MC

6cd3_8c56

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Yucky fly illustration. Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.
PhenotypeGenotypesProgeny
Count
 fuzzy, yuckyfy41,500
 fuzzyf+83,205
 yucky+y83,370
 wildtype++41,925
TOTAL =250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

41,500/250,000 = 41,500/250,000 = 0.1660 = 16.60 cM Incorrect 41,925/250,000 = 41,925/250,000 = 0.1677 = 16.77 cM Incorrect 83,205/250,000 = 83,205/250,000 = 0.3328 = 33.28 cM Incorrect 83,370/250,000 = 83,370/250,000 = 0.3335 = 33.35 cM Incorrect (41,500 + 41,925)/250,000 = 83,425/250,000 = 0.3337 = 33.37 cM Correct (41,500 + 83,205)/250,000 = 124,705/250,000 = 0.4988 = 49.88 cM Incorrect MC

96fc_75f2

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is associated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Kidney fly illustration. Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
PhenotypeGenotypesProgeny
Count
 horsey, kidneyhk35,621
 horseyh+14,556
 kidney+k14,214
 wildtype++35,609
TOTAL =100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

14,214/100,000 = 14,214/100,000 = 0.1421 = 14.21 cM Incorrect 14,556/100,000 = 14,556/100,000 = 0.1456 = 14.56 cM Incorrect (14,214 + 14,556)/100,000 = 28,770/100,000 = 0.2877 = 28.77 cM Correct 35,609/100,000 = 35,609/100,000 = 0.3561 = 35.61 cM Incorrect 35,621/100,000 = 35,621/100,000 = 0.3562 = 35.62 cM Incorrect (14,214 + 35,609)/100,000 = 49,823/100,000 = 0.4982 = 49.82 cM Incorrect MC

977b_bb0e

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Yucky fly illustration. Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.
PhenotypeGenotypesProgeny
Count
 fuzzy, yuckyfy16,720
 fuzzyf+5,632
 yucky+y5,690
 wildtype++16,958
TOTAL =45,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

5,632/45,000 = 5,632/45,000 = 0.1252 = 12.52 cM Incorrect 5,690/45,000 = 5,690/45,000 = 0.1264 = 12.64 cM Incorrect (5,632 + 5,690)/45,000 = 11,322/45,000 = 0.2516 = 25.16 cM Correct 16,720/45,000 = 16,720/45,000 = 0.3716 = 37.16 cM Incorrect 16,958/45,000 = 16,958/45,000 = 0.3768 = 37.68 cM Incorrect (5,632 + 16,958)/45,000 = 22,590/45,000 = 0.5020 = 50.20 cM Incorrect MC

6de2_4e9b

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Kidney fly illustration. Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Nerdy fly illustration. Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
PhenotypeGenotypesProgeny
Count
 kidney, nerdykn36,640
 kidneyk+108,632
 nerdy+n108,085
 wildtype++36,643
TOTAL =290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

36,640/290,000 = 36,640/290,000 = 0.1263 = 12.63 cM Incorrect 36,643/290,000 = 36,643/290,000 = 0.1264 = 12.64 cM Incorrect (36,640 + 36,643)/290,000 = 73,283/290,000 = 0.2527 = 25.27 cM Correct 108,085/290,000 = 108,085/290,000 = 0.3727 = 37.27 cM Incorrect 108,632/290,000 = 108,632/290,000 = 0.3746 = 37.46 cM Incorrect (36,640 + 108,632)/290,000 = 145,272/290,000 = 0.5009 = 50.09 cM Incorrect MC

a3f5_0fe0

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Rusty fly illustration. Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Xanthic fly illustration. Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
PhenotypeGenotypesProgeny
Count
 rusty, xanthicrx7,085
 rustyr+30,407
 xanthic+x30,508
 wildtype++7,000
TOTAL =75,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

7,000/75,000 = 7,000/75,000 = 0.0933 = 9.33 cM Incorrect 7,085/75,000 = 7,085/75,000 = 0.0945 = 9.45 cM Incorrect (7,000 + 7,085)/75,000 = 14,085/75,000 = 0.1878 = 18.78 cM Correct 30,407/75,000 = 30,407/75,000 = 0.4054 = 40.54 cM Incorrect 30,508/75,000 = 30,508/75,000 = 0.4068 = 40.68 cM Incorrect (7,000 + 30,508)/75,000 = 37,508/75,000 = 0.5001 = 50.01 cM Incorrect MC

913b_d0d5

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Mushy fly illustration. Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
PhenotypeGenotypesProgeny
Count
 horsey, mushyhm76,372
 horseyh+13,646
 mushy+m13,588
 wildtype++76,394
TOTAL =180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

13,588/180,000 = 13,588/180,000 = 0.0755 = 7.55 cM Incorrect 13,646/180,000 = 13,646/180,000 = 0.0758 = 7.58 cM Incorrect (13,588 + 13,646)/180,000 = 27,234/180,000 = 0.1513 = 15.13 cM Correct 76,372/180,000 = 76,372/180,000 = 0.4243 = 42.43 cM Incorrect 76,394/180,000 = 76,394/180,000 = 0.4244 = 42.44 cM Incorrect (13,588 + 76,394)/180,000 = 89,982/180,000 = 0.4999 = 49.99 cM Incorrect MC

4dcf_cf5b

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Waxy fly illustration. Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
PhenotypeGenotypesProgeny
Count
 horsey, waxyhw2,187
 horseyh+7,807
 waxy+w7,783
 wildtype++2,223
TOTAL =20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

