fb71_0016

Two-Point Test Cross Problem

A test cross is a way to explore the relationship between genes and their respective alleles. It is a useful tool for genetic mapping and deciphering the inheritance of traits. Specifically, a two-point test cross examines two (2) genes at the same time to learn about their assortment in gamete formation.

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is affiliated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
bumpy, jerky	b	j	45,573
bumpy	b	+	19,661
jerky	+	j	19,573
wildtype	+	+	45,193
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(19,573 + 19,661)}/_130,000 = ^39,234/_130,000 = 0.3018 = 30.18 cM Correct ^{(19,573 + 45,193)}/_130,000 = ^64,766/_130,000 = 0.4982 = 49.82 cM Incorrect ^{(19,573 + 45,573)}/_130,000 = ^65,146/_130,000 = 0.5011 = 50.11 cM Incorrect ^{(19,661 + 45,193)}/_130,000 = ^64,854/_130,000 = 0.4989 = 49.89 cM Incorrect ^{(19,661 + 45,573)}/_130,000 = ^65,234/_130,000 = 0.5018 = 50.18 cM Incorrect ^{(45,193 + 45,573)}/_130,000 = ^90,766/_130,000 = 0.6982 = 69.82 cM Incorrect MC

6c72_198c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
bumpy, rusty	b	r	6,027
bumpy	b	+	3,391
rusty	+	r	3,430
wildtype	+	+	6,152
TOTAL =			19,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(3,391 + 3,430)}/_19,000 = ^6,821/_19,000 = 0.3590 = 35.90 cM Correct ^{(3,391 + 6,027)}/_19,000 = ^9,418/_19,000 = 0.4957 = 49.57 cM Incorrect ^{(3,391 + 6,152)}/_19,000 = ^9,543/_19,000 = 0.5023 = 50.23 cM Incorrect ^{(3,430 + 6,027)}/_19,000 = ^9,457/_19,000 = 0.4977 = 49.77 cM Incorrect ^{(3,430 + 6,152)}/_19,000 = ^9,582/_19,000 = 0.5043 = 50.43 cM Incorrect ^{(6,027 + 6,152)}/_19,000 = ^12,179/_19,000 = 0.6410 = 64.10 cM Incorrect MC

6c4c_dddd

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
bumpy, prickly	b	p	20,758
bumpy	b	+	6,583
prickly	+	p	6,738
wildtype	+	+	20,921
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(20,758 + 20,921)}/_55,000 = ^41,679/_55,000 = 0.7578 = 75.78 cM Incorrect ^{(6,583 + 20,758)}/_55,000 = ^27,341/_55,000 = 0.4971 = 49.71 cM Incorrect ^{(6,583 + 20,921)}/_55,000 = ^27,504/_55,000 = 0.5001 = 50.01 cM Incorrect ^{(6,583 + 6,738)}/_55,000 = ^13,321/_55,000 = 0.2422 = 24.22 cM Correct ^{(6,738 + 20,758)}/_55,000 = ^27,496/_55,000 = 0.4999 = 49.99 cM Incorrect ^{(6,738 + 20,921)}/_55,000 = ^27,659/_55,000 = 0.5029 = 50.29 cM Incorrect MC

b0c1_3abf

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
waxy, xanthic	w	x	1,182
waxy	w	+	118
xanthic	+	x	129
wildtype	+	+	1,171
TOTAL =			2,600

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,171 + 1,182)}/_2,600 = ^2,353/_2,600 = 0.9050 = 90.50 cM Incorrect ^{(118 + 1,171)}/_2,600 = ^1,289/_2,600 = 0.4958 = 49.58 cM Incorrect ^{(118 + 1,182)}/_2,600 = ^1,300/_2,600 = 0.5000 = 50.00 cM Incorrect ^{(118 + 129)}/_2,600 = ²⁴⁷/_2,600 = 0.0950 = 9.50 cM Correct ^{(129 + 1,171)}/_2,600 = ^1,300/_2,600 = 0.5000 = 50.00 cM Incorrect ^{(129 + 1,182)}/_2,600 = ^1,311/_2,600 = 0.5042 = 50.42 cM Incorrect MC

71b0_f0d1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
chummy, rusty	c	r	17,851
chummy	c	+	54,910
rusty	+	r	54,449
wildtype	+	+	17,790
TOTAL =			145,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(17,790 + 17,851)}/_145,000 = ^35,641/_145,000 = 0.2458 = 24.58 cM Correct ^{(17,790 + 54,449)}/_145,000 = ^72,239/_145,000 = 0.4982 = 49.82 cM Incorrect ^{(17,790 + 54,910)}/_145,000 = ^72,700/_145,000 = 0.5014 = 50.14 cM Incorrect ^{(17,851 + 54,449)}/_145,000 = ^72,300/_145,000 = 0.4986 = 49.86 cM Incorrect ^{(17,851 + 54,910)}/_145,000 = ^72,761/_145,000 = 0.5018 = 50.18 cM Incorrect ^{(54,449 + 54,910)}/_145,000 = ^109,359/_145,000 = 0.7542 = 75.42 cM Incorrect MC

2e2e_0eec

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
nerdy, waxy	n	w	8,469
nerdy	n	+	26,670
waxy	+	w	26,432
wildtype	+	+	8,429
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(26,432 + 26,670)}/_70,000 = ^53,102/_70,000 = 0.7586 = 75.86 cM Incorrect ^{(8,429 + 26,432)}/_70,000 = ^34,861/_70,000 = 0.4980 = 49.80 cM Incorrect ^{(8,429 + 26,670)}/_70,000 = ^35,099/_70,000 = 0.5014 = 50.14 cM Incorrect ^{(8,429 + 8,469)}/_70,000 = ^16,898/_70,000 = 0.2414 = 24.14 cM Correct ^{(8,469 + 26,432)}/_70,000 = ^34,901/_70,000 = 0.4986 = 49.86 cM Incorrect ^{(8,469 + 26,670)}/_70,000 = ^35,139/_70,000 = 0.5020 = 50.20 cM Incorrect MC

ffc6_ccc6

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is associated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
horsey, jerky	h	j	4,385
horsey	h	+	1,376
jerky	+	j	1,315
wildtype	+	+	4,424
TOTAL =			11,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,315 + 1,376)}/_11,500 = ^2,691/_11,500 = 0.2340 = 23.40 cM Correct ^{(1,315 + 4,385)}/_11,500 = ^5,700/_11,500 = 0.4957 = 49.57 cM Incorrect ^{(1,315 + 4,424)}/_11,500 = ^5,739/_11,500 = 0.4990 = 49.90 cM Incorrect ^{(1,376 + 4,385)}/_11,500 = ^5,761/_11,500 = 0.5010 = 50.10 cM Incorrect ^{(1,376 + 4,424)}/_11,500 = ^5,800/_11,500 = 0.5043 = 50.43 cM Incorrect ^{(4,385 + 4,424)}/_11,500 = ^8,809/_11,500 = 0.7660 = 76.60 cM Incorrect MC

5a03_8f26

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
horsey, rusty	h	r	4,372
horsey	h	+	10,500
rusty	+	r	10,635
wildtype	+	+	4,493
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,500 + 10,635)}/_30,000 = ^21,135/_30,000 = 0.7045 = 70.45 cM Incorrect ^{(4,372 + 10,500)}/_30,000 = ^14,872/_30,000 = 0.4957 = 49.57 cM Incorrect ^{(4,372 + 10,635)}/_30,000 = ^15,007/_30,000 = 0.5002 = 50.02 cM Incorrect ^{(4,372 + 4,493)}/_30,000 = ^8,865/_30,000 = 0.2955 = 29.55 cM Correct ^{(4,493 + 10,500)}/_30,000 = ^14,993/_30,000 = 0.4998 = 49.98 cM Incorrect ^{(4,493 + 10,635)}/_30,000 = ^15,128/_30,000 = 0.5043 = 50.43 cM Incorrect MC

