3c7a_7c12

Three-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a three-point test cross examines three (3) genes at the same time to learn about their assortment in gamete formation.

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is connected with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes			Progeny Count
fuzzy, jerky, nerdy	f	j	n	36,895
fuzzy, jerky	f	j	+	51,731
fuzzy, nerdy	f	+	n	30,335
fuzzy	f	+	+	6,282
jerky, nerdy	+	j	n	6,304
jerky	+	j	+	30,104
nerdy	+	+	n	51,655
wildtype	+	+	+	36,694
TOTAL =				250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and J during meiosis.

calculate the genetic distance between the two genes F and J, expressing your answer in centimorgans (cM)

A. ^{(6,282 + 6,304 + 36,694)}/_250,000 = ^49,280/_250,000 = 0.1971 = 19.71 cM Incorrect B. ^{(51,655 + 51,731)}/_250,000 = ^103,386/_250,000 = 0.4135 = 41.35 cM Incorrect C. ^{(6,282 + 51,655)}/_250,000 = ^57,937/_250,000 = 0.2317 = 23.17 cM Incorrect D. ^{(6,282 + 6,304 + 30,104 + 30,335)}/_250,000 = ^73,025/_250,000 = 0.2921 = 29.21 cM Correct E. ^{(6,304 + 36,694 + 51,655)}/_250,000 = ^94,653/_250,000 = 0.3786 = 37.86 cM Incorrect F. ^{(6,282 + 51,731)}/_250,000 = ^58,013/_250,000 = 0.2321 = 23.21 cM Incorrect MC

bced_0e66

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is associated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene M is correlated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
horsey, mushy, xanthic	h	m	x	10,915
horsey, mushy	h	m	+	49,584
horsey, xanthic	h	+	x	8,466
horsey	h	+	+	956
mushy, xanthic	+	m	x	980
mushy	+	m	+	8,582
xanthic	+	+	x	49,568
wildtype	+	+	+	10,949
TOTAL =				140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and X during meiosis.

calculate the genetic distance between the two genes H and X, expressing your answer in centimorgans (cM)

A. ^{(10,915 + 49,568)}/_140,000 = ^60,483/_140,000 = 0.4320 = 43.20 cM Incorrect B. ^8,582/_140,000 = ^8,582/_140,000 = 0.0613 = 6.13 cM Incorrect C. ^{(49,568 + 49,584)}/_140,000 = ^99,152/_140,000 = 0.7082 = 70.82 cM Incorrect D. ^{(980 + 8,582 + 10,949)}/_140,000 = ^20,511/_140,000 = 0.1465 = 14.65 cM Incorrect E. ^{(956 + 980 + 10,915)}/_140,000 = ^12,851/_140,000 = 0.0918 = 9.18 cM Incorrect F. ^{(8,466 + 8,582 + 10,915 + 10,949)}/_140,000 = ^38,912/_140,000 = 0.2779 = 27.79 cM Correct MC

7a6d_8446

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes			Progeny Count
chummy, eery, jerky	c	e	j	15,414
chummy, eery	c	e	+	75,986
chummy, jerky	c	+	j	2,020
chummy	c	+	+	12,059
eery, jerky	+	e	j	12,000
eery	+	e	+	2,124
jerky	+	+	j	75,242
wildtype	+	+	+	15,155
TOTAL =				210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and J during meiosis.

calculate the genetic distance between the two genes C and J, expressing your answer in centimorgans (cM)

A. ^{(75,242 + 75,986)}/_210,000 = ^151,228/_210,000 = 0.7201 = 72.01 cM Incorrect B. ^{(2,020 + 2,124 + 15,155 + 15,414)}/_210,000 = ^34,713/_210,000 = 0.1653 = 16.53 cM Correct C. ^{(12,000 + 75,986)}/_210,000 = ^87,986/_210,000 = 0.4190 = 41.90 cM Incorrect D. ^12,059/_210,000 = ^12,059/_210,000 = 0.0574 = 5.74 cM Incorrect E. ^{(2,020 + 2,124 + 12,000)}/_210,000 = ^16,144/_210,000 = 0.0769 = 7.69 cM Incorrect F. ^{(15,414 + 75,242)}/_210,000 = ^90,656/_210,000 = 0.4317 = 43.17 cM Incorrect MC

5d8d_5809

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes			Progeny Count
chummy, dewy, eery	c	d	e	9,097
chummy, dewy	c	d	+	3,134
chummy, eery	c	+	e	13,619
chummy	c	+	+	34,344
dewy, eery	+	d	e	34,133
dewy	+	d	+	13,700
eery	+	+	e	3,063
wildtype	+	+	+	8,910
TOTAL =				120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and D during meiosis.

calculate the genetic distance between the two genes C and D, expressing your answer in centimorgans (cM)

A. ^3,134/_120,000 = ^3,134/_120,000 = 0.0261 = 2.61 cM Incorrect B. ^{(3,063 + 9,097)}/_120,000 = ^12,160/_120,000 = 0.1013 = 10.13 cM Incorrect C. ^{(34,133 + 34,344)}/_120,000 = ^68,477/_120,000 = 0.5706 = 57.06 cM Incorrect D. ^34,344/_120,000 = ^34,344/_120,000 = 0.2862 = 28.62 cM Incorrect E. ^9,097/_120,000 = ^9,097/_120,000 = 0.0758 = 7.58 cM Incorrect F. ^{(3,063 + 3,134 + 8,910 + 9,097)}/_120,000 = ^24,204/_120,000 = 0.2017 = 20.17 cM Correct MC

79ad_9d70

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
jerky, nerdy, yucky	j	n	y	55
jerky, nerdy	j	n	+	3,198
jerky, yucky	j	+	y	62,737
jerky	j	+	+	4,005
nerdy, yucky	+	n	y	3,931
nerdy	+	n	+	62,705
yucky	+	+	y	3,310
wildtype	+	+	+	59
TOTAL =				140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes J and N during meiosis.

calculate the genetic distance between the two genes J and N, expressing your answer in centimorgans (cM)

A. ^{(55 + 3,198 + 3,310 + 4,005)}/_140,000 = ^10,568/_140,000 = 0.0755 = 7.55 cM Incorrect B. ^{(55 + 62,737)}/_140,000 = ^62,792/_140,000 = 0.4485 = 44.85 cM Incorrect C. ^{(55 + 59 + 3,198 + 3,310 + 3,931)}/_140,000 = ^10,553/_140,000 = 0.0754 = 7.54 cM Incorrect D. ^{(55 + 59 + 3,198 + 3,310)}/_140,000 = ^6,622/_140,000 = 0.0473 = 4.73 cM Correct E. ^{(62,705 + 62,737)}/_140,000 = ^125,442/_140,000 = 0.8960 = 89.60 cM Incorrect F. ^{(59 + 4,005)}/_140,000 = ^4,064/_140,000 = 0.0290 = 2.90 cM Incorrect MC

c5e2_73af

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
horsey, waxy, yucky	h	w	y	32,680
horsey, waxy	h	w	+	2,941
horsey, yucky	h	+	y	29,396
horsey	h	+	+	24,988
waxy, yucky	+	w	y	24,965
waxy	+	w	+	29,179
yucky	+	+	y	3,086
wildtype	+	+	+	32,765
TOTAL =				180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and Y during meiosis.

calculate the genetic distance between the two genes H and Y, expressing your answer in centimorgans (cM)

A. ^{(24,965 + 32,680)}/_180,000 = ^57,645/_180,000 = 0.3202 = 32.02 cM Incorrect B. ^{(3,086 + 24,965 + 24,988)}/_180,000 = ^53,039/_180,000 = 0.2947 = 29.47 cM Incorrect C. ^{(2,941 + 3,086 + 24,965 + 24,988)}/_180,000 = ^55,980/_180,000 = 0.3110 = 31.10 cM Correct D. ^29,396/_180,000 = ^29,396/_180,000 = 0.1633 = 16.33 cM Incorrect E. ^{(24,965 + 24,988 + 29,179)}/_180,000 = ^79,132/_180,000 = 0.4396 = 43.96 cM Incorrect F. ^{(32,680 + 32,765)}/_180,000 = ^65,445/_180,000 = 0.3636 = 36.36 cM Incorrect MC

fbec_0d73

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is connected with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes			Progeny Count
fuzzy, jerky, nerdy	f	j	n	27,514
fuzzy, jerky	f	j	+	18,020
fuzzy, nerdy	f	+	n	74,676
fuzzy	f	+	+	4,870
jerky, nerdy	+	j	n	4,995
jerky	+	j	+	74,814
nerdy	+	+	n	18,015
wildtype	+	+	+	27,096
TOTAL =				250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and J during meiosis.

calculate the genetic distance between the two genes F and J, expressing your answer in centimorgans (cM)

A. ^{(74,676 + 74,814)}/_250,000 = ^149,490/_250,000 = 0.5980 = 59.80 cM Incorrect B. ^4,995/_250,000 = ^4,995/_250,000 = 0.0200 = 2.00 cM Incorrect C. ^18,015/_250,000 = ^18,015/_250,000 = 0.0721 = 7.21 cM Incorrect D. ^{(18,015 + 18,020 + 27,096 + 27,514)}/_250,000 = ^90,645/_250,000 = 0.3626 = 36.26 cM Correct E. ^{(4,995 + 27,096 + 27,514)}/_250,000 = ^59,605/_250,000 = 0.2384 = 23.84 cM Incorrect F. ^{(4,995 + 27,514 + 74,676)}/_250,000 = ^107,185/_250,000 = 0.4287 = 42.87 cM Incorrect MC

9686_b153

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene R is affiliated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
mushy, nerdy, rusty	m	n	r	81,946
mushy, nerdy	m	n	+	7,958
mushy, rusty	m	+	r	42,651
mushy	m	+	+	2,421
nerdy, rusty	+	n	r	2,471
nerdy	+	n	+	42,988
rusty	+	+	r	7,994
wildtype	+	+	+	81,571
TOTAL =				270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and R during meiosis.

calculate the genetic distance between the two genes M and R, expressing your answer in centimorgans (cM)

A. ^{(7,994 + 42,651)}/_270,000 = ^50,645/_270,000 = 0.1876 = 18.76 cM Incorrect B. ^7,994/_270,000 = ^7,994/_270,000 = 0.0296 = 2.96 cM Incorrect C. ^{(42,651 + 81,571)}/_270,000 = ^124,222/_270,000 = 0.4601 = 46.01 cM Incorrect D. ^{(2,421 + 42,651 + 42,988)}/_270,000 = ^88,060/_270,000 = 0.3261 = 32.61 cM Incorrect E. ^{(81,571 + 81,946)}/_270,000 = ^163,517/_270,000 = 0.6056 = 60.56 cM Incorrect F. ^{(2,421 + 2,471 + 7,958 + 7,994)}/_270,000 = ^20,844/_270,000 = 0.0772 = 7.72 cM Correct MC

dbe3_fd8f

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
fuzzy, jerky, yucky	f	j	y	791
fuzzy, jerky	f	j	+	161
fuzzy, yucky	f	+	y	8,188
fuzzy	f	+	+	15,964
jerky, yucky	+	j	y	15,604
jerky	+	j	+	8,259
yucky	+	+	y	172
wildtype	+	+	+	861
TOTAL =				50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and Y during meiosis.

calculate the genetic distance between the two genes F and Y, expressing your answer in centimorgans (cM)

A. ^{(791 + 861 + 8,188 + 8,259)}/_50,000 = ^18,099/_50,000 = 0.3620 = 36.20 cM Correct B. ^{(15,604 + 15,964)}/_50,000 = ^31,568/_50,000 = 0.6314 = 63.14 cM Incorrect C. ^{(8,188 + 15,964)}/_50,000 = ^24,152/_50,000 = 0.4830 = 48.30 cM Incorrect D. ^{(172 + 861)}/_50,000 = ^1,033/_50,000 = 0.0207 = 2.07 cM Incorrect E. ^{(172 + 791 + 861 + 15,604)}/_50,000 = ^17,428/_50,000 = 0.3486 = 34.86 cM Incorrect F. ^{(161 + 791 + 861 + 15,964)}/_50,000 = ^17,777/_50,000 = 0.3555 = 35.55 cM Incorrect MC

4a72_6afc

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is correlated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
eery, waxy, yucky	e	w	y	26,414
eery, waxy	e	w	+	866
eery, yucky	e	+	y	18,320
eery	e	+	+	29,026
waxy, yucky	+	w	y	29,157
waxy	+	w	+	18,477
yucky	+	+	y	902
wildtype	+	+	+	26,838
TOTAL =				150,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and Y during meiosis.

calculate the genetic distance between the two genes E and Y, expressing your answer in centimorgans (cM)

A. ^{(29,026 + 29,157)}/_150,000 = ^58,183/_150,000 = 0.3879 = 38.79 cM Incorrect B. ^{(18,320 + 18,477 + 26,414 + 26,838)}/_150,000 = ^90,049/_150,000 = 0.6003 = 60.03 cM Correct C. ^{(902 + 18,320 + 18,477 + 29,157)}/_150,000 = ^66,856/_150,000 = 0.4457 = 44.57 cM Incorrect D. ^{(902 + 18,320 + 18,477 + 29,026)}/_150,000 = ^66,725/_150,000 = 0.4448 = 44.48 cM Incorrect E. ⁸⁶⁶/_150,000 = ⁸⁶⁶/_150,000 = 0.0058 = 0.58 cM Incorrect F. ^{(18,477 + 29,157)}/_150,000 = ^47,634/_150,000 = 0.3176 = 31.76 cM Incorrect MC

6a24_516e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
horsey, prickly, waxy	h	p	w	2,735
horsey, prickly	h	p	+	643
horsey, waxy	h	+	w	3,174
horsey	h	+	+	3,450
prickly, waxy	+	p	w	3,434
prickly	+	p	+	3,126
waxy	+	+	w	651
wildtype	+	+	+	2,787
TOTAL =				20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes P and W during meiosis.

calculate the genetic distance between the two genes P and W, expressing your answer in centimorgans (cM)

A. ^{(2,735 + 2,787 + 3,450)}/_20,000 = ^8,972/_20,000 = 0.4486 = 44.86 cM Incorrect B. ^{(651 + 2,735 + 2,787)}/_20,000 = ^6,173/_20,000 = 0.3086 = 30.86 cM Incorrect C. ^{(651 + 2,735 + 3,434)}/_20,000 = ^6,820/_20,000 = 0.3410 = 34.10 cM Incorrect D. ^{(643 + 651 + 3,126 + 3,174)}/_20,000 = ^7,594/_20,000 = 0.3797 = 37.97 cM Correct E. ^{(651 + 2,787 + 3,126 + 3,174)}/_20,000 = ^9,738/_20,000 = 0.4869 = 48.69 cM Incorrect F. ^{(3,434 + 3,450)}/_20,000 = ^6,884/_20,000 = 0.3442 = 34.42 cM Incorrect MC

4f38_e53a

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes			Progeny Count
jerky, kidney, mushy	j	k	m	17,326
jerky, kidney	j	k	+	14,634
jerky, mushy	j	+	m	59,594
jerky	j	+	+	3,405
kidney, mushy	+	k	m	3,502
kidney	+	k	+	59,641
mushy	+	+	m	14,388
wildtype	+	+	+	17,510
TOTAL =				190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and M during meiosis.

calculate the genetic distance between the two genes K and M, expressing your answer in centimorgans (cM)

A. ^{(3,405 + 3,502 + 14,634 + 17,510)}/_190,000 = ^39,051/_190,000 = 0.2055 = 20.55 cM Incorrect B. ^{(59,594 + 59,641)}/_190,000 = ^119,235/_190,000 = 0.6276 = 62.76 cM Incorrect C. ^{(3,405 + 3,502 + 17,326 + 17,510)}/_190,000 = ^41,743/_190,000 = 0.2197 = 21.97 cM Correct D. ^59,641/_190,000 = ^59,641/_190,000 = 0.3139 = 31.39 cM Incorrect E. ^{(3,405 + 3,502 + 14,388 + 17,326 + 17,510)}/_190,000 = ^56,131/_190,000 = 0.2954 = 29.54 cM Incorrect F. ^{(3,502 + 14,388 + 14,634 + 17,510)}/_190,000 = ^50,034/_190,000 = 0.2633 = 26.33 cM Incorrect MC

890e_c83e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes			Progeny Count
chummy, kidney, nerdy	c	k	n	3,008
chummy, kidney	c	k	+	147
chummy, nerdy	c	+	n	9,026
chummy	c	+	+	2,729
kidney, nerdy	+	k	n	2,830
kidney	+	k	+	9,028
nerdy	+	+	n	129
wildtype	+	+	+	3,103
TOTAL =				30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and K during meiosis.

