de06_d9d3

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
nerdy, prickly	n	p	8,621
nerdy	n	+	25,011
prickly	+	p	25,128
wildtype	+	+	8,740
TOTAL =			67,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(25,011 + 25,128)}/_67,500 = ^50,139/_67,500 = 0.7428 = 74.28 cM Incorrect B. ^8,740/_67,500 = ^8,740/_67,500 = 0.1295 = 12.95 cM Incorrect C. ^8,621/_67,500 = ^8,621/_67,500 = 0.1277 = 12.77 cM Incorrect D. ^25,128/_67,500 = ^25,128/_67,500 = 0.3723 = 37.23 cM Incorrect E. ^{(8,621 + 8,740)}/_67,500 = ^17,361/_67,500 = 0.2572 = 25.72 cM Correct F. ^25,011/_67,500 = ^25,011/_67,500 = 0.3705 = 37.05 cM Incorrect MC

0b54_c59d

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is analogous to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
prickly, rusty	p	r	22,627
prickly	p	+	97,437
rusty	+	r	97,275
wildtype	+	+	22,661
TOTAL =			240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(97,275 + 97,437)}/_240,000 = ^194,712/_240,000 = 0.8113 = 81.13 cM Incorrect B. ^{(22,627 + 22,661)}/_240,000 = ^45,288/_240,000 = 0.1887 = 18.87 cM Correct C. ^22,627/_240,000 = ^22,627/_240,000 = 0.0943 = 9.43 cM Incorrect D. ^22,661/_240,000 = ^22,661/_240,000 = 0.0944 = 9.44 cM Incorrect E. ^97,437/_240,000 = ^97,437/_240,000 = 0.4060 = 40.60 cM Incorrect F. ^97,275/_240,000 = ^97,275/_240,000 = 0.4053 = 40.53 cM Incorrect MC

9b23_7596

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
kidney, nerdy	k	n	3,798
kidney	k	+	26,185
nerdy	+	n	26,231
wildtype	+	+	3,786
TOTAL =			60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^26,231/_60,000 = ^26,231/_60,000 = 0.4372 = 43.72 cM Incorrect B. ^{(3,786 + 3,798)}/_60,000 = ^7,584/_60,000 = 0.1264 = 12.64 cM Correct C. ^3,786/_60,000 = ^3,786/_60,000 = 0.0631 = 6.31 cM Incorrect D. ^26,185/_60,000 = ^26,185/_60,000 = 0.4364 = 43.64 cM Incorrect E. ^{(26,185 + 26,231)}/_60,000 = ^52,416/_60,000 = 0.8736 = 87.36 cM Incorrect F. ^3,798/_60,000 = ^3,798/_60,000 = 0.0633 = 6.33 cM Incorrect MC

b7ea_bc7e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes		Progeny Count
artsy, dewy	a	d	13,143
artsy	a	+	39,485
dewy	+	d	39,328
wildtype	+	+	13,044
TOTAL =			105,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^39,328/_105,000 = ^39,328/_105,000 = 0.3746 = 37.46 cM Incorrect B. ^{(39,328 + 39,485)}/_105,000 = ^78,813/_105,000 = 0.7506 = 75.06 cM Incorrect C. ^13,143/_105,000 = ^13,143/_105,000 = 0.1252 = 12.52 cM Incorrect D. ^13,044/_105,000 = ^13,044/_105,000 = 0.1242 = 12.42 cM Incorrect E. ^39,485/_105,000 = ^39,485/_105,000 = 0.3760 = 37.60 cM Incorrect F. ^{(13,044 + 13,143)}/_105,000 = ^26,187/_105,000 = 0.2494 = 24.94 cM Correct MC

d6a8_0da3

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene T is connected with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
chummy, tipsy	c	t	51,566
chummy	c	+	15,942
tipsy	+	t	15,891
wildtype	+	+	51,601
TOTAL =			135,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^15,942/_135,000 = ^15,942/_135,000 = 0.1181 = 11.81 cM Incorrect B. ^15,891/_135,000 = ^15,891/_135,000 = 0.1177 = 11.77 cM Incorrect C. ^{(51,566 + 51,601)}/_135,000 = ^103,167/_135,000 = 0.7642 = 76.42 cM Incorrect D. ^51,566/_135,000 = ^51,566/_135,000 = 0.3820 = 38.20 cM Incorrect E. ^51,601/_135,000 = ^51,601/_135,000 = 0.3822 = 38.22 cM Incorrect F. ^{(15,891 + 15,942)}/_135,000 = ^31,833/_135,000 = 0.2358 = 23.58 cM Correct MC

75df_3836

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is analogous to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
dewy, rusty	d	r	7,173
dewy	d	+	25,569
rusty	+	r	25,183
wildtype	+	+	7,075
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^7,075/_65,000 = ^7,075/_65,000 = 0.1088 = 10.88 cM Incorrect B. ^25,183/_65,000 = ^25,183/_65,000 = 0.3874 = 38.74 cM Incorrect C. ^{(7,075 + 7,173)}/_65,000 = ^14,248/_65,000 = 0.2192 = 21.92 cM Correct D. ^7,173/_65,000 = ^7,173/_65,000 = 0.1104 = 11.04 cM Incorrect E. ^{(25,183 + 25,569)}/_65,000 = ^50,752/_65,000 = 0.7808 = 78.08 cM Incorrect F. ^25,569/_65,000 = ^25,569/_65,000 = 0.3934 = 39.34 cM Incorrect MC

8a6e_3ea6

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene R is connected with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
jerky, rusty	j	r	53,968
jerky	j	+	5,852
rusty	+	r	5,980
wildtype	+	+	54,200
TOTAL =			120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^53,968/_120,000 = ^53,968/_120,000 = 0.4497 = 44.97 cM Incorrect B. ^54,200/_120,000 = ^54,200/_120,000 = 0.4517 = 45.17 cM Incorrect C. ^5,852/_120,000 = ^5,852/_120,000 = 0.0488 = 4.88 cM Incorrect D. ^{(53,968 + 54,200)}/_120,000 = ^108,168/_120,000 = 0.9014 = 90.14 cM Incorrect E. ^{(5,852 + 5,980)}/_120,000 = ^11,832/_120,000 = 0.0986 = 9.86 cM Correct F. ^5,980/_120,000 = ^5,980/_120,000 = 0.0498 = 4.98 cM Incorrect MC

470b_9615

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is associated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
bumpy, jerky	b	j	4,222
bumpy	b	+	23,347
jerky	+	j	23,205
wildtype	+	+	4,226
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(4,222 + 4,226)}/_55,000 = ^8,448/_55,000 = 0.1536 = 15.36 cM Correct B. ^4,222/_55,000 = ^4,222/_55,000 = 0.0768 = 7.68 cM Incorrect C. ^23,205/_55,000 = ^23,205/_55,000 = 0.4219 = 42.19 cM Incorrect D. ^23,347/_55,000 = ^23,347/_55,000 = 0.4245 = 42.45 cM Incorrect E. ^{(23,205 + 23,347)}/_55,000 = ^46,552/_55,000 = 0.8464 = 84.64 cM Incorrect F. ^4,226/_55,000 = ^4,226/_55,000 = 0.0768 = 7.68 cM Incorrect MC

d33c_382c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
rusty, yucky	r	y	10,323
rusty	r	+	89,890
yucky	+	y	89,570
wildtype	+	+	10,217
TOTAL =			200,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(89,570 + 89,890)}/_200,000 = ^179,460/_200,000 = 0.8973 = 89.73 cM Incorrect B. ^{(10,217 + 10,323)}/_200,000 = ^20,540/_200,000 = 0.1027 = 10.27 cM Correct C. ^89,890/_200,000 = ^89,890/_200,000 = 0.4495 = 44.95 cM Incorrect D. ^10,323/_200,000 = ^10,323/_200,000 = 0.0516 = 5.16 cM Incorrect E. ^89,570/_200,000 = ^89,570/_200,000 = 0.4479 = 44.79 cM Incorrect F. ^10,217/_200,000 = ^10,217/_200,000 = 0.0511 = 5.11 cM Incorrect MC

7755_f2da

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
dewy, horsey	d	h	17,676
dewy	d	+	8,717
horsey	+	h	8,587
wildtype	+	+	17,520
TOTAL =			52,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^8,587/_52,500 = ^8,587/_52,500 = 0.1636 = 16.36 cM Incorrect B. ^{(8,587 + 8,717)}/_52,500 = ^17,304/_52,500 = 0.3296 = 32.96 cM Correct C. ^17,676/_52,500 = ^17,676/_52,500 = 0.3367 = 33.67 cM Incorrect D. ^17,520/_52,500 = ^17,520/_52,500 = 0.3337 = 33.37 cM Incorrect E. ^{(17,520 + 17,676)}/_52,500 = ^35,196/_52,500 = 0.6704 = 67.04 cM Incorrect F. ^8,717/_52,500 = ^8,717/_52,500 = 0.1660 = 16.60 cM Incorrect MC

6f72_17dd

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
eery, rusty	e	r	24,097
eery	e	+	10,886
rusty	+	r	10,947
wildtype	+	+	24,070
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^10,947/_70,000 = ^10,947/_70,000 = 0.1564 = 15.64 cM Incorrect B. ^{(24,070 + 24,097)}/_70,000 = ^48,167/_70,000 = 0.6881 = 68.81 cM Incorrect C. ^24,070/_70,000 = ^24,070/_70,000 = 0.3439 = 34.39 cM Incorrect D. ^10,886/_70,000 = ^10,886/_70,000 = 0.1555 = 15.55 cM Incorrect E. ^24,097/_70,000 = ^24,097/_70,000 = 0.3442 = 34.42 cM Incorrect F. ^{(10,886 + 10,947)}/_70,000 = ^21,833/_70,000 = 0.3119 = 31.19 cM Correct MC

1c9f_d5da

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
eery, yucky	e	y	6,355
eery	e	+	1,768
yucky	+	y	1,680
wildtype	+	+	6,197
TOTAL =			16,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^1,680/_16,000 = ^1,680/_16,000 = 0.1050 = 10.50 cM Incorrect B. ^6,197/_16,000 = ^6,197/_16,000 = 0.3873 = 38.73 cM Incorrect C. ^{(6,197 + 6,355)}/_16,000 = ^12,552/_16,000 = 0.7845 = 78.45 cM Incorrect D. ^1,768/_16,000 = ^1,768/_16,000 = 0.1105 = 11.05 cM Incorrect E. ^{(1,680 + 1,768)}/_16,000 = ^3,448/_16,000 = 0.2155 = 21.55 cM Correct F. ^6,355/_16,000 = ^6,355/_16,000 = 0.3972 = 39.72 cM Incorrect MC

2307_3a18

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene B is connected with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.