7de9_e9af

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is correlated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
fuzzy, kidney	f	k	6,895
fuzzy	f	+	3,153
kidney	+	k	3,079
wildtype	+	+	6,873
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(3,079 + 3,153)}/_20,000 = ^6,232/_20,000 = 0.3116 = 31.16 cM Correct ^{(3,079 + 6,873)}/_20,000 = ^9,952/_20,000 = 0.4976 = 49.76 cM Incorrect ^{(3,079 + 6,895)}/_20,000 = ^9,974/_20,000 = 0.4987 = 49.87 cM Incorrect ^{(3,153 + 6,873)}/_20,000 = ^10,026/_20,000 = 0.5013 = 50.13 cM Incorrect ^{(3,153 + 6,895)}/_20,000 = ^10,048/_20,000 = 0.5024 = 50.24 cM Incorrect ^{(6,873 + 6,895)}/_20,000 = ^13,768/_20,000 = 0.6884 = 68.84 cM Incorrect MC

d1ea_3129

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
nerdy, prickly	n	p	5,841
nerdy	n	+	2,850
prickly	+	p	2,883
wildtype	+	+	5,926
TOTAL =			17,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,850 + 2,883)}/_17,500 = ^5,733/_17,500 = 0.3276 = 32.76 cM Correct ^{(2,850 + 5,841)}/_17,500 = ^8,691/_17,500 = 0.4966 = 49.66 cM Incorrect ^{(2,850 + 5,926)}/_17,500 = ^8,776/_17,500 = 0.5015 = 50.15 cM Incorrect ^{(2,883 + 5,841)}/_17,500 = ^8,724/_17,500 = 0.4985 = 49.85 cM Incorrect ^{(2,883 + 5,926)}/_17,500 = ^8,809/_17,500 = 0.5034 = 50.34 cM Incorrect ^{(5,841 + 5,926)}/_17,500 = ^11,767/_17,500 = 0.6724 = 67.24 cM Incorrect MC

6aea_6374

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
rusty, yucky	r	y	7,012
rusty	r	+	14,295
yucky	+	y	14,163
wildtype	+	+	7,030
TOTAL =			42,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,163 + 14,295)}/_42,500 = ^28,458/_42,500 = 0.6696 = 66.96 cM Incorrect ^{(7,012 + 14,163)}/_42,500 = ^21,175/_42,500 = 0.4982 = 49.82 cM Incorrect ^{(7,012 + 14,295)}/_42,500 = ^21,307/_42,500 = 0.5013 = 50.13 cM Incorrect ^{(7,012 + 7,030)}/_42,500 = ^14,042/_42,500 = 0.3304 = 33.04 cM Correct ^{(7,030 + 14,163)}/_42,500 = ^21,193/_42,500 = 0.4987 = 49.87 cM Incorrect ^{(7,030 + 14,295)}/_42,500 = ^21,325/_42,500 = 0.5018 = 50.18 cM Incorrect MC

af6d_5d48

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
horsey, rusty	h	r	2,847
horsey	h	+	12,222
rusty	+	r	12,126
wildtype	+	+	2,805
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,126 + 12,222)}/_30,000 = ^24,348/_30,000 = 0.8116 = 81.16 cM Incorrect ^{(2,805 + 12,126)}/_30,000 = ^14,931/_30,000 = 0.4977 = 49.77 cM Incorrect ^{(2,805 + 12,222)}/_30,000 = ^15,027/_30,000 = 0.5009 = 50.09 cM Incorrect ^{(2,805 + 2,847)}/_30,000 = ^5,652/_30,000 = 0.1884 = 18.84 cM Correct ^{(2,847 + 12,126)}/_30,000 = ^14,973/_30,000 = 0.4991 = 49.91 cM Incorrect ^{(2,847 + 12,222)}/_30,000 = ^15,069/_30,000 = 0.5023 = 50.23 cM Incorrect MC

4007_5d5a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
mushy, yucky	m	y	1,751
mushy	m	+	10,690
yucky	+	y	10,725
wildtype	+	+	1,834
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,751 + 1,834)}/_25,000 = ^3,585/_25,000 = 0.1434 = 14.34 cM Correct ^{(1,751 + 10,690)}/_25,000 = ^12,441/_25,000 = 0.4976 = 49.76 cM Incorrect ^{(1,751 + 10,725)}/_25,000 = ^12,476/_25,000 = 0.4990 = 49.90 cM Incorrect ^{(1,834 + 10,690)}/_25,000 = ^12,524/_25,000 = 0.5010 = 50.10 cM Incorrect ^{(1,834 + 10,725)}/_25,000 = ^12,559/_25,000 = 0.5024 = 50.24 cM Incorrect ^{(10,690 + 10,725)}/_25,000 = ^21,415/_25,000 = 0.8566 = 85.66 cM Incorrect MC

5231_bc08

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
dewy, waxy	d	w	4,313
dewy	d	+	2,210
waxy	+	w	2,223
wildtype	+	+	4,254
TOTAL =			13,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,210 + 2,223)}/_13,000 = ^4,433/_13,000 = 0.3410 = 34.10 cM Correct ^{(2,210 + 4,254)}/_13,000 = ^6,464/_13,000 = 0.4972 = 49.72 cM Incorrect ^{(2,210 + 4,313)}/_13,000 = ^6,523/_13,000 = 0.5018 = 50.18 cM Incorrect ^{(2,223 + 4,254)}/_13,000 = ^6,477/_13,000 = 0.4982 = 49.82 cM Incorrect ^{(2,223 + 4,313)}/_13,000 = ^6,536/_13,000 = 0.5028 = 50.28 cM Incorrect ^{(4,254 + 4,313)}/_13,000 = ^8,567/_13,000 = 0.6590 = 65.90 cM Incorrect MC

41dc_967f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
bumpy, horsey	b	h	6,379
bumpy	b	+	22,401
horsey	+	h	22,311
wildtype	+	+	6,409
TOTAL =			57,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,311 + 22,401)}/_57,500 = ^44,712/_57,500 = 0.7776 = 77.76 cM Incorrect ^{(6,379 + 22,311)}/_57,500 = ^28,690/_57,500 = 0.4990 = 49.90 cM Incorrect ^{(6,379 + 22,401)}/_57,500 = ^28,780/_57,500 = 0.5005 = 50.05 cM Incorrect ^{(6,379 + 6,409)}/_57,500 = ^12,788/_57,500 = 0.2224 = 22.24 cM Correct ^{(6,409 + 22,311)}/_57,500 = ^28,720/_57,500 = 0.4995 = 49.95 cM Incorrect ^{(6,409 + 22,401)}/_57,500 = ^28,810/_57,500 = 0.5010 = 50.10 cM Incorrect MC

804c_aee2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
artsy, tipsy	a	t	45,698
artsy	a	+	79,390
tipsy	+	t	79,585
wildtype	+	+	45,327
TOTAL =			250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(45,327 + 45,698)}/_250,000 = ^91,025/_250,000 = 0.3641 = 36.41 cM Correct ^{(45,327 + 79,390)}/_250,000 = ^124,717/_250,000 = 0.4989 = 49.89 cM Incorrect ^{(45,327 + 79,585)}/_250,000 = ^124,912/_250,000 = 0.4996 = 49.96 cM Incorrect ^{(45,698 + 79,390)}/_250,000 = ^125,088/_250,000 = 0.5004 = 50.04 cM Incorrect ^{(45,698 + 79,585)}/_250,000 = ^125,283/_250,000 = 0.5011 = 50.11 cM Incorrect ^{(79,390 + 79,585)}/_250,000 = ^158,975/_250,000 = 0.6359 = 63.59 cM Incorrect MC

541d_2b52

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
artsy, rusty	a	r	24,800
artsy	a	+	119,729
rusty	+	r	120,652
wildtype	+	+	24,819
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(119,729 + 120,652)}/_290,000 = ^240,381/_290,000 = 0.8289 = 82.89 cM Incorrect ^{(24,800 + 119,729)}/_290,000 = ^144,529/_290,000 = 0.4984 = 49.84 cM Incorrect ^{(24,800 + 120,652)}/_290,000 = ^145,452/_290,000 = 0.5016 = 50.16 cM Incorrect ^{(24,800 + 24,819)}/_290,000 = ^49,619/_290,000 = 0.1711 = 17.11 cM Correct ^{(24,819 + 119,729)}/_290,000 = ^144,548/_290,000 = 0.4984 = 49.84 cM Incorrect ^{(24,819 + 120,652)}/_290,000 = ^145,471/_290,000 = 0.5016 = 50.16 cM Incorrect MC

cc43_6494

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is correlated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
mushy, yucky	m	y	88,585
mushy	m	+	16,521
yucky	+	y	16,680
wildtype	+	+	88,214
TOTAL =			210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(16,521 + 16,680)}/_210,000 = ^33,201/_210,000 = 0.1581 = 15.81 cM Correct ^{(16,521 + 88,214)}/_210,000 = ^104,735/_210,000 = 0.4987 = 49.87 cM Incorrect ^{(16,521 + 88,585)}/_210,000 = ^105,106/_210,000 = 0.5005 = 50.05 cM Incorrect ^{(16,680 + 88,214)}/_210,000 = ^104,894/_210,000 = 0.4995 = 49.95 cM Incorrect ^{(16,680 + 88,585)}/_210,000 = ^105,265/_210,000 = 0.5013 = 50.13 cM Incorrect ^{(88,214 + 88,585)}/_210,000 = ^176,799/_210,000 = 0.8419 = 84.19 cM Incorrect MC