calculate the genetic distance between the two genes C and K, expressing your answer in centimorgans (cM)

A. ^{(129 + 2,830)}/_30,000 = ^2,959/_30,000 = 0.0986 = 9.86 cM Incorrect B. ^{(129 + 3,103 + 9,028)}/_30,000 = ^12,260/_30,000 = 0.4087 = 40.87 cM Incorrect C. ^{(9,026 + 9,028)}/_30,000 = ^18,054/_30,000 = 0.6018 = 60.18 cM Incorrect D. ^{(129 + 147 + 3,008 + 3,103)}/_30,000 = ^6,387/_30,000 = 0.2129 = 21.29 cM Correct E. ^{(3,008 + 3,103)}/_30,000 = ^6,111/_30,000 = 0.2037 = 20.37 cM Incorrect F. ^{(129 + 147 + 2,830 + 9,028)}/_30,000 = ^12,134/_30,000 = 0.4045 = 40.45 cM Incorrect MC

74b8_4610

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
nerdy, waxy, xanthic	n	w	x	12,972
nerdy, waxy	n	w	+	3,895
nerdy, xanthic	n	+	x	775
nerdy	n	+	+	17,084
waxy, xanthic	+	w	x	17,408
waxy	+	w	+	768
xanthic	+	+	x	3,921
wildtype	+	+	+	13,177
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes N and X during meiosis.

calculate the genetic distance between the two genes N and X, expressing your answer in centimorgans (cM)

A. ^{(3,921 + 13,177 + 17,084)}/_70,000 = ^34,182/_70,000 = 0.4883 = 48.83 cM Incorrect B. ^{(775 + 12,972 + 17,408)}/_70,000 = ^31,155/_70,000 = 0.4451 = 44.51 cM Incorrect C. ^{(12,972 + 17,084)}/_70,000 = ^30,056/_70,000 = 0.4294 = 42.94 cM Incorrect D. ⁷⁶⁸/_70,000 = ⁷⁶⁸/_70,000 = 0.0110 = 1.10 cM Incorrect E. ^{(768 + 775 + 12,972 + 13,177)}/_70,000 = ^27,692/_70,000 = 0.3956 = 39.56 cM Correct F. ^{(17,084 + 17,408)}/_70,000 = ^34,492/_70,000 = 0.4927 = 49.27 cM Incorrect MC

d638_b561

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes			Progeny Count
artsy, chummy, dewy	a	c	d	23,582
artsy, chummy	a	c	+	4,564
artsy, dewy	a	+	d	6,615
artsy	a	+	+	226
chummy, dewy	+	c	d	241
chummy	+	c	+	6,603
dewy	+	+	d	4,531
wildtype	+	+	+	23,638
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and D during meiosis.

calculate the genetic distance between the two genes C and D, expressing your answer in centimorgans (cM)

A. ^{(4,531 + 4,564 + 6,603 + 6,615)}/_70,000 = ^22,313/_70,000 = 0.3188 = 31.88 cM Correct B. ^{(226 + 241 + 23,582)}/_70,000 = ^24,049/_70,000 = 0.3436 = 34.36 cM Incorrect C. ^{(23,582 + 23,638)}/_70,000 = ^47,220/_70,000 = 0.6746 = 67.46 cM Incorrect D. ^{(226 + 4,564 + 6,615)}/_70,000 = ^11,405/_70,000 = 0.1629 = 16.29 cM Incorrect E. ^{(241 + 4,564 + 6,615)}/_70,000 = ^11,420/_70,000 = 0.1631 = 16.31 cM Incorrect F. ^23,638/_70,000 = ^23,638/_70,000 = 0.3377 = 33.77 cM Incorrect MC

587c_2383

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
horsey, kidney, prickly	h	k	p	18,901
horsey, kidney	h	k	+	1,660
horsey, prickly	h	+	p	152
horsey	h	+	+	6,859
kidney, prickly	+	k	p	6,704
kidney	+	k	+	178
prickly	+	+	p	1,607
wildtype	+	+	+	18,939
TOTAL =				55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and P during meiosis.

calculate the genetic distance between the two genes H and P, expressing your answer in centimorgans (cM)

A. ^{(1,607 + 1,660 + 6,704 + 6,859)}/_55,000 = ^16,830/_55,000 = 0.3060 = 30.60 cM Correct B. ^{(152 + 178 + 1,607 + 1,660)}/_55,000 = ^3,597/_55,000 = 0.0654 = 6.54 cM Incorrect C. ^{(1,660 + 18,939)}/_55,000 = ^20,599/_55,000 = 0.3745 = 37.45 cM Incorrect D. ^{(18,901 + 18,939)}/_55,000 = ^37,840/_55,000 = 0.6880 = 68.80 cM Incorrect E. ¹⁷⁸/_55,000 = ¹⁷⁸/_55,000 = 0.0032 = 0.32 cM Incorrect F. ^1,660/_55,000 = ^1,660/_55,000 = 0.0302 = 3.02 cM Incorrect MC

63af_a8d3

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene R is connected with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
kidney, nerdy, rusty	k	n	r	8,099
kidney, nerdy	k	n	+	2,739
kidney, rusty	k	+	r	26,400
kidney	k	+	+	37,441
nerdy, rusty	+	n	r	37,859
nerdy	+	n	+	26,625
rusty	+	+	r	2,631
wildtype	+	+	+	8,206
TOTAL =				150,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and N during meiosis.

calculate the genetic distance between the two genes K and N, expressing your answer in centimorgans (cM)

A. ^{(37,441 + 37,859)}/_150,000 = ^75,300/_150,000 = 0.5020 = 50.20 cM Incorrect B. ^8,206/_150,000 = ^8,206/_150,000 = 0.0547 = 5.47 cM Incorrect C. ^37,859/_150,000 = ^37,859/_150,000 = 0.2524 = 25.24 cM Incorrect D. ^2,739/_150,000 = ^2,739/_150,000 = 0.0183 = 1.83 cM Incorrect E. ^{(26,400 + 37,859)}/_150,000 = ^64,259/_150,000 = 0.4284 = 42.84 cM Incorrect F. ^{(2,631 + 2,739 + 8,099 + 8,206)}/_150,000 = ^21,675/_150,000 = 0.1445 = 14.45 cM Correct MC

49d4_07e0

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
artsy, nerdy, xanthic	a	n	x	1,344
artsy, nerdy	a	n	+	7,822
artsy, xanthic	a	+	x	82,154
artsy	a	+	+	48,955
nerdy, xanthic	+	n	x	49,122
nerdy	+	n	+	81,429
xanthic	+	+	x	7,879
wildtype	+	+	+	1,295
TOTAL =				280,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and X during meiosis.

calculate the genetic distance between the two genes A and X, expressing your answer in centimorgans (cM)

A. ^{(1,295 + 81,429)}/_280,000 = ^82,724/_280,000 = 0.2954 = 29.54 cM Incorrect B. ^{(7,879 + 81,429)}/_280,000 = ^89,308/_280,000 = 0.3190 = 31.90 cM Incorrect C. ^81,429/_280,000 = ^81,429/_280,000 = 0.2908 = 29.08 cM Incorrect D. ^{(81,429 + 82,154)}/_280,000 = ^163,583/_280,000 = 0.5842 = 58.42 cM Incorrect E. ^{(48,955 + 49,122)}/_280,000 = ^98,077/_280,000 = 0.3503 = 35.03 cM Incorrect F. ^{(7,822 + 7,879 + 48,955 + 49,122)}/_280,000 = ^113,778/_280,000 = 0.4063 = 40.63 cM Correct MC

32fa_995b

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is related to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
dewy, eery, prickly	d	e	p	1,929
dewy, eery	d	e	+	28,596
dewy, prickly	d	+	p	8,967
dewy	d	+	+	15,416
eery, prickly	+	e	p	15,704
eery	+	e	+	9,107
prickly	+	+	p	28,427
wildtype	+	+	+	1,854
TOTAL =				110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and P during meiosis.

calculate the genetic distance between the two genes D and P, expressing your answer in centimorgans (cM)

A. ^{(1,929 + 15,416)}/_110,000 = ^17,345/_110,000 = 0.1577 = 15.77 cM Incorrect B. ^{(15,416 + 28,596)}/_110,000 = ^44,012/_110,000 = 0.4001 = 40.01 cM Incorrect C. ^{(28,427 + 28,596)}/_110,000 = ^57,023/_110,000 = 0.5184 = 51.84 cM Incorrect D. ^8,967/_110,000 = ^8,967/_110,000 = 0.0815 = 8.15 cM Incorrect E. ^{(1,854 + 1,929 + 8,967 + 9,107)}/_110,000 = ^21,857/_110,000 = 0.1987 = 19.87 cM Correct F. ^{(8,967 + 9,107 + 15,416 + 15,704)}/_110,000 = ^49,194/_110,000 = 0.4472 = 44.72 cM Incorrect MC

8d04_61dd

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is associated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene P is connected with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene T is related to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
bumpy, prickly, tipsy	b	p	t	183
bumpy, prickly	b	p	+	37,679
bumpy, tipsy	b	+	t	5,151
bumpy	b	+	+	1,867
prickly, tipsy	+	p	t	1,960
prickly	+	p	+	5,246
tipsy	+	+	t	37,748
wildtype	+	+	+	166
TOTAL =				90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes B and T during meiosis.

calculate the genetic distance between the two genes B and T, expressing your answer in centimorgans (cM)

A. ^{(5,151 + 5,246)}/_90,000 = ^10,397/_90,000 = 0.1155 = 11.55 cM Incorrect B. ^1,960/_90,000 = ^1,960/_90,000 = 0.0218 = 2.18 cM Incorrect C. ^{(37,679 + 37,748)}/_90,000 = ^75,427/_90,000 = 0.8381 = 83.81 cM Incorrect D. ^5,246/_90,000 = ^5,246/_90,000 = 0.0583 = 5.83 cM Incorrect E. ^{(183 + 1,960 + 37,679)}/_90,000 = ^39,822/_90,000 = 0.4425 = 44.25 cM Incorrect F. ^{(166 + 183 + 5,151 + 5,246)}/_90,000 = ^10,746/_90,000 = 0.1194 = 11.94 cM Correct MC

2ef6_d284

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
waxy, xanthic, yucky	w	x	y	19,879
waxy, xanthic	w	x	+	3,531
waxy, yucky	w	+	y	37,521
waxy	w	+	+	64,140
xanthic, yucky	+	x	y	63,728
xanthic	+	x	+	37,636
yucky	+	+	y	3,487
wildtype	+	+	+	20,078
TOTAL =				250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes W and Y during meiosis.

calculate the genetic distance between the two genes W and Y, expressing your answer in centimorgans (cM)

A. ^{(3,531 + 19,879 + 20,078 + 37,636)}/_250,000 = ^81,124/_250,000 = 0.3245 = 32.45 cM Incorrect B. ^{(19,879 + 37,636)}/_250,000 = ^57,515/_250,000 = 0.2301 = 23.01 cM Incorrect C. ^3,487/_250,000 = ^3,487/_250,000 = 0.0139 = 1.39 cM Incorrect D. ^3,531/_250,000 = ^3,531/_250,000 = 0.0141 = 1.41 cM Incorrect E. ^{(19,879 + 20,078 + 37,521 + 37,636)}/_250,000 = ^115,114/_250,000 = 0.4605 = 46.05 cM Correct F. ^{(63,728 + 64,140)}/_250,000 = ^127,868/_250,000 = 0.5115 = 51.15 cM Incorrect MC

c55f_d008

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
eery, horsey, waxy	e	h	w	16,790
eery, horsey	e	h	+	294
eery, waxy	e	+	w	3,180
eery	e	+	+	35,004
horsey, waxy	+	h	w	34,678
horsey	+	h	+	3,071
waxy	+	+	w	231
wildtype	+	+	+	16,752
TOTAL =				110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and H during meiosis.

calculate the genetic distance between the two genes E and H, expressing your answer in centimorgans (cM)

A. ^16,790/_110,000 = ^16,790/_110,000 = 0.1526 = 15.26 cM Incorrect B. ^{(231 + 294 + 16,752 + 16,790)}/_110,000 = ^34,067/_110,000 = 0.3097 = 30.97 cM Correct C. ^16,752/_110,000 = ^16,752/_110,000 = 0.1523 = 15.23 cM Incorrect D. ^{(16,752 + 34,678)}/_110,000 = ^51,430/_110,000 = 0.4675 = 46.75 cM Incorrect E. ^{(34,678 + 35,004)}/_110,000 = ^69,682/_110,000 = 0.6335 = 63.35 cM Incorrect F. ^{(294 + 16,790 + 34,678)}/_110,000 = ^51,762/_110,000 = 0.4706 = 47.06 cM Incorrect MC

6cee_50f0

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
kidney, tipsy, waxy	k	t	w	16,076
kidney, tipsy	k	t	+	28,469
kidney, waxy	k	+	w	1,758
kidney	k	+	+	8,770
tipsy, waxy	+	t	w	8,896
tipsy	+	t	+	1,663
waxy	+	+	w	28,170
wildtype	+	+	+	16,198
TOTAL =				110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes T and W during meiosis.

calculate the genetic distance between the two genes T and W, expressing your answer in centimorgans (cM)

A. ^{(8,770 + 8,896 + 16,076 + 16,198)}/_110,000 = ^49,940/_110,000 = 0.4540 = 45.40 cM Correct B. ^{(28,170 + 28,469)}/_110,000 = ^56,639/_110,000 = 0.5149 = 51.49 cM Incorrect C. ^8,896/_110,000 = ^8,896/_110,000 = 0.0809 = 8.09 cM Incorrect D. ^1,758/_110,000 = ^1,758/_110,000 = 0.0160 = 1.60 cM Incorrect E. ^{(1,758 + 8,896 + 28,170)}/_110,000 = ^38,824/_110,000 = 0.3529 = 35.29 cM Incorrect F. ^{(8,896 + 16,076)}/_110,000 = ^24,972/_110,000 = 0.2270 = 22.70 cM Incorrect MC

5972_e22d

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is connected with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
bumpy, kidney, yucky	b	k	y	21,080
bumpy, kidney	b	k	+	357
bumpy, yucky	b	+	y	8,496
bumpy	b	+	+	2,572
kidney, yucky	+	k	y	2,603
kidney	+	k	+	8,522
yucky	+	+	y	357
wildtype	+	+	+	21,013
TOTAL =				65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and Y during meiosis.

calculate the genetic distance between the two genes K and Y, expressing your answer in centimorgans (cM)

A. ^{(2,572 + 2,603 + 21,080)}/_65,000 = ^26,255/_65,000 = 0.4039 = 40.39 cM Incorrect B. ^{(357 + 357 + 2,572 + 2,603 + 21,013)}/_65,000 = ^26,902/_65,000 = 0.4139 = 41.39 cM Incorrect C. ^{(357 + 357 + 8,496 + 8,522)}/_65,000 = ^17,732/_65,000 = 0.2728 = 27.28 cM Correct D. ^21,080/_65,000 = ^21,080/_65,000 = 0.3243 = 32.43 cM Incorrect E. ^{(21,013 + 21,080)}/_65,000 = ^42,093/_65,000 = 0.6476 = 64.76 cM Incorrect F. ^{(357 + 2,572 + 21,013)}/_65,000 = ^23,942/_65,000 = 0.3683 = 36.83 cM Incorrect MC

5ce8_3c14

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
kidney, nerdy, tipsy	k	n	t	9,224
kidney, nerdy	k	n	+	766
kidney, tipsy	k	+	t	75,463
kidney	k	+	+	14,299
nerdy, tipsy	+	n	t	14,614
nerdy	+	n	+	75,564
tipsy	+	+	t	761
wildtype	+	+	+	9,309
TOTAL =				200,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and T during meiosis.

calculate the genetic distance between the two genes K and T, expressing your answer in centimorgans (cM)

A. ⁷⁶⁶/_200,000 = ⁷⁶⁶/_200,000 = 0.0038 = 0.38 cM Incorrect B. ^{(766 + 14,299 + 75,463)}/_200,000 = ^90,528/_200,000 = 0.4526 = 45.26 cM Incorrect C. ^{(75,463 + 75,564)}/_200,000 = ^151,027/_200,000 = 0.7551 = 75.51 cM Incorrect D. ^{(761 + 766 + 14,614 + 75,564)}/_200,000 = ^91,705/_200,000 = 0.4585 = 45.85 cM Incorrect E. ^{(761 + 766 + 14,299 + 14,614)}/_200,000 = ^30,440/_200,000 = 0.1522 = 15.22 cM Correct F. ^{(14,299 + 14,614)}/_200,000 = ^28,913/_200,000 = 0.1446 = 14.46 cM Incorrect MC

