MC ca93_633a
Characteristics of Recessive Phenotypes
- Gene A is connected with the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene D is connected with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 105 |
| 2 | | | | | 3,050 |
| 3 | | | | | 4,845 |
| TOTAL = | 8,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED and on the SAME chromosome. Correct C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 594a_4255
Characteristics of Recessive Phenotypes
- Gene C is correlated with the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene K is linked with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,618 |
| 2 | | | | | 1,584 |
| 3 | | | | | 3,598 |
| TOTAL = | 8,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC cd70_79c4
Characteristics of Recessive Phenotypes
- Gene T is affiliated with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
- Gene Y is analogous to the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,080 |
| 2 | | | | | 1,088 |
| 3 | | | | | 32 |
| TOTAL = | 3,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 0dc9_7502
Characteristics of Recessive Phenotypes
- Gene K is analogous to the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
- Gene X is associated with the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,033 |
| 2 | | | | | 288 |
| 3 | | | | | 1,079 |
| TOTAL = | 2,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC cad5_d62f
Characteristics of Recessive Phenotypes
- Gene F is correlated with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene N is connected with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,150 |
| 2 | | | | | 1,772 |
| 3 | | | | | 78 |
| TOTAL = | 4,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC b551_3e8a
Characteristics of Recessive Phenotypes
- Gene C is related to the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene M is analogous to the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,640 |
| 2 | | | | | 2,304 |
| 3 | | | | | 3,656 |
| TOTAL = | 9,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC ada7_8a2f
Characteristics of Recessive Phenotypes
- Gene R is analogous to the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
- Gene T is connected with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,820 |
| 2 | | | | | 952 |
| 3 | | | | | 28 |
| TOTAL = | 2,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 79ea_0063
Characteristics of Recessive Phenotypes
- Gene D is analogous to the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene T is connected with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 4,016 |
| 2 | | | | | 704 |
| 3 | | | | | 4,080 |
| TOTAL = | 8,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 6c76_980d
Characteristics of Recessive Phenotypes
- Gene N is analogous to the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
- Gene P is linked with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,697 |
| 2 | | | | | 3,526 |
| 3 | | | | | 177 |
| TOTAL = | 7,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are LINKED and on the SAME chromosome. Correct C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 4334_9033
Characteristics of Recessive Phenotypes
- Gene D is correlated with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene K is analogous to the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,651 |
| 2 | | | | | 1,872 |
| 3 | | | | | 2,677 |
| TOTAL = | 7,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC b661_b3ef
Characteristics of Recessive Phenotypes
- Gene B is analogous to the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene W is affiliated with the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 102 |
| 2 | | | | | 2,412 |
| 3 | | | | | 3,086 |
| TOTAL = | 5,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 2662_6852
Characteristics of Recessive Phenotypes
- Gene F is connected with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene M is associated with the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,060 |
| 2 | | | | | 1,984 |
| 3 | | | | | 2,156 |
| TOTAL = | 6,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 7051_6063
Characteristics of Recessive Phenotypes
- Gene D is linked with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene J is analogous to the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 100 |
| 2 | | | | | 2,184 |
| 3 | | | | | 2,516 |
| TOTAL = | 4,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 3df4_827d
Characteristics of Recessive Phenotypes
- Gene E is affiliated with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene H is connected with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 928 |
| 2 | | | | | 728 |
| 3 | | | | | 944 |
| TOTAL = | 2,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 88ff_8570
Characteristics of Recessive Phenotypes
- Gene C is related to the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene Y is affiliated with the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,648 |
| 2 | | | | | 924 |
| 3 | | | | | 28 |
| TOTAL = | 2,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC c3b2_0c22
Characteristics of Recessive Phenotypes
- Gene M is analogous to the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
- Gene P is associated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,621 |
| 2 | | | | | 432 |
| 3 | | | | | 1,547 |
| TOTAL = | 3,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC a845_ad92
Characteristics of Recessive Phenotypes
- Gene F is correlated with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene H is correlated with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,798 |
| 2 | | | | | 3,620 |
| 3 | | | | | 182 |