5dac_f902

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
horsey, jerky	h	j	4,846
horsey	h	+	44,895
jerky	+	j	45,485
wildtype	+	+	4,774
TOTAL =			100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,774 + 4,846)}/_100,000 = ^9,620/_100,000 = 0.0962 = 9.62 cM Correct ^{(4,774 + 44,895)}/_100,000 = ^49,669/_100,000 = 0.4967 = 49.67 cM Incorrect ^{(4,774 + 45,485)}/_100,000 = ^50,259/_100,000 = 0.5026 = 50.26 cM Incorrect ^{(4,846 + 44,895)}/_100,000 = ^49,741/_100,000 = 0.4974 = 49.74 cM Incorrect ^{(4,846 + 45,485)}/_100,000 = ^50,331/_100,000 = 0.5033 = 50.33 cM Incorrect ^{(44,895 + 45,485)}/_100,000 = ^90,380/_100,000 = 0.9038 = 90.38 cM Incorrect MC

cebc_4d8b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is connected with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
waxy, yucky	w	y	23,697
waxy	w	+	2,400
yucky	+	y	2,451
wildtype	+	+	23,952
TOTAL =			52,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,400 + 2,451)}/_52,500 = ^4,851/_52,500 = 0.0924 = 9.24 cM Correct ^{(2,400 + 23,697)}/_52,500 = ^26,097/_52,500 = 0.4971 = 49.71 cM Incorrect ^{(2,400 + 23,952)}/_52,500 = ^26,352/_52,500 = 0.5019 = 50.19 cM Incorrect ^{(2,451 + 23,697)}/_52,500 = ^26,148/_52,500 = 0.4981 = 49.81 cM Incorrect ^{(2,451 + 23,952)}/_52,500 = ^26,403/_52,500 = 0.5029 = 50.29 cM Incorrect ^{(23,697 + 23,952)}/_52,500 = ^47,649/_52,500 = 0.9076 = 90.76 cM Incorrect MC

c3be_ed1a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
xanthic, yucky	x	y	13,762
xanthic	x	+	41,196
yucky	+	y	41,326
wildtype	+	+	13,716
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,716 + 13,762)}/_110,000 = ^27,478/_110,000 = 0.2498 = 24.98 cM Correct ^{(13,716 + 41,196)}/_110,000 = ^54,912/_110,000 = 0.4992 = 49.92 cM Incorrect ^{(13,716 + 41,326)}/_110,000 = ^55,042/_110,000 = 0.5004 = 50.04 cM Incorrect ^{(13,762 + 41,196)}/_110,000 = ^54,958/_110,000 = 0.4996 = 49.96 cM Incorrect ^{(13,762 + 41,326)}/_110,000 = ^55,088/_110,000 = 0.5008 = 50.08 cM Incorrect ^{(41,196 + 41,326)}/_110,000 = ^82,522/_110,000 = 0.7502 = 75.02 cM Incorrect MC

38f6_74fc

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
horsey, xanthic	h	x	9,883
horsey	h	+	60,361
xanthic	+	x	60,067
wildtype	+	+	9,689
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(60,067 + 60,361)}/_140,000 = ^120,428/_140,000 = 0.8602 = 86.02 cM Incorrect ^{(9,689 + 60,067)}/_140,000 = ^69,756/_140,000 = 0.4983 = 49.83 cM Incorrect ^{(9,689 + 60,361)}/_140,000 = ^70,050/_140,000 = 0.5004 = 50.04 cM Incorrect ^{(9,689 + 9,883)}/_140,000 = ^19,572/_140,000 = 0.1398 = 13.98 cM Correct ^{(9,883 + 60,067)}/_140,000 = ^69,950/_140,000 = 0.4996 = 49.96 cM Incorrect ^{(9,883 + 60,361)}/_140,000 = ^70,244/_140,000 = 0.5017 = 50.17 cM Incorrect MC

99dc_0f88

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
artsy, mushy	a	m	1,238
artsy	a	+	3,863
mushy	+	m	3,682
wildtype	+	+	1,217
TOTAL =			10,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,217 + 1,238)}/_10,000 = ^2,455/_10,000 = 0.2455 = 24.55 cM Correct ^{(1,217 + 3,682)}/_10,000 = ^4,899/_10,000 = 0.4899 = 48.99 cM Incorrect ^{(1,217 + 3,863)}/_10,000 = ^5,080/_10,000 = 0.5080 = 50.80 cM Incorrect ^{(1,238 + 3,682)}/_10,000 = ^4,920/_10,000 = 0.4920 = 49.20 cM Incorrect ^{(3,682 + 3,863)}/_10,000 = ^7,545/_10,000 = 0.7545 = 75.45 cM Incorrect ^1,217/_10,000 = ^1,217/_10,000 = 0.1217 = 12.17 cM Incorrect MC

078e_3e33

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
artsy, mushy	a	m	98,416
artsy	a	+	26,315
mushy	+	m	26,460
wildtype	+	+	98,809
TOTAL =			250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(26,315 + 26,460)}/_250,000 = ^52,775/_250,000 = 0.2111 = 21.11 cM Correct ^{(26,315 + 98,416)}/_250,000 = ^124,731/_250,000 = 0.4989 = 49.89 cM Incorrect ^{(26,315 + 98,809)}/_250,000 = ^125,124/_250,000 = 0.5005 = 50.05 cM Incorrect ^{(26,460 + 98,416)}/_250,000 = ^124,876/_250,000 = 0.4995 = 49.95 cM Incorrect ^{(26,460 + 98,809)}/_250,000 = ^125,269/_250,000 = 0.5011 = 50.11 cM Incorrect ^{(98,416 + 98,809)}/_250,000 = ^197,225/_250,000 = 0.7889 = 78.89 cM Incorrect MC

5a8d_7f66

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
rusty, xanthic	r	x	11,558
rusty	r	+	3,379
xanthic	+	x	3,263
wildtype	+	+	11,800
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,558 + 11,800)}/_30,000 = ^23,358/_30,000 = 0.7786 = 77.86 cM Incorrect ^{(3,263 + 11,558)}/_30,000 = ^14,821/_30,000 = 0.4940 = 49.40 cM Incorrect ^{(3,263 + 11,800)}/_30,000 = ^15,063/_30,000 = 0.5021 = 50.21 cM Incorrect ^{(3,263 + 3,379)}/_30,000 = ^6,642/_30,000 = 0.2214 = 22.14 cM Correct ^{(3,379 + 11,558)}/_30,000 = ^14,937/_30,000 = 0.4979 = 49.79 cM Incorrect ^{(3,379 + 11,800)}/_30,000 = ^15,179/_30,000 = 0.5060 = 50.60 cM Incorrect MC

e5b2_9836

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is associated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
bumpy, chummy	b	c	73,735
bumpy	b	+	31,506
chummy	+	c	31,473
wildtype	+	+	73,286
TOTAL =			210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(31,473 + 31,506)}/_210,000 = ^62,979/_210,000 = 0.2999 = 29.99 cM Correct ^{(31,473 + 73,286)}/_210,000 = ^104,759/_210,000 = 0.4989 = 49.89 cM Incorrect ^{(31,473 + 73,735)}/_210,000 = ^105,208/_210,000 = 0.5010 = 50.10 cM Incorrect ^{(31,506 + 73,286)}/_210,000 = ^104,792/_210,000 = 0.4990 = 49.90 cM Incorrect ^{(31,506 + 73,735)}/_210,000 = ^105,241/_210,000 = 0.5011 = 50.11 cM Incorrect ^{(73,286 + 73,735)}/_210,000 = ^147,021/_210,000 = 0.7001 = 70.01 cM Incorrect MC

d5bf_47c1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
bumpy, chummy	b	c	34,336
bumpy	b	+	76,039
chummy	+	c	75,387
wildtype	+	+	34,238
TOTAL =			220,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(34,238 + 34,336)}/_220,000 = ^68,574/_220,000 = 0.3117 = 31.17 cM Correct ^{(34,238 + 75,387)}/_220,000 = ^109,625/_220,000 = 0.4983 = 49.83 cM Incorrect ^{(34,238 + 76,039)}/_220,000 = ^110,277/_220,000 = 0.5013 = 50.13 cM Incorrect ^{(34,336 + 75,387)}/_220,000 = ^109,723/_220,000 = 0.4987 = 49.87 cM Incorrect ^{(34,336 + 76,039)}/_220,000 = ^110,375/_220,000 = 0.5017 = 50.17 cM Incorrect ^{(75,387 + 76,039)}/_220,000 = ^151,426/_220,000 = 0.6883 = 68.83 cM Incorrect MC