Phenotype	Genotypes		Progeny Count
artsy, bumpy	a	b	14,676
artsy	a	+	35,528
bumpy	+	b	35,252
wildtype	+	+	14,544
TOTAL =			100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^35,252/_100,000 = ^35,252/_100,000 = 0.3525 = 35.25 cM Incorrect B. ^{(14,544 + 14,676)}/_100,000 = ^29,220/_100,000 = 0.2922 = 29.22 cM Correct C. ^35,528/_100,000 = ^35,528/_100,000 = 0.3553 = 35.53 cM Incorrect D. ^14,544/_100,000 = ^14,544/_100,000 = 0.1454 = 14.54 cM Incorrect E. ^{(35,252 + 35,528)}/_100,000 = ^70,780/_100,000 = 0.7078 = 70.78 cM Incorrect F. ^14,676/_100,000 = ^14,676/_100,000 = 0.1468 = 14.68 cM Incorrect MC

6126_0870

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene P is connected with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
eery, prickly	e	p	3,375
eery	e	+	924
prickly	+	p	929
wildtype	+	+	3,272
TOTAL =			8,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ⁹²⁹/_8,500 = ⁹²⁹/_8,500 = 0.1093 = 10.93 cM Incorrect B. ^{(924 + 929)}/_8,500 = ^1,853/_8,500 = 0.2180 = 21.80 cM Correct C. ^{(3,272 + 3,375)}/_8,500 = ^6,647/_8,500 = 0.7820 = 78.20 cM Incorrect D. ⁹²⁴/_8,500 = ⁹²⁴/_8,500 = 0.1087 = 10.87 cM Incorrect E. ^3,272/_8,500 = ^3,272/_8,500 = 0.3849 = 38.49 cM Incorrect F. ^3,375/_8,500 = ^3,375/_8,500 = 0.3971 = 39.71 cM Incorrect MC

51eb_1769

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
mushy, xanthic	m	x	106,139
mushy	m	+	14,295
xanthic	+	x	14,097
wildtype	+	+	105,469
TOTAL =			240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^106,139/_240,000 = ^106,139/_240,000 = 0.4422 = 44.22 cM Incorrect B. ^14,295/_240,000 = ^14,295/_240,000 = 0.0596 = 5.96 cM Incorrect C. ^{(14,097 + 14,295)}/_240,000 = ^28,392/_240,000 = 0.1183 = 11.83 cM Correct D. ^14,097/_240,000 = ^14,097/_240,000 = 0.0587 = 5.87 cM Incorrect E. ^{(105,469 + 106,139)}/_240,000 = ^211,608/_240,000 = 0.8817 = 88.17 cM Incorrect F. ^105,469/_240,000 = ^105,469/_240,000 = 0.4395 = 43.95 cM Incorrect MC

9967_5f91

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is correlated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene P is analogous to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
artsy, prickly	a	p	48,429
artsy	a	+	16,685
prickly	+	p	16,777
wildtype	+	+	48,109
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^48,109/_130,000 = ^48,109/_130,000 = 0.3701 = 37.01 cM Incorrect B. ^{(48,109 + 48,429)}/_130,000 = ^96,538/_130,000 = 0.7426 = 74.26 cM Incorrect C. ^{(16,685 + 16,777)}/_130,000 = ^33,462/_130,000 = 0.2574 = 25.74 cM Correct D. ^16,777/_130,000 = ^16,777/_130,000 = 0.1291 = 12.91 cM Incorrect E. ^48,429/_130,000 = ^48,429/_130,000 = 0.3725 = 37.25 cM Incorrect F. ^16,685/_130,000 = ^16,685/_130,000 = 0.1283 = 12.83 cM Incorrect MC

315e_af4b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
artsy, horsey	a	h	922
artsy	a	+	201
horsey	+	h	236
wildtype	+	+	941
TOTAL =			2,300

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(201 + 236)}/_2,300 = ⁴³⁷/_2,300 = 0.1900 = 19.00 cM Correct B. ^{(201 + 922)}/_2,300 = ^1,123/_2,300 = 0.4883 = 48.83 cM Incorrect C. ⁹⁴¹/_2,300 = ⁹⁴¹/_2,300 = 0.4091 = 40.91 cM Incorrect D. ⁹²²/_2,300 = ⁹²²/_2,300 = 0.4009 = 40.09 cM Incorrect E. ^{(922 + 941)}/_2,300 = ^1,863/_2,300 = 0.8100 = 81.00 cM Incorrect F. ²³⁶/_2,300 = ²³⁶/_2,300 = 0.1026 = 10.26 cM Incorrect MC

8d12_c580

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
waxy, yucky	w	y	2,179
waxy	w	+	573
yucky	+	y	549
wildtype	+	+	2,199
TOTAL =			5,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^2,179/_5,500 = ^2,179/_5,500 = 0.3962 = 39.62 cM Incorrect B. ⁵⁴⁹/_5,500 = ⁵⁴⁹/_5,500 = 0.0998 = 9.98 cM Incorrect C. ^{(549 + 573)}/_5,500 = ^1,122/_5,500 = 0.2040 = 20.40 cM Correct D. ⁵⁷³/_5,500 = ⁵⁷³/_5,500 = 0.1042 = 10.42 cM Incorrect E. ^2,199/_5,500 = ^2,199/_5,500 = 0.3998 = 39.98 cM Incorrect F. ^{(2,179 + 2,199)}/_5,500 = ^4,378/_5,500 = 0.7960 = 79.60 cM Incorrect MC

bfbe_bb35

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene X is analogous to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
nerdy, xanthic	n	x	10,483
nerdy	n	+	18,231
xanthic	+	x	18,270
wildtype	+	+	10,516
TOTAL =			57,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(10,483 + 10,516)}/_57,500 = ^20,999/_57,500 = 0.3652 = 36.52 cM Correct B. ^{(18,231 + 18,270)}/_57,500 = ^36,501/_57,500 = 0.6348 = 63.48 cM Incorrect C. ^18,270/_57,500 = ^18,270/_57,500 = 0.3177 = 31.77 cM Incorrect D. ^10,516/_57,500 = ^10,516/_57,500 = 0.1829 = 18.29 cM Incorrect E. ^18,231/_57,500 = ^18,231/_57,500 = 0.3171 = 31.71 cM Incorrect F. ^10,483/_57,500 = ^10,483/_57,500 = 0.1823 = 18.23 cM Incorrect MC

1bb6_7522

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
eery, yucky	e	y	74,745
eery	e	+	30,434
yucky	+	y	30,907
wildtype	+	+	73,914
TOTAL =			210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^30,907/_210,000 = ^30,907/_210,000 = 0.1472 = 14.72 cM Incorrect B. ^{(73,914 + 74,745)}/_210,000 = ^148,659/_210,000 = 0.7079 = 70.79 cM Incorrect C. ^73,914/_210,000 = ^73,914/_210,000 = 0.3520 = 35.20 cM Incorrect D. ^74,745/_210,000 = ^74,745/_210,000 = 0.3559 = 35.59 cM Incorrect E. ^30,434/_210,000 = ^30,434/_210,000 = 0.1449 = 14.49 cM Incorrect F. ^{(30,434 + 30,907)}/_210,000 = ^61,341/_210,000 = 0.2921 = 29.21 cM Correct MC

b062_11db

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is connected with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes		Progeny Count
bumpy, dewy	b	d	887
bumpy	b	+	1,811
dewy	+	d	1,780
wildtype	+	+	922
TOTAL =			5,400

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ⁹²²/_5,400 = ⁹²²/_5,400 = 0.1707 = 17.07 cM Incorrect B. ^1,780/_5,400 = ^1,780/_5,400 = 0.3296 = 32.96 cM Incorrect C. ^1,811/_5,400 = ^1,811/_5,400 = 0.3354 = 33.54 cM Incorrect D. ^{(887 + 922)}/_5,400 = ^1,809/_5,400 = 0.3350 = 33.50 cM Correct E. ^{(1,780 + 1,811)}/_5,400 = ^3,591/_5,400 = 0.6650 = 66.50 cM Incorrect F. ⁸⁸⁷/_5,400 = ⁸⁸⁷/_5,400 = 0.1643 = 16.43 cM Incorrect MC

9f14_6a30

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene R is connected with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
kidney, rusty	k	r	6,321
kidney	k	+	14,669
rusty	+	r	14,668
wildtype	+	+	6,342
TOTAL =			42,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^14,668/_42,000 = ^14,668/_42,000 = 0.3492 = 34.92 cM Incorrect B. ^14,669/_42,000 = ^14,669/_42,000 = 0.3493 = 34.93 cM Incorrect C. ^{(14,668 + 14,669)}/_42,000 = ^29,337/_42,000 = 0.6985 = 69.85 cM Incorrect D. ^6,342/_42,000 = ^6,342/_42,000 = 0.1510 = 15.10 cM Incorrect E. ^{(6,321 + 6,342)}/_42,000 = ^12,663/_42,000 = 0.3015 = 30.15 cM Correct F. ^6,321/_42,000 = ^6,321/_42,000 = 0.1505 = 15.05 cM Incorrect MC

7e20_943a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
eery, fuzzy	e	f	6,140
eery	e	+	3,744
fuzzy	+	f	3,786
wildtype	+	+	6,330
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^6,330/_20,000 = ^6,330/_20,000 = 0.3165 = 31.65 cM Incorrect B. ^3,744/_20,000 = ^3,744/_20,000 = 0.1872 = 18.72 cM Incorrect C. ^{(3,744 + 3,786)}/_20,000 = ^7,530/_20,000 = 0.3765 = 37.65 cM Correct D. ^6,140/_20,000 = ^6,140/_20,000 = 0.3070 = 30.70 cM Incorrect E. ^3,786/_20,000 = ^3,786/_20,000 = 0.1893 = 18.93 cM Incorrect F. ^{(6,140 + 6,330)}/_20,000 = ^12,470/_20,000 = 0.6235 = 62.35 cM Incorrect MC

29b6_7e8b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
artsy, eery	a	e	1,107
artsy	a	+	7,987
eery	+	e	7,772
wildtype	+	+	1,134
TOTAL =			18,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^1,107/_18,000 = ^1,107/_18,000 = 0.0615 = 6.15 cM Incorrect B. ^7,772/_18,000 = ^7,772/_18,000 = 0.4318 = 43.18 cM Incorrect C. ^{(1,107 + 1,134)}/_18,000 = ^2,241/_18,000 = 0.1245 = 12.45 cM Correct D. ^{(7,772 + 7,987)}/_18,000 = ^15,759/_18,000 = 0.8755 = 87.55 cM Incorrect E. ^1,134/_18,000 = ^1,134/_18,000 = 0.0630 = 6.30 cM Incorrect F. ^7,987/_18,000 = ^7,987/_18,000 = 0.4437 = 44.37 cM Incorrect MC

d89d_0290

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is associated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene F is affiliated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
artsy, fuzzy	a	f	7,251
artsy	a	+	17,719
fuzzy	+	f	17,871
wildtype	+	+	7,159
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^7,159/_50,000 = ^7,159/_50,000 = 0.1432 = 14.32 cM Incorrect B. ^7,251/_50,000 = ^7,251/_50,000 = 0.1450 = 14.50 cM Incorrect C. ^{(7,159 + 7,251)}/_50,000 = ^14,410/_50,000 = 0.2882 = 28.82 cM Correct D. ^{(17,719 + 17,871)}/_50,000 = ^35,590/_50,000 = 0.7118 = 71.18 cM Incorrect E. ^17,871/_50,000 = ^17,871/_50,000 = 0.3574 = 35.74 cM Incorrect F. ^17,719/_50,000 = ^17,719/_50,000 = 0.3544 = 35.44 cM Incorrect MC