| TOTAL = | 7,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC efcf_5090
Characteristics of Recessive Phenotypes
- Gene H is analogous to the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene J is affiliated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,240 |
| 2 | | | | | 1,152 |
| 3 | | | | | 1,208 |
| TOTAL = | 3,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED and on the SAME chromosome. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 832e_f314
Characteristics of Recessive Phenotypes
- Gene T is analogous to the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
- Gene W is analogous to the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 68 |
| 2 | | | | | 2,312 |
| 3 | | | | | 4,420 |
| TOTAL = | 6,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are LINKED and on the SAME chromosome. Correct
MC 780b_23d6
Characteristics of Recessive Phenotypes
- Gene D is associated with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene W is connected with the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,039 |
| 2 | | | | | 288 |
| 3 | | | | | 1,073 |
| TOTAL = | 2,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 1477_06af
Characteristics of Recessive Phenotypes
- Gene A is affiliated with the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene P is related to the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 58 |
| 2 | | | | | 1,380 |
| 3 | | | | | 1,762 |
| TOTAL = | 3,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 2cce_dedb
Characteristics of Recessive Phenotypes
- Gene E is related to the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene K is correlated with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,170 |
| 2 | | | | | 1,080 |
| 3 | | | | | 2,150 |
| TOTAL = | 5,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC 181a_b6e3
Characteristics of Recessive Phenotypes
- Gene R is related to the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
- Gene X is analogous to the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 34 |
| 2 | | | | | 948 |
| 3 | | | | | 1,418 |
| TOTAL = | 2,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC f1f9_1439
Characteristics of Recessive Phenotypes
- Gene D is affiliated with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene R is connected with the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,132 |
| 2 | | | | | 364 |
| 3 | | | | | 1,104 |
| TOTAL = | 2,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 5c1e_dfb0
Characteristics of Recessive Phenotypes
- Gene T is related to the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
- Gene W is associated with the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 4,933 |
| 2 | | | | | 4,270 |
| 3 | | | | | 197 |
| TOTAL = | 9,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC f23f_f39c
Characteristics of Recessive Phenotypes
- Gene F is linked with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene M is analogous to the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,553 |
| 2 | | | | | 1,408 |
| 3 | | | | | 2,439 |
| TOTAL = | 6,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC d463_dcea
Characteristics of Recessive Phenotypes
- Gene E is connected with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene F is related to the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 5,814 |
| 2 | | | | | 3,660 |
| 3 | | | | | 126 |
| TOTAL = | 9,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC a9de_0464
Characteristics of Recessive Phenotypes
- Gene K is analogous to the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
- Gene T is related to the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,113 |
| 2 | | | | | 1,036 |
| 3 | | | | | 3,251 |
| TOTAL = | 7,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 299e_a300
Characteristics of Recessive Phenotypes
- Gene E is analogous to the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene J is correlated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,730 |
| 2 | | | | | 1,224 |
| 3 | | | | | 46 |
| TOTAL = | 3,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED and on the SAME chromosome. Correct
MC 1bae_155d
Characteristics of Recessive Phenotypes
- Gene K is affiliated with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
- Gene N is associated with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,852 |
| 2 | | | | | 1,260 |
| 3 | | | | | 2,888 |
| TOTAL = | 7,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 85f7_11ca
Characteristics of Recessive Phenotypes
- Gene H is affiliated with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene Y is affiliated with the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 87 |
| 2 | | | | | 2,278 |
| 3 | | | | | 3,235 |
| TOTAL = | 5,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 1712_a071
Characteristics of Recessive Phenotypes
- Gene C is related to the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene N is associated with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,165 |
| 2 | | | | | 1,080 |
| 3 | | | | | 2,155 |
| TOTAL = | 5,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 8ade_e46c
Characteristics of Recessive Phenotypes
- Gene B is affiliated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene R is affiliated with the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 4,408 |
| 2 | | | | | 3,632 |
| 3 | | | | | 160 |
| TOTAL = | 8,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC b534_791f
Characteristics of Recessive Phenotypes
- Gene N is affiliated with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
- Gene X is analogous to the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,198 |
| 2 | | | | | 952 |