23e7_9ed3

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is correlated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene D is analogous to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes		Progeny Count
artsy, dewy	a	d	4,386
artsy	a	+	8,212
dewy	+	d	8,023
wildtype	+	+	4,379
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,379 + 4,386)}/_25,000 = ^8,765/_25,000 = 0.3506 = 35.06 cM Correct ^{(4,379 + 8,023)}/_25,000 = ^12,402/_25,000 = 0.4961 = 49.61 cM Incorrect ^{(4,379 + 8,212)}/_25,000 = ^12,591/_25,000 = 0.5036 = 50.36 cM Incorrect ^{(4,386 + 8,023)}/_25,000 = ^12,409/_25,000 = 0.4964 = 49.64 cM Incorrect ^{(4,386 + 8,212)}/_25,000 = ^12,598/_25,000 = 0.5039 = 50.39 cM Incorrect ^{(8,023 + 8,212)}/_25,000 = ^16,235/_25,000 = 0.6494 = 64.94 cM Incorrect MC

9c1d_9c64

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
jerky, mushy	j	m	9,507
jerky	j	+	23,044
mushy	+	m	22,859
wildtype	+	+	9,590
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,859 + 23,044)}/_65,000 = ^45,903/_65,000 = 0.7062 = 70.62 cM Incorrect ^{(9,507 + 22,859)}/_65,000 = ^32,366/_65,000 = 0.4979 = 49.79 cM Incorrect ^{(9,507 + 23,044)}/_65,000 = ^32,551/_65,000 = 0.5008 = 50.08 cM Incorrect ^{(9,507 + 9,590)}/_65,000 = ^19,097/_65,000 = 0.2938 = 29.38 cM Correct ^{(9,590 + 22,859)}/_65,000 = ^32,449/_65,000 = 0.4992 = 49.92 cM Incorrect ^{(9,590 + 23,044)}/_65,000 = ^32,634/_65,000 = 0.5021 = 50.21 cM Incorrect MC

8986_bc23

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
jerky, waxy	j	w	3,596
jerky	j	+	412
waxy	+	w	444
wildtype	+	+	3,548
TOTAL =			8,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(3,548 + 3,596)}/_8,000 = ^7,144/_8,000 = 0.8930 = 89.30 cM Incorrect ^{(412 + 3,548)}/_8,000 = ^3,960/_8,000 = 0.4950 = 49.50 cM Incorrect ^{(412 + 3,596)}/_8,000 = ^4,008/_8,000 = 0.5010 = 50.10 cM Incorrect ^{(412 + 444)}/_8,000 = ⁸⁵⁶/_8,000 = 0.1070 = 10.70 cM Correct ^{(444 + 3,548)}/_8,000 = ^3,992/_8,000 = 0.4990 = 49.90 cM Incorrect ^{(444 + 3,596)}/_8,000 = ^4,040/_8,000 = 0.5050 = 50.50 cM Incorrect MC

f82c_82de

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene P is related to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
kidney, prickly	k	p	11,273
kidney	k	+	46,585
prickly	+	p	45,898
wildtype	+	+	11,244
TOTAL =			115,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,244 + 11,273)}/_115,000 = ^22,517/_115,000 = 0.1958 = 19.58 cM Correct ^{(11,244 + 45,898)}/_115,000 = ^57,142/_115,000 = 0.4969 = 49.69 cM Incorrect ^{(11,244 + 46,585)}/_115,000 = ^57,829/_115,000 = 0.5029 = 50.29 cM Incorrect ^{(11,273 + 45,898)}/_115,000 = ^57,171/_115,000 = 0.4971 = 49.71 cM Incorrect ^{(11,273 + 46,585)}/_115,000 = ^57,858/_115,000 = 0.5031 = 50.31 cM Incorrect ^{(45,898 + 46,585)}/_115,000 = ^92,483/_115,000 = 0.8042 = 80.42 cM Incorrect MC

ee78_fa91

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
horsey, rusty	h	r	9,447
horsey	h	+	35,779
rusty	+	r	35,150
wildtype	+	+	9,624
TOTAL =			90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(35,150 + 35,779)}/_90,000 = ^70,929/_90,000 = 0.7881 = 78.81 cM Incorrect ^{(9,447 + 35,150)}/_90,000 = ^44,597/_90,000 = 0.4955 = 49.55 cM Incorrect ^{(9,447 + 35,779)}/_90,000 = ^45,226/_90,000 = 0.5025 = 50.25 cM Incorrect ^{(9,447 + 9,624)}/_90,000 = ^19,071/_90,000 = 0.2119 = 21.19 cM Correct ^{(9,624 + 35,150)}/_90,000 = ^44,774/_90,000 = 0.4975 = 49.75 cM Incorrect ^{(9,624 + 35,779)}/_90,000 = ^45,403/_90,000 = 0.5045 = 50.45 cM Incorrect MC

f2d3_6114

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
horsey, xanthic	h	x	30,106
horsey	h	+	64,718
xanthic	+	x	65,185
wildtype	+	+	29,991
TOTAL =			190,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(29,991 + 30,106)}/_190,000 = ^60,097/_190,000 = 0.3163 = 31.63 cM Correct ^{(29,991 + 64,718)}/_190,000 = ^94,709/_190,000 = 0.4985 = 49.85 cM Incorrect ^{(29,991 + 65,185)}/_190,000 = ^95,176/_190,000 = 0.5009 = 50.09 cM Incorrect ^{(30,106 + 64,718)}/_190,000 = ^94,824/_190,000 = 0.4991 = 49.91 cM Incorrect ^{(30,106 + 65,185)}/_190,000 = ^95,291/_190,000 = 0.5015 = 50.15 cM Incorrect ^{(64,718 + 65,185)}/_190,000 = ^129,903/_190,000 = 0.6837 = 68.37 cM Incorrect MC

ec20_7060

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene R is analogous to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
nerdy, rusty	n	r	57,944
nerdy	n	+	17,071
rusty	+	r	17,174
wildtype	+	+	57,811
TOTAL =			150,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(17,071 + 17,174)}/_150,000 = ^34,245/_150,000 = 0.2283 = 22.83 cM Correct ^{(17,071 + 57,811)}/_150,000 = ^74,882/_150,000 = 0.4992 = 49.92 cM Incorrect ^{(17,071 + 57,944)}/_150,000 = ^75,015/_150,000 = 0.5001 = 50.01 cM Incorrect ^{(17,174 + 57,811)}/_150,000 = ^74,985/_150,000 = 0.4999 = 49.99 cM Incorrect ^{(17,174 + 57,944)}/_150,000 = ^75,118/_150,000 = 0.5008 = 50.08 cM Incorrect ^{(57,811 + 57,944)}/_150,000 = ^115,755/_150,000 = 0.7717 = 77.17 cM Incorrect MC

8dcc_4e36

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
artsy, prickly	a	p	7,526
artsy	a	+	3,448
prickly	+	p	3,449
wildtype	+	+	7,577
TOTAL =			22,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(3,448 + 3,449)}/_22,000 = ^6,897/_22,000 = 0.3135 = 31.35 cM Correct ^{(3,448 + 7,526)}/_22,000 = ^10,974/_22,000 = 0.4988 = 49.88 cM Incorrect ^{(3,448 + 7,577)}/_22,000 = ^11,025/_22,000 = 0.5011 = 50.11 cM Incorrect ^{(3,449 + 7,526)}/_22,000 = ^10,975/_22,000 = 0.4989 = 49.89 cM Incorrect ^{(3,449 + 7,577)}/_22,000 = ^11,026/_22,000 = 0.5012 = 50.12 cM Incorrect ^{(7,526 + 7,577)}/_22,000 = ^15,103/_22,000 = 0.6865 = 68.65 cM Incorrect MC

7318_ae40

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
mushy, tipsy	m	t	740
mushy	m	+	4,850
tipsy	+	t	4,866
wildtype	+	+	744
TOTAL =			11,200