2abc_7b5c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
kidney, waxy	k	w	8,672
kidney	k	+	21,620
waxy	+	w	21,328
wildtype	+	+	8,380
TOTAL =			60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^8,672/_60,000 = ^8,672/_60,000 = 0.1445 = 14.45 cM Incorrect B. ^21,620/_60,000 = ^21,620/_60,000 = 0.3603 = 36.03 cM Incorrect C. ^{(8,380 + 8,672)}/_60,000 = ^17,052/_60,000 = 0.2842 = 28.42 cM Correct D. ^{(21,328 + 21,620)}/_60,000 = ^42,948/_60,000 = 0.7158 = 71.58 cM Incorrect E. ^21,328/_60,000 = ^21,328/_60,000 = 0.3555 = 35.55 cM Incorrect F. ^8,380/_60,000 = ^8,380/_60,000 = 0.1397 = 13.97 cM Incorrect MC

7a39_7639

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
dewy, eery	d	e	8,954
dewy	d	+	3,600
eery	+	e	3,575
wildtype	+	+	8,871
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(8,871 + 8,954)}/_25,000 = ^17,825/_25,000 = 0.7130 = 71.30 cM Incorrect B. ^3,600/_25,000 = ^3,600/_25,000 = 0.1440 = 14.40 cM Incorrect C. ^8,871/_25,000 = ^8,871/_25,000 = 0.3548 = 35.48 cM Incorrect D. ^{(3,575 + 3,600)}/_25,000 = ^7,175/_25,000 = 0.2870 = 28.70 cM Correct E. ^3,575/_25,000 = ^3,575/_25,000 = 0.1430 = 14.30 cM Incorrect F. ^8,954/_25,000 = ^8,954/_25,000 = 0.3582 = 35.82 cM Incorrect MC

bd34_f89b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
tipsy, yucky	t	y	71,831
tipsy	t	+	18,517
yucky	+	y	18,365
wildtype	+	+	71,287
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^71,287/_180,000 = ^71,287/_180,000 = 0.3960 = 39.60 cM Incorrect B. ^71,831/_180,000 = ^71,831/_180,000 = 0.3991 = 39.91 cM Incorrect C. ^18,365/_180,000 = ^18,365/_180,000 = 0.1020 = 10.20 cM Incorrect D. ^{(71,287 + 71,831)}/_180,000 = ^143,118/_180,000 = 0.7951 = 79.51 cM Incorrect E. ^18,517/_180,000 = ^18,517/_180,000 = 0.1029 = 10.29 cM Incorrect F. ^{(18,365 + 18,517)}/_180,000 = ^36,882/_180,000 = 0.2049 = 20.49 cM Correct MC

2805_ebb7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
eery, nerdy	e	n	10,531
eery	e	+	18,512
nerdy	+	n	18,579
wildtype	+	+	10,378
TOTAL =			58,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(10,378 + 10,531)}/_58,000 = ^20,909/_58,000 = 0.3605 = 36.05 cM Correct B. ^{(18,512 + 18,579)}/_58,000 = ^37,091/_58,000 = 0.6395 = 63.95 cM Incorrect C. ^10,378/_58,000 = ^10,378/_58,000 = 0.1789 = 17.89 cM Incorrect D. ^18,579/_58,000 = ^18,579/_58,000 = 0.3203 = 32.03 cM Incorrect E. ^10,531/_58,000 = ^10,531/_58,000 = 0.1816 = 18.16 cM Incorrect F. ^18,512/_58,000 = ^18,512/_58,000 = 0.3192 = 31.92 cM Incorrect MC

d76e_6c0b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is linked with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
bumpy, tipsy	b	t	9,517
bumpy	b	+	2,928
tipsy	+	t	2,967
wildtype	+	+	9,588
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(9,517 + 9,588)}/_25,000 = ^19,105/_25,000 = 0.7642 = 76.42 cM Incorrect B. ^9,517/_25,000 = ^9,517/_25,000 = 0.3807 = 38.07 cM Incorrect C. ^{(2,928 + 2,967)}/_25,000 = ^5,895/_25,000 = 0.2358 = 23.58 cM Correct D. ^2,928/_25,000 = ^2,928/_25,000 = 0.1171 = 11.71 cM Incorrect E. ^9,588/_25,000 = ^9,588/_25,000 = 0.3835 = 38.35 cM Incorrect F. ^2,967/_25,000 = ^2,967/_25,000 = 0.1187 = 11.87 cM Incorrect MC

bdfa_3325

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
dewy, horsey	d	h	394
dewy	d	+	1,130
horsey	+	h	1,123
wildtype	+	+	353
TOTAL =			3,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(353 + 394)}/_3,000 = ⁷⁴⁷/_3,000 = 0.2490 = 24.90 cM Correct B. ^1,123/_3,000 = ^1,123/_3,000 = 0.3743 = 37.43 cM Incorrect C. ^{(1,123 + 1,130)}/_3,000 = ^2,253/_3,000 = 0.7510 = 75.10 cM Incorrect D. ^1,130/_3,000 = ^1,130/_3,000 = 0.3767 = 37.67 cM Incorrect E. ³⁵³/_3,000 = ³⁵³/_3,000 = 0.1177 = 11.77 cM Incorrect F. ³⁹⁴/_3,000 = ³⁹⁴/_3,000 = 0.1313 = 13.13 cM Incorrect MC

7845_7c53

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
nerdy, waxy	n	w	45,935
nerdy	n	+	11,576
waxy	+	w	11,585
wildtype	+	+	45,904
TOTAL =			115,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^11,585/_115,000 = ^11,585/_115,000 = 0.1007 = 10.07 cM Incorrect B. ^45,935/_115,000 = ^45,935/_115,000 = 0.3994 = 39.94 cM Incorrect C. ^{(45,904 + 45,935)}/_115,000 = ^91,839/_115,000 = 0.7986 = 79.86 cM Incorrect D. ^{(11,576 + 11,585)}/_115,000 = ^23,161/_115,000 = 0.2014 = 20.14 cM Correct E. ^45,904/_115,000 = ^45,904/_115,000 = 0.3992 = 39.92 cM Incorrect F. ^11,576/_115,000 = ^11,576/_115,000 = 0.1007 = 10.07 cM Incorrect MC

66d8_dd13

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
artsy, waxy	a	w	4,979
artsy	a	+	19,920
waxy	+	w	20,050
wildtype	+	+	5,051
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^4,979/_50,000 = ^4,979/_50,000 = 0.0996 = 9.96 cM Incorrect B. ^19,920/_50,000 = ^19,920/_50,000 = 0.3984 = 39.84 cM Incorrect C. ^{(4,979 + 5,051)}/_50,000 = ^10,030/_50,000 = 0.2006 = 20.06 cM Correct D. ^5,051/_50,000 = ^5,051/_50,000 = 0.1010 = 10.10 cM Incorrect E. ^{(19,920 + 20,050)}/_50,000 = ^39,970/_50,000 = 0.7994 = 79.94 cM Incorrect F. ^20,050/_50,000 = ^20,050/_50,000 = 0.4010 = 40.10 cM Incorrect MC

0b58_05e2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
artsy, eery	a	e	38,963
artsy	a	+	105,592
eery	+	e	106,427
wildtype	+	+	39,018
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^39,018/_290,000 = ^39,018/_290,000 = 0.1345 = 13.45 cM Incorrect B. ^38,963/_290,000 = ^38,963/_290,000 = 0.1344 = 13.44 cM Incorrect C. ^{(38,963 + 39,018)}/_290,000 = ^77,981/_290,000 = 0.2689 = 26.89 cM Correct D. ^106,427/_290,000 = ^106,427/_290,000 = 0.3670 = 36.70 cM Incorrect E. ^105,592/_290,000 = ^105,592/_290,000 = 0.3641 = 36.41 cM Incorrect F. ^{(105,592 + 106,427)}/_290,000 = ^212,019/_290,000 = 0.7311 = 73.11 cM Incorrect MC

aa2d_b5da

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
dewy, kidney	d	k	2,091
dewy	d	+	441
kidney	+	k	394
wildtype	+	+	2,074
TOTAL =			5,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(2,074 + 2,091)}/_5,000 = ^4,165/_5,000 = 0.8330 = 83.30 cM Incorrect B. ^2,074/_5,000 = ^2,074/_5,000 = 0.4148 = 41.48 cM Incorrect C. ⁴⁴¹/_5,000 = ⁴⁴¹/_5,000 = 0.0882 = 8.82 cM Incorrect D. ³⁹⁴/_5,000 = ³⁹⁴/_5,000 = 0.0788 = 7.88 cM Incorrect E. ^2,091/_5,000 = ^2,091/_5,000 = 0.4182 = 41.82 cM Incorrect F. ^{(394 + 441)}/_5,000 = ⁸³⁵/_5,000 = 0.1670 = 16.70 cM Correct MC

712d_e5e3

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
eery, tipsy	e	t	3,998
eery	e	+	28,369
tipsy	+	t	28,519
wildtype	+	+	4,114
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(3,998 + 4,114)}/_65,000 = ^8,112/_65,000 = 0.1248 = 12.48 cM Correct B. ^28,519/_65,000 = ^28,519/_65,000 = 0.4388 = 43.88 cM Incorrect C. ^3,998/_65,000 = ^3,998/_65,000 = 0.0615 = 6.15 cM Incorrect D. ^4,114/_65,000 = ^4,114/_65,000 = 0.0633 = 6.33 cM Incorrect E. ^28,369/_65,000 = ^28,369/_65,000 = 0.4364 = 43.64 cM Incorrect F. ^{(28,369 + 28,519)}/_65,000 = ^56,888/_65,000 = 0.8752 = 87.52 cM Incorrect MC

569b_c91a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
horsey, kidney	h	k	18,155
horsey	h	+	46,744
kidney	+	k	46,999
wildtype	+	+	18,102
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^18,155/_130,000 = ^18,155/_130,000 = 0.1397 = 13.97 cM Incorrect B. ^46,744/_130,000 = ^46,744/_130,000 = 0.3596 = 35.96 cM Incorrect C. ^{(46,744 + 46,999)}/_130,000 = ^93,743/_130,000 = 0.7211 = 72.11 cM Incorrect D. ^18,102/_130,000 = ^18,102/_130,000 = 0.1392 = 13.92 cM Incorrect E. ^{(18,102 + 18,155)}/_130,000 = ^36,257/_130,000 = 0.2789 = 27.89 cM Correct F. ^46,999/_130,000 = ^46,999/_130,000 = 0.3615 = 36.15 cM Incorrect MC