2,187/20,000 = 2,187/20,000 = 0.1094 = 10.94 cM Incorrect 2,223/20,000 = 2,223/20,000 = 0.1111 = 11.12 cM Incorrect (2,187 + 2,223)/20,000 = 4,410/20,000 = 0.2205 = 22.05 cM Correct 7,783/20,000 = 7,783/20,000 = 0.3891 = 38.91 cM Incorrect 7,807/20,000 = 7,807/20,000 = 0.3903 = 39.03 cM Incorrect (2,187 + 7,783)/20,000 = 9,970/20,000 = 0.4985 = 49.85 cM Incorrect MC

85b0_a931

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is connected with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Rusty fly illustration. Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
PhenotypeGenotypesProgeny
Count
 fuzzy, rustyfr73,692
 fuzzyf+31,161
 rusty+r31,062
 wildtype++74,085
TOTAL =210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

31,062/210,000 = 31,062/210,000 = 0.1479 = 14.79 cM Incorrect 31,161/210,000 = 31,161/210,000 = 0.1484 = 14.84 cM Incorrect (31,062 + 31,161)/210,000 = 62,223/210,000 = 0.2963 = 29.63 cM Correct 73,692/210,000 = 73,692/210,000 = 0.3509 = 35.09 cM Incorrect 74,085/210,000 = 74,085/210,000 = 0.3528 = 35.28 cM Incorrect (31,161 + 73,692)/210,000 = 104,853/210,000 = 0.4993 = 49.93 cM Incorrect MC

62ea_b331

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Chummy fly illustration. Gene C is associated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Jerky fly illustration. Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
PhenotypeGenotypesProgeny
Count
 chummy, jerkycj1,297
 chummyc+12,691
 jerky+j12,761
 wildtype++1,251
TOTAL =28,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

1,251/28,000 = 1,251/28,000 = 0.0447 = 4.47 cM Incorrect 1,297/28,000 = 1,297/28,000 = 0.0463 = 4.63 cM Incorrect (1,251 + 1,297)/28,000 = 2,548/28,000 = 0.0910 = 9.10 cM Correct 12,691/28,000 = 12,691/28,000 = 0.4532 = 45.32 cM Incorrect 12,761/28,000 = 12,761/28,000 = 0.4557 = 45.57 cM Incorrect (1,297 + 12,761)/28,000 = 14,058/28,000 = 0.5021 = 50.21 cM Incorrect MC

79d1_7f8e

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Chummy fly illustration. Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Tipsy fly illustration. Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
PhenotypeGenotypesProgeny
Count
 chummy, tipsyct25,829
 chummyc+14,163
 tipsy+t14,149
 wildtype++25,859
TOTAL =80,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

14,149/80,000 = 14,149/80,000 = 0.1769 = 17.69 cM Incorrect 14,163/80,000 = 14,163/80,000 = 0.1770 = 17.70 cM Incorrect 25,829/80,000 = 25,829/80,000 = 0.3229 = 32.29 cM Incorrect 25,859/80,000 = 25,859/80,000 = 0.3232 = 32.32 cM Incorrect (14,149 + 14,163)/80,000 = 28,312/80,000 = 0.3539 = 35.39 cM Correct (14,163 + 25,829)/80,000 = 39,992/80,000 = 0.4999 = 49.99 cM Incorrect MC

81c3_85b5

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Kidney fly illustration. Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Mushy fly illustration. Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
PhenotypeGenotypesProgeny
Count
 kidney, mushykm20,614
 kidneyk+4,289
 mushy+m4,441
 wildtype++20,656
TOTAL =50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

4,289/50,000 = 4,289/50,000 = 0.0858 = 8.58 cM Incorrect 4,441/50,000 = 4,441/50,000 = 0.0888 = 8.88 cM Incorrect (4,289 + 4,441)/50,000 = 8,730/50,000 = 0.1746 = 17.46 cM Correct 20,614/50,000 = 20,614/50,000 = 0.4123 = 41.23 cM Incorrect 20,656/50,000 = 20,656/50,000 = 0.4131 = 41.31 cM Incorrect (4,289 + 20,614)/50,000 = 24,903/50,000 = 0.4981 = 49.81 cM Incorrect MC

3549_861e

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Artsy fly illustration. Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Mushy fly illustration. Gene M is correlated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
PhenotypeGenotypesProgeny
Count
 artsy, mushyam11,925
 artsya+23,140
 mushy+m23,291
 wildtype++11,644
TOTAL =70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

11,644/70,000 = 11,644/70,000 = 0.1663 = 16.63 cM Incorrect 11,925/70,000 = 11,925/70,000 = 0.1704 = 17.04 cM Incorrect 23,140/70,000 = 23,140/70,000 = 0.3306 = 33.06 cM Incorrect 23,291/70,000 = 23,291/70,000 = 0.3327 = 33.27 cM Incorrect (11,644 + 11,925)/70,000 = 23,569/70,000 = 0.3367 = 33.67 cM Correct (11,925 + 23,140)/70,000 = 35,065/70,000 = 0.5009 = 50.09 cM Incorrect MC

262a_c931

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Prickly fly illustration. Gene P is related to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Waxy fly illustration. Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
PhenotypeGenotypesProgeny
Count
 prickly, waxypw83,786
 pricklyp+21,178
 waxy+w21,389
 wildtype++83,647
TOTAL =210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