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,850 + 4,866)}/_11,200 = ^9,716/_11,200 = 0.8675 = 86.75 cM Incorrect ^{(740 + 4,850)}/_11,200 = ^5,590/_11,200 = 0.4991 = 49.91 cM Incorrect ^{(740 + 4,866)}/_11,200 = ^5,606/_11,200 = 0.5005 = 50.05 cM Incorrect ^{(740 + 744)}/_11,200 = ^1,484/_11,200 = 0.1325 = 13.25 cM Correct ^{(744 + 4,850)}/_11,200 = ^5,594/_11,200 = 0.4995 = 49.95 cM Incorrect ^{(744 + 4,866)}/_11,200 = ^5,610/_11,200 = 0.5009 = 50.09 cM Incorrect MC

fa4b_b487

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
artsy, tipsy	a	t	18,981
artsy	a	+	96,127
tipsy	+	t	96,176
wildtype	+	+	18,716
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(18,716 + 18,981)}/_230,000 = ^37,697/_230,000 = 0.1639 = 16.39 cM Correct ^{(18,716 + 96,127)}/_230,000 = ^114,843/_230,000 = 0.4993 = 49.93 cM Incorrect ^{(18,716 + 96,176)}/_230,000 = ^114,892/_230,000 = 0.4995 = 49.95 cM Incorrect ^{(18,981 + 96,127)}/_230,000 = ^115,108/_230,000 = 0.5005 = 50.05 cM Incorrect ^{(18,981 + 96,176)}/_230,000 = ^115,157/_230,000 = 0.5007 = 50.07 cM Incorrect ^{(96,127 + 96,176)}/_230,000 = ^192,303/_230,000 = 0.8361 = 83.61 cM Incorrect MC

d520_c8c5

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
mushy, waxy	m	w	74,369
mushy	m	+	10,492
waxy	+	w	10,537
wildtype	+	+	74,602
TOTAL =			170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,492 + 10,537)}/_170,000 = ^21,029/_170,000 = 0.1237 = 12.37 cM Correct ^{(10,492 + 74,369)}/_170,000 = ^84,861/_170,000 = 0.4992 = 49.92 cM Incorrect ^{(10,492 + 74,602)}/_170,000 = ^85,094/_170,000 = 0.5006 = 50.06 cM Incorrect ^{(10,537 + 74,369)}/_170,000 = ^84,906/_170,000 = 0.4994 = 49.94 cM Incorrect ^{(10,537 + 74,602)}/_170,000 = ^85,139/_170,000 = 0.5008 = 50.08 cM Incorrect ^{(74,369 + 74,602)}/_170,000 = ^148,971/_170,000 = 0.8763 = 87.63 cM Incorrect MC

953f_45a8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene P is related to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
kidney, prickly	k	p	4,980
kidney	k	+	7,557
prickly	+	p	7,488
wildtype	+	+	4,975
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,975 + 4,980)}/_25,000 = ^9,955/_25,000 = 0.3982 = 39.82 cM Correct ^{(4,975 + 7,488)}/_25,000 = ^12,463/_25,000 = 0.4985 = 49.85 cM Incorrect ^{(4,975 + 7,557)}/_25,000 = ^12,532/_25,000 = 0.5013 = 50.13 cM Incorrect ^{(4,980 + 7,488)}/_25,000 = ^12,468/_25,000 = 0.4987 = 49.87 cM Incorrect ^{(4,980 + 7,557)}/_25,000 = ^12,537/_25,000 = 0.5015 = 50.15 cM Incorrect ^{(7,488 + 7,557)}/_25,000 = ^15,045/_25,000 = 0.6018 = 60.18 cM Incorrect MC

075f_a977

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
dewy, waxy	d	w	13,958
dewy	d	+	23,597
waxy	+	w	23,608
wildtype	+	+	13,837
TOTAL =			75,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,837 + 13,958)}/_75,000 = ^27,795/_75,000 = 0.3706 = 37.06 cM Correct ^{(13,837 + 23,597)}/_75,000 = ^37,434/_75,000 = 0.4991 = 49.91 cM Incorrect ^{(13,837 + 23,608)}/_75,000 = ^37,445/_75,000 = 0.4993 = 49.93 cM Incorrect ^{(13,958 + 23,597)}/_75,000 = ^37,555/_75,000 = 0.5007 = 50.07 cM Incorrect ^{(13,958 + 23,608)}/_75,000 = ^37,566/_75,000 = 0.5009 = 50.09 cM Incorrect ^{(23,597 + 23,608)}/_75,000 = ^47,205/_75,000 = 0.6294 = 62.94 cM Incorrect MC

fa44_e63a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
horsey, mushy	h	m	21,054
horsey	h	+	48,934
mushy	+	m	48,968
wildtype	+	+	21,044
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(21,044 + 21,054)}/_140,000 = ^42,098/_140,000 = 0.3007 = 30.07 cM Correct ^{(21,044 + 48,934)}/_140,000 = ^69,978/_140,000 = 0.4998 = 49.98 cM Incorrect ^{(21,044 + 48,968)}/_140,000 = ^70,012/_140,000 = 0.5001 = 50.01 cM Incorrect ^{(21,054 + 48,934)}/_140,000 = ^69,988/_140,000 = 0.4999 = 49.99 cM Incorrect ^{(21,054 + 48,968)}/_140,000 = ^70,022/_140,000 = 0.5002 = 50.02 cM Incorrect ^{(48,934 + 48,968)}/_140,000 = ^97,902/_140,000 = 0.6993 = 69.93 cM Incorrect MC

ed70_86f9

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
horsey, rusty	h	r	27,102
horsey	h	+	43,136
rusty	+	r	42,642
wildtype	+	+	27,120
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(27,102 + 27,120)}/_140,000 = ^54,222/_140,000 = 0.3873 = 38.73 cM Correct ^{(27,102 + 42,642)}/_140,000 = ^69,744/_140,000 = 0.4982 = 49.82 cM Incorrect ^{(27,102 + 43,136)}/_140,000 = ^70,238/_140,000 = 0.5017 = 50.17 cM Incorrect ^{(27,120 + 42,642)}/_140,000 = ^69,762/_140,000 = 0.4983 = 49.83 cM Incorrect ^{(27,120 + 43,136)}/_140,000 = ^70,256/_140,000 = 0.5018 = 50.18 cM Incorrect ^{(42,642 + 43,136)}/_140,000 = ^85,778/_140,000 = 0.6127 = 61.27 cM Incorrect MC

ead0_3e2a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene T is related to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
tipsy, waxy	t	w	3,277
tipsy	t	+	11,584
waxy	+	w	11,750
wildtype	+	+	3,389
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,584 + 11,750)}/_30,000 = ^23,334/_30,000 = 0.7778 = 77.78 cM Incorrect ^{(3,277 + 11,584)}/_30,000 = ^14,861/_30,000 = 0.4954 = 49.54 cM Incorrect ^{(3,277 + 11,750)}/_30,000 = ^15,027/_30,000 = 0.5009 = 50.09 cM Incorrect ^{(3,277 + 3,389)}/_30,000 = ^6,666/_30,000 = 0.2222 = 22.22 cM Correct ^{(3,389 + 11,584)}/_30,000 = ^14,973/_30,000 = 0.4991 = 49.91 cM Incorrect ^{(3,389 + 11,750)}/_30,000 = ^15,139/_30,000 = 0.5046 = 50.46 cM Incorrect MC

1a19_37f4

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is correlated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
eery, kidney	e	k	23,912
eery	e	+	86,557
kidney	+	k	85,945
wildtype	+	+	23,586
TOTAL =			220,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(23,586 + 23,912)}/_220,000 = ^47,498/_220,000 = 0.2159 = 21.59 cM Correct ^{(23,586 + 85,945)}/_220,000 = ^109,531/_220,000 = 0.4979 = 49.79 cM Incorrect ^{(23,586 + 86,557)}/_220,000 = ^110,143/_220,000 = 0.5007 = 50.07 cM Incorrect ^{(23,912 + 85,945)}/_220,000 = ^109,857/_220,000 = 0.4994 = 49.94 cM Incorrect ^{(23,912 + 86,557)}/_220,000 = ^110,469/_220,000 = 0.5021 = 50.21 cM Incorrect ^{(85,945 + 86,557)}/_220,000 = ^172,502/_220,000 = 0.7841 = 78.41 cM Incorrect MC

43bd_bea7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is related to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
jerky, kidney	j	k	10,252
jerky	j	+	54,885
kidney	+	k	54,601
wildtype	+	+	10,262
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,252 + 10,262)}/_130,000 = ^20,514/_130,000 = 0.1578 = 15.78 cM Correct ^{(10,252 + 54,601)}/_130,000 = ^64,853/_130,000 = 0.4989 = 49.89 cM Incorrect ^{(10,252 + 54,885)}/_130,000 = ^65,137/_130,000 = 0.5011 = 50.11 cM Incorrect ^{(10,262 + 54,601)}/_130,000 = ^64,863/_130,000 = 0.4989 = 49.89 cM Incorrect ^{(10,262 + 54,885)}/_130,000 = ^65,147/_130,000 = 0.5011 = 50.11 cM Incorrect ^{(54,601 + 54,885)}/_130,000 = ^109,486/_130,000 = 0.8422 = 84.22 cM Incorrect MC

