _133.0	1.083
Pink Flowers	275	249.8	^{(275-249.8)²}⁄ _249.8	2.542
White Flowers	105	117.3	^{(105-117.3)²}⁄ _117.3	1.290
(sum) χ² =				4.915

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.52 and q=0.48. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

7424_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	71	64.2	^(71-64.2)²⁄ _64.2	0.720
Pink Flowers	68	81.8	^(68-81.8)²⁄ _81.8	2.328
White Flowers	33	26.1	^(33-26.1)²⁄ _26.1	1.824
(sum) χ² =				4.873

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.61 and q=0.39. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

18c6_470b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	29	24.8	^(29-24.8)²⁄ _24.8	0.711
Pink Flowers	24	32.5	^(24-32.5)²⁄ _32.5	2.223
White Flowers	15	10.6	^(15-10.6)²⁄ _10.6	1.826
(sum) χ² =				4.761

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.60 and q=0.40. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

d51f_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	202	213.3	^{(202-213.3)²}⁄ _213.3	0.599
Pink Flowers	249	226.5	^{(249-226.5)²}⁄ _226.5	2.235
White Flowers	49	60.1	^(49-60.1)²⁄ _60.1	2.050
(sum) χ² =				4.884

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d0e5_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	283	273.1	^{(283-273.1)²}⁄ _273.1	0.359
Pink Flowers	174	192.8	^{(174-192.8)²}⁄ _192.8	1.833
White Flowers	44	34.0	^(44-34.0)²⁄ _34.0	2.941
(sum) χ² =				5.133

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.74 and q=0.26. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

7ab5_30a8

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	212	200.3	^{(212-200.3)²}⁄ _200.3	0.683
Pink Flowers	209	232.3	^{(209-232.3)²}⁄ _232.3	2.337
White Flowers	79	67.4	^(79-67.4)²⁄ _67.4	1.996
(sum) χ² =				5.017

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.63 and q=0.37. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

e330_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	270	259.7	^{(270-259.7)²}⁄ _259.7	0.409
Pink Flowers	181	201.3	^{(181-201.3)²}⁄ _201.3	2.047
White Flowers	49	39.0	^(49-39.0)²⁄ _39.0	2.564
(sum) χ² =				5.020

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

ca79_b4da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	157	144.9	^{(157-144.9)²}⁄ _144.9	1.010
Pink Flowers	224	248.5	^{(224-248.5)²}⁄ _248.5	2.415
White Flowers	119	106.6	^{(119-106.6)²}⁄ _106.6	1.442
(sum) χ² =				4.868

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

e721_42da

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	167	154.3	^{(167-154.3)²}⁄ _154.3	1.045
Pink Flowers	222	246.9	^{(222-246.9)²}⁄ _246.9	2.511
White Flowers	111	98.8	^(111-98.8)²⁄ _98.8	1.506
(sum) χ² =				5.063

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ccbe_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	91	103.4	^(91-103.4)²⁄ _103.4	1.487
Pink Flowers	273	248.0	^{(273-248.0)²}⁄ _248.0	2.520
White Flowers	136	148.6	^{(136-148.6)²}⁄ _148.6	1.068
(sum) χ² =				5.076

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.45 and q=0.55. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d1c9_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	220	208.1	^{(220-208.1)²}⁄ _208.1	0.680
Pink Flowers	206	228.9	^{(206-228.9)²}⁄ _228.9	2.291
White Flowers	74	63.0	^(74-63.0)²⁄ _63.0	1.921
(sum) χ² =				4.892

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.65 and q=0.35. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ee14_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	311	319.4	^{(311-319.4)²}⁄ _319.4	0.221
Pink Flowers	177	160.5	^{(177-160.5)²}⁄ _160.5	1.696
White Flowers	12	20.2	^(12-20.2)²⁄ _20.2	3.329
(sum) χ² =				5.246

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

42e8_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	291	281.2	^{(291-281.2)²}⁄ _281.2	0.342
Pink Flowers	169	187.6	^{(169-187.6)²}⁄ _187.6	1.844
White Flowers	41	31.3	^(41-31.3)²⁄ _31.3	3.006
(sum) χ² =				5.192