21,178/210,000 = 21,178/210,000 = 0.1008 = 10.08 cM Incorrect 21,389/210,000 = 21,389/210,000 = 0.1019 = 10.19 cM Incorrect (21,178 + 21,389)/210,000 = 42,567/210,000 = 0.2027 = 20.27 cM Correct 83,647/210,000 = 83,647/210,000 = 0.3983 = 39.83 cM Incorrect 83,786/210,000 = 83,786/210,000 = 0.3990 = 39.90 cM Incorrect (21,389 + 83,786)/210,000 = 105,175/210,000 = 0.5008 = 50.08 cM Incorrect MC

4c85_8113

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Bumpy fly illustration. Gene B is linked with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Kidney fly illustration. Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
PhenotypeGenotypesProgeny
Count
 bumpy, kidneybk87,343
 bumpyb+17,700
 kidney+k17,349
 wildtype++87,608
TOTAL =210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

17,349/210,000 = 17,349/210,000 = 0.0826 = 8.26 cM Incorrect 17,700/210,000 = 17,700/210,000 = 0.0843 = 8.43 cM Incorrect (17,349 + 17,700)/210,000 = 35,049/210,000 = 0.1669 = 16.69 cM Correct 87,343/210,000 = 87,343/210,000 = 0.4159 = 41.59 cM Incorrect 87,608/210,000 = 87,608/210,000 = 0.4172 = 41.72 cM Incorrect (17,349 + 87,343)/210,000 = 104,692/210,000 = 0.4985 = 49.85 cM Incorrect MC

780c_88bd

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Mushy fly illustration. Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Nerdy fly illustration. Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
PhenotypeGenotypesProgeny
Count
 mushy, nerdymn45,711
 mushym+14,175
 nerdy+n14,457
 wildtype++45,657
TOTAL =120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

14,175/120,000 = 14,175/120,000 = 0.1181 = 11.81 cM Incorrect 14,457/120,000 = 14,457/120,000 = 0.1205 = 12.05 cM Incorrect (14,175 + 14,457)/120,000 = 28,632/120,000 = 0.2386 = 23.86 cM Correct 45,657/120,000 = 45,657/120,000 = 0.3805 = 38.05 cM Incorrect 45,711/120,000 = 45,711/120,000 = 0.3809 = 38.09 cM Incorrect (14,457 + 45,711)/120,000 = 60,168/120,000 = 0.5014 = 50.14 cM Incorrect MC

60b7_5042

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Rusty fly illustration. Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
PhenotypeGenotypesProgeny
Count
 fuzzy, rustyfr35,129
 fuzzyf+95,000
 rusty+r94,462
 wildtype++35,409
TOTAL =260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

35,129/260,000 = 35,129/260,000 = 0.1351 = 13.51 cM Incorrect 35,409/260,000 = 35,409/260,000 = 0.1362 = 13.62 cM Incorrect (35,129 + 35,409)/260,000 = 70,538/260,000 = 0.2713 = 27.13 cM Correct 94,462/260,000 = 94,462/260,000 = 0.3633 = 36.33 cM Incorrect 95,000/260,000 = 95,000/260,000 = 0.3654 = 36.54 cM Incorrect (35,129 + 94,462)/260,000 = 129,591/260,000 = 0.4984 = 49.84 cM Incorrect MC

84b7_23b2

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Chummy fly illustration. Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Eery fly illustration. Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
PhenotypeGenotypesProgeny
Count
 chummy, eeryce4,515
 chummyc+10,548
 eery+e10,536
 wildtype++4,401
TOTAL =30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

4,401/30,000 = 4,401/30,000 = 0.1467 = 14.67 cM Incorrect 4,515/30,000 = 4,515/30,000 = 0.1505 = 15.05 cM Incorrect (4,401 + 4,515)/30,000 = 8,916/30,000 = 0.2972 = 29.72 cM Correct 10,536/30,000 = 10,536/30,000 = 0.3512 = 35.12 cM Incorrect 10,548/30,000 = 10,548/30,000 = 0.3516 = 35.16 cM Incorrect (4,401 + 10,548)/30,000 = 14,949/30,000 = 0.4983 = 49.83 cM Incorrect MC

2f6d_2f0f

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Artsy fly illustration. Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Bumpy fly illustration. Gene B is affiliated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
PhenotypeGenotypesProgeny
Count
 artsy, bumpyab618
 artsya+314
 bumpy+b307
 wildtype++561
TOTAL =1,800

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

307/1,800 = 307/1,800 = 0.1706 = 17.06 cM Incorrect 314/1,800 = 314/1,800 = 0.1744 = 17.44 cM Incorrect 561/1,800 = 561/1,800 = 0.3117 = 31.17 cM Incorrect 618/1,800 = 618/1,800 = 0.3433 = 34.33 cM Incorrect (307 + 314)/1,800 = 621/1,800 = 0.3450 = 34.50 cM Correct (314 + 618)/1,800 = 932/1,800 = 0.5178 = 51.78 cM Incorrect MC

502c_8542

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Chummy fly illustration. Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Tipsy fly illustration. Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
PhenotypeGenotypesProgeny
Count
 chummy, tipsyct47,052
 chummyc+8,283
 tipsy+t8,184
 wildtype++46,481
TOTAL =110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

8,184/110,000 = 8,184/110,000 = 0.0744 = 7.44 cM Incorrect 8,283/110,000 = 8,283/110,000 = 0.0753 = 7.53 cM Incorrect (8,184 + 8,283)/110,000 = 16,467/110,000 = 0.1497 = 14.97 cM Correct 46,481/110,000 = 46,481/110,000 = 0.4226 = 42.26 cM Incorrect 47,052/110,000 = 47,052/110,000 = 0.4277 = 42.77 cM Incorrect (8,184 + 47,052)/110,000 = 55,236/110,000 = 0.5021 = 50.21 cM Incorrect MC