7fa7_f0d2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
chummy, eery	c	e	36,909
chummy	c	+	12,809
eery	+	e	13,101
wildtype	+	+	37,181
TOTAL =			100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,809 + 13,101)}/_100,000 = ^25,910/_100,000 = 0.2591 = 25.91 cM Correct ^{(12,809 + 36,909)}/_100,000 = ^49,718/_100,000 = 0.4972 = 49.72 cM Incorrect ^{(12,809 + 37,181)}/_100,000 = ^49,990/_100,000 = 0.4999 = 49.99 cM Incorrect ^{(13,101 + 36,909)}/_100,000 = ^50,010/_100,000 = 0.5001 = 50.01 cM Incorrect ^{(13,101 + 37,181)}/_100,000 = ^50,282/_100,000 = 0.5028 = 50.28 cM Incorrect ^{(36,909 + 37,181)}/_100,000 = ^74,090/_100,000 = 0.7409 = 74.09 cM Incorrect MC

ca85_278f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
chummy, eery	c	e	21,711
chummy	c	+	68,592
eery	+	e	68,190
wildtype	+	+	21,507
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(21,507 + 21,711)}/_180,000 = ^43,218/_180,000 = 0.2401 = 24.01 cM Correct ^{(21,507 + 68,190)}/_180,000 = ^89,697/_180,000 = 0.4983 = 49.83 cM Incorrect ^{(21,507 + 68,592)}/_180,000 = ^90,099/_180,000 = 0.5006 = 50.06 cM Incorrect ^{(21,711 + 68,190)}/_180,000 = ^89,901/_180,000 = 0.4995 = 49.95 cM Incorrect ^{(21,711 + 68,592)}/_180,000 = ^90,303/_180,000 = 0.5017 = 50.17 cM Incorrect ^{(68,190 + 68,592)}/_180,000 = ^136,782/_180,000 = 0.7599 = 75.99 cM Incorrect MC

5dc8_b242

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
chummy, nerdy	c	n	12,162
chummy	c	+	3,912
nerdy	+	n	3,944
wildtype	+	+	11,982
TOTAL =			32,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,982 + 12,162)}/_32,000 = ^24,144/_32,000 = 0.7545 = 75.45 cM Incorrect ^{(3,912 + 11,982)}/_32,000 = ^15,894/_32,000 = 0.4967 = 49.67 cM Incorrect ^{(3,912 + 12,162)}/_32,000 = ^16,074/_32,000 = 0.5023 = 50.23 cM Incorrect ^{(3,912 + 3,944)}/_32,000 = ^7,856/_32,000 = 0.2455 = 24.55 cM Correct ^{(3,944 + 11,982)}/_32,000 = ^15,926/_32,000 = 0.4977 = 49.77 cM Incorrect ^{(3,944 + 12,162)}/_32,000 = ^16,106/_32,000 = 0.5033 = 50.33 cM Incorrect MC

b0c9_5e00

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is associated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
artsy, eery	a	e	27,181
artsy	a	+	5,426
eery	+	e	5,377
wildtype	+	+	27,016
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(27,016 + 27,181)}/_65,000 = ^54,197/_65,000 = 0.8338 = 83.38 cM Incorrect ^{(5,377 + 27,016)}/_65,000 = ^32,393/_65,000 = 0.4984 = 49.84 cM Incorrect ^{(5,377 + 27,181)}/_65,000 = ^32,558/_65,000 = 0.5009 = 50.09 cM Incorrect ^{(5,377 + 5,426)}/_65,000 = ^10,803/_65,000 = 0.1662 = 16.62 cM Correct ^{(5,426 + 27,016)}/_65,000 = ^32,442/_65,000 = 0.4991 = 49.91 cM Incorrect ^{(5,426 + 27,181)}/_65,000 = ^32,607/_65,000 = 0.5016 = 50.16 cM Incorrect MC

7746_ec76

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is related to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
nerdy, tipsy	n	t	18,406
nerdy	n	+	6,625
tipsy	+	t	6,700
wildtype	+	+	18,269
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(18,269 + 18,406)}/_50,000 = ^36,675/_50,000 = 0.7335 = 73.35 cM Incorrect ^{(6,625 + 18,269)}/_50,000 = ^24,894/_50,000 = 0.4979 = 49.79 cM Incorrect ^{(6,625 + 18,406)}/_50,000 = ^25,031/_50,000 = 0.5006 = 50.06 cM Incorrect ^{(6,625 + 6,700)}/_50,000 = ^13,325/_50,000 = 0.2665 = 26.65 cM Correct ^{(6,700 + 18,269)}/_50,000 = ^24,969/_50,000 = 0.4994 = 49.94 cM Incorrect ^{(6,700 + 18,406)}/_50,000 = ^25,106/_50,000 = 0.5021 = 50.21 cM Incorrect MC

86b5_a8f7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
fuzzy, waxy	f	w	19,815
fuzzy	f	+	30,039
waxy	+	w	30,051
wildtype	+	+	20,095
TOTAL =			100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(19,815 + 20,095)}/_100,000 = ^39,910/_100,000 = 0.3991 = 39.91 cM Correct ^{(19,815 + 30,039)}/_100,000 = ^49,854/_100,000 = 0.4985 = 49.85 cM Incorrect ^{(19,815 + 30,051)}/_100,000 = ^49,866/_100,000 = 0.4987 = 49.87 cM Incorrect ^{(20,095 + 30,039)}/_100,000 = ^50,134/_100,000 = 0.5013 = 50.13 cM Incorrect ^{(20,095 + 30,051)}/_100,000 = ^50,146/_100,000 = 0.5015 = 50.15 cM Incorrect ^{(30,039 + 30,051)}/_100,000 = ^60,090/_100,000 = 0.6009 = 60.09 cM Incorrect MC

e1d0_a9e3

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
artsy, xanthic	a	x	15,989
artsy	a	+	84,108
xanthic	+	x	84,072
wildtype	+	+	15,831
TOTAL =			200,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(15,831 + 15,989)}/_200,000 = ^31,820/_200,000 = 0.1591 = 15.91 cM Correct ^{(15,831 + 84,072)}/_200,000 = ^99,903/_200,000 = 0.4995 = 49.95 cM Incorrect ^{(15,831 + 84,108)}/_200,000 = ^99,939/_200,000 = 0.4997 = 49.97 cM Incorrect ^{(15,989 + 84,072)}/_200,000 = ^100,061/_200,000 = 0.5003 = 50.03 cM Incorrect ^{(15,989 + 84,108)}/_200,000 = ^100,097/_200,000 = 0.5005 = 50.05 cM Incorrect ^{(84,072 + 84,108)}/_200,000 = ^168,180/_200,000 = 0.8409 = 84.09 cM Incorrect MC

f193_2624

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
jerky, mushy	j	m	843
jerky	j	+	7,093
mushy	+	m	7,219
wildtype	+	+	845
TOTAL =			16,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(7,093 + 7,219)}/_16,000 = ^14,312/_16,000 = 0.8945 = 89.45 cM Incorrect ^{(843 + 7,093)}/_16,000 = ^7,936/_16,000 = 0.4960 = 49.60 cM Incorrect ^{(843 + 7,219)}/_16,000 = ^8,062/_16,000 = 0.5039 = 50.39 cM Incorrect ^{(843 + 845)}/_16,000 = ^1,688/_16,000 = 0.1055 = 10.55 cM Correct ^{(845 + 7,093)}/_16,000 = ^7,938/_16,000 = 0.4961 = 49.61 cM Incorrect ^{(845 + 7,219)}/_16,000 = ^8,064/_16,000 = 0.5040 = 50.40 cM Incorrect MC

f0c4_7010

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
rusty, yucky	r	y	5,856
rusty	r	+	17,897
yucky	+	y	17,880
wildtype	+	+	5,867
TOTAL =			47,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(17,880 + 17,897)}/_47,500 = ^35,777/_47,500 = 0.7532 = 75.32 cM Incorrect ^{(5,856 + 17,880)}/_47,500 = ^23,736/_47,500 = 0.4997 = 49.97 cM Incorrect ^{(5,856 + 17,897)}/_47,500 = ^23,753/_47,500 = 0.5001 = 50.01 cM Incorrect ^{(5,856 + 5,867)}/_47,500 = ^11,723/_47,500 = 0.2468 = 24.68 cM Correct ^{(5,867 + 17,880)}/_47,500 = ^23,747/_47,500 = 0.4999 = 49.99 cM Incorrect ^{(5,867 + 17,897)}/_47,500 = ^23,764/_47,500 = 0.5003 = 50.03 cM Incorrect MC

0d31_2202

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
nerdy, xanthic	n	x	11,634
nerdy	n	+	4,625
xanthic	+	x	4,527
wildtype	+	+	11,714
TOTAL =			32,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,634 + 11,714)}/_32,500 = ^23,348/_32,500 = 0.7184 = 71.84 cM Incorrect ^{(4,527 + 11,634)}/_32,500 = ^16,161/_32,500 = 0.4973 = 49.73 cM Incorrect ^{(4,527 + 11,714)}/_32,500 = ^16,241/_32,500 = 0.4997 = 49.97 cM Incorrect ^{(4,527 + 4,625)}/_32,500 = ^9,152/_32,500 = 0.2816 = 28.16 cM Correct ^{(4,625 + 11,634)}/_32,500 = ^16,259/_32,500 = 0.5003 = 50.03 cM Incorrect ^{(4,625 + 11,714)}/_32,500 = ^16,339/_32,500 = 0.5027 = 50.27 cM Incorrect MC