4eeb_572f

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
dewy, nerdy, waxy	d	n	w	16,912
dewy, nerdy	d	n	+	16,455
dewy, waxy	d	+	w	3,187
dewy	d	+	+	18,632
nerdy, waxy	+	n	w	18,448
nerdy	+	n	+	3,159
waxy	+	+	w	16,381
wildtype	+	+	+	16,826
TOTAL =				110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes N and W during meiosis.

calculate the genetic distance between the two genes N and W, expressing your answer in centimorgans (cM)

A. ^{(3,187 + 16,826)}/_110,000 = ^20,013/_110,000 = 0.1819 = 18.19 cM Incorrect B. ^16,826/_110,000 = ^16,826/_110,000 = 0.1530 = 15.30 cM Incorrect C. ^{(3,159 + 3,187 + 16,381 + 16,455)}/_110,000 = ^39,182/_110,000 = 0.3562 = 35.62 cM Correct D. ^{(18,448 + 18,632)}/_110,000 = ^37,080/_110,000 = 0.3371 = 33.71 cM Incorrect E. ^{(3,159 + 3,187 + 16,826 + 18,448)}/_110,000 = ^41,620/_110,000 = 0.3784 = 37.84 cM Incorrect F. ^{(3,187 + 16,455 + 16,826 + 16,912)}/_110,000 = ^53,380/_110,000 = 0.4853 = 48.53 cM Incorrect MC

7894_1775

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
jerky, mushy, tipsy	j	m	t	27,337
jerky, mushy	j	m	+	6,394
jerky, tipsy	j	+	t	63,624
jerky	j	+	+	42,576
mushy, tipsy	+	m	t	42,847
mushy	+	m	+	63,669
tipsy	+	+	t	6,491
wildtype	+	+	+	27,062
TOTAL =				280,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and T during meiosis.

calculate the genetic distance between the two genes M and T, expressing your answer in centimorgans (cM)

A. ^{(63,624 + 63,669)}/_280,000 = ^127,293/_280,000 = 0.4546 = 45.46 cM Incorrect B. ^{(27,062 + 27,337 + 42,576 + 42,847)}/_280,000 = ^139,822/_280,000 = 0.4994 = 49.94 cM Correct C. ^{(27,337 + 42,576 + 63,624)}/_280,000 = ^133,537/_280,000 = 0.4769 = 47.69 cM Incorrect D. ^{(27,337 + 42,847)}/_280,000 = ^70,184/_280,000 = 0.2507 = 25.07 cM Incorrect E. ^63,624/_280,000 = ^63,624/_280,000 = 0.2272 = 22.72 cM Incorrect F. ^{(27,062 + 27,337 + 42,847)}/_280,000 = ^97,246/_280,000 = 0.3473 = 34.73 cM Incorrect MC

97ad_14fc

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene N is related to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
chummy, nerdy, tipsy	c	n	t	1,301
chummy, nerdy	c	n	+	17,898
chummy, tipsy	c	+	t	17,795
chummy	c	+	+	23,089
nerdy, tipsy	+	n	t	23,421
nerdy	+	n	+	17,523
tipsy	+	+	t	17,588
wildtype	+	+	+	1,385
TOTAL =				120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and T during meiosis.

calculate the genetic distance between the two genes C and T, expressing your answer in centimorgans (cM)

A. ^1,385/_120,000 = ^1,385/_120,000 = 0.0115 = 1.15 cM Incorrect B. ^{(17,795 + 17,898)}/_120,000 = ^35,693/_120,000 = 0.2974 = 29.74 cM Incorrect C. ^{(1,301 + 1,385 + 17,523 + 17,898)}/_120,000 = ^38,107/_120,000 = 0.3176 = 31.76 cM Incorrect D. ^{(1,301 + 1,385 + 17,523 + 17,795)}/_120,000 = ^38,004/_120,000 = 0.3167 = 31.67 cM Correct E. ^{(23,089 + 23,421)}/_120,000 = ^46,510/_120,000 = 0.3876 = 38.76 cM Incorrect F. ^{(17,523 + 17,588)}/_120,000 = ^35,111/_120,000 = 0.2926 = 29.26 cM Incorrect MC

8c24_4f27

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene H is associated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
bumpy, horsey, waxy	b	h	w	13,105
bumpy, horsey	b	h	+	898
bumpy, waxy	b	+	w	35,069
bumpy	b	+	+	16,305
horsey, waxy	+	h	w	16,177
horsey	+	h	+	34,603
waxy	+	+	w	940
wildtype	+	+	+	12,903
TOTAL =				130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes B and H during meiosis.

calculate the genetic distance between the two genes B and H, expressing your answer in centimorgans (cM)

A. ^{(940 + 16,305)}/_130,000 = ^17,245/_130,000 = 0.1327 = 13.27 cM Incorrect B. ^{(898 + 35,069)}/_130,000 = ^35,967/_130,000 = 0.2767 = 27.67 cM Incorrect C. ^{(13,105 + 35,069)}/_130,000 = ^48,174/_130,000 = 0.3706 = 37.06 cM Incorrect D. ^{(13,105 + 16,305)}/_130,000 = ^29,410/_130,000 = 0.2262 = 22.62 cM Incorrect E. ^{(898 + 940 + 12,903 + 13,105)}/_130,000 = ^27,846/_130,000 = 0.2142 = 21.42 cM Correct F. ^{(34,603 + 35,069)}/_130,000 = ^69,672/_130,000 = 0.5359 = 53.59 cM Incorrect MC

feda_b6d8

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is related to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
jerky, kidney, prickly	j	k	p	17,598
jerky, kidney	j	k	+	4,136
jerky, prickly	j	+	p	96,862
jerky	j	+	+	26,101
kidney, prickly	+	k	p	26,365
kidney	+	k	+	97,375
prickly	+	+	p	4,008
wildtype	+	+	+	17,555
TOTAL =				290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes J and P during meiosis.

calculate the genetic distance between the two genes J and P, expressing your answer in centimorgans (cM)

A. ^{(4,008 + 97,375)}/_290,000 = ^101,383/_290,000 = 0.3496 = 34.96 cM Incorrect B. ^26,365/_290,000 = ^26,365/_290,000 = 0.0909 = 9.09 cM Incorrect C. ^{(4,008 + 4,136 + 17,598 + 26,365)}/_290,000 = ^52,107/_290,000 = 0.1797 = 17.97 cM Incorrect D. ^{(4,008 + 4,136 + 26,101)}/_290,000 = ^34,245/_290,000 = 0.1181 = 11.81 cM Incorrect E. ^{(96,862 + 97,375)}/_290,000 = ^194,237/_290,000 = 0.6698 = 66.98 cM Incorrect F. ^{(4,008 + 4,136 + 26,101 + 26,365)}/_290,000 = ^60,610/_290,000 = 0.2090 = 20.90 cM Correct MC

08bf_8468

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes			Progeny Count
chummy, jerky, kidney	c	j	k	3,054
chummy, jerky	c	j	+	24,057
chummy, kidney	c	+	k	205
chummy	c	+	+	52,629
jerky, kidney	+	j	k	52,803
jerky	+	j	+	235
kidney	+	+	k	23,983
wildtype	+	+	+	3,034
TOTAL =				160,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and K during meiosis.

calculate the genetic distance between the two genes C and K, expressing your answer in centimorgans (cM)

A. ^{(205 + 235 + 3,034 + 3,054)}/_160,000 = ^6,528/_160,000 = 0.0408 = 4.08 cM Correct B. ^{(205 + 24,057)}/_160,000 = ^24,262/_160,000 = 0.1516 = 15.16 cM Incorrect C. ^52,803/_160,000 = ^52,803/_160,000 = 0.3300 = 33.00 cM Incorrect D. ^{(3,034 + 3,054)}/_160,000 = ^6,088/_160,000 = 0.0381 = 3.81 cM Incorrect E. ^{(52,629 + 52,803)}/_160,000 = ^105,432/_160,000 = 0.6590 = 65.90 cM Incorrect F. ^52,629/_160,000 = ^52,629/_160,000 = 0.3289 = 32.89 cM Incorrect MC

5661_a5bd

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
chummy, mushy, waxy	c	m	w	9,233
chummy, mushy	c	m	+	4,705
chummy, waxy	c	+	w	1,367
chummy	c	+	+	19,423
mushy, waxy	+	m	w	19,746
mushy	+	m	+	1,444
waxy	+	+	w	4,769
wildtype	+	+	+	9,313
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and W during meiosis.

calculate the genetic distance between the two genes C and W, expressing your answer in centimorgans (cM)

A. ^{(1,367 + 1,444 + 9,233 + 19,423)}/_70,000 = ^31,467/_70,000 = 0.4495 = 44.95 cM Incorrect B. ^{(4,705 + 19,423)}/_70,000 = ^24,128/_70,000 = 0.3447 = 34.47 cM Incorrect C. ^{(1,367 + 4,769 + 9,313)}/_70,000 = ^15,449/_70,000 = 0.2207 = 22.07 cM Incorrect D. ^{(19,423 + 19,746)}/_70,000 = ^39,169/_70,000 = 0.5596 = 55.96 cM Incorrect E. ^{(1,367 + 1,444 + 9,233 + 9,313)}/_70,000 = ^21,357/_70,000 = 0.3051 = 30.51 cM Correct F. ^{(4,705 + 9,233)}/_70,000 = ^13,938/_70,000 = 0.1991 = 19.91 cM Incorrect MC

50fc_04f9

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene P is connected with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
kidney, nerdy, prickly	k	n	p	81,728
kidney, nerdy	k	n	+	29,972
kidney, prickly	k	+	p	17,503
kidney	k	+	+	5,610
nerdy, prickly	+	n	p	5,494
nerdy	+	n	+	17,698
prickly	+	+	p	29,556
wildtype	+	+	+	82,439
TOTAL =				270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and N during meiosis.

calculate the genetic distance between the two genes K and N, expressing your answer in centimorgans (cM)

A. ^{(5,610 + 17,503 + 29,972)}/_270,000 = ^53,085/_270,000 = 0.1966 = 19.66 cM Incorrect B. ^5,610/_270,000 = ^5,610/_270,000 = 0.0208 = 2.08 cM Incorrect C. ^81,728/_270,000 = ^81,728/_270,000 = 0.3027 = 30.27 cM Incorrect D. ^{(81,728 + 82,439)}/_270,000 = ^164,167/_270,000 = 0.6080 = 60.80 cM Incorrect E. ^{(5,494 + 5,610 + 17,503 + 17,698)}/_270,000 = ^46,305/_270,000 = 0.1715 = 17.15 cM Correct F. ^{(5,494 + 5,610 + 17,698 + 29,556)}/_270,000 = ^58,358/_270,000 = 0.2161 = 21.61 cM Incorrect MC

eed9_9a6a

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is correlated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene P is related to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
fuzzy, mushy, prickly	f	m	p	27,434
fuzzy, mushy	f	m	+	17,409
fuzzy, prickly	f	+	p	72,944
fuzzy	f	+	+	2,052
mushy, prickly	+	m	p	2,194
mushy	+	m	+	73,550
prickly	+	+	p	17,417
wildtype	+	+	+	27,000
TOTAL =				240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and P during meiosis.

calculate the genetic distance between the two genes F and P, expressing your answer in centimorgans (cM)

A. ^{(2,194 + 27,434)}/_240,000 = ^29,628/_240,000 = 0.1235 = 12.35 cM Incorrect B. ^{(17,409 + 72,944)}/_240,000 = ^90,353/_240,000 = 0.3765 = 37.65 cM Incorrect C. ^{(2,052 + 2,194 + 17,409 + 17,417)}/_240,000 = ^39,072/_240,000 = 0.1628 = 16.28 cM Correct D. ^{(2,052 + 17,417 + 27,000)}/_240,000 = ^46,469/_240,000 = 0.1936 = 19.36 cM Incorrect E. ^72,944/_240,000 = ^72,944/_240,000 = 0.3039 = 30.39 cM Incorrect F. ^{(72,944 + 73,550)}/_240,000 = ^146,494/_240,000 = 0.6104 = 61.04 cM Incorrect MC

7dd1_6ed3

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene T is connected with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
rusty, tipsy, waxy	r	t	w	23,201
rusty, tipsy	r	t	+	99,381
rusty, waxy	r	+	w	433
rusty	r	+	+	6,577
tipsy, waxy	+	t	w	6,701
tipsy	+	t	+	433
waxy	+	+	w	99,605
wildtype	+	+	+	23,669
TOTAL =				260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes R and T during meiosis.

calculate the genetic distance between the two genes R and T, expressing your answer in centimorgans (cM)

A. ^{(99,381 + 99,605)}/_260,000 = ^198,986/_260,000 = 0.7653 = 76.53 cM Incorrect B. ^{(433 + 6,701 + 23,669)}/_260,000 = ^30,803/_260,000 = 0.1185 = 11.85 cM Incorrect C. ^99,381/_260,000 = ^99,381/_260,000 = 0.3822 = 38.22 cM Incorrect D. ^{(433 + 6,577 + 23,669)}/_260,000 = ^30,679/_260,000 = 0.1180 = 11.80 cM Incorrect E. ^{(433 + 433 + 6,577 + 6,701)}/_260,000 = ^14,144/_260,000 = 0.0544 = 5.44 cM Correct F. ^{(433 + 433 + 23,201 + 23,669)}/_260,000 = ^47,736/_260,000 = 0.1836 = 18.36 cM Incorrect MC

008f_c305

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is connected with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
dewy, tipsy, waxy	d	t	w	1,899
dewy, tipsy	d	t	+	17,022
dewy, waxy	d	+	w	9,074
dewy	d	+	+	751
tipsy, waxy	+	t	w	745
tipsy	+	t	+	9,049
waxy	+	+	w	16,996
wildtype	+	+	+	1,964
TOTAL =				57,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and W during meiosis.

calculate the genetic distance between the two genes D and W, expressing your answer in centimorgans (cM)

A. ^{(745 + 9,074)}/_57,500 = ^9,819/_57,500 = 0.1708 = 17.08 cM Incorrect B. ^{(1,899 + 1,964 + 9,049 + 9,074)}/_57,500 = ^21,986/_57,500 = 0.3824 = 38.24 cM Correct C. ^{(745 + 751 + 1,964 + 17,022)}/_57,500 = ^20,482/_57,500 = 0.3562 = 35.62 cM Incorrect D. ^{(16,996 + 17,022)}/_57,500 = ^34,018/_57,500 = 0.5916 = 59.16 cM Incorrect E. ^17,022/_57,500 = ^17,022/_57,500 = 0.2960 = 29.60 cM Incorrect F. ^{(751 + 1,964)}/_57,500 = ^2,715/_57,500 = 0.0472 = 4.72 cM Incorrect MC

d85f_f2be

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene J is related to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene N is related to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes			Progeny Count
chummy, jerky, nerdy	c	j	n	29,013
chummy, jerky	c	j	+	5,945
chummy, nerdy	c	+	n	21,919
chummy	c	+	+	879
jerky, nerdy	+	j	n	913
jerky	+	j	+	21,392
nerdy	+	+	n	5,971
wildtype	+	+	+	28,968
TOTAL =				115,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and J during meiosis.

calculate the genetic distance between the two genes C and J, expressing your answer in centimorgans (cM)

A. ^{(28,968 + 29,013)}/_115,000 = ^57,981/_115,000 = 0.5042 = 50.42 cM Incorrect B. ^{(913 + 5,945 + 29,013)}/_115,000 = ^35,871/_115,000 = 0.3119 = 31.19 cM Incorrect C. ^{(5,945 + 21,392)}/_115,000 = ^27,337/_115,000 = 0.2377 = 23.77 cM Incorrect D. ^{(913 + 28,968)}/_115,000 = ^29,881/_115,000 = 0.2598 = 25.98 cM Incorrect E. ^{(879 + 913 + 21,392 + 21,919)}/_115,000 = ^45,103/_115,000 = 0.3922 = 39.22 cM Correct F. ^28,968/_115,000 = ^28,968/_115,000 = 0.2519 = 25.19 cM Incorrect MC

57cd_0b37

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is correlated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
mushy, nerdy, waxy	m	n	w	8,263
mushy, nerdy	m	n	+	759
mushy, waxy	m	+	w	6,117
mushy	m	+	+	4,784
nerdy, waxy	+	n	w	4,801
nerdy	+	n	+	6,096
waxy	+	+	w	768
wildtype	+	+	+	8,412
TOTAL =				40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes N and W during meiosis.