9136_9967

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
artsy, prickly	a	p	20,519
artsy	a	+	49,589
prickly	+	p	49,405
wildtype	+	+	20,487
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(49,405 + 49,589)}/_140,000 = ^98,994/_140,000 = 0.7071 = 70.71 cM Incorrect B. ^20,487/_140,000 = ^20,487/_140,000 = 0.1463 = 14.63 cM Incorrect C. ^49,405/_140,000 = ^49,405/_140,000 = 0.3529 = 35.29 cM Incorrect D. ^20,519/_140,000 = ^20,519/_140,000 = 0.1466 = 14.66 cM Incorrect E. ^{(20,487 + 20,519)}/_140,000 = ^41,006/_140,000 = 0.2929 = 29.29 cM Correct F. ^49,589/_140,000 = ^49,589/_140,000 = 0.3542 = 35.42 cM Incorrect MC

04b4_7222

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
eery, xanthic	e	x	13,685
eery	e	+	101,607
xanthic	+	x	100,862
wildtype	+	+	13,846
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^100,862/_230,000 = ^100,862/_230,000 = 0.4385 = 43.85 cM Incorrect B. ^{(100,862 + 101,607)}/_230,000 = ^202,469/_230,000 = 0.8803 = 88.03 cM Incorrect C. ^{(13,685 + 13,846)}/_230,000 = ^27,531/_230,000 = 0.1197 = 11.97 cM Correct D. ^13,685/_230,000 = ^13,685/_230,000 = 0.0595 = 5.95 cM Incorrect E. ^101,607/_230,000 = ^101,607/_230,000 = 0.4418 = 44.18 cM Incorrect F. ^13,846/_230,000 = ^13,846/_230,000 = 0.0602 = 6.02 cM Incorrect MC

a141_c60b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
eery, fuzzy	e	f	59,154
eery	e	+	25,921
fuzzy	+	f	25,470
wildtype	+	+	59,455
TOTAL =			170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(25,470 + 25,921)}/_170,000 = ^51,391/_170,000 = 0.3023 = 30.23 cM Correct B. ^59,154/_170,000 = ^59,154/_170,000 = 0.3480 = 34.80 cM Incorrect C. ^25,470/_170,000 = ^25,470/_170,000 = 0.1498 = 14.98 cM Incorrect D. ^{(59,154 + 59,455)}/_170,000 = ^118,609/_170,000 = 0.6977 = 69.77 cM Incorrect E. ^25,921/_170,000 = ^25,921/_170,000 = 0.1525 = 15.25 cM Incorrect F. ^59,455/_170,000 = ^59,455/_170,000 = 0.3497 = 34.97 cM Incorrect MC

221f_3715

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
bumpy, horsey	b	h	16,215
bumpy	b	+	1,917
horsey	+	h	1,845
wildtype	+	+	16,023
TOTAL =			36,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(1,845 + 1,917)}/_36,000 = ^3,762/_36,000 = 0.1045 = 10.45 cM Correct B. ^16,023/_36,000 = ^16,023/_36,000 = 0.4451 = 44.51 cM Incorrect C. ^1,917/_36,000 = ^1,917/_36,000 = 0.0532 = 5.33 cM Incorrect D. ^16,215/_36,000 = ^16,215/_36,000 = 0.4504 = 45.04 cM Incorrect E. ^1,845/_36,000 = ^1,845/_36,000 = 0.0512 = 5.12 cM Incorrect F. ^{(16,023 + 16,215)}/_36,000 = ^32,238/_36,000 = 0.8955 = 89.55 cM Incorrect MC

aebf_a07b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
kidney, yucky	k	y	19,760
kidney	k	+	4,187
yucky	+	y	4,237
wildtype	+	+	19,816
TOTAL =			48,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^4,237/_48,000 = ^4,237/_48,000 = 0.0883 = 8.83 cM Incorrect B. ^{(4,187 + 4,237)}/_48,000 = ^8,424/_48,000 = 0.1755 = 17.55 cM Correct C. ^4,187/_48,000 = ^4,187/_48,000 = 0.0872 = 8.72 cM Incorrect D. ^19,760/_48,000 = ^19,760/_48,000 = 0.4117 = 41.17 cM Incorrect E. ^{(19,760 + 19,816)}/_48,000 = ^39,576/_48,000 = 0.8245 = 82.45 cM Incorrect F. ^19,816/_48,000 = ^19,816/_48,000 = 0.4128 = 41.28 cM Incorrect MC

54e6_e11e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
artsy, mushy	a	m	8,455
artsy	a	+	1,512
mushy	+	m	1,512
wildtype	+	+	8,521
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^8,521/_20,000 = ^8,521/_20,000 = 0.4260 = 42.60 cM Incorrect B. ^{(8,455 + 8,521)}/_20,000 = ^16,976/_20,000 = 0.8488 = 84.88 cM Incorrect C. ^{(1,512 + 1,512)}/_20,000 = ^3,024/_20,000 = 0.1512 = 15.12 cM Correct D. ^1,512/_20,000 = ^1,512/_20,000 = 0.0756 = 7.56 cM Incorrect E. ^8,455/_20,000 = ^8,455/_20,000 = 0.4228 = 42.27 cM Incorrect MC

15d4_d990

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
chummy, nerdy	c	n	5,698
chummy	c	+	14,288
nerdy	+	n	14,476
wildtype	+	+	5,538
TOTAL =			40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^5,698/_40,000 = ^5,698/_40,000 = 0.1424 = 14.24 cM Incorrect B. ^14,476/_40,000 = ^14,476/_40,000 = 0.3619 = 36.19 cM Incorrect C. ^5,538/_40,000 = ^5,538/_40,000 = 0.1384 = 13.84 cM Incorrect D. ^{(14,288 + 14,476)}/_40,000 = ^28,764/_40,000 = 0.7191 = 71.91 cM Incorrect E. ^{(5,538 + 5,698)}/_40,000 = ^11,236/_40,000 = 0.2809 = 28.09 cM Correct F. ^14,288/_40,000 = ^14,288/_40,000 = 0.3572 = 35.72 cM Incorrect MC

8e12_6734

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
fuzzy, yucky	f	y	34,980
fuzzy	f	+	5,213
yucky	+	y	5,235
wildtype	+	+	34,572
TOTAL =			80,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^34,572/_80,000 = ^34,572/_80,000 = 0.4321 = 43.21 cM Incorrect B. ^{(5,213 + 5,235)}/_80,000 = ^10,448/_80,000 = 0.1306 = 13.06 cM Correct C. ^{(34,572 + 34,980)}/_80,000 = ^69,552/_80,000 = 0.8694 = 86.94 cM Incorrect D. ^34,980/_80,000 = ^34,980/_80,000 = 0.4373 = 43.73 cM Incorrect E. ^5,235/_80,000 = ^5,235/_80,000 = 0.0654 = 6.54 cM Incorrect F. ^5,213/_80,000 = ^5,213/_80,000 = 0.0652 = 6.52 cM Incorrect MC

6386_ac11

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
kidney, nerdy	k	n	8,391
kidney	k	+	4,059
nerdy	+	n	3,881
wildtype	+	+	8,669
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^8,669/_25,000 = ^8,669/_25,000 = 0.3468 = 34.68 cM Incorrect B. ^3,881/_25,000 = ^3,881/_25,000 = 0.1552 = 15.52 cM Incorrect C. ^4,059/_25,000 = ^4,059/_25,000 = 0.1624 = 16.24 cM Incorrect D. ^8,391/_25,000 = ^8,391/_25,000 = 0.3356 = 33.56 cM Incorrect E. ^{(8,391 + 8,669)}/_25,000 = ^17,060/_25,000 = 0.6824 = 68.24 cM Incorrect F. ^{(3,881 + 4,059)}/_25,000 = ^7,940/_25,000 = 0.3176 = 31.76 cM Correct MC

59bd_b241

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is related to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
kidney, nerdy	k	n	489
kidney	k	+	1,001
nerdy	+	n	1,006
wildtype	+	+	504
TOTAL =			3,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ⁴⁸⁹/_3,000 = ⁴⁸⁹/_3,000 = 0.1630 = 16.30 cM Incorrect B. ^{(1,001 + 1,006)}/_3,000 = ^2,007/_3,000 = 0.6690 = 66.90 cM Incorrect C. ⁵⁰⁴/_3,000 = ⁵⁰⁴/_3,000 = 0.1680 = 16.80 cM Incorrect D. ^1,001/_3,000 = ^1,001/_3,000 = 0.3337 = 33.37 cM Incorrect E. ^1,006/_3,000 = ^1,006/_3,000 = 0.3353 = 33.53 cM Incorrect F. ^{(489 + 504)}/_3,000 = ⁹⁹³/_3,000 = 0.3310 = 33.10 cM Correct MC

a30c_8d6f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
dewy, fuzzy	d	f	3,713
dewy	d	+	442
fuzzy	+	f	419
wildtype	+	+	3,826
TOTAL =			8,400

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ⁴⁴²/_8,400 = ⁴⁴²/_8,400 = 0.0526 = 5.26 cM Incorrect B. ^{(419 + 442)}/_8,400 = ⁸⁶¹/_8,400 = 0.1025 = 10.25 cM Correct C. ^3,826/_8,400 = ^3,826/_8,400 = 0.4555 = 45.55 cM Incorrect D. ^{(3,713 + 3,826)}/_8,400 = ^7,539/_8,400 = 0.8975 = 89.75 cM Incorrect E. ^3,713/_8,400 = ^3,713/_8,400 = 0.4420 = 44.20 cM Incorrect F. ⁴¹⁹/_8,400 = ⁴¹⁹/_8,400 = 0.0499 = 4.99 cM Incorrect MC

5a28_e806

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
horsey, prickly	h	p	81,771
horsey	h	+	43,525
prickly	+	p	43,450
wildtype	+	+	81,254
TOTAL =			250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(43,450 + 43,525)}/_250,000 = ^86,975/_250,000 = 0.3479 = 34.79 cM Correct B. ^81,771/_250,000 = ^81,771/_250,000 = 0.3271 = 32.71 cM Incorrect C. ^43,450/_250,000 = ^43,450/_250,000 = 0.1738 = 17.38 cM Incorrect D. ^{(81,254 + 81,771)}/_250,000 = ^163,025/_250,000 = 0.6521 = 65.21 cM Incorrect E. ^81,254/_250,000 = ^81,254/_250,000 = 0.3250 = 32.50 cM Incorrect F. ^43,525/_250,000 = ^43,525/_250,000 = 0.1741 = 17.41 cM Incorrect MC