| 3 | | | | | 1,250 |
| TOTAL = | 3,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 6037_8a2f
Characteristics of Recessive Phenotypes
- Gene C is related to the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene E is linked with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 151 |
| 2 | | | | | 3,270 |
| 3 | | | | | 3,779 |
| TOTAL = | 7,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 77ae_8b42
Characteristics of Recessive Phenotypes
- Gene A is connected with the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene H is linked with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 338 |
| 2 | | | | | 280 |
| 3 | | | | | 382 |
| TOTAL = | 1,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 1376_d3df
Characteristics of Recessive Phenotypes
- Gene J is related to the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene X is linked with the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 5,850 |
| 2 | | | | | 3,060 |
| 3 | | | | | 90 |
| TOTAL = | 9,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are LINKED and on the SAME chromosome. Correct C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 8440_8646
Characteristics of Recessive Phenotypes
- Gene H is connected with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene M is associated with the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 658 |
| 2 | | | | | 320 |
| 3 | | | | | 622 |
| TOTAL = | 1,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are LINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC b7d9_6d4a
Characteristics of Recessive Phenotypes
- Gene E is affiliated with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene W is analogous to the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 66 |
| 2 | | | | | 1,508 |
| 3 | | | | | 1,826 |
| TOTAL = | 3,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED and on the SAME chromosome. Correct C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC 682e_b967
Characteristics of Recessive Phenotypes
- Gene T is correlated with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
- Gene W is related to the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 993 |
| 2 | | | | | 840 |
| 3 | | | | | 967 |
| TOTAL = | 2,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC c456_6dcd
Characteristics of Recessive Phenotypes
- Gene X is associated with the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
- Gene Y is related to the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 4,732 |
| 2 | | | | | 3,896 |
| 3 | | | | | 172 |
| TOTAL = | 8,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED and on the SAME chromosome. Correct C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC 40c1_1997
Characteristics of Recessive Phenotypes
- Gene T is correlated with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
- Gene W is connected with the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,808 |
| 2 | | | | | 792 |
| 3 | | | | | 1,800 |
| TOTAL = | 4,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC c601_c5ac
Characteristics of Recessive Phenotypes
- Gene C is associated with the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene P is associated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 90 |
| 2 | | | | | 1,860 |
| 3 | | | | | 2,050 |
| TOTAL = | 4,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 42e5_f767
Characteristics of Recessive Phenotypes
- Gene K is linked with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
- Gene M is connected with the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,107 |
| 2 | | | | | 1,368 |
| 3 | | | | | 3,125 |
| TOTAL = | 7,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC ad62_a936
Characteristics of Recessive Phenotypes
- Gene B is affiliated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene C is correlated with the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 46 |
| 2 | | | | | 1,564 |
| 3 | | | | | 2,990 |
| TOTAL = | 4,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED and on the SAME chromosome. Correct E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC bf61_d118
Characteristics of Recessive Phenotypes
- Gene B is related to the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene D is related to the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 509 |
| 2 | | | | | 420 |
| 3 | | | | | 471 |
| TOTAL = | 1,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC beec_cacf
Characteristics of Recessive Phenotypes
- Gene B is associated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene F is related to the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 510 |
| 2 | | | | | 468 |
| 3 | | | | | 22 |
| TOTAL = | 1,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 9cf4_dee8
Characteristics of Recessive Phenotypes
- Gene B is affiliated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene Y is connected with the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,868 |
| 2 | | | | | 1,456 |
| 3 | | | | | 1,876 |
| TOTAL = | 5,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC 3f42_5775
Characteristics of Recessive Phenotypes
- Gene D is associated with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene X is analogous to the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 50 |
| 2 | | | | | 1,548 |
| 3 | | | | | 2,602 |
| TOTAL = | 4,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED and on the SAME chromosome. Correct
MC a8a1_3d07
Characteristics of Recessive Phenotypes
- Gene B is linked with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene T is affiliated with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,473 |
| 2 | | | | | 1,716 |
| 3 | | | | | 2,411 |