calculate the genetic distance between the two genes N and W, expressing your answer in centimorgans (cM)

A. ^6,117/_40,000 = ^6,117/_40,000 = 0.1529 = 15.29 cM Incorrect B. ^{(768 + 8,412)}/_40,000 = ^9,180/_40,000 = 0.2295 = 22.95 cM Incorrect C. ^{(759 + 768 + 8,263 + 8,412)}/_40,000 = ^18,202/_40,000 = 0.4551 = 45.51 cM Incorrect D. ^{(759 + 768 + 8,412)}/_40,000 = ^9,939/_40,000 = 0.2485 = 24.85 cM Incorrect E. ^{(759 + 768 + 6,096 + 6,117)}/_40,000 = ^13,740/_40,000 = 0.3435 = 34.35 cM Correct F. ^{(8,263 + 8,412)}/_40,000 = ^16,675/_40,000 = 0.4169 = 41.69 cM Incorrect MC

020b_5f8c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
dewy, prickly, yucky	d	p	y	1,921
dewy, prickly	d	p	+	13,702
dewy, yucky	d	+	y	14,866
dewy	d	+	+	84,326
prickly, yucky	+	p	y	84,579
prickly	+	p	+	14,949
yucky	+	+	y	13,767
wildtype	+	+	+	1,890
TOTAL =				230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and Y during meiosis.

calculate the genetic distance between the two genes D and Y, expressing your answer in centimorgans (cM)

A. ^13,767/_230,000 = ^13,767/_230,000 = 0.0599 = 5.99 cM Incorrect B. ^{(84,326 + 84,579)}/_230,000 = ^168,905/_230,000 = 0.7344 = 73.44 cM Incorrect C. ^{(1,890 + 1,921 + 14,866 + 14,949)}/_230,000 = ^33,626/_230,000 = 0.1462 = 14.62 cM Correct D. ^{(13,702 + 13,767 + 14,866)}/_230,000 = ^42,335/_230,000 = 0.1841 = 18.41 cM Incorrect E. ^{(14,949 + 84,326)}/_230,000 = ^99,275/_230,000 = 0.4316 = 43.16 cM Incorrect F. ^{(13,767 + 14,949)}/_230,000 = ^28,716/_230,000 = 0.1249 = 12.49 cM Incorrect MC

e178_182e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
kidney, waxy, yucky	k	w	y	5,446
kidney, waxy	k	w	+	6,756
kidney, yucky	k	+	y	1,515
kidney	k	+	+	21,339
waxy, yucky	+	w	y	21,412
waxy	+	w	+	1,455
yucky	+	+	y	6,612
wildtype	+	+	+	5,465
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and W during meiosis.

calculate the genetic distance between the two genes K and W, expressing your answer in centimorgans (cM)

A. ^{(1,455 + 1,515 + 21,339)}/_70,000 = ^24,309/_70,000 = 0.3473 = 34.73 cM Incorrect B. ^{(5,446 + 5,465 + 6,612 + 6,756)}/_70,000 = ^24,279/_70,000 = 0.3468 = 34.68 cM Correct C. ^{(5,465 + 6,612)}/_70,000 = ^12,077/_70,000 = 0.1725 = 17.25 cM Incorrect D. ^{(21,339 + 21,412)}/_70,000 = ^42,751/_70,000 = 0.6107 = 61.07 cM Incorrect E. ^5,446/_70,000 = ^5,446/_70,000 = 0.0778 = 7.78 cM Incorrect F. ^6,612/_70,000 = ^6,612/_70,000 = 0.0945 = 9.45 cM Incorrect MC

400c_9d12

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes			Progeny Count
fuzzy, kidney, mushy	f	k	m	26,004
fuzzy, kidney	f	k	+	19,345
fuzzy, mushy	f	+	m	3,620
fuzzy	f	+	+	56,486
kidney, mushy	+	k	m	56,134
kidney	+	k	+	3,475
mushy	+	+	m	18,941
wildtype	+	+	+	25,995
TOTAL =				210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and M during meiosis.

calculate the genetic distance between the two genes F and M, expressing your answer in centimorgans (cM)

A. ^{(3,620 + 18,941 + 19,345 + 56,486)}/_210,000 = ^98,392/_210,000 = 0.4685 = 46.85 cM Incorrect B. ^{(3,620 + 25,995 + 56,134)}/_210,000 = ^85,749/_210,000 = 0.4083 = 40.83 cM Incorrect C. ^{(3,475 + 3,620 + 25,995 + 26,004)}/_210,000 = ^59,094/_210,000 = 0.2814 = 28.14 cM Correct D. ^{(3,475 + 18,941 + 19,345)}/_210,000 = ^41,761/_210,000 = 0.1989 = 19.89 cM Incorrect E. ^{(3,475 + 3,620 + 18,941 + 19,345 + 56,134)}/_210,000 = ^101,515/_210,000 = 0.4834 = 48.34 cM Incorrect F. ^{(56,134 + 56,486)}/_210,000 = ^112,620/_210,000 = 0.5363 = 53.63 cM Incorrect MC

faa4_669e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
artsy, jerky, xanthic	a	j	x	25
artsy, jerky	a	j	+	3,052
artsy, xanthic	a	+	x	20,120
artsy	a	+	+	1,696
jerky, xanthic	+	j	x	1,735
jerky	+	j	+	20,294
xanthic	+	+	x	3,049
wildtype	+	+	+	29
TOTAL =				50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and X during meiosis.

calculate the genetic distance between the two genes A and X, expressing your answer in centimorgans (cM)

A. ^{(1,696 + 1,735 + 3,049 + 3,052)}/_50,000 = ^9,532/_50,000 = 0.1906 = 19.06 cM Correct B. ^{(29 + 1,735 + 20,120)}/_50,000 = ^21,884/_50,000 = 0.4377 = 43.77 cM Incorrect C. ^1,735/_50,000 = ^1,735/_50,000 = 0.0347 = 3.47 cM Incorrect D. ^{(20,120 + 20,294)}/_50,000 = ^40,414/_50,000 = 0.8083 = 80.83 cM Incorrect E. ^{(25 + 1,696)}/_50,000 = ^1,721/_50,000 = 0.0344 = 3.44 cM Incorrect F. ^20,294/_50,000 = ^20,294/_50,000 = 0.4059 = 40.59 cM Incorrect MC

e2aa_697c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene M is correlated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene P is related to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
dewy, mushy, prickly	d	m	p	39,687
dewy, mushy	d	m	+	1,550
dewy, prickly	d	+	p	72,122
dewy	d	+	+	21,575
mushy, prickly	+	m	p	21,588
mushy	+	m	+	72,284
prickly	+	+	p	1,592
wildtype	+	+	+	39,602
TOTAL =				270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and P during meiosis.

calculate the genetic distance between the two genes M and P, expressing your answer in centimorgans (cM)

A. ^{(39,687 + 72,284)}/_270,000 = ^111,971/_270,000 = 0.4147 = 41.47 cM Incorrect B. ^{(1,550 + 72,122)}/_270,000 = ^73,672/_270,000 = 0.2729 = 27.29 cM Incorrect C. ^1,592/_270,000 = ^1,592/_270,000 = 0.0059 = 0.59 cM Incorrect D. ^{(21,575 + 21,588 + 39,602 + 39,687)}/_270,000 = ^122,452/_270,000 = 0.4535 = 45.35 cM Correct E. ^{(21,575 + 21,588 + 39,602)}/_270,000 = ^82,765/_270,000 = 0.3065 = 30.65 cM Incorrect F. ^{(72,122 + 72,284)}/_270,000 = ^144,406/_270,000 = 0.5348 = 53.48 cM Incorrect MC

89d6_b3d8

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
mushy, nerdy, yucky	m	n	y	8,979
mushy, nerdy	m	n	+	21,210
mushy, yucky	m	+	y	4,001
mushy	m	+	+	943
nerdy, yucky	+	n	y	997
nerdy	+	n	+	3,866
yucky	+	+	y	21,141
wildtype	+	+	+	8,863
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and Y during meiosis.

calculate the genetic distance between the two genes M and Y, expressing your answer in centimorgans (cM)

A. ^{(3,866 + 4,001 + 8,863 + 8,979)}/_70,000 = ^25,709/_70,000 = 0.3673 = 36.73 cM Correct B. ^{(3,866 + 8,979)}/_70,000 = ^12,845/_70,000 = 0.1835 = 18.35 cM Incorrect C. ^{(21,141 + 21,210)}/_70,000 = ^42,351/_70,000 = 0.6050 = 60.50 cM Incorrect D. ⁹⁴³/_70,000 = ⁹⁴³/_70,000 = 0.0135 = 1.35 cM Incorrect E. ^8,979/_70,000 = ^8,979/_70,000 = 0.1283 = 12.83 cM Incorrect F. ^3,866/_70,000 = ^3,866/_70,000 = 0.0552 = 5.52 cM Incorrect MC

11fa_a630

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene F is correlated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes			Progeny Count
eery, fuzzy, jerky	e	f	j	67,147
eery, fuzzy	e	f	+	17,681
eery, jerky	e	+	j	4,644
eery	e	+	+	25,745
fuzzy, jerky	+	f	j	25,850
fuzzy	+	f	+	4,458
jerky	+	+	j	17,561
wildtype	+	+	+	66,914
TOTAL =				230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and J during meiosis.

calculate the genetic distance between the two genes F and J, expressing your answer in centimorgans (cM)

A. ^{(17,681 + 25,745)}/_230,000 = ^43,426/_230,000 = 0.1888 = 18.88 cM Incorrect B. ^{(4,458 + 4,644 + 17,561 + 17,681)}/_230,000 = ^44,344/_230,000 = 0.1928 = 19.28 cM Correct C. ^{(66,914 + 67,147)}/_230,000 = ^134,061/_230,000 = 0.5829 = 58.29 cM Incorrect D. ^4,644/_230,000 = ^4,644/_230,000 = 0.0202 = 2.02 cM Incorrect E. ^{(25,745 + 66,914)}/_230,000 = ^92,659/_230,000 = 0.4029 = 40.29 cM Incorrect F. ^{(4,458 + 67,147)}/_230,000 = ^71,605/_230,000 = 0.3113 = 31.13 cM Incorrect MC

ff33_545c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene N is related to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
horsey, nerdy, xanthic	h	n	x	5,121
horsey, nerdy	h	n	+	486
horsey, xanthic	h	+	x	21,558
horsey	h	+	+	2,730
nerdy, xanthic	+	n	x	2,761
nerdy	+	n	+	21,797
xanthic	+	+	x	473
wildtype	+	+	+	5,074
TOTAL =				60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and N during meiosis.

calculate the genetic distance between the two genes H and N, expressing your answer in centimorgans (cM)

A. ^{(21,558 + 21,797)}/_60,000 = ^43,355/_60,000 = 0.7226 = 72.26 cM Incorrect B. ^{(473 + 486 + 2,730 + 2,761 + 21,797)}/_60,000 = ^28,247/_60,000 = 0.4708 = 47.08 cM Incorrect C. ^{(473 + 2,730 + 2,761 + 5,074 + 5,121)}/_60,000 = ^16,159/_60,000 = 0.2693 = 26.93 cM Incorrect D. ^2,730/_60,000 = ^2,730/_60,000 = 0.0455 = 4.55 cM Incorrect E. ^{(473 + 486 + 2,730 + 2,761 + 21,558)}/_60,000 = ^28,008/_60,000 = 0.4668 = 46.68 cM Incorrect F. ^{(473 + 486 + 5,074 + 5,121)}/_60,000 = ^11,154/_60,000 = 0.1859 = 18.59 cM Correct MC

d052_bee2

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
eery, prickly, waxy	e	p	w	1,043
eery, prickly	e	p	+	10,606
eery, waxy	e	+	w	10,642
eery	e	+	+	7,682
prickly, waxy	+	p	w	7,600
prickly	+	p	+	10,886
waxy	+	+	w	10,580
wildtype	+	+	+	961
TOTAL =				60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and W during meiosis.

calculate the genetic distance between the two genes E and W, expressing your answer in centimorgans (cM)

A. ^{(961 + 10,886)}/_60,000 = ^11,847/_60,000 = 0.1974 = 19.74 cM Incorrect B. ^{(961 + 1,043 + 7,682 + 10,580)}/_60,000 = ^20,266/_60,000 = 0.3378 = 33.78 cM Incorrect C. ⁹⁶¹/_60,000 = ⁹⁶¹/_60,000 = 0.0160 = 1.60 cM Incorrect D. ^{(7,600 + 10,580)}/_60,000 = ^18,180/_60,000 = 0.3030 = 30.30 cM Incorrect E. ^{(10,642 + 10,886)}/_60,000 = ^21,528/_60,000 = 0.3588 = 35.88 cM Incorrect F. ^{(7,600 + 7,682 + 10,580 + 10,606)}/_60,000 = ^36,468/_60,000 = 0.6078 = 60.78 cM Correct MC

7224_2b1b

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene B is connected with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes			Progeny Count
artsy, bumpy, kidney	a	b	k	8,151
artsy, bumpy	a	b	+	17,617
artsy, kidney	a	+	k	15,001
artsy	a	+	+	24,184
bumpy, kidney	+	b	k	24,238
bumpy	+	b	+	14,876
kidney	+	+	k	17,746
wildtype	+	+	+	8,187
TOTAL =				130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and K during meiosis.

calculate the genetic distance between the two genes A and K, expressing your answer in centimorgans (cM)

A. ^{(24,184 + 24,238)}/_130,000 = ^48,422/_130,000 = 0.3725 = 37.25 cM Incorrect B. ^17,746/_130,000 = ^17,746/_130,000 = 0.1365 = 13.65 cM Incorrect C. ^{(8,151 + 8,187 + 14,876 + 15,001)}/_130,000 = ^46,215/_130,000 = 0.3555 = 35.55 cM Correct D. ^{(8,151 + 17,617 + 17,746)}/_130,000 = ^43,514/_130,000 = 0.3347 = 33.47 cM Incorrect E. ^8,151/_130,000 = ^8,151/_130,000 = 0.0627 = 6.27 cM Incorrect F. ^{(14,876 + 15,001 + 24,238)}/_130,000 = ^54,115/_130,000 = 0.4163 = 41.63 cM Incorrect MC

a8ab_f461

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is associated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes			Progeny Count
chummy, fuzzy, nerdy	c	f	n	10,274
chummy, fuzzy	c	f	+	558
chummy, nerdy	c	+	n	3,906
chummy	c	+	+	187
fuzzy, nerdy	+	f	n	166
fuzzy	+	f	+	4,006
nerdy	+	+	n	532
wildtype	+	+	+	10,371
TOTAL =				30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and F during meiosis.

calculate the genetic distance between the two genes C and F, expressing your answer in centimorgans (cM)

A. ^{(166 + 187 + 3,906 + 4,006)}/_30,000 = ^8,265/_30,000 = 0.2755 = 27.55 cM Correct B. ^10,371/_30,000 = ^10,371/_30,000 = 0.3457 = 34.57 cM Incorrect C. ^{(10,274 + 10,371)}/_30,000 = ^20,645/_30,000 = 0.6882 = 68.82 cM Incorrect D. ^{(187 + 532 + 3,906)}/_30,000 = ^4,625/_30,000 = 0.1542 = 15.42 cM Incorrect E. ^{(558 + 10,274)}/_30,000 = ^10,832/_30,000 = 0.3611 = 36.11 cM Incorrect F. ^{(166 + 187 + 3,906)}/_30,000 = ^4,259/_30,000 = 0.1420 = 14.20 cM Incorrect MC

cd32_6619

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes			Progeny Count
artsy, horsey, kidney	a	h	k	707
artsy, horsey	a	h	+	2,172
artsy, kidney	a	+	k	13,592
artsy	a	+	+	7,206
horsey, kidney	+	h	k	6,988
horsey	+	h	+	13,938
kidney	+	+	k	2,180
wildtype	+	+	+	717
TOTAL =				47,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and H during meiosis.

calculate the genetic distance between the two genes A and H, expressing your answer in centimorgans (cM)