7aff_8888

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is analogous to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene C is affiliated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
bumpy, chummy	b	c	4,660
bumpy	b	+	16,542
chummy	+	c	16,281
wildtype	+	+	4,517
TOTAL =			42,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(16,281 + 16,542)}/_42,000 = ^32,823/_42,000 = 0.7815 = 78.15 cM Incorrect ^{(4,517 + 16,281)}/_42,000 = ^20,798/_42,000 = 0.4952 = 49.52 cM Incorrect ^{(4,517 + 16,542)}/_42,000 = ^21,059/_42,000 = 0.5014 = 50.14 cM Incorrect ^{(4,517 + 4,660)}/_42,000 = ^9,177/_42,000 = 0.2185 = 21.85 cM Correct ^{(4,660 + 16,281)}/_42,000 = ^20,941/_42,000 = 0.4986 = 49.86 cM Incorrect ^{(4,660 + 16,542)}/_42,000 = ^21,202/_42,000 = 0.5048 = 50.48 cM Incorrect MC

e7d5_d5fd

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
chummy, xanthic	c	x	25,386
chummy	c	+	44,516
xanthic	+	x	44,776
wildtype	+	+	25,322
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(25,322 + 25,386)}/_140,000 = ^50,708/_140,000 = 0.3622 = 36.22 cM Correct ^{(25,322 + 44,516)}/_140,000 = ^69,838/_140,000 = 0.4988 = 49.88 cM Incorrect ^{(25,322 + 44,776)}/_140,000 = ^70,098/_140,000 = 0.5007 = 50.07 cM Incorrect ^{(25,386 + 44,516)}/_140,000 = ^69,902/_140,000 = 0.4993 = 49.93 cM Incorrect ^{(25,386 + 44,776)}/_140,000 = ^70,162/_140,000 = 0.5012 = 50.12 cM Incorrect ^{(44,516 + 44,776)}/_140,000 = ^89,292/_140,000 = 0.6378 = 63.78 cM Incorrect MC

2a6c_49c7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
artsy, chummy	a	c	9,712
artsy	a	+	21,527
chummy	+	c	21,698
wildtype	+	+	9,563
TOTAL =			62,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(21,527 + 21,698)}/_62,500 = ^43,225/_62,500 = 0.6916 = 69.16 cM Incorrect ^{(9,563 + 21,527)}/_62,500 = ^31,090/_62,500 = 0.4974 = 49.74 cM Incorrect ^{(9,563 + 21,698)}/_62,500 = ^31,261/_62,500 = 0.5002 = 50.02 cM Incorrect ^{(9,563 + 9,712)}/_62,500 = ^19,275/_62,500 = 0.3084 = 30.84 cM Correct ^{(9,712 + 21,527)}/_62,500 = ^31,239/_62,500 = 0.4998 = 49.98 cM Incorrect ^{(9,712 + 21,698)}/_62,500 = ^31,410/_62,500 = 0.5026 = 50.26 cM Incorrect MC

f92a_e4e7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is connected with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene H is related to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
dewy, horsey	d	h	38,911
dewy	d	+	23,728
horsey	+	h	23,547
wildtype	+	+	38,814
TOTAL =			125,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(23,547 + 23,728)}/_125,000 = ^47,275/_125,000 = 0.3782 = 37.82 cM Correct ^{(23,547 + 38,814)}/_125,000 = ^62,361/_125,000 = 0.4989 = 49.89 cM Incorrect ^{(23,547 + 38,911)}/_125,000 = ^62,458/_125,000 = 0.4997 = 49.97 cM Incorrect ^{(23,728 + 38,814)}/_125,000 = ^62,542/_125,000 = 0.5003 = 50.03 cM Incorrect ^{(23,728 + 38,911)}/_125,000 = ^62,639/_125,000 = 0.5011 = 50.11 cM Incorrect ^{(38,814 + 38,911)}/_125,000 = ^77,725/_125,000 = 0.6218 = 62.18 cM Incorrect MC

f094_7dbb

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
jerky, yucky	j	y	13,073
jerky	j	+	49,338
yucky	+	y	49,187
wildtype	+	+	13,402
TOTAL =			125,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,073 + 13,402)}/_125,000 = ^26,475/_125,000 = 0.2118 = 21.18 cM Correct ^{(13,073 + 49,187)}/_125,000 = ^62,260/_125,000 = 0.4981 = 49.81 cM Incorrect ^{(13,073 + 49,338)}/_125,000 = ^62,411/_125,000 = 0.4993 = 49.93 cM Incorrect ^{(13,402 + 49,187)}/_125,000 = ^62,589/_125,000 = 0.5007 = 50.07 cM Incorrect ^{(13,402 + 49,338)}/_125,000 = ^62,740/_125,000 = 0.5019 = 50.19 cM Incorrect ^{(49,187 + 49,338)}/_125,000 = ^98,525/_125,000 = 0.7882 = 78.82 cM Incorrect MC

a6bb_d1a8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene W is associated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
jerky, waxy	j	w	38,894
jerky	j	+	95,942
waxy	+	w	96,055
wildtype	+	+	39,109
TOTAL =			270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(38,894 + 39,109)}/_270,000 = ^78,003/_270,000 = 0.2889 = 28.89 cM Correct ^{(38,894 + 95,942)}/_270,000 = ^134,836/_270,000 = 0.4994 = 49.94 cM Incorrect ^{(38,894 + 96,055)}/_270,000 = ^134,949/_270,000 = 0.4998 = 49.98 cM Incorrect ^{(39,109 + 95,942)}/_270,000 = ^135,051/_270,000 = 0.5002 = 50.02 cM Incorrect ^{(39,109 + 96,055)}/_270,000 = ^135,164/_270,000 = 0.5006 = 50.06 cM Incorrect ^{(95,942 + 96,055)}/_270,000 = ^191,997/_270,000 = 0.7111 = 71.11 cM Incorrect MC

ca9e_2b96

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
fuzzy, mushy	f	m	3,115
fuzzy	f	+	12,841
mushy	+	m	12,967
wildtype	+	+	3,077
TOTAL =			32,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,841 + 12,967)}/_32,000 = ^25,808/_32,000 = 0.8065 = 80.65 cM Incorrect ^{(3,077 + 12,841)}/_32,000 = ^15,918/_32,000 = 0.4974 = 49.74 cM Incorrect ^{(3,077 + 12,967)}/_32,000 = ^16,044/_32,000 = 0.5014 = 50.14 cM Incorrect ^{(3,077 + 3,115)}/_32,000 = ^6,192/_32,000 = 0.1935 = 19.35 cM Correct ^{(3,115 + 12,841)}/_32,000 = ^15,956/_32,000 = 0.4986 = 49.86 cM Incorrect ^{(3,115 + 12,967)}/_32,000 = ^16,082/_32,000 = 0.5026 = 50.26 cM Incorrect MC

3b4b_0524

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is correlated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene P is correlated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
artsy, prickly	a	p	4,267
artsy	a	+	14,612
prickly	+	p	14,428
wildtype	+	+	4,193
TOTAL =			37,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,428 + 14,612)}/_37,500 = ^29,040/_37,500 = 0.7744 = 77.44 cM Incorrect ^{(4,193 + 14,428)}/_37,500 = ^18,621/_37,500 = 0.4966 = 49.66 cM Incorrect ^{(4,193 + 14,612)}/_37,500 = ^18,805/_37,500 = 0.5015 = 50.15 cM Incorrect ^{(4,193 + 4,267)}/_37,500 = ^8,460/_37,500 = 0.2256 = 22.56 cM Correct ^{(4,267 + 14,428)}/_37,500 = ^18,695/_37,500 = 0.4985 = 49.85 cM Incorrect ^{(4,267 + 14,612)}/_37,500 = ^18,879/_37,500 = 0.5034 = 50.34 cM Incorrect MC

8860_bae1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
mushy, prickly	m	p	13,923
mushy	m	+	106,099
prickly	+	p	105,893
wildtype	+	+	14,085
TOTAL =			240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(105,893 + 106,099)}/_240,000 = ^211,992/_240,000 = 0.8833 = 88.33 cM Incorrect ^{(13,923 + 105,893)}/_240,000 = ^119,816/_240,000 = 0.4992 = 49.92 cM Incorrect ^{(13,923 + 106,099)}/_240,000 = ^120,022/_240,000 = 0.5001 = 50.01 cM Incorrect ^{(13,923 + 14,085)}/_240,000 = ^28,008/_240,000 = 0.1167 = 11.67 cM Correct ^{(14,085 + 105,893)}/_240,000 = ^119,978/_240,000 = 0.4999 = 49.99 cM Incorrect ^{(14,085 + 106,099)}/_240,000 = ^120,184/_240,000 = 0.5008 = 50.08 cM Incorrect MC

cb36_a11f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
kidney, mushy	k	m	2,427
kidney	k	+	370
mushy	+	m	456
wildtype	+	+	2,347
TOTAL =			5,600