| TOTAL = | 6,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED and on the SAME chromosome. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC e6cd_5f8b
Characteristics of Recessive Phenotypes
- Gene F is correlated with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene N is related to the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 26 |
| 2 | | | | | 812 |
| 3 | | | | | 1,362 |
| TOTAL = | 2,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 3cc7_6dcd
Characteristics of Recessive Phenotypes
- Gene H is linked with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene P is affiliated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,421 |
| 2 | | | | | 416 |
| 3 | | | | | 2,363 |
| TOTAL = | 5,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC 4e4c_cfa6
Characteristics of Recessive Phenotypes
- Gene E is affiliated with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene J is correlated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,612 |
| 2 | | | | | 2,680 |
| 3 | | | | | 108 |
| TOTAL = | 6,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 499a_0c47
Characteristics of Recessive Phenotypes
- Gene R is linked with the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
- Gene T is linked with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,207 |
| 2 | | | | | 2,016 |
| 3 | | | | | 3,177 |
| TOTAL = | 8,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC d3cd_2f1c
Characteristics of Recessive Phenotypes
- Gene H is connected with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene R is connected with the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 4,218 |
| 2 | | | | | 2,500 |
| 3 | | | | | 82 |
| TOTAL = | 6,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC c28a_5e2a
Characteristics of Recessive Phenotypes
- Gene C is related to the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene P is correlated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,677 |
| 2 | | | | | 1,196 |
| 3 | | | | | 1,727 |
| TOTAL = | 4,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC 966e_9e23
Characteristics of Recessive Phenotypes
- Gene H is analogous to the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene P is analogous to the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 87 |
| 2 | | | | | 2,514 |
| 3 | | | | | 3,999 |
| TOTAL = | 6,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 011b_393f
Characteristics of Recessive Phenotypes
- Gene F is associated with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene Y is associated with the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,719 |
| 2 | | | | | 480 |
| 3 | | | | | 2,801 |
| TOTAL = | 6,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC 5f30_d3a4
Characteristics of Recessive Phenotypes
- Gene F is analogous to the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene N is associated with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 55 |
| 2 | | | | | 1,694 |
| 3 | | | | | 2,851 |
| TOTAL = | 4,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED and on the SAME chromosome. Correct E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 3cfa_bb0c
Characteristics of Recessive Phenotypes
- Gene A is connected with the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene J is connected with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,687 |
| 2 | | | | | 640 |
| 3 | | | | | 1,673 |
| TOTAL = | 4,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 48d0_3d08
Characteristics of Recessive Phenotypes
- Gene J is related to the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene M is affiliated with the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 58 |
| 2 | | | | | 1,764 |
| 3 | | | | | 2,978 |
| TOTAL = | 4,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC 815f_4daf
Characteristics of Recessive Phenotypes
- Gene A is analogous to the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene P is connected with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 744 |
| 2 | | | | | 288 |
| 3 | | | | | 768 |
| TOTAL = | 1,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 52de_294c
Characteristics of Recessive Phenotypes
- Gene P is linked with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
- Gene W is analogous to the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 56 |
| 2 | | | | | 1,464 |
| 3 | | | | | 2,080 |
| TOTAL = | 3,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 43a6_658d
Characteristics of Recessive Phenotypes
- Gene M is related to the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
- Gene N is analogous to the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,302 |
| 2 | | | | | 512 |
| 3 | | | | | 1,386 |
| TOTAL = | 3,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 15d7_6063
Characteristics of Recessive Phenotypes
- Gene J is associated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene R is correlated with the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,635 |
| 2 | | | | | 2,286 |
| 3 | | | | | 79 |
| TOTAL = | 6,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC 1b18_8649
Characteristics of Recessive Phenotypes
- Gene K is correlated with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
- Gene P is associated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,452 |
| 2 | | | | | 1,904 |
| 3 | | | | | 2,444 |
| TOTAL = | 6,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 54a4_5b86
Characteristics of Recessive Phenotypes
- Gene C is associated with the 'clumpy' phenotype. A budding yeast that is homozygous recessive for Gene C grows in dense, irregular clusters, with cells clumping together rather than spreading smoothly.