A. ^{(707 + 717 + 2,180 + 13,592)}/_47,500 = ^17,196/_47,500 = 0.3620 = 36.20 cM Incorrect B. ^{(707 + 6,988)}/_47,500 = ^7,695/_47,500 = 0.1620 = 16.20 cM Incorrect C. ^{(717 + 2,172 + 7,206)}/_47,500 = ^10,095/_47,500 = 0.2125 = 21.25 cM Incorrect D. ^{(707 + 717 + 2,172 + 2,180)}/_47,500 = ^5,776/_47,500 = 0.1216 = 12.16 cM Correct E. ^{(2,172 + 2,180)}/_47,500 = ^4,352/_47,500 = 0.0916 = 9.16 cM Incorrect F. ^{(13,592 + 13,938)}/_47,500 = ^27,530/_47,500 = 0.5796 = 57.96 cM Incorrect MC

dac7_8c5c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
artsy, prickly, rusty	a	p	r	27,481
artsy, prickly	a	p	+	43,043
artsy, rusty	a	+	r	2,311
artsy	a	+	+	16,937
prickly, rusty	+	p	r	17,143
prickly	+	p	+	2,363
rusty	+	+	r	43,171
wildtype	+	+	+	27,551
TOTAL =				180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and R during meiosis.

calculate the genetic distance between the two genes A and R, expressing your answer in centimorgans (cM)

A. ^{(2,311 + 2,363 + 27,481 + 27,551)}/_180,000 = ^59,706/_180,000 = 0.3317 = 33.17 cM Correct B. ^{(17,143 + 43,043)}/_180,000 = ^60,186/_180,000 = 0.3344 = 33.44 cM Incorrect C. ^27,551/_180,000 = ^27,551/_180,000 = 0.1531 = 15.31 cM Incorrect D. ^2,311/_180,000 = ^2,311/_180,000 = 0.0128 = 1.28 cM Incorrect E. ^{(43,043 + 43,171)}/_180,000 = ^86,214/_180,000 = 0.4790 = 47.90 cM Incorrect F. ^{(27,481 + 27,551)}/_180,000 = ^55,032/_180,000 = 0.3057 = 30.57 cM Incorrect MC

4514_c9a0

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
horsey, nerdy, yucky	h	n	y	7,301
horsey, nerdy	h	n	+	88,995
horsey, yucky	h	+	y	13,442
horsey	h	+	+	636
nerdy, yucky	+	n	y	651
nerdy	+	n	+	13,211
yucky	+	+	y	88,424
wildtype	+	+	+	7,340
TOTAL =				220,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and N during meiosis.

calculate the genetic distance between the two genes H and N, expressing your answer in centimorgans (cM)

A. ^{(88,424 + 88,995)}/_220,000 = ^177,419/_220,000 = 0.8065 = 80.64 cM Incorrect B. ^13,211/_220,000 = ^13,211/_220,000 = 0.0600 = 6.00 cM Incorrect C. ^{(13,211 + 13,442)}/_220,000 = ^26,653/_220,000 = 0.1211 = 12.12 cM Incorrect D. ^{(636 + 651 + 13,211 + 13,442)}/_220,000 = ^27,940/_220,000 = 0.1270 = 12.70 cM Correct E. ^{(7,301 + 88,424)}/_220,000 = ^95,725/_220,000 = 0.4351 = 43.51 cM Incorrect F. ^{(636 + 13,211 + 88,424)}/_220,000 = ^102,271/_220,000 = 0.4649 = 46.49 cM Incorrect MC

d011_d94d

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
eery, mushy, waxy	e	m	w	3,783
eery, mushy	e	m	+	12,099
eery, waxy	e	+	w	18,400
eery	e	+	+	671
mushy, waxy	+	m	w	678
mushy	+	m	+	18,495
waxy	+	+	w	12,151
wildtype	+	+	+	3,723
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and M during meiosis.

calculate the genetic distance between the two genes E and M, expressing your answer in centimorgans (cM)

A. ^{(3,723 + 18,400)}/_70,000 = ^22,123/_70,000 = 0.3160 = 31.60 cM Incorrect B. ⁶⁷¹/_70,000 = ⁶⁷¹/_70,000 = 0.0096 = 0.96 cM Incorrect C. ^{(3,723 + 3,783 + 12,099 + 12,151)}/_70,000 = ^31,756/_70,000 = 0.4537 = 45.37 cM Correct D. ^{(671 + 18,495)}/_70,000 = ^19,166/_70,000 = 0.2738 = 27.38 cM Incorrect E. ^{(18,400 + 18,495)}/_70,000 = ^36,895/_70,000 = 0.5271 = 52.71 cM Incorrect F. ^12,099/_70,000 = ^12,099/_70,000 = 0.1728 = 17.28 cM Incorrect MC

d6f7_4bc0

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene F is affiliated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes			Progeny Count
dewy, fuzzy, mushy	d	f	m	42,382
dewy, fuzzy	d	f	+	23,323
dewy, mushy	d	+	m	925
dewy	d	+	+	3,236
fuzzy, mushy	+	f	m	3,395
fuzzy	+	f	+	900
mushy	+	+	m	23,194
wildtype	+	+	+	42,645
TOTAL =				140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and M during meiosis.

calculate the genetic distance between the two genes D and M, expressing your answer in centimorgans (cM)

A. ^{(925 + 42,382)}/_140,000 = ^43,307/_140,000 = 0.3093 = 30.93 cM Incorrect B. ^{(3,236 + 3,395 + 23,194 + 23,323)}/_140,000 = ^53,148/_140,000 = 0.3796 = 37.96 cM Correct C. ^23,194/_140,000 = ^23,194/_140,000 = 0.1657 = 16.57 cM Incorrect D. ^{(42,382 + 42,645)}/_140,000 = ^85,027/_140,000 = 0.6073 = 60.73 cM Incorrect E. ^{(900 + 23,194 + 23,323)}/_140,000 = ^47,417/_140,000 = 0.3387 = 33.87 cM Incorrect F. ^{(3,236 + 42,382)}/_140,000 = ^45,618/_140,000 = 0.3258 = 32.58 cM Incorrect MC

3984_d7d4

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
horsey, rusty, xanthic	h	r	x	10,075
horsey, rusty	h	r	+	106,845
horsey, xanthic	h	+	x	21,556
horsey	h	+	+	1,663
rusty, xanthic	+	r	x	1,620
rusty	+	r	+	21,781
xanthic	+	+	x	106,158
wildtype	+	+	+	10,302
TOTAL =				280,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and R during meiosis.

calculate the genetic distance between the two genes H and R, expressing your answer in centimorgans (cM)

A. ^{(1,620 + 1,663 + 21,556 + 21,781)}/_280,000 = ^46,620/_280,000 = 0.1665 = 16.65 cM Correct B. ^{(106,158 + 106,845)}/_280,000 = ^213,003/_280,000 = 0.7607 = 76.07 cM Incorrect C. ^{(1,620 + 1,663)}/_280,000 = ^3,283/_280,000 = 0.0117 = 1.17 cM Incorrect D. ^1,620/_280,000 = ^1,620/_280,000 = 0.0058 = 0.58 cM Incorrect E. ^{(1,663 + 10,075 + 10,302 + 21,781)}/_280,000 = ^43,821/_280,000 = 0.1565 = 15.65 cM Incorrect F. ^{(21,781 + 106,845)}/_280,000 = ^128,626/_280,000 = 0.4594 = 45.94 cM Incorrect MC

5d46_658f

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is correlated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
chummy, nerdy, yucky	c	n	y	85,599
chummy, nerdy	c	n	+	97
chummy, yucky	c	+	y	3,231
chummy	c	+	+	5,835
nerdy, yucky	+	n	y	5,894
nerdy	+	n	+	3,178
yucky	+	+	y	87
wildtype	+	+	+	86,079
TOTAL =				190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes N and Y during meiosis.

calculate the genetic distance between the two genes N and Y, expressing your answer in centimorgans (cM)

A. ^{(97 + 3,178)}/_190,000 = ^3,275/_190,000 = 0.0172 = 1.72 cM Incorrect B. ^{(87 + 97 + 3,178 + 3,231)}/_190,000 = ^6,593/_190,000 = 0.0347 = 3.47 cM Correct C. ^86,079/_190,000 = ^86,079/_190,000 = 0.4530 = 45.30 cM Incorrect D. ^{(85,599 + 86,079)}/_190,000 = ^171,678/_190,000 = 0.9036 = 90.36 cM Incorrect E. ^5,894/_190,000 = ^5,894/_190,000 = 0.0310 = 3.10 cM Incorrect F. ^{(3,178 + 85,599)}/_190,000 = ^88,777/_190,000 = 0.4672 = 46.72 cM Incorrect MC

124c_2406

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
dewy, prickly, yucky	d	p	y	21,860
dewy, prickly	d	p	+	449
dewy, yucky	d	+	y	86,853
dewy	d	+	+	10,719
prickly, yucky	+	p	y	10,681
prickly	+	p	+	87,227
yucky	+	+	y	471
wildtype	+	+	+	21,740
TOTAL =				240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and P during meiosis.

calculate the genetic distance between the two genes D and P, expressing your answer in centimorgans (cM)

A. ^{(471 + 86,853)}/_240,000 = ^87,324/_240,000 = 0.3639 = 36.38 cM Incorrect B. ^{(471 + 21,860)}/_240,000 = ^22,331/_240,000 = 0.0930 = 9.30 cM Incorrect C. ^10,719/_240,000 = ^10,719/_240,000 = 0.0447 = 4.47 cM Incorrect D. ^{(449 + 471 + 21,740 + 21,860)}/_240,000 = ^44,520/_240,000 = 0.1855 = 18.55 cM Correct E. ^{(86,853 + 87,227)}/_240,000 = ^174,080/_240,000 = 0.7253 = 72.53 cM Incorrect F. ^{(10,681 + 87,227)}/_240,000 = ^97,908/_240,000 = 0.4079 = 40.79 cM Incorrect MC

5dd7_5d1d

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
mushy, rusty, xanthic	m	r	x	5,883
mushy, rusty	m	r	+	6,142
mushy, xanthic	m	+	x	1,202
mushy	m	+	+	21,822
rusty, xanthic	+	r	x	21,679
rusty	+	r	+	1,300
xanthic	+	+	x	6,091
wildtype	+	+	+	5,881
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes R and X during meiosis.

calculate the genetic distance between the two genes R and X, expressing your answer in centimorgans (cM)

A. ^21,822/_70,000 = ^21,822/_70,000 = 0.3117 = 31.17 cM Incorrect B. ^{(1,202 + 21,822)}/_70,000 = ^23,024/_70,000 = 0.3289 = 32.89 cM Incorrect C. ^{(5,883 + 21,822)}/_70,000 = ^27,705/_70,000 = 0.3958 = 39.58 cM Incorrect D. ^{(5,883 + 6,142)}/_70,000 = ^12,025/_70,000 = 0.1718 = 17.18 cM Incorrect E. ^{(1,202 + 1,300 + 6,091 + 6,142)}/_70,000 = ^14,735/_70,000 = 0.2105 = 21.05 cM Correct F. ^{(21,679 + 21,822)}/_70,000 = ^43,501/_70,000 = 0.6214 = 62.14 cM Incorrect MC

6ab0_dba4

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene B is connected with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes			Progeny Count
artsy, bumpy, jerky	a	b	j	53,363
artsy, bumpy	a	b	+	41,050
artsy, jerky	a	+	j	26,047
artsy	a	+	+	4,710
bumpy, jerky	+	b	j	4,685
bumpy	+	b	+	25,933
jerky	+	+	j	41,405
wildtype	+	+	+	52,807
TOTAL =				250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes B and J during meiosis.

calculate the genetic distance between the two genes B and J, expressing your answer in centimorgans (cM)

A. ^{(25,933 + 26,047 + 41,050 + 41,405)}/_250,000 = ^134,435/_250,000 = 0.5377 = 53.77 cM Correct B. ^{(4,710 + 25,933 + 53,363)}/_250,000 = ^84,006/_250,000 = 0.3360 = 33.60 cM Incorrect C. ^52,807/_250,000 = ^52,807/_250,000 = 0.2112 = 21.12 cM Incorrect D. ^{(4,685 + 25,933 + 26,047 + 41,405)}/_250,000 = ^98,070/_250,000 = 0.3923 = 39.23 cM Incorrect E. ^{(52,807 + 53,363)}/_250,000 = ^106,170/_250,000 = 0.4247 = 42.47 cM Incorrect F. ^41,405/_250,000 = ^41,405/_250,000 = 0.1656 = 16.56 cM Incorrect MC

c15e_9191

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is affiliated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
bumpy, tipsy, waxy	b	t	w	3,682
bumpy, tipsy	b	t	+	56,123
bumpy, waxy	b	+	w	14,193
bumpy	b	+	+	733
tipsy, waxy	+	t	w	729
tipsy	+	t	+	14,285
waxy	+	+	w	56,609
wildtype	+	+	+	3,646
TOTAL =				150,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes B and T during meiosis.

calculate the genetic distance between the two genes B and T, expressing your answer in centimorgans (cM)

A. ^{(729 + 733 + 14,193 + 14,285)}/_150,000 = ^29,940/_150,000 = 0.1996 = 19.96 cM Correct B. ^{(56,123 + 56,609)}/_150,000 = ^112,732/_150,000 = 0.7515 = 75.15 cM Incorrect C. ^{(729 + 733 + 3,646 + 14,193)}/_150,000 = ^19,301/_150,000 = 0.1287 = 12.87 cM Incorrect D. ^{(3,646 + 3,682)}/_150,000 = ^7,328/_150,000 = 0.0489 = 4.89 cM Incorrect E. ^{(733 + 14,193 + 14,285)}/_150,000 = ^29,211/_150,000 = 0.1947 = 19.47 cM Incorrect F. ^{(3,646 + 14,193)}/_150,000 = ^17,839/_150,000 = 0.1189 = 11.89 cM Incorrect MC

e4c1_009a

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is correlated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
artsy, jerky, waxy	a	j	w	131
artsy, jerky	a	j	+	14,245
artsy, waxy	a	+	w	3,963
artsy	a	+	+	1,638
jerky, waxy	+	j	w	1,685
jerky	+	j	+	4,016
waxy	+	+	w	14,208
wildtype	+	+	+	114
TOTAL =				40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes J and W during meiosis.

calculate the genetic distance between the two genes J and W, expressing your answer in centimorgans (cM)

A. ^{(114 + 131 + 1,638 + 1,685)}/_40,000 = ^3,568/_40,000 = 0.0892 = 8.92 cM Correct B. ^{(1,638 + 1,685 + 3,963)}/_40,000 = ^7,286/_40,000 = 0.1822 = 18.21 cM Incorrect C. ^{(14,208 + 14,245)}/_40,000 = ^28,453/_40,000 = 0.7113 = 71.13 cM Incorrect D. ^{(114 + 131)}/_40,000 = ²⁴⁵/_40,000 = 0.0061 = 0.61 cM Incorrect E. ^{(114 + 131 + 1,638 + 1,685 + 3,963 + 4,016)}/_40,000 = ^11,547/_40,000 = 0.2887 = 28.87 cM Incorrect F. ^{(4,016 + 14,208)}/_40,000 = ^18,224/_40,000 = 0.4556 = 45.56 cM Incorrect MC

eac7_b80e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is correlated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
bumpy, jerky, tipsy	b	j	t	28,587
bumpy, jerky	b	j	+	25,531
bumpy, tipsy	b	+	t	8,649
bumpy	b	+	+	51,775
jerky, tipsy	+	j	t	52,454
jerky	+	j	+	8,617
tipsy	+	+	t	25,720
wildtype	+	+	+	28,667
TOTAL =				230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes J and T during meiosis.

calculate the genetic distance between the two genes J and T, expressing your answer in centimorgans (cM)

A. ^{(25,720 + 28,587 + 52,454)}/_230,000 = ^106,761/_230,000 = 0.4642 = 46.42 cM Incorrect B. ^8,617/_230,000 = ^8,617/_230,000 = 0.0375 = 3.75 cM Incorrect C. ^{(8,617 + 8,649 + 25,531 + 25,720)}/_230,000 = ^68,517/_230,000 = 0.2979 = 29.79 cM Correct D. ^{(51,775 + 52,454)}/_230,000 = ^104,229/_230,000 = 0.4532 = 45.32 cM Incorrect E. ^{(8,649 + 25,531 + 25,720)}/_230,000 = ^59,900/_230,000 = 0.2604 = 26.04 cM Incorrect F. ^{(8,617 + 25,531 + 51,775)}/_230,000 = ^85,923/_230,000 = 0.3736 = 37.36 cM Incorrect MC