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.75 and q=0.25. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8d04_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	311	302.1	^{(311-302.1)²}⁄ _302.1	0.262
Pink Flowers	156	173.1	^{(156-173.1)²}⁄ _173.1	1.689
White Flowers	33	24.8	^(33-24.8)²⁄ _24.8	2.711
(sum) χ² =				4.663

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

41a9_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	75	69.8	^(75-69.8)²⁄ _69.8	0.387
Pink Flowers	43	53.8	^(43-53.8)²⁄ _53.8	2.168
White Flowers	16	10.4	^(16-10.4)²⁄ _10.4	3.015
(sum) χ² =				5.571

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.72 and q=0.28. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0940_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	57	52.3	^(57-52.3)²⁄ _52.3	0.422
Pink Flowers	34	43.6	^(34-43.6)²⁄ _43.6	2.114
White Flowers	14	9.1	^(14-9.1)²⁄ _9.1	2.638
(sum) χ² =				5.175

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.71 and q=0.29. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

cd8c_2dc7

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	21	16.5	^(21-16.5)²⁄ _16.5	1.227
Pink Flowers	20	28.3	^(20-28.3)²⁄ _28.3	2.434
White Flowers	16	12.2	^(16-12.2)²⁄ _12.2	1.184
(sum) χ² =				4.845

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.54 and q=0.46. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

3c8f_dbd3

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	2366	2307.1	^{(2366-2307.1)²}⁄ _2307.1	1.504
Pink Flowers	5390	5506.8	^{(5390-5506.8)²}⁄ _5506.8	2.477
White Flowers	3344	3286.0	^{(3344-3286.0)²}⁄ _3286.0	1.024
(sum) χ² =				5.005

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.46 and q=0.54. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct MC

5581_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	26	20.6	^(26-20.6)²⁄ _20.6	1.416
Pink Flowers	44	56.1	^(44-56.1)²⁄ _56.1	2.610
White Flowers	44	38.3	^(44-38.3)²⁄ _38.3	0.848
(sum) χ² =				4.874

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.42 and q=0.58. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

298e_6034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	119	131.1	^{(119-131.1)²}⁄ _131.1	1.117
Pink Flowers	275	249.9	^{(275-249.9)²}⁄ _249.9	2.521
White Flowers	107	119.0	^{(107-119.0)²}⁄ _119.0	1.210
(sum) χ² =				4.848

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

82f2_481c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	65	59.0	^(65-59.0)²⁄ _59.0	0.610
Pink Flowers	55	67.0	^(55-67.0)²⁄ _67.0	2.149
White Flowers	25	19.0	^(25-19.0)²⁄ _19.0	1.895
(sum) χ² =				4.654

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.64 and q=0.36. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

8fb6_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	72	83.9	^(72-83.9)²⁄ _83.9	1.688
Pink Flowers	266	241.8	^{(266-241.8)²}⁄ _241.8	2.422
White Flowers	162	174.2	^{(162-174.2)²}⁄ _174.2	0.854
(sum) χ² =				4.964

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.41 and q=0.59. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

14ce_81fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	227	219.9	^{(227-219.9)²}⁄ _219.9	0.229
Pink Flowers	108	122.9	^{(108-122.9)²}⁄ _122.9	1.806
White Flowers	24	17.2	^(24-17.2)²⁄ _17.2	2.688
(sum) χ² =				4.724

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect MC

3a7e_ba65

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	171	158.5	^{(171-158.5)²}⁄ _158.5	0.986
Pink Flowers	221	246.0	^{(221-246.0)²}⁄ _246.0	2.541
White Flowers	108	95.5	^(108-95.5)²⁄ _95.5	1.636
(sum) χ² =				5.163

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.56 and q=0.44. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

9508_66fe

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	326	317.8	^{(326-317.8)²}⁄ _317.8	0.212
Pink Flowers	145	161.6	^{(145-161.6)²}⁄ _161.6	1.705
White Flowers	29	20.6	^(29-20.6)²⁄ _20.6	3.425
(sum) χ² =				5.342

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.80 and q=0.20. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0cc5_4df2