- Gene E is related to the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 82 |
| 2 | | | | | 2,788 |
| 3 | | | | | 5,330 |
| TOTAL = | 8,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are BOTH linked AND unlinked. Incorrect
MC dffd_b357
Characteristics of Recessive Phenotypes
- Gene N is affiliated with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
- Gene T is analogous to the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,574 |
| 2 | | | | | 432 |
| 3 | | | | | 1,594 |
| TOTAL = | 3,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct
MC 0f7d_c1d0
Characteristics of Recessive Phenotypes
- Gene H is linked with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene T is connected with the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 31 |
| 2 | | | | | 958 |
| 3 | | | | | 1,611 |
| TOTAL = | 2,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC a1f8_7dc9
Characteristics of Recessive Phenotypes
- Gene K is correlated with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
- Gene T is related to the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,044 |
| 2 | | | | | 840 |
| 3 | | | | | 1,116 |
| TOTAL = | 3,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect
MC e042_d997
Characteristics of Recessive Phenotypes
- Gene A is linked with the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene W is linked with the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 108 |
| 2 | | | | | 2,680 |
| 3 | | | | | 3,612 |
| TOTAL = | 6,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 397c_5cc3
Characteristics of Recessive Phenotypes
- Gene B is analogous to the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene P is linked with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,976 |
| 2 | | | | | 816 |
| 3 | | | | | 3,008 |
| TOTAL = | 6,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are LINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 6f86_dcea
Characteristics of Recessive Phenotypes
- Gene E is connected with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene K is affiliated with the 'knotted' phenotype. A budding yeast that is homozygous recessive for Gene K cells grow in twisted, coiled shapes, resulting in a knotted or gnarled appearance.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 131 |
| 2 | | | | | 3,414 |
| 3 | | | | | 4,855 |
| TOTAL = | 8,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC 6bb0_557d
Characteristics of Recessive Phenotypes
- Gene P is affiliated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
- Gene Y is analogous to the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,361 |
| 2 | | | | | 1,044 |
| 3 | | | | | 2,395 |
| TOTAL = | 5,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC bfdd_e1af
Characteristics of Recessive Phenotypes
- Gene D is affiliated with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene N is connected with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 709 |
| 2 | | | | | 474 |
| 3 | | | | | 17 |
| TOTAL = | 1,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect F. The two genes are LINKED and on the SAME chromosome. Correct
MC a694_a01e
Characteristics of Recessive Phenotypes
- Gene H is affiliated with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
- Gene P is associated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 703 |
| 2 | | | | | 396 |
| 3 | | | | | 701 |
| TOTAL = | 1,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 2f60_f678
Characteristics of Recessive Phenotypes
- Gene N is related to the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
- Gene W is related to the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 129 |
| 2 | | | | | 2,922 |
| 3 | | | | | 3,549 |
| TOTAL = | 6,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are NEITHER linked NOR unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC 6492_f123
Characteristics of Recessive Phenotypes
- Gene B is associated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene D is associated with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,551 |
| 2 | | | | | 1,472 |
| 3 | | | | | 1,577 |
| TOTAL = | 4,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC 92a1_7057
Characteristics of Recessive Phenotypes
- Gene B is correlated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene J is correlated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 29 |
| 2 | | | | | 838 |
| 3 | | | | | 1,333 |
| TOTAL = | 2,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC 5750_c801
Characteristics of Recessive Phenotypes
- Gene J is correlated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene M is related to the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,548 |
| 2 | | | | | 2,496 |
| 3 | | | | | 3,556 |
| TOTAL = | 9,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are LINKED and on the SAME chromosome. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC a09f_10ad
Characteristics of Recessive Phenotypes
- Gene P is affiliated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
- Gene X is linked with the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,333 |
| 2 | | | | | 2,746 |
| 3 | | | | | 121 |
| TOTAL = | 6,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC 9aee_c867
Characteristics of Recessive Phenotypes
- Gene A is associated with the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene Y is linked with the 'yolk' phenotype. A budding yeast that is homozygous recessive for Gene Y cells develop a dense, yellowish core that resembles an egg yolk when viewed under a microscope.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,395 |
| 2 | | | | | 2,100 |
| 3 | | | | | 2,505 |
| TOTAL = | 7,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC a1f7_e96d
Characteristics of Recessive Phenotypes