3f39_5189

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Bumpy fly illustration. Gene B is affiliated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Fuzzy fly illustration. Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
PhenotypeGenotypesProgeny
Count
 bumpy, fuzzybf8,555
 bumpyb+26,571
 fuzzy+f26,615
 wildtype++8,259
TOTAL =70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

8,259/70,000 = 8,259/70,000 = 0.1180 = 11.80 cM Incorrect 8,555/70,000 = 8,555/70,000 = 0.1222 = 12.22 cM Incorrect (8,259 + 8,555)/70,000 = 16,814/70,000 = 0.2402 = 24.02 cM Correct 26,571/70,000 = 26,571/70,000 = 0.3796 = 37.96 cM Incorrect 26,615/70,000 = 26,615/70,000 = 0.3802 = 38.02 cM Incorrect (8,555 + 26,571)/70,000 = 35,126/70,000 = 0.5018 = 50.18 cM Incorrect MC

ef1c_b35e

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Jerky fly illustration. Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Prickly fly illustration. Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
PhenotypeGenotypesProgeny
Count
 jerky, pricklyjp10,375
 jerkyj+3,943
 prickly+p3,974
 wildtype++10,708
TOTAL =29,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

3,943/29,000 = 3,943/29,000 = 0.1360 = 13.60 cM Incorrect 3,974/29,000 = 3,974/29,000 = 0.1370 = 13.70 cM Incorrect (3,943 + 3,974)/29,000 = 7,917/29,000 = 0.2730 = 27.30 cM Correct 10,375/29,000 = 10,375/29,000 = 0.3578 = 35.78 cM Incorrect 10,708/29,000 = 10,708/29,000 = 0.3692 = 36.92 cM Incorrect (3,943 + 10,375)/29,000 = 14,318/29,000 = 0.4937 = 49.37 cM Incorrect MC

57e7_29f6

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is connected with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Nerdy fly illustration. Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
PhenotypeGenotypesProgeny
Count
 fuzzy, nerdyfn114,602
 fuzzyf+25,254
 nerdy+n25,062
 wildtype++115,082
TOTAL =280,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

25,062/280,000 = 25,062/280,000 = 0.0895 = 8.95 cM Incorrect 25,254/280,000 = 25,254/280,000 = 0.0902 = 9.02 cM Incorrect (25,062 + 25,254)/280,000 = 50,316/280,000 = 0.1797 = 17.97 cM Correct 114,602/280,000 = 114,602/280,000 = 0.4093 = 40.93 cM Incorrect 115,082/280,000 = 115,082/280,000 = 0.4110 = 41.10 cM Incorrect (25,062 + 114,602)/280,000 = 139,664/280,000 = 0.4988 = 49.88 cM Incorrect MC

417f_73fa

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Bumpy fly illustration. Gene B is connected with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Dewy fly illustration. Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
PhenotypeGenotypesProgeny
Count
 bumpy, dewybd13,668
 bumpyb+81,593
 dewy+d80,990
 wildtype++13,749
TOTAL =190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

13,668/190,000 = 13,668/190,000 = 0.0719 = 7.19 cM Incorrect 13,749/190,000 = 13,749/190,000 = 0.0724 = 7.24 cM Incorrect (13,668 + 13,749)/190,000 = 27,417/190,000 = 0.1443 = 14.43 cM Correct 80,990/190,000 = 80,990/190,000 = 0.4263 = 42.63 cM Incorrect 81,593/190,000 = 81,593/190,000 = 0.4294 = 42.94 cM Incorrect (13,749 + 80,990)/190,000 = 94,739/190,000 = 0.4986 = 49.86 cM Incorrect MC

42e1_fc1f

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Nerdy fly illustration. Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Rusty fly illustration. Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
PhenotypeGenotypesProgeny
Count
 nerdy, rustynr10,089
 nerdyn+29,751
 rusty+r29,921
 wildtype++10,239
TOTAL =80,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

10,089/80,000 = 10,089/80,000 = 0.1261 = 12.61 cM Incorrect 10,239/80,000 = 10,239/80,000 = 0.1280 = 12.80 cM Incorrect (10,089 + 10,239)/80,000 = 20,328/80,000 = 0.2541 = 25.41 cM Correct 29,751/80,000 = 29,751/80,000 = 0.3719 = 37.19 cM Incorrect 29,921/80,000 = 29,921/80,000 = 0.3740 = 37.40 cM Incorrect (10,089 + 29,751)/80,000 = 39,840/80,000 = 0.4980 = 49.80 cM Incorrect MC

9a5c_c6b6

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Eery fly illustration. Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Prickly fly illustration. Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
PhenotypeGenotypesProgeny
Count
 eery, pricklyep7,519
 eerye+24,764
 prickly+p25,182
 wildtype++7,535
TOTAL =65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

7,519/65,000 = 7,519/65,000 = 0.1157 = 11.57 cM Incorrect 7,535/65,000 = 7,535/65,000 = 0.1159 = 11.59 cM Incorrect (7,519 + 7,535)/65,000 = 15,054/65,000 = 0.2316 = 23.16 cM Correct 24,764/65,000 = 24,764/65,000 = 0.3810 = 38.10 cM Incorrect 25,182/65,000 = 25,182/65,000 = 0.3874 = 38.74 cM Incorrect (7,535 + 24,764)/65,000 = 32,299/65,000 = 0.4969 = 49.69 cM Incorrect MC