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	69	64.7	^(69-64.7)²⁄ _64.7	0.286
Pink Flowers	32	40.1	^(32-40.1)²⁄ _40.1	1.636
White Flowers	10	6.2	^(10-6.2)²⁄ _6.2	2.329
(sum) χ² =				4.251

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect MC

f7d8_3b39

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	238	248.4	^{(238-248.4)²}⁄ _248.4	0.435
Pink Flowers	229	208.1	^{(229-208.1)²}⁄ _208.1	2.099
White Flowers	33	43.6	^(33-43.6)²⁄ _43.6	2.577
(sum) χ² =				5.112

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

605f_af1c

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	248	237.5	^{(248-237.5)²}⁄ _237.5	0.464
Pink Flowers	193	214.2	^{(193-214.2)²}⁄ _214.2	2.098
White Flowers	59	48.3	^(59-48.3)²⁄ _48.3	2.370
(sum) χ² =				4.933

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.69 and q=0.31. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect MC

dc5b_91de

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	96	90.3	^(96-90.3)²⁄ _90.3	0.360
Pink Flowers	55	66.5	^(55-66.5)²⁄ _66.5	1.989
White Flowers	18	12.2	^(18-12.2)²⁄ _12.2	2.757
(sum) χ² =				5.106

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.73 and q=0.27. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

d855_67ca

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	279	288.4	^{(279-288.4)²}⁄ _288.4	0.306
Pink Flowers	201	182.7	^{(201-182.7)²}⁄ _182.7	1.833
White Flowers	20	28.9	^(20-28.9)²⁄ _28.9	2.741
(sum) χ² =				4.880

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.76 and q=0.24. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

ca6e_0940

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	294	302.9	^{(294-302.9)²}⁄ _302.9	0.262
Pink Flowers	190	172.5	^{(190-172.5)²}⁄ _172.5	1.775
White Flowers	16	24.6	^(16-24.6)²⁄ _24.6	3.007
(sum) χ² =				5.043

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.78 and q=0.22. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

3bfd_3034

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	254	243.1	^{(254-243.1)²}⁄ _243.1	0.489
Pink Flowers	190	211.1	^{(190-211.1)²}⁄ _211.1	2.109
White Flowers	56	45.8	^(56-45.8)²⁄ _45.8	2.272
(sum) χ² =				4.869

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.70 and q=0.30. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

c1f0_b10b

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	143	130.0	^{(143-130.0)²}⁄ _130.0	1.300
Pink Flowers	225	249.9	^{(225-249.9)²}⁄ _249.9	2.481
White Flowers	133	120.1	^{(133-120.1)²}⁄ _120.1	1.386
(sum) χ² =				5.167

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.51 and q=0.49. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

0495_0222

Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom	Probability
Degrees of Freedom	0.95	0.90	0.75	0.50	0.25	0.10	0.05	0.01
1	0.00	0.02	0.10	0.45	1.32	2.71	3.84	6.63
2	0.10	0.21	0.58	1.39	2.77	4.61	5.99	9.21
3	0.35	0.58	1.21	2.37	4.11	6.25	7.81	11.34
4	0.71	1.06	1.92	3.36	5.39	7.78	9.49	13.28

Table 1
Phenotype	Observed	Expected	Calculation	Statistic
Red Flowers	112	124.2	^{(112-124.2)²}⁄ _124.2	1.198
Pink Flowers	275	250.0	^{(275-250.0)²}⁄ _250.0	2.500
White Flowers	113	125.8	^{(113-125.8)²}⁄ _125.8	1.302
(sum) χ² =				5.001

You finally have a new competent lab partner that you trust.

This lab partner calculated the allele frequencies of p=0.50 and q=0.50. Then they did a chi-squared (χ²) test for your Hardy-Weinberg data.

They need you to decide whether you reject or accept the null hypothesis using the information provided.

the chi-squared (χ²) sum is GREATER than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is LESS than the critical value and we ACCEPT the null hypothesis Incorrect the chi-squared (χ²) sum is GREATER than the critical value and we REJECT the null hypothesis Correct the chi-squared (χ²) sum is LESS than the critical value and we REJECT the null hypothesis Incorrect