- Gene J is correlated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene P is analogous to the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,512 |
| 2 | | | | | 2,212 |
| 3 | | | | | 76 |
| TOTAL = | 5,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are LINKED and on the SAME chromosome. Correct F. The two genes are BOTH linked AND unlinked. Incorrect
MC e021_3ca9
Characteristics of Recessive Phenotypes
- Gene D is linked with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene X is analogous to the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,751 |
| 2 | | | | | 1,204 |
| 3 | | | | | 3,645 |
| TOTAL = | 8,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC 5795_f23e
Characteristics of Recessive Phenotypes
- Gene J is correlated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene P is associated with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 193 |
| 2 | | | | | 4,178 |
| 3 | | | | | 4,829 |
| TOTAL = | 9,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED and on the SAME chromosome. Correct
MC 4182_8c58
Characteristics of Recessive Phenotypes
- Gene D is linked with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
- Gene F is associated with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,112 |
| 2 | | | | | 1,456 |
| 3 | | | | | 2,032 |
| TOTAL = | 5,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC f4f9_d748
Characteristics of Recessive Phenotypes
- Gene F is affiliated with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene R is connected with the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 60 |
| 2 | | | | | 1,756 |
| 3 | | | | | 2,784 |
| TOTAL = | 4,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC a103_658d
Characteristics of Recessive Phenotypes
- Gene J is associated with the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene X is analogous to the 'xenon' phenotype. A budding yeast that is homozygous recessive for Gene X cells emit a faint glow under UV light, as if they were fluorescent.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 4,239 |
| 2 | | | | | 736 |
| 3 | | | | | 4,225 |
| TOTAL = | 9,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC 896b_5d16
Characteristics of Recessive Phenotypes
- Gene F is linked with the 'fuzzy' phenotype. A budding yeast that is homozygous recessive for Gene F colonies are covered in soft, fine filaments, giving them a fuzzy, cotton-like texture.
- Gene N is correlated with the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,380 |
| 2 | | | | | 1,768 |
| 3 | | | | | 52 |
| TOTAL = | 5,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are BOTH linked AND unlinked. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are NEITHER linked NOR unlinked. Incorrect
MC e226_4dbe
Characteristics of Recessive Phenotypes
- Gene B is affiliated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene H is related to the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,770 |
| 2 | | | | | 1,540 |
| 3 | | | | | 2,690 |
| TOTAL = | 7,000 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are LINKED and on the SAME chromosome. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC a668_9387
Characteristics of Recessive Phenotypes
- Gene A is related to the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene B is associated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 121 |
| 2 | | | | | 3,018 |
| 3 | | | | | 4,061 |
| TOTAL = | 7,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are BOTH linked AND unlinked. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are NEITHER linked NOR unlinked. Incorrect D. The two genes are LINKED and on the SAME chromosome. Correct E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC 7dae_0c87
Characteristics of Recessive Phenotypes
- Gene N is analogous to the 'nude' phenotype. A budding yeast that is homozygous recessive for Gene N cells have an unusually smooth surface with no visible external features or textures.
- Gene R is related to the 'rusty' phenotype. A budding yeast that is homozygous recessive for Gene R colonies develop a reddish-brown pigmentation, reminiscent of rusted metal.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,828 |
| 2 | | | | | 1,456 |
| 3 | | | | | 1,916 |
| TOTAL = | 5,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and on the SAME chromosome. Incorrect D. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC 8e22_9ad7
Characteristics of Recessive Phenotypes
- Gene B is associated with the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene D is linked with the 'doubled' phenotype. A budding yeast that is homozygous recessive for Gene D cells display double or multiple budding, with several buds emerging simultaneously.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 2,729 |
| 2 | | | | | 1,618 |
| 3 | | | | | 53 |
| TOTAL = | 4,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Correct B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect
MC e379_897c
Characteristics of Recessive Phenotypes
- Gene E is connected with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene P is connected with the 'pebble' phenotype. A budding yeast that is homozygous recessive for Gene P produces colonies with a rough, uneven surface that resembles a collection of tiny pebbles.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,802 |
| 2 | | | | | 1,032 |
| 3 | | | | | 3,766 |
| TOTAL = | 8,600 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and on the SAME chromosome. Incorrect B. The two genes are LINKED and on the SAME chromosome. Incorrect C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct F. The two genes are BOTH linked AND unlinked. Incorrect
MC b7f2_9e37
Characteristics of Recessive Phenotypes
- Gene B is related to the 'bubbly' phenotype. A budding yeast that is homozygous recessive for Gene B produces excessive gas bubbles during growth, causing foamy appearance of the media.