23e1_760e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes			Progeny Count
artsy, chummy, kidney	a	c	k	1,578
artsy, chummy	a	c	+	5,643
artsy, kidney	a	+	k	6,166
artsy	a	+	+	6,715
chummy, kidney	+	c	k	6,835
chummy	+	c	+	5,984
kidney	+	+	k	5,455
wildtype	+	+	+	1,624
TOTAL =				40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and K during meiosis.

calculate the genetic distance between the two genes A and K, expressing your answer in centimorgans (cM)

A. ^{(6,166 + 6,715)}/_40,000 = ^12,881/_40,000 = 0.3220 = 32.20 cM Incorrect B. ^{(1,578 + 1,624 + 5,984 + 6,166)}/_40,000 = ^15,352/_40,000 = 0.3838 = 38.38 cM Correct C. ^{(1,624 + 5,455 + 5,984 + 6,166)}/_40,000 = ^19,229/_40,000 = 0.4807 = 48.07 cM Incorrect D. ^{(1,624 + 5,455)}/_40,000 = ^7,079/_40,000 = 0.1770 = 17.70 cM Incorrect E. ^{(6,715 + 6,835)}/_40,000 = ^13,550/_40,000 = 0.3387 = 33.88 cM Incorrect F. ^{(5,455 + 6,715 + 6,835)}/_40,000 = ^19,005/_40,000 = 0.4751 = 47.51 cM Incorrect MC

3b7b_4dfa

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
artsy, kidney, yucky	a	k	y	5,655
artsy, kidney	a	k	+	40,844
artsy, yucky	a	+	y	24,752
artsy	a	+	+	33,545
kidney, yucky	+	k	y	33,786
kidney	+	k	+	24,582
yucky	+	+	y	41,114
wildtype	+	+	+	5,722
TOTAL =				210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and Y during meiosis.

calculate the genetic distance between the two genes K and Y, expressing your answer in centimorgans (cM)

A. ^{(5,655 + 5,722 + 24,582 + 24,752 + 41,114)}/_210,000 = ^101,825/_210,000 = 0.4849 = 48.49 cM Incorrect B. ^{(40,844 + 41,114)}/_210,000 = ^81,958/_210,000 = 0.3903 = 39.03 cM Incorrect C. ^{(5,655 + 5,722)}/_210,000 = ^11,377/_210,000 = 0.0542 = 5.42 cM Incorrect D. ^{(5,655 + 5,722 + 33,545 + 33,786)}/_210,000 = ^78,708/_210,000 = 0.3748 = 37.48 cM Correct E. ^{(5,722 + 33,545 + 41,114)}/_210,000 = ^80,381/_210,000 = 0.3828 = 38.28 cM Incorrect F. ^{(5,722 + 33,545)}/_210,000 = ^39,267/_210,000 = 0.1870 = 18.70 cM Incorrect MC

e8e0_8350

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
artsy, tipsy, yucky	a	t	y	2,078
artsy, tipsy	a	t	+	18,458
artsy, yucky	a	+	y	53,809
artsy	a	+	+	538
tipsy, yucky	+	t	y	564
tipsy	+	t	+	54,123
yucky	+	+	y	18,270
wildtype	+	+	+	2,160
TOTAL =				150,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes T and Y during meiosis.

calculate the genetic distance between the two genes T and Y, expressing your answer in centimorgans (cM)

A. ^{(538 + 564 + 18,270)}/_150,000 = ^19,372/_150,000 = 0.1291 = 12.91 cM Incorrect B. ^{(53,809 + 54,123)}/_150,000 = ^107,932/_150,000 = 0.7195 = 71.95 cM Incorrect C. ^{(538 + 564 + 2,160 + 18,270 + 18,458)}/_150,000 = ^39,990/_150,000 = 0.2666 = 26.66 cM Incorrect D. ^{(564 + 18,270 + 18,458)}/_150,000 = ^37,292/_150,000 = 0.2486 = 24.86 cM Incorrect E. ^54,123/_150,000 = ^54,123/_150,000 = 0.3608 = 36.08 cM Incorrect F. ^{(538 + 564 + 2,078 + 2,160)}/_150,000 = ^5,340/_150,000 = 0.0356 = 3.56 cM Correct MC

2583_86d6

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene M is correlated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
kidney, mushy, rusty	k	m	r	5,888
kidney, mushy	k	m	+	1,560
kidney, rusty	k	+	r	53,119
kidney	k	+	+	29,768
mushy, rusty	+	m	r	29,921
mushy	+	m	+	52,486
rusty	+	+	r	1,517
wildtype	+	+	+	5,741
TOTAL =				180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and M during meiosis.

calculate the genetic distance between the two genes K and M, expressing your answer in centimorgans (cM)

A. ^{(52,486 + 53,119)}/_180,000 = ^105,605/_180,000 = 0.5867 = 58.67 cM Incorrect B. ^{(1,517 + 1,560 + 5,741 + 5,888)}/_180,000 = ^14,706/_180,000 = 0.0817 = 8.17 cM Correct C. ^29,768/_180,000 = ^29,768/_180,000 = 0.1654 = 16.54 cM Incorrect D. ^{(1,517 + 1,560 + 5,741 + 53,119)}/_180,000 = ^61,937/_180,000 = 0.3441 = 34.41 cM Incorrect E. ^5,741/_180,000 = ^5,741/_180,000 = 0.0319 = 3.19 cM Incorrect F. ^{(1,560 + 5,741 + 5,888 + 29,768 + 29,921)}/_180,000 = ^72,878/_180,000 = 0.4049 = 40.49 cM Incorrect MC

9cd5_a8c6

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
fuzzy, nerdy, rusty	f	n	r	10,861
fuzzy, nerdy	f	n	+	7,867
fuzzy, rusty	f	+	r	16,144
fuzzy	f	+	+	1,440
nerdy, rusty	+	n	r	1,402
nerdy	+	n	+	16,249
rusty	+	+	r	7,967
wildtype	+	+	+	10,570
TOTAL =				72,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and N during meiosis.

calculate the genetic distance between the two genes F and N, expressing your answer in centimorgans (cM)

A. ^{(10,570 + 16,249)}/_72,500 = ^26,819/_72,500 = 0.3699 = 36.99 cM Incorrect B. ^{(16,144 + 16,249)}/_72,500 = ^32,393/_72,500 = 0.4468 = 44.68 cM Incorrect C. ^{(7,867 + 7,967 + 10,570 + 10,861)}/_72,500 = ^37,265/_72,500 = 0.5140 = 51.40 cM Correct D. ^{(1,440 + 7,867 + 16,249)}/_72,500 = ^25,556/_72,500 = 0.3525 = 35.25 cM Incorrect E. ^{(1,440 + 7,867 + 7,967 + 16,144)}/_72,500 = ^33,418/_72,500 = 0.4609 = 46.09 cM Incorrect F. ^1,402/_72,500 = ^1,402/_72,500 = 0.0193 = 1.93 cM Incorrect MC

ebd0_fb0d

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
chummy, eery, xanthic	c	e	x	13,890
chummy, eery	c	e	+	9,868
chummy, xanthic	c	+	x	1,845
chummy	c	+	+	4,582
eery, xanthic	+	e	x	4,583
eery	+	e	+	1,914
xanthic	+	+	x	9,641
wildtype	+	+	+	13,677
TOTAL =				60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and E during meiosis.

calculate the genetic distance between the two genes C and E, expressing your answer in centimorgans (cM)

A. ^{(1,845 + 1,914 + 4,582 + 4,583)}/_60,000 = ^12,924/_60,000 = 0.2154 = 21.54 cM Correct B. ^4,583/_60,000 = ^4,583/_60,000 = 0.0764 = 7.64 cM Incorrect C. ^{(13,677 + 13,890)}/_60,000 = ^27,567/_60,000 = 0.4595 = 45.95 cM Incorrect D. ^{(1,845 + 1,914 + 4,582 + 4,583 + 13,890)}/_60,000 = ^26,814/_60,000 = 0.4469 = 44.69 cM Incorrect E. ^1,845/_60,000 = ^1,845/_60,000 = 0.0307 = 3.08 cM Incorrect F. ^{(1,845 + 1,914 + 4,582 + 9,868)}/_60,000 = ^18,209/_60,000 = 0.3035 = 30.35 cM Incorrect MC

6cf2_269c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes			Progeny Count
horsey, kidney, prickly	h	k	p	382
horsey, kidney	h	k	+	5,107
horsey, prickly	h	+	p	29,630
horsey	h	+	+	59,612
kidney, prickly	+	k	p	60,043
kidney	+	k	+	29,733
prickly	+	+	p	5,103
wildtype	+	+	+	390
TOTAL =				190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and P during meiosis.

calculate the genetic distance between the two genes H and P, expressing your answer in centimorgans (cM)

A. ^{(59,612 + 60,043)}/_190,000 = ^119,655/_190,000 = 0.6298 = 62.98 cM Incorrect B. ^{(390 + 60,043)}/_190,000 = ^60,433/_190,000 = 0.3181 = 31.81 cM Incorrect C. ^{(5,103 + 60,043)}/_190,000 = ^65,146/_190,000 = 0.3429 = 34.29 cM Incorrect D. ^{(5,103 + 29,630)}/_190,000 = ^34,733/_190,000 = 0.1828 = 18.28 cM Incorrect E. ^{(382 + 390 + 29,630 + 29,733)}/_190,000 = ^60,135/_190,000 = 0.3165 = 31.65 cM Correct F. ^{(390 + 5,107 + 29,630)}/_190,000 = ^35,127/_190,000 = 0.1849 = 18.49 cM Incorrect MC

e2bc_8aec

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
mushy, rusty, xanthic	m	r	x	266
mushy, rusty	m	r	+	11,573
mushy, xanthic	m	+	x	3,480
mushy	m	+	+	49,592
rusty, xanthic	+	r	x	49,606
rusty	+	r	+	3,532
xanthic	+	+	x	11,663
wildtype	+	+	+	288
TOTAL =				130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and X during meiosis.

calculate the genetic distance between the two genes M and X, expressing your answer in centimorgans (cM)

A. ^{(266 + 3,480 + 3,532 + 49,592)}/_130,000 = ^56,870/_130,000 = 0.4375 = 43.75 cM Incorrect B. ^{(266 + 288 + 3,480 + 3,532)}/_130,000 = ^7,566/_130,000 = 0.0582 = 5.82 cM Correct C. ^{(49,592 + 49,606)}/_130,000 = ^99,198/_130,000 = 0.7631 = 76.31 cM Incorrect D. ^{(266 + 11,663 + 49,606)}/_130,000 = ^61,535/_130,000 = 0.4733 = 47.33 cM Incorrect E. ^49,606/_130,000 = ^49,606/_130,000 = 0.3816 = 38.16 cM Incorrect F. ^3,532/_130,000 = ^3,532/_130,000 = 0.0272 = 2.72 cM Incorrect MC

bc5e_9746

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes			Progeny Count
chummy, eery, horsey	c	e	h	1,348
chummy, eery	c	e	+	76,181
chummy, horsey	c	+	h	4,230
chummy	c	+	+	28,165
eery, horsey	+	e	h	28,021
eery	+	e	+	4,238
horsey	+	+	h	76,479
wildtype	+	+	+	1,338
TOTAL =				220,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and H during meiosis.

calculate the genetic distance between the two genes E and H, expressing your answer in centimorgans (cM)

A. ^{(76,181 + 76,479)}/_220,000 = ^152,660/_220,000 = 0.6939 = 69.39 cM Incorrect B. ^{(1,338 + 1,348 + 28,021 + 28,165)}/_220,000 = ^58,872/_220,000 = 0.2676 = 26.76 cM Correct C. ^{(1,338 + 1,348 + 28,021 + 76,181)}/_220,000 = ^106,888/_220,000 = 0.4859 = 48.59 cM Incorrect D. ^4,230/_220,000 = ^4,230/_220,000 = 0.0192 = 1.92 cM Incorrect E. ^28,165/_220,000 = ^28,165/_220,000 = 0.1280 = 12.80 cM Incorrect F. ^{(1,348 + 4,230 + 4,238)}/_220,000 = ^9,816/_220,000 = 0.0446 = 4.46 cM Incorrect MC

88d8_ab62

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is affiliated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
fuzzy, tipsy, xanthic	f	t	x	389
fuzzy, tipsy	f	t	+	105,985
fuzzy, xanthic	f	+	x	24,823
fuzzy	f	+	+	3,905
tipsy, xanthic	+	t	x	3,854
tipsy	+	t	+	24,840
xanthic	+	+	x	105,793
wildtype	+	+	+	411
TOTAL =				270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and T during meiosis.

calculate the genetic distance between the two genes F and T, expressing your answer in centimorgans (cM)

A. ^{(389 + 411 + 3,905 + 24,840)}/_270,000 = ^29,545/_270,000 = 0.1094 = 10.94 cM Incorrect B. ^{(105,793 + 105,985)}/_270,000 = ^211,778/_270,000 = 0.7844 = 78.44 cM Incorrect C. ^3,905/_270,000 = ^3,905/_270,000 = 0.0145 = 1.45 cM Incorrect D. ^{(3,854 + 3,905 + 24,823 + 24,840)}/_270,000 = ^57,422/_270,000 = 0.2127 = 21.27 cM Correct E. ^{(389 + 411 + 3,854 + 3,905 + 24,823 + 24,840)}/_270,000 = ^58,222/_270,000 = 0.2156 = 21.56 cM Incorrect F. ^{(389 + 3,905)}/_270,000 = ^4,294/_270,000 = 0.0159 = 1.59 cM Incorrect MC

24cf_93a0

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
horsey, rusty, tipsy	h	r	t	4,063
horsey, rusty	h	r	+	22,759
horsey, tipsy	h	+	t	10,749
horsey	h	+	+	12,352
rusty, tipsy	+	r	t	12,404
rusty	+	r	+	10,847
tipsy	+	+	t	22,725
wildtype	+	+	+	4,101
TOTAL =				100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes R and T during meiosis.

calculate the genetic distance between the two genes R and T, expressing your answer in centimorgans (cM)

A. ^{(22,725 + 22,759)}/_100,000 = ^45,484/_100,000 = 0.4548 = 45.48 cM Incorrect B. ^{(4,101 + 10,847 + 22,725)}/_100,000 = ^37,673/_100,000 = 0.3767 = 37.67 cM Incorrect C. ^4,101/_100,000 = ^4,101/_100,000 = 0.0410 = 4.10 cM Incorrect D. ^{(4,063 + 10,749 + 22,725)}/_100,000 = ^37,537/_100,000 = 0.3754 = 37.54 cM Incorrect E. ^12,352/_100,000 = ^12,352/_100,000 = 0.1235 = 12.35 cM Incorrect F. ^{(4,063 + 4,101 + 12,352 + 12,404)}/_100,000 = ^32,920/_100,000 = 0.3292 = 32.92 cM Correct MC

6967_1102

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
artsy, mushy, xanthic	a	m	x	3,772
artsy, mushy	a	m	+	50,427
artsy, xanthic	a	+	x	5,623
artsy	a	+	+	251
mushy, xanthic	+	m	x	217
mushy	+	m	+	5,705
xanthic	+	+	x	50,085
wildtype	+	+	+	3,920
TOTAL =				120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and X during meiosis.

calculate the genetic distance between the two genes M and X, expressing your answer in centimorgans (cM)

A. ^{(50,085 + 50,427)}/_120,000 = ^100,512/_120,000 = 0.8376 = 83.76 cM Incorrect B. ^{(251 + 3,772 + 5,623)}/_120,000 = ^9,646/_120,000 = 0.0804 = 8.04 cM Incorrect C. ^{(217 + 251 + 50,427)}/_120,000 = ^50,895/_120,000 = 0.4241 = 42.41 cM Incorrect D. ^{(5,623 + 50,427)}/_120,000 = ^56,050/_120,000 = 0.4671 = 46.71 cM Incorrect E. ^{(217 + 251 + 3,772 + 3,920)}/_120,000 = ^8,160/_120,000 = 0.0680 = 6.80 cM Correct F. ^{(3,920 + 5,705)}/_120,000 = ^9,625/_120,000 = 0.0802 = 8.02 cM Incorrect MC

e472_dea6

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is correlated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
chummy, waxy, yucky	c	w	y	8,388
chummy, waxy	c	w	+	1,126
chummy, yucky	c	+	y	19,967
chummy	c	+	+	25,577
waxy, yucky	+	w	y	25,596
waxy	+	w	+	19,830
yucky	+	+	y	1,053
wildtype	+	+	+	8,463
TOTAL =				110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes C and W during meiosis.

calculate the genetic distance between the two genes C and W, expressing your answer in centimorgans (cM)