0e45_4c8f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
horsey, rusty	h	r	14,179
horsey	h	+	5,929
rusty	+	r	5,819
wildtype	+	+	14,073
TOTAL =			40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^5,929/_40,000 = ^5,929/_40,000 = 0.1482 = 14.82 cM Incorrect B. ^5,819/_40,000 = ^5,819/_40,000 = 0.1455 = 14.55 cM Incorrect C. ^{(14,073 + 14,179)}/_40,000 = ^28,252/_40,000 = 0.7063 = 70.63 cM Incorrect D. ^{(5,819 + 5,929)}/_40,000 = ^11,748/_40,000 = 0.2937 = 29.37 cM Correct E. ^14,073/_40,000 = ^14,073/_40,000 = 0.3518 = 35.18 cM Incorrect F. ^14,179/_40,000 = ^14,179/_40,000 = 0.3545 = 35.45 cM Incorrect MC

1fe6_d2b1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is associated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
chummy, yucky	c	y	12,215
chummy	c	+	1,578
yucky	+	y	1,513
wildtype	+	+	12,194
TOTAL =			27,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^1,513/_27,500 = ^1,513/_27,500 = 0.0550 = 5.50 cM Incorrect B. ^{(1,513 + 1,578)}/_27,500 = ^3,091/_27,500 = 0.1124 = 11.24 cM Correct C. ^1,578/_27,500 = ^1,578/_27,500 = 0.0574 = 5.74 cM Incorrect D. ^{(12,194 + 12,215)}/_27,500 = ^24,409/_27,500 = 0.8876 = 88.76 cM Incorrect E. ^12,215/_27,500 = ^12,215/_27,500 = 0.4442 = 44.42 cM Incorrect F. ^12,194/_27,500 = ^12,194/_27,500 = 0.4434 = 44.34 cM Incorrect MC

d0db_7425

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
artsy, chummy	a	c	11,716
artsy	a	+	53,630
chummy	+	c	52,931
wildtype	+	+	11,723
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(11,716 + 11,723)}/_130,000 = ^23,439/_130,000 = 0.1803 = 18.03 cM Correct B. ^11,716/_130,000 = ^11,716/_130,000 = 0.0901 = 9.01 cM Incorrect C. ^{(52,931 + 53,630)}/_130,000 = ^106,561/_130,000 = 0.8197 = 81.97 cM Incorrect D. ^52,931/_130,000 = ^52,931/_130,000 = 0.4072 = 40.72 cM Incorrect E. ^11,723/_130,000 = ^11,723/_130,000 = 0.0902 = 9.02 cM Incorrect F. ^53,630/_130,000 = ^53,630/_130,000 = 0.4125 = 41.25 cM Incorrect MC

57d2_fadb

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
eery, prickly	e	p	3,874
eery	e	+	23,437
prickly	+	p	23,797
wildtype	+	+	3,892
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^3,892/_55,000 = ^3,892/_55,000 = 0.0708 = 7.08 cM Incorrect B. ^23,437/_55,000 = ^23,437/_55,000 = 0.4261 = 42.61 cM Incorrect C. ^23,797/_55,000 = ^23,797/_55,000 = 0.4327 = 43.27 cM Incorrect D. ^3,874/_55,000 = ^3,874/_55,000 = 0.0704 = 7.04 cM Incorrect E. ^{(23,437 + 23,797)}/_55,000 = ^47,234/_55,000 = 0.8588 = 85.88 cM Incorrect F. ^{(3,874 + 3,892)}/_55,000 = ^7,766/_55,000 = 0.1412 = 14.12 cM Correct MC

8062_2d6e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
waxy, yucky	w	y	23,398
waxy	w	+	5,297
yucky	+	y	5,306
wildtype	+	+	23,499
TOTAL =			57,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(23,398 + 23,499)}/_57,500 = ^46,897/_57,500 = 0.8156 = 81.56 cM Incorrect B. ^5,297/_57,500 = ^5,297/_57,500 = 0.0921 = 9.21 cM Incorrect C. ^{(5,297 + 5,306)}/_57,500 = ^10,603/_57,500 = 0.1844 = 18.44 cM Correct D. ^5,306/_57,500 = ^5,306/_57,500 = 0.0923 = 9.23 cM Incorrect E. ^23,499/_57,500 = ^23,499/_57,500 = 0.4087 = 40.87 cM Incorrect F. ^23,398/_57,500 = ^23,398/_57,500 = 0.4069 = 40.69 cM Incorrect MC

0263_34dc

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene T is related to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
horsey, tipsy	h	t	13,917
horsey	h	+	4,258
tipsy	+	t	4,076
wildtype	+	+	13,749
TOTAL =			36,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^4,076/_36,000 = ^4,076/_36,000 = 0.1132 = 11.32 cM Incorrect B. ^13,917/_36,000 = ^13,917/_36,000 = 0.3866 = 38.66 cM Incorrect C. ^{(13,749 + 13,917)}/_36,000 = ^27,666/_36,000 = 0.7685 = 76.85 cM Incorrect D. ^{(4,076 + 4,258)}/_36,000 = ^8,334/_36,000 = 0.2315 = 23.15 cM Correct E. ^13,749/_36,000 = ^13,749/_36,000 = 0.3819 = 38.19 cM Incorrect F. ^4,258/_36,000 = ^4,258/_36,000 = 0.1183 = 11.83 cM Incorrect MC

4fc5_7c1d

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is related to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
horsey, kidney	h	k	9,085
horsey	h	+	19,536
kidney	+	k	19,771
wildtype	+	+	9,108
TOTAL =			57,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(19,536 + 19,771)}/_57,500 = ^39,307/_57,500 = 0.6836 = 68.36 cM Incorrect B. ^{(9,085 + 9,108)}/_57,500 = ^18,193/_57,500 = 0.3164 = 31.64 cM Correct C. ^9,108/_57,500 = ^9,108/_57,500 = 0.1584 = 15.84 cM Incorrect D. ^19,771/_57,500 = ^19,771/_57,500 = 0.3438 = 34.38 cM Incorrect E. ^19,536/_57,500 = ^19,536/_57,500 = 0.3398 = 33.98 cM Incorrect F. ^9,085/_57,500 = ^9,085/_57,500 = 0.1580 = 15.80 cM Incorrect MC

70c1_32d8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
kidney, nerdy	k	n	43,909
kidney	k	+	16,018
nerdy	+	n	15,938
wildtype	+	+	44,135
TOTAL =			120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^15,938/_120,000 = ^15,938/_120,000 = 0.1328 = 13.28 cM Incorrect B. ^16,018/_120,000 = ^16,018/_120,000 = 0.1335 = 13.35 cM Incorrect C. ^{(15,938 + 16,018)}/_120,000 = ^31,956/_120,000 = 0.2663 = 26.63 cM Correct D. ^43,909/_120,000 = ^43,909/_120,000 = 0.3659 = 36.59 cM Incorrect E. ^{(43,909 + 44,135)}/_120,000 = ^88,044/_120,000 = 0.7337 = 73.37 cM Incorrect F. ^44,135/_120,000 = ^44,135/_120,000 = 0.3678 = 36.78 cM Incorrect MC

c241_04d7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
artsy, yucky	a	y	5,870
artsy	a	+	1,076
yucky	+	y	1,052
wildtype	+	+	6,002
TOTAL =			14,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^1,076/_14,000 = ^1,076/_14,000 = 0.0769 = 7.69 cM Incorrect B. ^5,870/_14,000 = ^5,870/_14,000 = 0.4193 = 41.93 cM Incorrect C. ^6,002/_14,000 = ^6,002/_14,000 = 0.4287 = 42.87 cM Incorrect D. ^1,052/_14,000 = ^1,052/_14,000 = 0.0751 = 7.51 cM Incorrect E. ^{(5,870 + 6,002)}/_14,000 = ^11,872/_14,000 = 0.8480 = 84.80 cM Incorrect F. ^{(1,052 + 1,076)}/_14,000 = ^2,128/_14,000 = 0.1520 = 15.20 cM Correct MC

b3da_1470

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
horsey, waxy	h	w	39,603
horsey	h	+	15,413
waxy	+	w	15,321
wildtype	+	+	39,663
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^15,321/_110,000 = ^15,321/_110,000 = 0.1393 = 13.93 cM Incorrect B. ^39,603/_110,000 = ^39,603/_110,000 = 0.3600 = 36.00 cM Incorrect C. ^{(39,603 + 39,663)}/_110,000 = ^79,266/_110,000 = 0.7206 = 72.06 cM Incorrect D. ^{(15,321 + 15,413)}/_110,000 = ^30,734/_110,000 = 0.2794 = 27.94 cM Correct E. ^39,663/_110,000 = ^39,663/_110,000 = 0.3606 = 36.06 cM Incorrect F. ^15,413/_110,000 = ^15,413/_110,000 = 0.1401 = 14.01 cM Incorrect MC

c778_77de

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
horsey, waxy	h	w	60,694
horsey	h	+	6,700
waxy	+	w	6,611
wildtype	+	+	60,995
TOTAL =			135,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^60,995/_135,000 = ^60,995/_135,000 = 0.4518 = 45.18 cM Incorrect B. ^60,694/_135,000 = ^60,694/_135,000 = 0.4496 = 44.96 cM Incorrect C. ^{(6,611 + 6,700)}/_135,000 = ^13,311/_135,000 = 0.0986 = 9.86 cM Correct D. ^6,700/_135,000 = ^6,700/_135,000 = 0.0496 = 4.96 cM Incorrect E. ^6,611/_135,000 = ^6,611/_135,000 = 0.0490 = 4.90 cM Incorrect F. ^{(60,694 + 60,995)}/_135,000 = ^121,689/_135,000 = 0.9014 = 90.14 cM Incorrect MC

ca5d_3122

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is analogous to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene Y is correlated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
dewy, yucky	d	y	3,745
dewy	d	+	11,360
yucky	+	y	11,263
wildtype	+	+	3,632
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^3,632/_30,000 = ^3,632/_30,000 = 0.1211 = 12.11 cM Incorrect B. ^{(11,263 + 11,360)}/_30,000 = ^22,623/_30,000 = 0.7541 = 75.41 cM Incorrect C. ^3,745/_30,000 = ^3,745/_30,000 = 0.1248 = 12.48 cM Incorrect D. ^11,360/_30,000 = ^11,360/_30,000 = 0.3787 = 37.87 cM Incorrect E. ^11,263/_30,000 = ^11,263/_30,000 = 0.3754 = 37.54 cM Incorrect F. ^{(3,632 + 3,745)}/_30,000 = ^7,377/_30,000 = 0.2459 = 24.59 cM Correct MC

bd87_8f4a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is associated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
artsy, chummy	a	c	26,270
artsy	a	+	104,111
chummy	+	c	103,603
wildtype	+	+	26,016
TOTAL =			260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^104,111/_260,000 = ^104,111/_260,000 = 0.4004 = 40.04 cM Incorrect B. ^103,603/_260,000 = ^103,603/_260,000 = 0.3985 = 39.85 cM Incorrect C. ^26,016/_260,000 = ^26,016/_260,000 = 0.1001 = 10.01 cM Incorrect D. ^26,270/_260,000 = ^26,270/_260,000 = 0.1010 = 10.10 cM Incorrect E. ^{(26,016 + 26,270)}/_260,000 = ^52,286/_260,000 = 0.2011 = 20.11 cM Correct F. ^{(103,603 + 104,111)}/_260,000 = ^207,714/_260,000 = 0.7989 = 79.89 cM Incorrect MC

f6a6_2a3f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is analogous to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene D is connected with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes		Progeny Count
bumpy, dewy	b	d	17,981
bumpy	b	+	96,863
dewy	+	d	97,188
wildtype	+	+	17,968
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^17,968/_230,000 = ^17,968/_230,000 = 0.0781 = 7.81 cM Incorrect B. ^{(17,968 + 17,981)}/_230,000 = ^35,949/_230,000 = 0.1563 = 15.63 cM Correct C. ^97,188/_230,000 = ^97,188/_230,000 = 0.4226 = 42.26 cM Incorrect D. ^{(96,863 + 97,188)}/_230,000 = ^194,051/_230,000 = 0.8437 = 84.37 cM Incorrect E. ^96,863/_230,000 = ^96,863/_230,000 = 0.4211 = 42.11 cM Incorrect F. ^17,981/_230,000 = ^17,981/_230,000 = 0.0782 = 7.82 cM Incorrect MC