2425_5fdb

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Nerdy fly illustration. Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Xanthic fly illustration. Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
PhenotypeGenotypesProgeny
Count
 nerdy, xanthicnx31,233
 nerdyn+4,886
 xanthic+x4,800
 wildtype++31,581
TOTAL =72,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

4,800/72,500 = 4,800/72,500 = 0.0662 = 6.62 cM Incorrect 4,886/72,500 = 4,886/72,500 = 0.0674 = 6.74 cM Incorrect (4,800 + 4,886)/72,500 = 9,686/72,500 = 0.1336 = 13.36 cM Correct 31,233/72,500 = 31,233/72,500 = 0.4308 = 43.08 cM Incorrect 31,581/72,500 = 31,581/72,500 = 0.4356 = 43.56 cM Incorrect (4,800 + 31,581)/72,500 = 36,381/72,500 = 0.5018 = 50.18 cM Incorrect MC

cb31_c947

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is connected with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Horsey fly illustration. Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
PhenotypeGenotypesProgeny
Count
 fuzzy, horseyfh1,426
 fuzzyf+4,848
 horsey+h4,847
 wildtype++1,379
TOTAL =12,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

1,379/12,500 = 1,379/12,500 = 0.1103 = 11.03 cM Incorrect 1,426/12,500 = 1,426/12,500 = 0.1141 = 11.41 cM Incorrect (1,379 + 1,426)/12,500 = 2,805/12,500 = 0.2244 = 22.44 cM Correct 4,847/12,500 = 4,847/12,500 = 0.3878 = 38.78 cM Incorrect (1,379 + 4,847)/12,500 = 6,226/12,500 = 0.4981 = 49.81 cM Incorrect (1,426 + 4,848)/12,500 = 6,274/12,500 = 0.5019 = 50.19 cM Incorrect MC

da26_bae5

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Jerky fly illustration. Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
PhenotypeGenotypesProgeny
Count
 fuzzy, jerkyfj58
 fuzzyf+220
 jerky+j251
 wildtype++71
TOTAL =600

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

58/600 = 58/600 = 0.0967 = 9.67 cM Incorrect 71/600 = 71/600 = 0.1183 = 11.83 cM Incorrect (58 + 71)/600 = 129/600 = 0.2150 = 21.50 cM Correct 220/600 = 220/600 = 0.3667 = 36.67 cM Incorrect 251/600 = 251/600 = 0.4183 = 41.83 cM Incorrect (71 + 251)/600 = 322/600 = 0.5367 = 53.67 cM Incorrect MC

f5f3_966e

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Kidney fly illustration. Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Prickly fly illustration. Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
PhenotypeGenotypesProgeny
Count
 kidney, pricklykp241
 kidneyk+872
 prickly+p866
 wildtype++221
TOTAL =2,200

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

221/2,200 = 221/2,200 = 0.1005 = 10.05 cM Incorrect 241/2,200 = 241/2,200 = 0.1095 = 10.95 cM Incorrect (221 + 241)/2,200 = 462/2,200 = 0.2100 = 21.00 cM Correct 866/2,200 = 866/2,200 = 0.3936 = 39.36 cM Incorrect 872/2,200 = 872/2,200 = 0.3964 = 39.64 cM Incorrect (241 + 872)/2,200 = 1,113/2,200 = 0.5059 = 50.59 cM Incorrect MC

bc83_6b8e

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Tipsy fly illustration. Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Waxy fly illustration. Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
PhenotypeGenotypesProgeny
Count
 tipsy, waxytw30,873
 tipsyt+83,969
 waxy+w83,632
 wildtype++31,526
TOTAL =230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

30,873/230,000 = 30,873/230,000 = 0.1342 = 13.42 cM Incorrect 31,526/230,000 = 31,526/230,000 = 0.1371 = 13.71 cM Incorrect (30,873 + 31,526)/230,000 = 62,399/230,000 = 0.2713 = 27.13 cM Correct 83,632/230,000 = 83,632/230,000 = 0.3636 = 36.36 cM Incorrect 83,969/230,000 = 83,969/230,000 = 0.3651 = 36.51 cM Incorrect (30,873 + 83,969)/230,000 = 114,842/230,000 = 0.4993 = 49.93 cM Incorrect MC

dd48_c9cb

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Eery fly illustration. Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Tipsy fly illustration. Gene T is related to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
PhenotypeGenotypesProgeny
Count
 eery, tipsyet24,225
 eerye+3,240
 tipsy+t3,338
 wildtype++24,197
TOTAL =55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

3,240/55,000 = 3,240/55,000 = 0.0589 = 5.89 cM Incorrect 3,338/55,000 = 3,338/55,000 = 0.0607 = 6.07 cM Incorrect (3,240 + 3,338)/55,000 = 6,578/55,000 = 0.1196 = 11.96 cM Correct 24,197/55,000 = 24,197/55,000 = 0.4399 = 43.99 cM Incorrect 24,225/55,000 = 24,225/55,000 = 0.4405 = 44.05 cM Incorrect (3,338 + 24,197)/55,000 = 27,535/55,000 = 0.5006 = 50.06 cM Incorrect MC

68f8_71d8

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Rusty fly illustration. Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Waxy fly illustration. Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
PhenotypeGenotypesProgeny
Count
 rusty, waxyrw5,223
 rustyr+24,621
 waxy+w24,795
 wildtype++5,361
TOTAL =60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