A. ^{(1,053 + 19,830 + 25,596)}/_110,000 = ^46,479/_110,000 = 0.4225 = 42.25 cM Incorrect B. ^{(1,053 + 1,126 + 8,388 + 8,463)}/_110,000 = ^19,030/_110,000 = 0.1730 = 17.30 cM Correct C. ^{(1,126 + 19,830 + 25,596)}/_110,000 = ^46,552/_110,000 = 0.4232 = 42.32 cM Incorrect D. ^{(1,053 + 8,388)}/_110,000 = ^9,441/_110,000 = 0.0858 = 8.58 cM Incorrect E. ^{(25,577 + 25,596)}/_110,000 = ^51,173/_110,000 = 0.4652 = 46.52 cM Incorrect F. ^{(8,463 + 25,596)}/_110,000 = ^34,059/_110,000 = 0.3096 = 30.96 cM Incorrect MC

3545_f558

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is associated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
artsy, chummy, rusty	a	c	r	2,893
artsy, chummy	a	c	+	15,810
artsy, rusty	a	+	r	84,088
artsy	a	+	+	42,275
chummy, rusty	+	c	r	42,423
chummy	+	c	+	83,978
rusty	+	+	r	15,615
wildtype	+	+	+	2,918
TOTAL =				290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes A and C during meiosis.

calculate the genetic distance between the two genes A and C, expressing your answer in centimorgans (cM)

A. ^{(2,918 + 42,275 + 84,088)}/_290,000 = ^129,281/_290,000 = 0.4458 = 44.58 cM Incorrect B. ^42,423/_290,000 = ^42,423/_290,000 = 0.1463 = 14.63 cM Incorrect C. ^{(2,893 + 42,423 + 84,088)}/_290,000 = ^129,404/_290,000 = 0.4462 = 44.62 cM Incorrect D. ^{(83,978 + 84,088)}/_290,000 = ^168,066/_290,000 = 0.5795 = 57.95 cM Incorrect E. ^{(2,893 + 2,918 + 15,615 + 15,810)}/_290,000 = ^37,236/_290,000 = 0.1284 = 12.84 cM Correct F. ^{(15,615 + 84,088)}/_290,000 = ^99,703/_290,000 = 0.3438 = 34.38 cM Incorrect MC

38d4_9de3

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
eery, nerdy, xanthic	e	n	x	7,379
eery, nerdy	e	n	+	7,512
eery, xanthic	e	+	x	894
eery	e	+	+	36,724
nerdy, xanthic	+	n	x	36,712
nerdy	+	n	+	869
xanthic	+	+	x	7,483
wildtype	+	+	+	7,427
TOTAL =				105,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes N and X during meiosis.

calculate the genetic distance between the two genes N and X, expressing your answer in centimorgans (cM)

A. ^7,379/_105,000 = ^7,379/_105,000 = 0.0703 = 7.03 cM Incorrect B. ^{(7,483 + 7,512)}/_105,000 = ^14,995/_105,000 = 0.1428 = 14.28 cM Incorrect C. ^{(36,712 + 36,724)}/_105,000 = ^73,436/_105,000 = 0.6994 = 69.94 cM Incorrect D. ^{(869 + 894 + 7,483 + 7,512)}/_105,000 = ^16,758/_105,000 = 0.1596 = 15.96 cM Correct E. ^{(894 + 7,379 + 7,427 + 7,483 + 7,512)}/_105,000 = ^30,695/_105,000 = 0.2923 = 29.23 cM Incorrect F. ^{(894 + 7,379 + 7,427 + 7,483)}/_105,000 = ^23,183/_105,000 = 0.2208 = 22.08 cM Incorrect MC

7f99_ff84

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
dewy, waxy, yucky	d	w	y	27
dewy, waxy	d	w	+	4,422
dewy, yucky	d	+	y	1,652
dewy	d	+	+	38,955
waxy, yucky	+	w	y	38,941
waxy	+	w	+	1,641
yucky	+	+	y	4,316
wildtype	+	+	+	46
TOTAL =				90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes W and Y during meiosis.

calculate the genetic distance between the two genes W and Y, expressing your answer in centimorgans (cM)

A. ^{(27 + 46 + 1,652 + 38,941)}/_90,000 = ^40,666/_90,000 = 0.4518 = 45.18 cM Incorrect B. ^{(27 + 1,641 + 4,422)}/_90,000 = ^6,090/_90,000 = 0.0677 = 6.77 cM Incorrect C. ^4,422/_90,000 = ^4,422/_90,000 = 0.0491 = 4.91 cM Incorrect D. ^{(1,641 + 1,652 + 4,316 + 4,422)}/_90,000 = ^12,031/_90,000 = 0.1337 = 13.37 cM Correct E. ^{(38,941 + 38,955)}/_90,000 = ^77,896/_90,000 = 0.8655 = 86.55 cM Incorrect F. ²⁷/_90,000 = ²⁷/_90,000 = 0.0003 = 0.03 cM Incorrect MC

66bb_ddc6

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
eery, mushy, yucky	e	m	y	27,413
eery, mushy	e	m	+	51,578
eery, yucky	e	+	y	3,979
eery	e	+	+	31,876
mushy, yucky	+	m	y	32,095
mushy	+	m	+	3,879
yucky	+	+	y	51,546
wildtype	+	+	+	27,634
TOTAL =				230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and M during meiosis.

calculate the genetic distance between the two genes E and M, expressing your answer in centimorgans (cM)

A. ^{(3,879 + 3,979 + 31,876 + 32,095)}/_230,000 = ^71,829/_230,000 = 0.3123 = 31.23 cM Correct B. ^{(51,546 + 51,578)}/_230,000 = ^103,124/_230,000 = 0.4484 = 44.84 cM Incorrect C. ^31,876/_230,000 = ^31,876/_230,000 = 0.1386 = 13.86 cM Incorrect D. ^27,634/_230,000 = ^27,634/_230,000 = 0.1201 = 12.01 cM Incorrect E. ^51,546/_230,000 = ^51,546/_230,000 = 0.2241 = 22.41 cM Incorrect F. ^{(3,879 + 31,876 + 51,546)}/_230,000 = ^87,301/_230,000 = 0.3796 = 37.96 cM Incorrect MC

75e8_a97c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
fuzzy, prickly, tipsy	f	p	t	14,067
fuzzy, prickly	f	p	+	4,881
fuzzy, tipsy	f	+	t	30,030
fuzzy	f	+	+	56,196
prickly, tipsy	+	p	t	55,727
prickly	+	p	+	30,037
tipsy	+	+	t	4,961
wildtype	+	+	+	14,101
TOTAL =				210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and T during meiosis.

calculate the genetic distance between the two genes F and T, expressing your answer in centimorgans (cM)

A. ^{(4,881 + 4,961 + 14,101 + 55,727)}/_210,000 = ^79,670/_210,000 = 0.3794 = 37.94 cM Incorrect B. ^55,727/_210,000 = ^55,727/_210,000 = 0.2654 = 26.54 cM Incorrect C. ^{(14,067 + 14,101 + 30,030 + 30,037)}/_210,000 = ^88,235/_210,000 = 0.4202 = 42.02 cM Correct D. ^{(14,067 + 56,196)}/_210,000 = ^70,263/_210,000 = 0.3346 = 33.46 cM Incorrect E. ^14,101/_210,000 = ^14,101/_210,000 = 0.0671 = 6.71 cM Incorrect F. ^{(55,727 + 56,196)}/_210,000 = ^111,923/_210,000 = 0.5330 = 53.30 cM Incorrect MC

e150_7268

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is linked with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes			Progeny Count
bumpy, fuzzy, nerdy	b	f	n	17,897
bumpy, fuzzy	b	f	+	3,625
bumpy, nerdy	b	+	n	51,137
bumpy	b	+	+	72,295
fuzzy, nerdy	+	f	n	72,147
fuzzy	+	f	+	51,356
nerdy	+	+	n	3,618
wildtype	+	+	+	17,925
TOTAL =				290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and N during meiosis.

calculate the genetic distance between the two genes F and N, expressing your answer in centimorgans (cM)

A. ^{(3,618 + 3,625 + 72,147)}/_290,000 = ^79,390/_290,000 = 0.2738 = 27.38 cM Incorrect B. ^{(72,147 + 72,295)}/_290,000 = ^144,442/_290,000 = 0.4981 = 49.81 cM Incorrect C. ^51,137/_290,000 = ^51,137/_290,000 = 0.1763 = 17.63 cM Incorrect D. ^{(3,618 + 3,625 + 51,137 + 51,356)}/_290,000 = ^109,736/_290,000 = 0.3784 = 37.84 cM Correct E. ^17,897/_290,000 = ^17,897/_290,000 = 0.0617 = 6.17 cM Incorrect F. ^{(51,137 + 72,147)}/_290,000 = ^123,284/_290,000 = 0.4251 = 42.51 cM Incorrect MC

6aae_1373

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is connected with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
dewy, kidney, tipsy	d	k	t	2,914
dewy, kidney	d	k	+	72,257
dewy, tipsy	d	+	t	35,049
dewy	d	+	+	34,804
kidney, tipsy	+	k	t	34,955
kidney	+	k	+	34,768
tipsy	+	+	t	72,236
wildtype	+	+	+	3,017
TOTAL =				290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes K and T during meiosis.

calculate the genetic distance between the two genes K and T, expressing your answer in centimorgans (cM)

A. ^{(2,914 + 3,017 + 34,804 + 72,236)}/_290,000 = ^112,971/_290,000 = 0.3896 = 38.96 cM Incorrect B. ^{(2,914 + 3,017 + 34,804 + 34,955)}/_290,000 = ^75,690/_290,000 = 0.2610 = 26.10 cM Correct C. ^{(2,914 + 3,017 + 34,804 + 72,257)}/_290,000 = ^112,992/_290,000 = 0.3896 = 38.96 cM Incorrect D. ^{(72,236 + 72,257)}/_290,000 = ^144,493/_290,000 = 0.4983 = 49.83 cM Incorrect E. ^{(3,017 + 34,955 + 72,236)}/_290,000 = ^110,208/_290,000 = 0.3800 = 38.00 cM Incorrect F. ^{(2,914 + 3,017 + 35,049)}/_290,000 = ^40,980/_290,000 = 0.1413 = 14.13 cM Incorrect MC

ca1d_6d1a

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is affiliated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is associated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes			Progeny Count
dewy, eery, horsey	d	e	h	10,615
dewy, eery	d	e	+	32,785
dewy, horsey	d	+	h	3,116
dewy	d	+	+	48,339
eery, horsey	+	e	h	48,682
eery	+	e	+	3,104
horsey	+	+	h	32,739
wildtype	+	+	+	10,620
TOTAL =				190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and H during meiosis.

calculate the genetic distance between the two genes E and H, expressing your answer in centimorgans (cM)

A. ^{(48,339 + 48,682)}/_190,000 = ^97,021/_190,000 = 0.5106 = 51.06 cM Incorrect B. ^48,682/_190,000 = ^48,682/_190,000 = 0.2562 = 25.62 cM Incorrect C. ^48,339/_190,000 = ^48,339/_190,000 = 0.2544 = 25.44 cM Incorrect D. ^{(3,104 + 3,116 + 10,620 + 32,785)}/_190,000 = ^49,625/_190,000 = 0.2612 = 26.12 cM Incorrect E. ^{(3,104 + 3,116 + 32,739 + 32,785)}/_190,000 = ^71,744/_190,000 = 0.3776 = 37.76 cM Correct F. ^{(3,116 + 10,615 + 10,620 + 32,785)}/_190,000 = ^57,136/_190,000 = 0.3007 = 30.07 cM Incorrect MC

8324_cdec

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene P is analogous to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
nerdy, prickly, rusty	n	p	r	7,760
nerdy, prickly	n	p	+	1,577
nerdy, rusty	n	+	r	563
nerdy	n	+	+	29
prickly, rusty	+	p	r	46
prickly	+	p	+	512
rusty	+	+	r	1,614
wildtype	+	+	+	7,899
TOTAL =				20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes P and R during meiosis.

calculate the genetic distance between the two genes P and R, expressing your answer in centimorgans (cM)

A. ^{(29 + 46 + 512 + 563 + 7,899)}/_20,000 = ^9,049/_20,000 = 0.4525 = 45.25 cM Incorrect B. ^{(7,760 + 7,899)}/_20,000 = ^15,659/_20,000 = 0.7830 = 78.30 cM Incorrect C. ^{(563 + 1,577 + 1,614)}/_20,000 = ^3,754/_20,000 = 0.1877 = 18.77 cM Incorrect D. ⁴⁶/_20,000 = ⁴⁶/_20,000 = 0.0023 = 0.23 cM Incorrect E. ^{(512 + 563 + 1,577 + 1,614)}/_20,000 = ^4,266/_20,000 = 0.2133 = 21.33 cM Correct F. ^{(46 + 7,760)}/_20,000 = ^7,806/_20,000 = 0.3903 = 39.03 cM Incorrect MC

6414_8a0e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
jerky, prickly, waxy	j	p	w	10,977
jerky, prickly	j	p	+	749
jerky, waxy	j	+	w	18,750
jerky	j	+	+	4,324
prickly, waxy	+	p	w	4,314
prickly	+	p	+	19,064
waxy	+	+	w	770
wildtype	+	+	+	11,052
TOTAL =				70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes J and P during meiosis.

calculate the genetic distance between the two genes J and P, expressing your answer in centimorgans (cM)

A. ^{(770 + 4,324)}/_70,000 = ^5,094/_70,000 = 0.0728 = 7.28 cM Incorrect B. ^{(18,750 + 19,064)}/_70,000 = ^37,814/_70,000 = 0.5402 = 54.02 cM Incorrect C. ^{(770 + 4,324 + 10,977)}/_70,000 = ^16,071/_70,000 = 0.2296 = 22.96 cM Incorrect D. ^{(749 + 770 + 10,977 + 11,052)}/_70,000 = ^23,548/_70,000 = 0.3364 = 33.64 cM Correct E. ^{(4,324 + 10,977 + 11,052)}/_70,000 = ^26,353/_70,000 = 0.3765 = 37.65 cM Incorrect F. ^{(4,324 + 11,052)}/_70,000 = ^15,376/_70,000 = 0.2197 = 21.97 cM Incorrect MC

d244_e158

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
horsey, prickly, xanthic	h	p	x	24,252
horsey, prickly	h	p	+	5,697
horsey, xanthic	h	+	x	52,786
horsey	h	+	+	2,305
prickly, xanthic	+	p	x	2,232
prickly	+	p	+	52,765
xanthic	+	+	x	5,593
wildtype	+	+	+	24,370
TOTAL =				170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and X during meiosis.

calculate the genetic distance between the two genes H and X, expressing your answer in centimorgans (cM)

A. ^52,786/_170,000 = ^52,786/_170,000 = 0.3105 = 31.05 cM Incorrect B. ^5,697/_170,000 = ^5,697/_170,000 = 0.0335 = 3.35 cM Incorrect C. ^{(2,305 + 5,697)}/_170,000 = ^8,002/_170,000 = 0.0471 = 4.71 cM Incorrect D. ^52,765/_170,000 = ^52,765/_170,000 = 0.3104 = 31.04 cM Incorrect E. ^{(2,232 + 2,305 + 5,593 + 5,697)}/_170,000 = ^15,827/_170,000 = 0.0931 = 9.31 cM Correct F. ^{(52,765 + 52,786)}/_170,000 = ^105,551/_170,000 = 0.6209 = 62.09 cM Incorrect MC

efdb_f85d

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes			Progeny Count
jerky, mushy, rusty	j	m	r	15,660
jerky, mushy	j	m	+	28,855
jerky, rusty	j	+	r	15,823
jerky	j	+	+	4,118
mushy, rusty	+	m	r	4,122
mushy	+	m	+	16,133
rusty	+	+	r	29,214
wildtype	+	+	+	16,075
TOTAL =				130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes J and R during meiosis.

calculate the genetic distance between the two genes J and R, expressing your answer in centimorgans (cM)

A. ^{(15,660 + 29,214)}/_130,000 = ^44,874/_130,000 = 0.3452 = 34.52 cM Incorrect B. ^{(4,118 + 4,122 + 15,823 + 29,214)}/_130,000 = ^53,277/_130,000 = 0.4098 = 40.98 cM Incorrect C. ^{(15,660 + 15,823 + 16,075 + 16,133)}/_130,000 = ^63,691/_130,000 = 0.4899 = 48.99 cM Correct D. ^{(4,122 + 29,214)}/_130,000 = ^33,336/_130,000 = 0.2564 = 25.64 cM Incorrect E. ^{(4,118 + 16,075 + 16,133)}/_130,000 = ^36,326/_130,000 = 0.2794 = 27.94 cM Incorrect F. ^{(28,855 + 29,214)}/_130,000 = ^58,069/_130,000 = 0.4467 = 44.67 cM Incorrect MC

d18e_1006

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
eery, tipsy, waxy	e	t	w	879
eery, tipsy	e	t	+	22,837
eery, waxy	e	+	w	84,722
eery	e	+	+	11,302
tipsy, waxy	+	t	w	11,318
tipsy	+	t	+	84,922
waxy	+	+	w	23,135
wildtype	+	+	+	885
TOTAL =				240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes T and W during meiosis.