2930_e527

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
eery, xanthic	e	x	14,981
eery	e	+	114,986
xanthic	+	x	115,140
wildtype	+	+	14,893
TOTAL =			260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^114,986/_260,000 = ^114,986/_260,000 = 0.4423 = 44.23 cM Incorrect B. ^{(14,893 + 14,981)}/_260,000 = ^29,874/_260,000 = 0.1149 = 11.49 cM Correct C. ^115,140/_260,000 = ^115,140/_260,000 = 0.4428 = 44.28 cM Incorrect D. ^{(114,986 + 115,140)}/_260,000 = ^230,126/_260,000 = 0.8851 = 88.51 cM Incorrect E. ^14,981/_260,000 = ^14,981/_260,000 = 0.0576 = 5.76 cM Incorrect F. ^14,893/_260,000 = ^14,893/_260,000 = 0.0573 = 5.73 cM Incorrect MC

39a4_7233

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
kidney, rusty	k	r	7,970
kidney	k	+	2,147
rusty	+	r	2,043
wildtype	+	+	7,840
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^2,043/_20,000 = ^2,043/_20,000 = 0.1022 = 10.21 cM Incorrect B. ^{(2,043 + 2,147)}/_20,000 = ^4,190/_20,000 = 0.2095 = 20.95 cM Correct C. ^7,840/_20,000 = ^7,840/_20,000 = 0.3920 = 39.20 cM Incorrect D. ^{(7,840 + 7,970)}/_20,000 = ^15,810/_20,000 = 0.7905 = 79.05 cM Incorrect E. ^7,970/_20,000 = ^7,970/_20,000 = 0.3985 = 39.85 cM Incorrect F. ^2,147/_20,000 = ^2,147/_20,000 = 0.1074 = 10.73 cM Incorrect MC

080f_1b60

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
dewy, fuzzy	d	f	48,715
dewy	d	+	96,282
fuzzy	+	f	96,539
wildtype	+	+	48,464
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(48,464 + 48,715)}/_290,000 = ^97,179/_290,000 = 0.3351 = 33.51 cM Correct B. ^{(96,282 + 96,539)}/_290,000 = ^192,821/_290,000 = 0.6649 = 66.49 cM Incorrect C. ^96,539/_290,000 = ^96,539/_290,000 = 0.3329 = 33.29 cM Incorrect D. ^48,715/_290,000 = ^48,715/_290,000 = 0.1680 = 16.80 cM Incorrect E. ^96,282/_290,000 = ^96,282/_290,000 = 0.3320 = 33.20 cM Incorrect F. ^48,464/_290,000 = ^48,464/_290,000 = 0.1671 = 16.71 cM Incorrect MC

b8d0_93a9

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is affiliated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
dewy, eery	d	e	27,625
dewy	d	+	7,467
eery	+	e	7,422
wildtype	+	+	27,486
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(7,422 + 7,467)}/_70,000 = ^14,889/_70,000 = 0.2127 = 21.27 cM Correct B. ^27,625/_70,000 = ^27,625/_70,000 = 0.3946 = 39.46 cM Incorrect C. ^7,467/_70,000 = ^7,467/_70,000 = 0.1067 = 10.67 cM Incorrect D. ^27,486/_70,000 = ^27,486/_70,000 = 0.3927 = 39.27 cM Incorrect E. ^7,422/_70,000 = ^7,422/_70,000 = 0.1060 = 10.60 cM Incorrect F. ^{(27,486 + 27,625)}/_70,000 = ^55,111/_70,000 = 0.7873 = 78.73 cM Incorrect MC

a5dc_bdfb

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
horsey, nerdy	h	n	338
horsey	h	+	1,044
nerdy	+	n	1,098
wildtype	+	+	320
TOTAL =			2,800

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(320 + 1,044)}/_2,800 = ^1,364/_2,800 = 0.4871 = 48.71 cM Incorrect B. ^{(1,044 + 1,098)}/_2,800 = ^2,142/_2,800 = 0.7650 = 76.50 cM Incorrect C. ³²⁰/_2,800 = ³²⁰/_2,800 = 0.1143 = 11.43 cM Incorrect D. ^{(320 + 338)}/_2,800 = ⁶⁵⁸/_2,800 = 0.2350 = 23.50 cM Correct E. ^1,098/_2,800 = ^1,098/_2,800 = 0.3921 = 39.21 cM Incorrect F. ^1,044/_2,800 = ^1,044/_2,800 = 0.3729 = 37.29 cM Incorrect MC

a4f8_b731

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
mushy, tipsy	m	t	18,576
mushy	m	+	46,760
tipsy	+	t	46,151
wildtype	+	+	18,513
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^18,576/_130,000 = ^18,576/_130,000 = 0.1429 = 14.29 cM Incorrect B. ^{(46,151 + 46,760)}/_130,000 = ^92,911/_130,000 = 0.7147 = 71.47 cM Incorrect C. ^46,151/_130,000 = ^46,151/_130,000 = 0.3550 = 35.50 cM Incorrect D. ^{(18,513 + 18,576)}/_130,000 = ^37,089/_130,000 = 0.2853 = 28.53 cM Correct E. ^46,760/_130,000 = ^46,760/_130,000 = 0.3597 = 35.97 cM Incorrect F. ^18,513/_130,000 = ^18,513/_130,000 = 0.1424 = 14.24 cM Incorrect MC

b292_bfd5

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
jerky, kidney	j	k	1,272
jerky	j	+	2,720
kidney	+	k	2,652
wildtype	+	+	1,356
TOTAL =			8,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(1,272 + 1,356)}/_8,000 = ^2,628/_8,000 = 0.3285 = 32.85 cM Correct B. ^1,272/_8,000 = ^1,272/_8,000 = 0.1590 = 15.90 cM Incorrect C. ^{(2,652 + 2,720)}/_8,000 = ^5,372/_8,000 = 0.6715 = 67.15 cM Incorrect D. ^2,652/_8,000 = ^2,652/_8,000 = 0.3315 = 33.15 cM Incorrect E. ^1,356/_8,000 = ^1,356/_8,000 = 0.1695 = 16.95 cM Incorrect F. ^2,720/_8,000 = ^2,720/_8,000 = 0.3400 = 34.00 cM Incorrect MC

b291_b4bb

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is affiliated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
dewy, yucky	d	y	20,802
dewy	d	+	33,983
yucky	+	y	34,184
wildtype	+	+	21,031
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(33,983 + 34,184)}/_110,000 = ^68,167/_110,000 = 0.6197 = 61.97 cM Incorrect B. ^33,983/_110,000 = ^33,983/_110,000 = 0.3089 = 30.89 cM Incorrect C. ^20,802/_110,000 = ^20,802/_110,000 = 0.1891 = 18.91 cM Incorrect D. ^{(20,802 + 21,031)}/_110,000 = ^41,833/_110,000 = 0.3803 = 38.03 cM Correct E. ^34,184/_110,000 = ^34,184/_110,000 = 0.3108 = 31.08 cM Incorrect F. ^21,031/_110,000 = ^21,031/_110,000 = 0.1912 = 19.12 cM Incorrect MC

3368_3c42

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene X is analogous to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
tipsy, xanthic	t	x	16,409
tipsy	t	+	6,048
xanthic	+	x	6,084
wildtype	+	+	16,459
TOTAL =			45,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(6,048 + 6,084)}/_45,000 = ^12,132/_45,000 = 0.2696 = 26.96 cM Correct B. ^{(16,409 + 16,459)}/_45,000 = ^32,868/_45,000 = 0.7304 = 73.04 cM Incorrect C. ^6,084/_45,000 = ^6,084/_45,000 = 0.1352 = 13.52 cM Incorrect D. ^16,409/_45,000 = ^16,409/_45,000 = 0.3646 = 36.46 cM Incorrect E. ^16,459/_45,000 = ^16,459/_45,000 = 0.3658 = 36.58 cM Incorrect F. ^6,048/_45,000 = ^6,048/_45,000 = 0.1344 = 13.44 cM Incorrect MC

bc78_a569

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
jerky, kidney	j	k	8,915
jerky	j	+	81,027
kidney	+	k	80,919
wildtype	+	+	9,139
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(80,919 + 81,027)}/_180,000 = ^161,946/_180,000 = 0.8997 = 89.97 cM Incorrect B. ^80,919/_180,000 = ^80,919/_180,000 = 0.4496 = 44.95 cM Incorrect C. ^9,139/_180,000 = ^9,139/_180,000 = 0.0508 = 5.08 cM Incorrect D. ^{(8,915 + 9,139)}/_180,000 = ^18,054/_180,000 = 0.1003 = 10.03 cM Correct E. ^81,027/_180,000 = ^81,027/_180,000 = 0.4501 = 45.02 cM Incorrect F. ^8,915/_180,000 = ^8,915/_180,000 = 0.0495 = 4.95 cM Incorrect MC

4052_24b0

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
dewy, rusty	d	r	8,532
dewy	d	+	26,378
rusty	+	r	26,479
wildtype	+	+	8,611
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^8,532/_70,000 = ^8,532/_70,000 = 0.1219 = 12.19 cM Incorrect B. ^{(26,378 + 26,479)}/_70,000 = ^52,857/_70,000 = 0.7551 = 75.51 cM Incorrect C. ^8,611/_70,000 = ^8,611/_70,000 = 0.1230 = 12.30 cM Incorrect D. ^{(8,532 + 8,611)}/_70,000 = ^17,143/_70,000 = 0.2449 = 24.49 cM Correct E. ^26,378/_70,000 = ^26,378/_70,000 = 0.3768 = 37.68 cM Incorrect F. ^26,479/_70,000 = ^26,479/_70,000 = 0.3783 = 37.83 cM Incorrect MC