5,223/60,000 = 5,223/60,000 = 0.0871 = 8.71 cM Incorrect 5,361/60,000 = 5,361/60,000 = 0.0893 = 8.94 cM Incorrect (5,223 + 5,361)/60,000 = 10,584/60,000 = 0.1764 = 17.64 cM Correct 24,621/60,000 = 24,621/60,000 = 0.4103 = 41.03 cM Incorrect 24,795/60,000 = 24,795/60,000 = 0.4133 = 41.33 cM Incorrect (5,223 + 24,621)/60,000 = 29,844/60,000 = 0.4974 = 49.74 cM Incorrect MC

53f1_87df

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Dewy fly illustration. Gene D is affiliated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Yucky fly illustration. Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.
PhenotypeGenotypesProgeny
Count
 dewy, yuckydy23,593
 dewyd+6,450
 yucky+y6,426
 wildtype++23,531
TOTAL =60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

6,426/60,000 = 6,426/60,000 = 0.1071 = 10.71 cM Incorrect 6,450/60,000 = 6,450/60,000 = 0.1075 = 10.75 cM Incorrect (6,426 + 6,450)/60,000 = 12,876/60,000 = 0.2146 = 21.46 cM Correct 23,531/60,000 = 23,531/60,000 = 0.3922 = 39.22 cM Incorrect 23,593/60,000 = 23,593/60,000 = 0.3932 = 39.32 cM Incorrect (6,450 + 23,593)/60,000 = 30,043/60,000 = 0.5007 = 50.07 cM Incorrect MC

926b_c190

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Chummy fly illustration. Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Nerdy fly illustration. Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
PhenotypeGenotypesProgeny
Count
 chummy, nerdycn16,251
 chummyc+8,743
 nerdy+n8,627
 wildtype++16,379
TOTAL =50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

8,627/50,000 = 8,627/50,000 = 0.1725 = 17.25 cM Incorrect 8,743/50,000 = 8,743/50,000 = 0.1749 = 17.49 cM Incorrect 16,251/50,000 = 16,251/50,000 = 0.3250 = 32.50 cM Incorrect 16,379/50,000 = 16,379/50,000 = 0.3276 = 32.76 cM Incorrect (8,627 + 8,743)/50,000 = 17,370/50,000 = 0.3474 = 34.74 cM Correct (8,627 + 16,251)/50,000 = 24,878/50,000 = 0.4976 = 49.76 cM Incorrect MC

58ff_95b0

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Mushy fly illustration. Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Rusty fly illustration. Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
PhenotypeGenotypesProgeny
Count
 mushy, rustymr1,016
 mushym+8,459
 rusty+r8,470
 wildtype++1,055
TOTAL =19,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

1,016/19,000 = 1,016/19,000 = 0.0535 = 5.35 cM Incorrect 1,055/19,000 = 1,055/19,000 = 0.0555 = 5.55 cM Incorrect (1,016 + 1,055)/19,000 = 2,071/19,000 = 0.1090 = 10.90 cM Correct 8,459/19,000 = 8,459/19,000 = 0.4452 = 44.52 cM Incorrect 8,470/19,000 = 8,470/19,000 = 0.4458 = 44.58 cM Incorrect (1,016 + 8,459)/19,000 = 9,475/19,000 = 0.4987 = 49.87 cM Incorrect MC

749b_950f

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Eery fly illustration. Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Tipsy fly illustration. Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
PhenotypeGenotypesProgeny
Count
 eery, tipsyet38,855
 eerye+6,063
 tipsy+t5,934
 wildtype++39,148
TOTAL =90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

5,934/90,000 = 5,934/90,000 = 0.0659 = 6.59 cM Incorrect 6,063/90,000 = 6,063/90,000 = 0.0674 = 6.74 cM Incorrect (5,934 + 6,063)/90,000 = 11,997/90,000 = 0.1333 = 13.33 cM Correct 38,855/90,000 = 38,855/90,000 = 0.4317 = 43.17 cM Incorrect 39,148/90,000 = 39,148/90,000 = 0.4350 = 43.50 cM Incorrect (6,063 + 39,148)/90,000 = 45,211/90,000 = 0.5023 = 50.23 cM Incorrect MC

e2fd_9789

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Eery fly illustration. Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Tipsy fly illustration. Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
PhenotypeGenotypesProgeny
Count
 eery, tipsyet2,300
 eerye+910
 tipsy+t858
 wildtype++2,432
TOTAL =6,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

858/6,500 = 858/6,500 = 0.1320 = 13.20 cM Incorrect 910/6,500 = 910/6,500 = 0.1400 = 14.00 cM Incorrect (858 + 910)/6,500 = 1,768/6,500 = 0.2720 = 27.20 cM Correct 2,300/6,500 = 2,300/6,500 = 0.3538 = 35.38 cM Incorrect 2,432/6,500 = 2,432/6,500 = 0.3742 = 37.42 cM Incorrect (858 + 2,432)/6,500 = 3,290/6,500 = 0.5062 = 50.62 cM Incorrect MC

4a05_28a5

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Bumpy fly illustration. Gene B is correlated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Kidney fly illustration. Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
PhenotypeGenotypesProgeny
Count
 bumpy, kidneybk687
 bumpyb+91
 kidney+k117
 wildtype++705
TOTAL =1,600