calculate the genetic distance between the two genes T and W, expressing your answer in centimorgans (cM)

A. ^{(11,302 + 22,837 + 23,135)}/_240,000 = ^57,274/_240,000 = 0.2386 = 23.86 cM Incorrect B. ^{(879 + 885 + 11,302 + 11,318)}/_240,000 = ^24,384/_240,000 = 0.1016 = 10.16 cM Correct C. ^{(84,722 + 84,922)}/_240,000 = ^169,644/_240,000 = 0.7068 = 70.69 cM Incorrect D. ^11,318/_240,000 = ^11,318/_240,000 = 0.0472 = 4.72 cM Incorrect E. ^{(11,302 + 11,318 + 23,135)}/_240,000 = ^45,755/_240,000 = 0.1906 = 19.06 cM Incorrect F. ^{(885 + 11,318 + 84,722)}/_240,000 = ^96,925/_240,000 = 0.4039 = 40.39 cM Incorrect MC

cb5e_a550

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene Y is correlated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
eery, horsey, yucky	e	h	y	30,629
eery, horsey	e	h	+	4,783
eery, yucky	e	+	y	80,448
eery	e	+	+	14,539
horsey, yucky	+	h	y	14,332
horsey	+	h	+	79,701
yucky	+	+	y	4,748
wildtype	+	+	+	30,820
TOTAL =				260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and H during meiosis.

calculate the genetic distance between the two genes E and H, expressing your answer in centimorgans (cM)

A. ^{(4,748 + 14,332 + 14,539 + 79,701)}/_260,000 = ^113,320/_260,000 = 0.4358 = 43.58 cM Incorrect B. ^{(4,748 + 14,332 + 80,448)}/_260,000 = ^99,528/_260,000 = 0.3828 = 38.28 cM Incorrect C. ^{(4,748 + 4,783 + 30,629 + 30,820)}/_260,000 = ^70,980/_260,000 = 0.2730 = 27.30 cM Correct D. ^{(4,748 + 4,783 + 14,332 + 30,820)}/_260,000 = ^54,683/_260,000 = 0.2103 = 21.03 cM Incorrect E. ^80,448/_260,000 = ^80,448/_260,000 = 0.3094 = 30.94 cM Incorrect F. ^{(79,701 + 80,448)}/_260,000 = ^160,149/_260,000 = 0.6160 = 61.60 cM Incorrect MC

dfa5_582c

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
chummy, prickly, xanthic	c	p	x	6,879
chummy, prickly	c	p	+	14,980
chummy, xanthic	c	+	x	22,672
chummy	c	+	+	3,109
prickly, xanthic	+	p	x	2,989
prickly	+	p	+	22,756
xanthic	+	+	x	14,927
wildtype	+	+	+	6,688
TOTAL =				95,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes P and X during meiosis.

calculate the genetic distance between the two genes P and X, expressing your answer in centimorgans (cM)

A. ^6,879/_95,000 = ^6,879/_95,000 = 0.0724 = 7.24 cM Incorrect B. ^{(2,989 + 6,879 + 14,927 + 14,980)}/_95,000 = ^39,775/_95,000 = 0.4187 = 41.87 cM Incorrect C. ^14,927/_95,000 = ^14,927/_95,000 = 0.1571 = 15.71 cM Incorrect D. ^{(2,989 + 3,109 + 6,688 + 6,879)}/_95,000 = ^19,665/_95,000 = 0.2070 = 20.70 cM Correct E. ^{(3,109 + 14,980)}/_95,000 = ^18,089/_95,000 = 0.1904 = 19.04 cM Incorrect F. ^{(22,672 + 22,756)}/_95,000 = ^45,428/_95,000 = 0.4782 = 47.82 cM Incorrect MC

d8c5_9a48

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
mushy, rusty, waxy	m	r	w	2,037
mushy, rusty	m	r	+	81,325
mushy, waxy	m	+	w	15,129
mushy	m	+	+	31,355
rusty, waxy	+	r	w	31,288
rusty	+	r	+	15,352
waxy	+	+	w	81,530
wildtype	+	+	+	1,984
TOTAL =				260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes M and W during meiosis.

calculate the genetic distance between the two genes M and W, expressing your answer in centimorgans (cM)

A. ^{(81,325 + 81,530)}/_260,000 = ^162,855/_260,000 = 0.6264 = 62.64 cM Incorrect B. ^{(1,984 + 2,037 + 15,129 + 15,352)}/_260,000 = ^34,502/_260,000 = 0.1327 = 13.27 cM Correct C. ^{(1,984 + 15,352)}/_260,000 = ^17,336/_260,000 = 0.0667 = 6.67 cM Incorrect D. ^{(2,037 + 15,129 + 15,352 + 31,355)}/_260,000 = ^63,873/_260,000 = 0.2457 = 24.57 cM Incorrect E. ^{(1,984 + 2,037 + 15,352 + 81,530)}/_260,000 = ^100,903/_260,000 = 0.3881 = 38.81 cM Incorrect F. ^31,355/_260,000 = ^31,355/_260,000 = 0.1206 = 12.06 cM Incorrect MC

9fe3_37be

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
dewy, tipsy, xanthic	d	t	x	9,281
dewy, tipsy	d	t	+	2,285
dewy, xanthic	d	+	x	82,582
dewy	d	+	+	25,422
tipsy, xanthic	+	t	x	25,437
tipsy	+	t	+	83,351
xanthic	+	+	x	2,416
wildtype	+	+	+	9,226
TOTAL =				240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and T during meiosis.

calculate the genetic distance between the two genes D and T, expressing your answer in centimorgans (cM)

A. ^{(2,285 + 2,416 + 9,226 + 9,281)}/_240,000 = ^23,208/_240,000 = 0.0967 = 9.67 cM Correct B. ^{(25,422 + 25,437)}/_240,000 = ^50,859/_240,000 = 0.2119 = 21.19 cM Incorrect C. ^9,281/_240,000 = ^9,281/_240,000 = 0.0387 = 3.87 cM Incorrect D. ^{(82,582 + 83,351)}/_240,000 = ^165,933/_240,000 = 0.6914 = 69.14 cM Incorrect E. ^25,437/_240,000 = ^25,437/_240,000 = 0.1060 = 10.60 cM Incorrect F. ^{(2,416 + 9,281)}/_240,000 = ^11,697/_240,000 = 0.0487 = 4.87 cM Incorrect MC

540b_8b02

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes			Progeny Count
eery, jerky, xanthic	e	j	x	27,115
eery, jerky	e	j	+	5,976
eery, xanthic	e	+	x	39,615
eery	e	+	+	12,314
jerky, xanthic	+	j	x	12,506
jerky	+	j	+	39,010
xanthic	+	+	x	6,043
wildtype	+	+	+	27,421
TOTAL =				170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and X during meiosis.

calculate the genetic distance between the two genes E and X, expressing your answer in centimorgans (cM)

A. ^{(39,010 + 39,615)}/_170,000 = ^78,625/_170,000 = 0.4625 = 46.25 cM Incorrect B. ^{(5,976 + 12,314 + 12,506)}/_170,000 = ^30,796/_170,000 = 0.1812 = 18.12 cM Incorrect C. ^{(27,421 + 39,010)}/_170,000 = ^66,431/_170,000 = 0.3908 = 39.08 cM Incorrect D. ^{(12,506 + 39,615)}/_170,000 = ^52,121/_170,000 = 0.3066 = 30.66 cM Incorrect E. ^6,043/_170,000 = ^6,043/_170,000 = 0.0355 = 3.55 cM Incorrect F. ^{(5,976 + 6,043 + 12,314 + 12,506)}/_170,000 = ^36,839/_170,000 = 0.2167 = 21.67 cM Correct MC

57ac_2b6f

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
fuzzy, horsey, tipsy	f	h	t	11,307
fuzzy, horsey	f	h	+	21,669
fuzzy, tipsy	f	+	t	35,105
fuzzy	f	+	+	1,817
horsey, tipsy	+	h	t	1,899
horsey	+	h	+	34,915
tipsy	+	+	t	21,907
wildtype	+	+	+	11,381
TOTAL =				140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes H and T during meiosis.

calculate the genetic distance between the two genes H and T, expressing your answer in centimorgans (cM)

A. ^{(34,915 + 35,105)}/_140,000 = ^70,020/_140,000 = 0.5001 = 50.01 cM Incorrect B. ^11,307/_140,000 = ^11,307/_140,000 = 0.0808 = 8.08 cM Incorrect C. ^{(1,817 + 1,899 + 11,307 + 11,381)}/_140,000 = ^26,404/_140,000 = 0.1886 = 18.86 cM Correct D. ^21,907/_140,000 = ^21,907/_140,000 = 0.1565 = 15.65 cM Incorrect E. ^{(11,307 + 21,907 + 34,915)}/_140,000 = ^68,129/_140,000 = 0.4866 = 48.66 cM Incorrect F. ^11,381/_140,000 = ^11,381/_140,000 = 0.0813 = 8.13 cM Incorrect MC

5687_185f

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes			Progeny Count
fuzzy, jerky, waxy	f	j	w	25,612
fuzzy, jerky	f	j	+	986
fuzzy, waxy	f	+	w	10,494
fuzzy	f	+	+	7,779
jerky, waxy	+	j	w	7,711
jerky	+	j	+	10,630
waxy	+	+	w	1,011
wildtype	+	+	+	25,777
TOTAL =				90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and W during meiosis.

calculate the genetic distance between the two genes F and W, expressing your answer in centimorgans (cM)

A. ^{(25,612 + 25,777)}/_90,000 = ^51,389/_90,000 = 0.5710 = 57.10 cM Incorrect B. ^{(986 + 7,779)}/_90,000 = ^8,765/_90,000 = 0.0974 = 9.74 cM Incorrect C. ^{(986 + 1,011 + 7,711 + 25,777)}/_90,000 = ^35,485/_90,000 = 0.3943 = 39.43 cM Incorrect D. ^{(986 + 1,011 + 7,711 + 7,779 + 25,612)}/_90,000 = ^43,099/_90,000 = 0.4789 = 47.89 cM Incorrect E. ^25,777/_90,000 = ^25,777/_90,000 = 0.2864 = 28.64 cM Incorrect F. ^{(986 + 1,011 + 7,711 + 7,779)}/_90,000 = ^17,487/_90,000 = 0.1943 = 19.43 cM Correct MC

48b5_56c8

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is analogous to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes			Progeny Count
dewy, waxy, yucky	d	w	y	1,586
dewy, waxy	d	w	+	18,640
dewy, yucky	d	+	y	424
dewy	d	+	+	9,288
waxy, yucky	+	w	y	9,370
waxy	+	w	+	400
yucky	+	+	y	18,712
wildtype	+	+	+	1,580
TOTAL =				60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and Y during meiosis.

calculate the genetic distance between the two genes D and Y, expressing your answer in centimorgans (cM)

A. ^9,370/_60,000 = ^9,370/_60,000 = 0.1562 = 15.62 cM Incorrect B. ^{(1,580 + 1,586)}/_60,000 = ^3,166/_60,000 = 0.0528 = 5.28 cM Incorrect C. ^9,288/_60,000 = ^9,288/_60,000 = 0.1548 = 15.48 cM Incorrect D. ^{(18,640 + 18,712)}/_60,000 = ^37,352/_60,000 = 0.6225 = 62.25 cM Incorrect E. ^{(400 + 424 + 1,580 + 1,586)}/_60,000 = ^3,990/_60,000 = 0.0665 = 6.65 cM Correct F. ^{(400 + 424 + 1,580 + 18,640)}/_60,000 = ^21,044/_60,000 = 0.3507 = 35.07 cM Incorrect MC

3af1_007f

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is affiliated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene T is related to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
fuzzy, rusty, tipsy	f	r	t	2,444
fuzzy, rusty	f	r	+	42,524
fuzzy, tipsy	f	+	t	18,553
fuzzy	f	+	+	6,521
rusty, tipsy	+	r	t	6,292
rusty	+	r	+	18,634
tipsy	+	+	t	42,607
wildtype	+	+	+	2,425
TOTAL =				140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes F and R during meiosis.

calculate the genetic distance between the two genes F and R, expressing your answer in centimorgans (cM)

A. ^{(42,524 + 42,607)}/_140,000 = ^85,131/_140,000 = 0.6081 = 60.81 cM Incorrect B. ^{(2,444 + 18,634)}/_140,000 = ^21,078/_140,000 = 0.1506 = 15.06 cM Incorrect C. ^{(6,292 + 42,607)}/_140,000 = ^48,899/_140,000 = 0.3493 = 34.93 cM Incorrect D. ^{(6,292 + 6,521 + 18,553 + 18,634)}/_140,000 = ^50,000/_140,000 = 0.3571 = 35.71 cM Correct E. ^42,607/_140,000 = ^42,607/_140,000 = 0.3043 = 30.43 cM Incorrect F. ^{(2,444 + 6,292 + 6,521 + 18,553 + 18,634)}/_140,000 = ^52,444/_140,000 = 0.3746 = 37.46 cM Incorrect MC

9622_b06e

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
dewy, mushy, tipsy	d	m	t	10,100
dewy, mushy	d	m	+	1,805
dewy, tipsy	d	+	t	14,733
dewy	d	+	+	18,528
mushy, tipsy	+	m	t	18,278
mushy	+	m	+	14,638
tipsy	+	+	t	1,836
wildtype	+	+	+	10,082
TOTAL =				90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes D and M during meiosis.

calculate the genetic distance between the two genes D and M, expressing your answer in centimorgans (cM)

A. ^{(1,805 + 1,836 + 14,638 + 14,733)}/_90,000 = ^33,012/_90,000 = 0.3668 = 36.68 cM Incorrect B. ^{(14,638 + 14,733)}/_90,000 = ^29,371/_90,000 = 0.3263 = 32.63 cM Incorrect C. ^{(1,805 + 1,836 + 10,082 + 10,100)}/_90,000 = ^23,823/_90,000 = 0.2647 = 26.47 cM Correct D. ^{(18,278 + 18,528)}/_90,000 = ^36,806/_90,000 = 0.4090 = 40.90 cM Incorrect E. ^10,082/_90,000 = ^10,082/_90,000 = 0.1120 = 11.20 cM Incorrect F. ^{(10,100 + 14,638 + 18,528)}/_90,000 = ^43,266/_90,000 = 0.4807 = 48.07 cM Incorrect MC

4614_b1bb

Three-Point Test Cross Problem

A standard three-point test cross involves crossing a heterozygous organism for all three genes with an organism that is homozygous recessive for all three genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for three genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes			Progeny Count
eery, fuzzy, tipsy	e	f	t	9,631
eery, fuzzy	e	f	+	17,678
eery, tipsy	e	+	t	2,850
eery	e	+	+	7,819
fuzzy, tipsy	+	f	t	7,639
fuzzy	+	f	+	2,677
tipsy	+	+	t	17,174
wildtype	+	+	+	9,532
TOTAL =				75,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, and using only the genotypes that result from crossover events between the two genes E and F during meiosis.

calculate the genetic distance between the two genes E and F, expressing your answer in centimorgans (cM)

A. ^{(2,677 + 7,639)}/_75,000 = ^10,316/_75,000 = 0.1375 = 13.75 cM Incorrect B. ^{(2,677 + 2,850 + 7,639 + 7,819)}/_75,000 = ^20,985/_75,000 = 0.2798 = 27.98 cM Correct C. ^{(2,677 + 2,850 + 7,639 + 9,532)}/_75,000 = ^22,698/_75,000 = 0.3026 = 30.26 cM Incorrect D. ^2,850/_75,000 = ^2,850/_75,000 = 0.0380 = 3.80 cM Incorrect E. ^{(2,850 + 9,631 + 17,174)}/_75,000 = ^29,655/_75,000 = 0.3954 = 39.54 cM Incorrect F. ^{(17,174 + 17,678)}/_75,000 = ^34,852/_75,000 = 0.4647 = 46.47 cM Incorrect