2638_4788

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
chummy, kidney	c	k	3,424
chummy	c	+	21,707
kidney	+	k	21,438
wildtype	+	+	3,431
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^3,431/_50,000 = ^3,431/_50,000 = 0.0686 = 6.86 cM Incorrect B. ^3,424/_50,000 = ^3,424/_50,000 = 0.0685 = 6.85 cM Incorrect C. ^{(3,424 + 3,431)}/_50,000 = ^6,855/_50,000 = 0.1371 = 13.71 cM Correct D. ^{(21,438 + 21,707)}/_50,000 = ^43,145/_50,000 = 0.8629 = 86.29 cM Incorrect E. ^21,438/_50,000 = ^21,438/_50,000 = 0.4288 = 42.88 cM Incorrect F. ^21,707/_50,000 = ^21,707/_50,000 = 0.4341 = 43.41 cM Incorrect MC

9ffa_2192

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is associated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
chummy, yucky	c	y	22,987
chummy	c	+	10,696
yucky	+	y	10,796
wildtype	+	+	23,021
TOTAL =			67,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^10,796/_67,500 = ^10,796/_67,500 = 0.1599 = 15.99 cM Incorrect B. ^23,021/_67,500 = ^23,021/_67,500 = 0.3411 = 34.11 cM Incorrect C. ^{(10,696 + 10,796)}/_67,500 = ^21,492/_67,500 = 0.3184 = 31.84 cM Correct D. ^10,696/_67,500 = ^10,696/_67,500 = 0.1585 = 15.85 cM Incorrect E. ^{(22,987 + 23,021)}/_67,500 = ^46,008/_67,500 = 0.6816 = 68.16 cM Incorrect F. ^22,987/_67,500 = ^22,987/_67,500 = 0.3405 = 34.05 cM Incorrect MC

60d1_3d26

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
eery, xanthic	e	x	3,110
eery	e	+	15,445
xanthic	+	x	15,770
wildtype	+	+	3,175
TOTAL =			37,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^3,175/_37,500 = ^3,175/_37,500 = 0.0847 = 8.47 cM Incorrect B. ^15,770/_37,500 = ^15,770/_37,500 = 0.4205 = 42.05 cM Incorrect C. ^{(15,445 + 15,770)}/_37,500 = ^31,215/_37,500 = 0.8324 = 83.24 cM Incorrect D. ^3,110/_37,500 = ^3,110/_37,500 = 0.0829 = 8.29 cM Incorrect E. ^{(3,110 + 3,175)}/_37,500 = ^6,285/_37,500 = 0.1676 = 16.76 cM Correct F. ^15,445/_37,500 = ^15,445/_37,500 = 0.4119 = 41.19 cM Incorrect MC

80ae_4c82

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
chummy, xanthic	c	x	3,748
chummy	c	+	16,275
xanthic	+	x	16,237
wildtype	+	+	3,740
TOTAL =			40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(3,740 + 3,748)}/_40,000 = ^7,488/_40,000 = 0.1872 = 18.72 cM Correct B. ^3,740/_40,000 = ^3,740/_40,000 = 0.0935 = 9.35 cM Incorrect C. ^{(16,237 + 16,275)}/_40,000 = ^32,512/_40,000 = 0.8128 = 81.28 cM Incorrect D. ^16,275/_40,000 = ^16,275/_40,000 = 0.4069 = 40.69 cM Incorrect E. ^3,748/_40,000 = ^3,748/_40,000 = 0.0937 = 9.37 cM Incorrect F. ^16,237/_40,000 = ^16,237/_40,000 = 0.4059 = 40.59 cM Incorrect MC

7c06_2977

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is related to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
horsey, xanthic	h	x	3,437
horsey	h	+	22,564
xanthic	+	x	22,390
wildtype	+	+	3,609
TOTAL =			52,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(3,437 + 3,609)}/_52,000 = ^7,046/_52,000 = 0.1355 = 13.55 cM Correct B. ^22,390/_52,000 = ^22,390/_52,000 = 0.4306 = 43.06 cM Incorrect C. ^{(22,390 + 22,564)}/_52,000 = ^44,954/_52,000 = 0.8645 = 86.45 cM Incorrect D. ^3,437/_52,000 = ^3,437/_52,000 = 0.0661 = 6.61 cM Incorrect E. ^3,609/_52,000 = ^3,609/_52,000 = 0.0694 = 6.94 cM Incorrect F. ^22,564/_52,000 = ^22,564/_52,000 = 0.4339 = 43.39 cM Incorrect MC

3a53_8330

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is associated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
bumpy, fuzzy	b	f	20,851
bumpy	b	+	6,672
fuzzy	+	f	6,649
wildtype	+	+	20,828
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^20,851/_55,000 = ^20,851/_55,000 = 0.3791 = 37.91 cM Incorrect B. ^20,828/_55,000 = ^20,828/_55,000 = 0.3787 = 37.87 cM Incorrect C. ^{(20,828 + 20,851)}/_55,000 = ^41,679/_55,000 = 0.7578 = 75.78 cM Incorrect D. ^6,672/_55,000 = ^6,672/_55,000 = 0.1213 = 12.13 cM Incorrect E. ^{(6,649 + 6,672)}/_55,000 = ^13,321/_55,000 = 0.2422 = 24.22 cM Correct F. ^6,649/_55,000 = ^6,649/_55,000 = 0.1209 = 12.09 cM Incorrect MC

b53b_8b74

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
chummy, jerky	c	j	72,809
chummy	c	+	17,385
jerky	+	j	17,301
wildtype	+	+	72,505
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^72,505/_180,000 = ^72,505/_180,000 = 0.4028 = 40.28 cM Incorrect B. ^17,301/_180,000 = ^17,301/_180,000 = 0.0961 = 9.61 cM Incorrect C. ^{(17,301 + 17,385)}/_180,000 = ^34,686/_180,000 = 0.1927 = 19.27 cM Correct D. ^17,385/_180,000 = ^17,385/_180,000 = 0.0966 = 9.66 cM Incorrect E. ^{(72,505 + 72,809)}/_180,000 = ^145,314/_180,000 = 0.8073 = 80.73 cM Incorrect F. ^72,809/_180,000 = ^72,809/_180,000 = 0.4045 = 40.45 cM Incorrect MC

26ac_e132

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
eery, horsey	e	h	20,458
eery	e	+	8,539
horsey	+	h	8,658
wildtype	+	+	20,345
TOTAL =			58,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(8,539 + 8,658)}/_58,000 = ^17,197/_58,000 = 0.2965 = 29.65 cM Correct B. ^{(20,345 + 20,458)}/_58,000 = ^40,803/_58,000 = 0.7035 = 70.35 cM Incorrect C. ^8,658/_58,000 = ^8,658/_58,000 = 0.1493 = 14.93 cM Incorrect D. ^20,458/_58,000 = ^20,458/_58,000 = 0.3527 = 35.27 cM Incorrect E. ^8,539/_58,000 = ^8,539/_58,000 = 0.1472 = 14.72 cM Incorrect F. ^20,345/_58,000 = ^20,345/_58,000 = 0.3508 = 35.08 cM Incorrect MC

dcc6_f1e9

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
horsey, tipsy	h	t	60,356
horsey	h	+	39,682
tipsy	+	t	39,858
wildtype	+	+	60,104
TOTAL =			200,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^39,682/_200,000 = ^39,682/_200,000 = 0.1984 = 19.84 cM Incorrect B. ^39,858/_200,000 = ^39,858/_200,000 = 0.1993 = 19.93 cM Incorrect C. ^{(60,104 + 60,356)}/_200,000 = ^120,460/_200,000 = 0.6023 = 60.23 cM Incorrect D. ^60,104/_200,000 = ^60,104/_200,000 = 0.3005 = 30.05 cM Incorrect E. ^60,356/_200,000 = ^60,356/_200,000 = 0.3018 = 30.18 cM Incorrect F. ^{(39,682 + 39,858)}/_200,000 = ^79,540/_200,000 = 0.3977 = 39.77 cM Correct MC

f860_8eba

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
eery, waxy	e	w	16,046
eery	e	+	7,215
waxy	+	w	7,068
wildtype	+	+	15,671
TOTAL =			46,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(7,068 + 7,215)}/_46,000 = ^14,283/_46,000 = 0.3105 = 31.05 cM Correct B. ^7,068/_46,000 = ^7,068/_46,000 = 0.1537 = 15.37 cM Incorrect C. ^7,215/_46,000 = ^7,215/_46,000 = 0.1568 = 15.68 cM Incorrect D. ^{(15,671 + 16,046)}/_46,000 = ^31,717/_46,000 = 0.6895 = 68.95 cM Incorrect E. ^15,671/_46,000 = ^15,671/_46,000 = 0.3407 = 34.07 cM Incorrect F. ^16,046/_46,000 = ^16,046/_46,000 = 0.3488 = 34.88 cM Incorrect MC

36ef_14d6

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
rusty, waxy	r	w	8,558
rusty	r	+	5,141
waxy	+	w	5,155
wildtype	+	+	8,646
TOTAL =			27,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^5,155/_27,500 = ^5,155/_27,500 = 0.1875 = 18.75 cM Incorrect B. ^8,558/_27,500 = ^8,558/_27,500 = 0.3112 = 31.12 cM Incorrect C. ^{(8,558 + 8,646)}/_27,500 = ^17,204/_27,500 = 0.6256 = 62.56 cM Incorrect D. ^{(5,141 + 5,155)}/_27,500 = ^10,296/_27,500 = 0.3744 = 37.44 cM Correct E. ^8,646/_27,500 = ^8,646/_27,500 = 0.3144 = 31.44 cM Incorrect F. ^5,141/_27,500 = ^5,141/_27,500 = 0.1869 = 18.69 cM Incorrect MC

1fda_7f93

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
mushy, rusty	m	r	19,650
mushy	m	+	75,129
rusty	+	r	75,712
wildtype	+	+	19,509
TOTAL =			190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(19,509 + 19,650)}/_190,000 = ^39,159/_190,000 = 0.2061 = 20.61 cM Correct B. ^{(75,129 + 75,712)}/_190,000 = ^150,841/_190,000 = 0.7939 = 79.39 cM Incorrect C. ^75,712/_190,000 = ^75,712/_190,000 = 0.3985 = 39.85 cM Incorrect D. ^19,509/_190,000 = ^19,509/_190,000 = 0.1027 = 10.27 cM Incorrect E. ^19,650/_190,000 = ^19,650/_190,000 = 0.1034 = 10.34 cM Incorrect F. ^75,129/_190,000 = ^75,129/_190,000 = 0.3954 = 39.54 cM Incorrect MC

6a73_2672

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
artsy, eery	a	e	51,522
artsy	a	+	8,497
eery	+	e	8,507
wildtype	+	+	51,474
TOTAL =			120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(51,474 + 51,522)}/_120,000 = ^102,996/_120,000 = 0.8583 = 85.83 cM Incorrect B. ^51,522/_120,000 = ^51,522/_120,000 = 0.4294 = 42.94 cM Incorrect C. ^{(8,497 + 8,507)}/_120,000 = ^17,004/_120,000 = 0.1417 = 14.17 cM Correct D. ^51,474/_120,000 = ^51,474/_120,000 = 0.4289 = 42.90 cM Incorrect E. ^8,507/_120,000 = ^8,507/_120,000 = 0.0709 = 7.09 cM Incorrect F. ^8,497/_120,000 = ^8,497/_120,000 = 0.0708 = 7.08 cM Incorrect MC