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

91/1,600 = 91/1,600 = 0.0569 = 5.69 cM Incorrect 117/1,600 = 117/1,600 = 0.0731 = 7.31 cM Incorrect (91 + 117)/1,600 = 208/1,600 = 0.1300 = 13.00 cM Correct 687/1,600 = 687/1,600 = 0.4294 = 42.94 cM Incorrect 705/1,600 = 705/1,600 = 0.4406 = 44.06 cM Incorrect (91 + 687)/1,600 = 778/1,600 = 0.4863 = 48.62 cM Incorrect MC

5559_c77a

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Yucky fly illustration. Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.
PhenotypeGenotypesProgeny
Count
 horsey, yuckyhy2,931
 horseyh+11,992
 yucky+y12,101
 wildtype++2,976
TOTAL =30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

2,931/30,000 = 2,931/30,000 = 0.0977 = 9.77 cM Incorrect 2,976/30,000 = 2,976/30,000 = 0.0992 = 9.92 cM Incorrect (2,931 + 2,976)/30,000 = 5,907/30,000 = 0.1969 = 19.69 cM Correct 11,992/30,000 = 11,992/30,000 = 0.3997 = 39.97 cM Incorrect 12,101/30,000 = 12,101/30,000 = 0.4034 = 40.34 cM Incorrect (2,931 + 11,992)/30,000 = 14,923/30,000 = 0.4974 = 49.74 cM Incorrect MC

36d4_7913

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Tipsy fly illustration. Gene T is connected with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Xanthic fly illustration. Gene X is analogous to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
PhenotypeGenotypesProgeny
Count
 tipsy, xanthictx9,139
 tipsyt+35,864
 xanthic+x35,893
 wildtype++9,104
TOTAL =90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

9,104/90,000 = 9,104/90,000 = 0.1012 = 10.12 cM Incorrect 9,139/90,000 = 9,139/90,000 = 0.1015 = 10.15 cM Incorrect (9,104 + 9,139)/90,000 = 18,243/90,000 = 0.2027 = 20.27 cM Correct 35,864/90,000 = 35,864/90,000 = 0.3985 = 39.85 cM Incorrect 35,893/90,000 = 35,893/90,000 = 0.3988 = 39.88 cM Incorrect (9,104 + 35,893)/90,000 = 44,997/90,000 = 0.5000 = 50.00 cM Incorrect MC

1585_8ea4

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Fuzzy fly illustration. Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Kidney fly illustration. Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
PhenotypeGenotypesProgeny
Count
 fuzzy, kidneyfk30,208
 fuzzyf+5,848
 kidney+k5,984
 wildtype++30,460
TOTAL =72,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

5,848/72,500 = 5,848/72,500 = 0.0807 = 8.07 cM Incorrect 5,984/72,500 = 5,984/72,500 = 0.0825 = 8.25 cM Incorrect (5,848 + 5,984)/72,500 = 11,832/72,500 = 0.1632 = 16.32 cM Correct 30,208/72,500 = 30,208/72,500 = 0.4167 = 41.67 cM Incorrect 30,460/72,500 = 30,460/72,500 = 0.4201 = 42.01 cM Incorrect (5,848 + 30,460)/72,500 = 36,308/72,500 = 0.5008 = 50.08 cM Incorrect MC

fd72_02b0

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Dewy fly illustration. Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Horsey fly illustration. Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
PhenotypeGenotypesProgeny
Count
 dewy, horseydh12,916
 dewyd+37,107
 horsey+h36,963
 wildtype++13,014
TOTAL =100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

12,916/100,000 = 12,916/100,000 = 0.1292 = 12.92 cM Incorrect 13,014/100,000 = 13,014/100,000 = 0.1301 = 13.01 cM Incorrect (12,916 + 13,014)/100,000 = 25,930/100,000 = 0.2593 = 25.93 cM Correct 36,963/100,000 = 36,963/100,000 = 0.3696 = 36.96 cM Incorrect 37,107/100,000 = 37,107/100,000 = 0.3711 = 37.11 cM Incorrect (13,014 + 36,963)/100,000 = 49,977/100,000 = 0.4998 = 49.98 cM Incorrect MC

f010_1bec

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Eery fly illustration. Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Fuzzy fly illustration. Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
PhenotypeGenotypesProgeny
Count
 eery, fuzzyef16,978
 eerye+28,083
 fuzzy+f27,915
 wildtype++17,024
TOTAL =90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

16,978/90,000 = 16,978/90,000 = 0.1886 = 18.86 cM Incorrect 17,024/90,000 = 17,024/90,000 = 0.1892 = 18.92 cM Incorrect 27,915/90,000 = 27,915/90,000 = 0.3102 = 31.02 cM Incorrect 28,083/90,000 = 28,083/90,000 = 0.3120 = 31.20 cM Incorrect (16,978 + 17,024)/90,000 = 34,002/90,000 = 0.3778 = 37.78 cM Correct (16,978 + 27,915)/90,000 = 44,893/90,000 = 0.4988 = 49.88 cM Incorrect MC

268e_d7d0

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Chummy fly illustration. Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Eery fly illustration. Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
PhenotypeGenotypesProgeny
Count
 chummy, eeryce21,931
 chummyc+7,977
 eery+e8,127
 wildtype++21,965
TOTAL =60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

7,977/60,000 = 7,977/60,000 = 0.1330 = 13.30 cM Incorrect 8,127/60,000 = 8,127/60,000 = 0.1354 = 13.54 cM Incorrect (7,977 + 8,127)/60,000 = 16,104/60,000 = 0.2684 = 26.84 cM Correct 21,931/60,000 = 21,931/60,000 = 0.3655 = 36.55 cM Incorrect 21,965/60,000 = 21,965/60,000 = 0.3661 = 36.61 cM Incorrect (8,127 + 21,931)/60,000 = 30,058/60,000 = 0.5010 = 50.10 cM Incorrect MC

fa59_6871

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Yucky fly illustration. Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.
PhenotypeGenotypesProgeny
Count
 horsey, yuckyhy74,866
 horseyh+25,072
 yucky+y25,068
 wildtype++74,994
TOTAL =200,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