- Gene H is connected with the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 111 |
| 2 | | | | | 3,198 |
| 3 | | | | | 5,091 |
| TOTAL = | 8,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are BOTH linked AND unlinked. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect
MC ef2f_d748
Characteristics of Recessive Phenotypes
- Gene E is affiliated with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
- Gene H is analogous to the 'hairy' phenotype. A budding yeast that is homozygous recessive for Gene H cells develop long, thread-like filaments that extend outward, creating a hairy, shaggy texture on the colony.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,451 |
| 2 | | | | | 320 |
| 3 | | | | | 1,429 |
| TOTAL = | 3,200 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are LINKED and on the SAME chromosome. Incorrect B. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct C. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are BOTH linked AND unlinked. Incorrect F. The two genes are UNLINKED and on the SAME chromosome. Incorrect
MC d168_c279
Characteristics of Recessive Phenotypes
- Gene J is analogous to the 'jeweled' phenotype. A budding yeast that is homozygous recessive for Gene J colonies appear dotted with tiny, iridescent spots that sparkle under light.
- Gene T is analogous to the 'toxic' phenotype. A budding yeast that is homozygous recessive for Gene T secretes a toxic compound that inhibits or kills other microbial colonies nearby.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 3,679 |
| 2 | | | | | 2,058 |
| 3 | | | | | 63 |
| TOTAL = | 5,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are NEITHER linked NOR unlinked. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect E. The two genes are UNLINKED and on the SAME chromosome. Incorrect F. The two genes are LINKED and on the SAME chromosome. Correct
MC 397a_e16f
Characteristics of Recessive Phenotypes
- Gene M is connected with the 'militant' phenotype. A budding yeast that is homozygous recessive for Gene M colonies are small, dense, and secrete compounds that inhibit the growth of nearby colonies.
- Gene W is related to the 'webbed' phenotype. A budding yeast that is homozygous recessive for Gene W colonies produce delicate, web-like strands that connect neighboring colonies in a cobweb pattern.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 1,041 |
| 2 | | | | | 288 |
| 3 | | | | | 1,071 |
| TOTAL = | 2,400 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Correct B. The two genes are UNLINKED and on the SAME chromosome. Incorrect C. The two genes are BOTH linked AND unlinked. Incorrect D. The two genes are NEITHER linked NOR unlinked. Incorrect E. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect F. The two genes are LINKED and on the SAME chromosome. Incorrect
MC e513_5175
Characteristics of Recessive Phenotypes
- Gene A is related to the 'amber' phenotype. A budding yeast that is homozygous recessive for Gene A cells develop a rich yellow-orange pigmentation, giving the colony a warm, amber hue.
- Gene E is associated with the 'elephant' phenotype. A budding yeast that is homozygous recessive for Gene E cells absorb excessive amounts of liquid, resulting in giant, swollen cells.
| Set # | Tetrad Genotypes | Progeny
Count |
| 1 | | | | | 83 |
| 2 | | | | | 2,286 |
| 3 | | | | | 3,431 |
| TOTAL = | 5,800 |
The resulting phenotypes are summarized in the table above.
Step-by-Step Instructions
- Step 1: Find the row with the Parental Type for both genes.
- Step 2: Assign PD, NPD, TT for the other rows
- Step 3: Determine if the two genes are linked.
- PD >> NPD → linked; PD ≈ NPD → unlinked
Unordered Tetrad Two Gene Determine Linkage
The yeast Saccharomyces cerevisiae has unordered tetrads. A cross is made to study the linkage relationships among two genes.
Using the table above, determine the linkage between the two genes.
A. The two genes are UNLINKED and likely on DIFFERENT chromosomes. Incorrect B. The two genes are LINKED but are likely on DIFFERENT chromosomes. Incorrect C. The two genes are LINKED and on the SAME chromosome. Correct D. The two genes are UNLINKED and on the SAME chromosome. Incorrect E. The two genes are NEITHER linked NOR unlinked. Incorrect F. The two genes are BOTH linked AND unlinked. Incorrect