90fd_d46a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene T is connected with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
artsy, tipsy	a	t	20,539
artsy	a	+	59,086
tipsy	+	t	59,906
wildtype	+	+	20,469
TOTAL =			160,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(59,086 + 59,906)}/_160,000 = ^118,992/_160,000 = 0.7437 = 74.37 cM Incorrect B. ^59,086/_160,000 = ^59,086/_160,000 = 0.3693 = 36.93 cM Incorrect C. ^{(20,469 + 20,539)}/_160,000 = ^41,008/_160,000 = 0.2563 = 25.63 cM Correct D. ^20,539/_160,000 = ^20,539/_160,000 = 0.1284 = 12.84 cM Incorrect E. ^20,469/_160,000 = ^20,469/_160,000 = 0.1279 = 12.79 cM Incorrect F. ^59,906/_160,000 = ^59,906/_160,000 = 0.3744 = 37.44 cM Incorrect MC

fb3e_4a38

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is linked with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene W is connected with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
eery, waxy	e	w	6,345
eery	e	+	1,139
waxy	+	w	1,144
wildtype	+	+	6,372
TOTAL =			15,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(1,139 + 1,144)}/_15,000 = ^2,283/_15,000 = 0.1522 = 15.22 cM Correct B. ^1,139/_15,000 = ^1,139/_15,000 = 0.0759 = 7.59 cM Incorrect C. ^6,372/_15,000 = ^6,372/_15,000 = 0.4248 = 42.48 cM Incorrect D. ^{(6,345 + 6,372)}/_15,000 = ^12,717/_15,000 = 0.8478 = 84.78 cM Incorrect E. ^6,345/_15,000 = ^6,345/_15,000 = 0.4230 = 42.30 cM Incorrect F. ^1,144/_15,000 = ^1,144/_15,000 = 0.0763 = 7.63 cM Incorrect MC

bb5b_d545

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
artsy, mushy	a	m	14,184
artsy	a	+	91,185
mushy	+	m	90,528
wildtype	+	+	14,103
TOTAL =			210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^14,184/_210,000 = ^14,184/_210,000 = 0.0675 = 6.75 cM Incorrect B. ^{(14,103 + 14,184)}/_210,000 = ^28,287/_210,000 = 0.1347 = 13.47 cM Correct C. ^{(90,528 + 91,185)}/_210,000 = ^181,713/_210,000 = 0.8653 = 86.53 cM Incorrect D. ^14,103/_210,000 = ^14,103/_210,000 = 0.0672 = 6.72 cM Incorrect E. ^91,185/_210,000 = ^91,185/_210,000 = 0.4342 = 43.42 cM Incorrect F. ^90,528/_210,000 = ^90,528/_210,000 = 0.4311 = 43.11 cM Incorrect MC

bdff_be04

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
fuzzy, mushy	f	m	10,277
fuzzy	f	+	59,788
mushy	+	m	59,730
wildtype	+	+	10,205
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^59,788/_140,000 = ^59,788/_140,000 = 0.4271 = 42.71 cM Incorrect B. ^{(59,730 + 59,788)}/_140,000 = ^119,518/_140,000 = 0.8537 = 85.37 cM Incorrect C. ^59,730/_140,000 = ^59,730/_140,000 = 0.4266 = 42.66 cM Incorrect D. ^10,277/_140,000 = ^10,277/_140,000 = 0.0734 = 7.34 cM Incorrect E. ^{(10,205 + 10,277)}/_140,000 = ^20,482/_140,000 = 0.1463 = 14.63 cM Correct F. ^10,205/_140,000 = ^10,205/_140,000 = 0.0729 = 7.29 cM Incorrect MC

f10f_151b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene D is related to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes		Progeny Count
chummy, dewy	c	d	7,651
chummy	c	+	47,418
dewy	+	d	47,083
wildtype	+	+	7,848
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^7,651/_110,000 = ^7,651/_110,000 = 0.0696 = 6.96 cM Incorrect B. ^47,083/_110,000 = ^47,083/_110,000 = 0.4280 = 42.80 cM Incorrect C. ^7,848/_110,000 = ^7,848/_110,000 = 0.0713 = 7.13 cM Incorrect D. ^47,418/_110,000 = ^47,418/_110,000 = 0.4311 = 43.11 cM Incorrect E. ^{(7,651 + 7,848)}/_110,000 = ^15,499/_110,000 = 0.1409 = 14.09 cM Correct F. ^{(47,083 + 47,418)}/_110,000 = ^94,501/_110,000 = 0.8591 = 85.91 cM Incorrect MC

86d1_ce0c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene R is analogous to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
fuzzy, rusty	f	r	2,295
fuzzy	f	+	310
rusty	+	r	288
wildtype	+	+	2,307
TOTAL =			5,200

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ³¹⁰/_5,200 = ³¹⁰/_5,200 = 0.0596 = 5.96 cM Incorrect B. ^{(2,295 + 2,307)}/_5,200 = ^4,602/_5,200 = 0.8850 = 88.50 cM Incorrect C. ^2,295/_5,200 = ^2,295/_5,200 = 0.4413 = 44.13 cM Incorrect D. ^{(288 + 310)}/_5,200 = ⁵⁹⁸/_5,200 = 0.1150 = 11.50 cM Correct E. ²⁸⁸/_5,200 = ²⁸⁸/_5,200 = 0.0554 = 5.54 cM Incorrect F. ^2,307/_5,200 = ^2,307/_5,200 = 0.4437 = 44.37 cM Incorrect MC

d7b9_150f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
kidney, waxy	k	w	8,604
kidney	k	+	2,630
waxy	+	w	2,644
wildtype	+	+	8,622
TOTAL =			22,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(8,604 + 8,622)}/_22,500 = ^17,226/_22,500 = 0.7656 = 76.56 cM Incorrect B. ^{(2,630 + 2,644)}/_22,500 = ^5,274/_22,500 = 0.2344 = 23.44 cM Correct C. ^2,630/_22,500 = ^2,630/_22,500 = 0.1169 = 11.69 cM Incorrect D. ^8,604/_22,500 = ^8,604/_22,500 = 0.3824 = 38.24 cM Incorrect E. ^2,644/_22,500 = ^2,644/_22,500 = 0.1175 = 11.75 cM Incorrect F. ^8,622/_22,500 = ^8,622/_22,500 = 0.3832 = 38.32 cM Incorrect MC

dc7b_16ef

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is linked with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
bumpy, waxy	b	w	16,920
bumpy	b	+	38,113
waxy	+	w	38,150
wildtype	+	+	16,817
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^38,113/_110,000 = ^38,113/_110,000 = 0.3465 = 34.65 cM Incorrect B. ^16,817/_110,000 = ^16,817/_110,000 = 0.1529 = 15.29 cM Incorrect C. ^16,920/_110,000 = ^16,920/_110,000 = 0.1538 = 15.38 cM Incorrect D. ^{(16,817 + 16,920)}/_110,000 = ^33,737/_110,000 = 0.3067 = 30.67 cM Correct E. ^{(38,113 + 38,150)}/_110,000 = ^76,263/_110,000 = 0.6933 = 69.33 cM Incorrect F. ^38,150/_110,000 = ^38,150/_110,000 = 0.3468 = 34.68 cM Incorrect MC

b775_a631

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
horsey, jerky	h	j	232
horsey	h	+	1,809
jerky	+	j	1,761
wildtype	+	+	198
TOTAL =			4,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^1,809/_4,000 = ^1,809/_4,000 = 0.4522 = 45.23 cM Incorrect B. ²³²/_4,000 = ²³²/_4,000 = 0.0580 = 5.80 cM Incorrect C. ^{(198 + 232)}/_4,000 = ⁴³⁰/_4,000 = 0.1075 = 10.75 cM Correct D. ^{(1,761 + 1,809)}/_4,000 = ^3,570/_4,000 = 0.8925 = 89.25 cM Incorrect E. ^{(198 + 1,761)}/_4,000 = ^1,959/_4,000 = 0.4898 = 48.98 cM Incorrect F. ¹⁹⁸/_4,000 = ¹⁹⁸/_4,000 = 0.0495 = 4.95 cM Incorrect MC

9024_844f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
tipsy, yucky	t	y	2,370
tipsy	t	+	7,678
yucky	+	y	7,496
wildtype	+	+	2,456
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(2,370 + 2,456)}/_20,000 = ^4,826/_20,000 = 0.2413 = 24.13 cM Correct B. ^7,496/_20,000 = ^7,496/_20,000 = 0.3748 = 37.48 cM Incorrect C. ^2,456/_20,000 = ^2,456/_20,000 = 0.1228 = 12.28 cM Incorrect D. ^{(7,496 + 7,678)}/_20,000 = ^15,174/_20,000 = 0.7587 = 75.87 cM Incorrect E. ^7,678/_20,000 = ^7,678/_20,000 = 0.3839 = 38.39 cM Incorrect F. ^2,370/_20,000 = ^2,370/_20,000 = 0.1185 = 11.85 cM Incorrect MC

163a_7319

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is analogous to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
prickly, xanthic	p	x	13,976
prickly	p	+	71,276
xanthic	+	x	70,827
wildtype	+	+	13,921
TOTAL =			170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^13,921/_170,000 = ^13,921/_170,000 = 0.0819 = 8.19 cM Incorrect B. ^71,276/_170,000 = ^71,276/_170,000 = 0.4193 = 41.93 cM Incorrect C. ^{(13,921 + 13,976)}/_170,000 = ^27,897/_170,000 = 0.1641 = 16.41 cM Correct D. ^{(70,827 + 71,276)}/_170,000 = ^142,103/_170,000 = 0.8359 = 83.59 cM Incorrect E. ^70,827/_170,000 = ^70,827/_170,000 = 0.4166 = 41.66 cM Incorrect F. ^13,976/_170,000 = ^13,976/_170,000 = 0.0822 = 8.22 cM Incorrect MC

e13a_777e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
tipsy, xanthic	t	x	4,952
tipsy	t	+	7,616
xanthic	+	x	7,604
wildtype	+	+	4,828
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

A. ^{(4,828 + 4,952)}/_25,000 = ^9,780/_25,000 = 0.3912 = 39.12 cM Correct B. ^7,616/_25,000 = ^7,616/_25,000 = 0.3046 = 30.46 cM Incorrect C. ^{(7,604 + 7,616)}/_25,000 = ^15,220/_25,000 = 0.6088 = 60.88 cM Incorrect D. ^4,828/_25,000 = ^4,828/_25,000 = 0.1931 = 19.31 cM Incorrect E. ^7,604/_25,000 = ^7,604/_25,000 = 0.3042 = 30.42 cM Incorrect F. ^4,952/_25,000 = ^4,952/_25,000 = 0.1981 = 19.81 cM Incorrect