25,068/200,000 = 25,068/200,000 = 0.1253 = 12.53 cM Incorrect 25,072/200,000 = 25,072/200,000 = 0.1254 = 12.54 cM Incorrect (25,068 + 25,072)/200,000 = 50,140/200,000 = 0.2507 = 25.07 cM Correct 74,866/200,000 = 74,866/200,000 = 0.3743 = 37.43 cM Incorrect 74,994/200,000 = 74,994/200,000 = 0.3750 = 37.50 cM Incorrect (25,072 + 74,866)/200,000 = 99,938/200,000 = 0.4997 = 49.97 cM Incorrect MC

268b_17c4

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Bumpy fly illustration. Gene B is analogous to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Xanthic fly illustration. Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
PhenotypeGenotypesProgeny
Count
 bumpy, xanthicbx8,720
 bumpyb+1,390
 xanthic+x1,340
 wildtype++8,550
TOTAL =20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

1,340/20,000 = 1,340/20,000 = 0.0670 = 6.70 cM Incorrect 1,390/20,000 = 1,390/20,000 = 0.0695 = 6.95 cM Incorrect (1,340 + 1,390)/20,000 = 2,730/20,000 = 0.1365 = 13.65 cM Correct 8,550/20,000 = 8,550/20,000 = 0.4275 = 42.75 cM Incorrect 8,720/20,000 = 8,720/20,000 = 0.4360 = 43.60 cM Incorrect (1,390 + 8,720)/20,000 = 10,110/20,000 = 0.5055 = 50.55 cM Incorrect MC

00fe_003b

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Mushy fly illustration. Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
PhenotypeGenotypesProgeny
Count
 horsey, mushyhm2,755
 horseyh+17,218
 mushy+m17,294
 wildtype++2,733
TOTAL =40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

2,733/40,000 = 2,733/40,000 = 0.0683 = 6.83 cM Incorrect 2,755/40,000 = 2,755/40,000 = 0.0689 = 6.89 cM Incorrect (2,733 + 2,755)/40,000 = 5,488/40,000 = 0.1372 = 13.72 cM Correct 17,218/40,000 = 17,218/40,000 = 0.4304 = 43.05 cM Incorrect 17,294/40,000 = 17,294/40,000 = 0.4324 = 43.23 cM Incorrect (2,733 + 17,294)/40,000 = 20,027/40,000 = 0.5007 = 50.07 cM Incorrect MC

60c5_d49b

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Tipsy fly illustration. Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Yucky fly illustration. Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.
PhenotypeGenotypesProgeny
Count
 tipsy, yuckyty51,664
 tipsyt+84,026
 yucky+y83,293
 wildtype++51,017
TOTAL =270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

51,017/270,000 = 51,017/270,000 = 0.1890 = 18.90 cM Incorrect 51,664/270,000 = 51,664/270,000 = 0.1913 = 19.13 cM Incorrect 83,293/270,000 = 83,293/270,000 = 0.3085 = 30.85 cM Incorrect 84,026/270,000 = 84,026/270,000 = 0.3112 = 31.12 cM Incorrect (51,017 + 51,664)/270,000 = 102,681/270,000 = 0.3803 = 38.03 cM Correct (51,664 + 83,293)/270,000 = 134,957/270,000 = 0.4998 = 49.98 cM Incorrect MC

ebda_aa0a

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Dewy fly illustration. Gene D is affiliated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Mushy fly illustration. Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
PhenotypeGenotypesProgeny
Count
 dewy, mushydm18,825
 dewyd+8,477
 mushy+m8,236
 wildtype++18,462
TOTAL =54,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

8,236/54,000 = 8,236/54,000 = 0.1525 = 15.25 cM Incorrect 8,477/54,000 = 8,477/54,000 = 0.1570 = 15.70 cM Incorrect (8,236 + 8,477)/54,000 = 16,713/54,000 = 0.3095 = 30.95 cM Correct 18,462/54,000 = 18,462/54,000 = 0.3419 = 34.19 cM Incorrect 18,825/54,000 = 18,825/54,000 = 0.3486 = 34.86 cM Incorrect (8,236 + 18,462)/54,000 = 26,698/54,000 = 0.4944 = 49.44 cM Incorrect MC

371e_56a0

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes
Horsey fly illustration. Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Prickly fly illustration. Gene P is connected with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
PhenotypeGenotypesProgeny
Count
 horsey, pricklyhp9,630
 horseyh+95,565
 prickly+p95,388
 wildtype++9,417
TOTAL =210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

9,417/210,000 = 9,417/210,000 = 0.0448 = 4.48 cM Incorrect 9,630/210,000 = 9,630/210,000 = 0.0459 = 4.59 cM Incorrect (9,417 + 9,630)/210,000 = 19,047/210,000 = 0.0907 = 9.07 cM Correct 95,388/210,000 = 95,388/210,000 = 0.4542 = 45.42 cM Incorrect 95,565/210,000 = 95,565/210,000 = 0.4551 = 45.51 cM Incorrect (9,417 + 95,565)/210,000 = 104,982/210,000 = 0.4999 = 49.99 cM Incorrect