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,347 + 2,427)}/_5,600 = ^4,774/_5,600 = 0.8525 = 85.25 cM Incorrect ^{(370 + 2,347)}/_5,600 = ^2,717/_5,600 = 0.4852 = 48.52 cM Incorrect ^{(370 + 2,427)}/_5,600 = ^2,797/_5,600 = 0.4995 = 49.95 cM Incorrect ^{(370 + 456)}/_5,600 = ⁸²⁶/_5,600 = 0.1475 = 14.75 cM Correct ^{(456 + 2,347)}/_5,600 = ^2,803/_5,600 = 0.5005 = 50.05 cM Incorrect ³⁷⁰/_5,600 = ³⁷⁰/_5,600 = 0.0661 = 6.61 cM Incorrect MC

5bcb_d95e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
chummy, tipsy	c	t	53,362
chummy	c	+	91,575
tipsy	+	t	92,024
wildtype	+	+	53,039
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(53,039 + 53,362)}/_290,000 = ^106,401/_290,000 = 0.3669 = 36.69 cM Correct ^{(53,039 + 91,575)}/_290,000 = ^144,614/_290,000 = 0.4987 = 49.87 cM Incorrect ^{(53,039 + 92,024)}/_290,000 = ^145,063/_290,000 = 0.5002 = 50.02 cM Incorrect ^{(53,362 + 91,575)}/_290,000 = ^144,937/_290,000 = 0.4998 = 49.98 cM Incorrect ^{(53,362 + 92,024)}/_290,000 = ^145,386/_290,000 = 0.5013 = 50.13 cM Incorrect ^{(91,575 + 92,024)}/_290,000 = ^183,599/_290,000 = 0.6331 = 63.31 cM Incorrect MC

ed59_456f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
eery, prickly	e	p	20,545
eery	e	+	7,196
prickly	+	p	7,038
wildtype	+	+	20,221
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(20,221 + 20,545)}/_55,000 = ^40,766/_55,000 = 0.7412 = 74.12 cM Incorrect ^{(7,038 + 20,221)}/_55,000 = ^27,259/_55,000 = 0.4956 = 49.56 cM Incorrect ^{(7,038 + 20,545)}/_55,000 = ^27,583/_55,000 = 0.5015 = 50.15 cM Incorrect ^{(7,038 + 7,196)}/_55,000 = ^14,234/_55,000 = 0.2588 = 25.88 cM Correct ^{(7,196 + 20,221)}/_55,000 = ^27,417/_55,000 = 0.4985 = 49.85 cM Incorrect ^{(7,196 + 20,545)}/_55,000 = ^27,741/_55,000 = 0.5044 = 50.44 cM Incorrect MC

9ce4_cbb9

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is analogous to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
nerdy, yucky	n	y	5,825
nerdy	n	+	12,951
yucky	+	y	12,954
wildtype	+	+	5,770
TOTAL =			37,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,951 + 12,954)}/_37,500 = ^25,905/_37,500 = 0.6908 = 69.08 cM Incorrect ^{(5,770 + 12,951)}/_37,500 = ^18,721/_37,500 = 0.4992 = 49.92 cM Incorrect ^{(5,770 + 12,954)}/_37,500 = ^18,724/_37,500 = 0.4993 = 49.93 cM Incorrect ^{(5,770 + 5,825)}/_37,500 = ^11,595/_37,500 = 0.3092 = 30.92 cM Correct ^{(5,825 + 12,951)}/_37,500 = ^18,776/_37,500 = 0.5007 = 50.07 cM Incorrect ^{(5,825 + 12,954)}/_37,500 = ^18,779/_37,500 = 0.5008 = 50.08 cM Incorrect MC

2d85_a04c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
nerdy, yucky	n	y	1,362
nerdy	n	+	686
yucky	+	y	684
wildtype	+	+	1,268
TOTAL =			4,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,268 + 1,362)}/_4,000 = ^2,630/_4,000 = 0.6575 = 65.75 cM Incorrect ^{(684 + 1,268)}/_4,000 = ^1,952/_4,000 = 0.4880 = 48.80 cM Incorrect ^{(684 + 686)}/_4,000 = ^1,370/_4,000 = 0.3425 = 34.25 cM Correct ^{(686 + 1,268)}/_4,000 = ^1,954/_4,000 = 0.4885 = 48.85 cM Incorrect ^1,362/_4,000 = ^1,362/_4,000 = 0.3405 = 34.05 cM Incorrect ⁶⁸⁴/_4,000 = ⁶⁸⁴/_4,000 = 0.1710 = 17.10 cM Incorrect MC

6283_accf

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene W is connected with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
artsy, waxy	a	w	3,052
artsy	a	+	5,970
waxy	+	w	6,063
wildtype	+	+	2,915
TOTAL =			18,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,915 + 3,052)}/_18,000 = ^5,967/_18,000 = 0.3315 = 33.15 cM Correct ^{(2,915 + 5,970)}/_18,000 = ^8,885/_18,000 = 0.4936 = 49.36 cM Incorrect ^{(2,915 + 6,063)}/_18,000 = ^8,978/_18,000 = 0.4988 = 49.88 cM Incorrect ^{(3,052 + 5,970)}/_18,000 = ^9,022/_18,000 = 0.5012 = 50.12 cM Incorrect ^{(3,052 + 6,063)}/_18,000 = ^9,115/_18,000 = 0.5064 = 50.64 cM Incorrect ^{(5,970 + 6,063)}/_18,000 = ^12,033/_18,000 = 0.6685 = 66.85 cM Incorrect MC

3152_ba85

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is analogous to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
eery, yucky	e	y	89,632
eery	e	+	40,293
yucky	+	y	40,489
wildtype	+	+	89,586
TOTAL =			260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(40,293 + 40,489)}/_260,000 = ^80,782/_260,000 = 0.3107 = 31.07 cM Correct ^{(40,293 + 89,586)}/_260,000 = ^129,879/_260,000 = 0.4995 = 49.95 cM Incorrect ^{(40,293 + 89,632)}/_260,000 = ^129,925/_260,000 = 0.4997 = 49.97 cM Incorrect ^{(40,489 + 89,586)}/_260,000 = ^130,075/_260,000 = 0.5003 = 50.03 cM Incorrect ^{(40,489 + 89,632)}/_260,000 = ^130,121/_260,000 = 0.5005 = 50.05 cM Incorrect ^{(89,586 + 89,632)}/_260,000 = ^179,218/_260,000 = 0.6893 = 68.93 cM Incorrect MC

8419_0c9b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
kidney, yucky	k	y	811
kidney	k	+	1,413
yucky	+	y	1,425
wildtype	+	+	751
TOTAL =			4,400

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,413 + 1,425)}/_4,400 = ^2,838/_4,400 = 0.6450 = 64.50 cM Incorrect ^{(751 + 1,413)}/_4,400 = ^2,164/_4,400 = 0.4918 = 49.18 cM Incorrect ^{(751 + 1,425)}/_4,400 = ^2,176/_4,400 = 0.4945 = 49.45 cM Incorrect ^{(751 + 811)}/_4,400 = ^1,562/_4,400 = 0.3550 = 35.50 cM Correct ^{(811 + 1,413)}/_4,400 = ^2,224/_4,400 = 0.5055 = 50.55 cM Incorrect ^{(811 + 1,425)}/_4,400 = ^2,236/_4,400 = 0.5082 = 50.82 cM Incorrect MC

cb6c_f282

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
artsy, yucky	a	y	648
artsy	a	+	2,512
yucky	+	y	2,592
wildtype	+	+	648
TOTAL =			6,400

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,512 + 2,592)}/_6,400 = ^5,104/_6,400 = 0.7975 = 79.75 cM Incorrect ^{(648 + 2,512)}/_6,400 = ^3,160/_6,400 = 0.4938 = 49.38 cM Incorrect ^{(648 + 2,592)}/_6,400 = ^3,240/_6,400 = 0.5062 = 50.62 cM Incorrect ^{(648 + 648)}/_6,400 = ^1,296/_6,400 = 0.2025 = 20.25 cM Correct ^2,592/_6,400 = ^2,592/_6,400 = 0.4050 = 40.50 cM Incorrect ⁶⁴⁸/_6,400 = ⁶⁴⁸/_6,400 = 0.1013 = 10.12 cM Incorrect MC

c9fa_3bcb

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.

Phenotype	Genotypes		Progeny Count
artsy, bumpy	a	b	1,978
artsy	a	+	12,956
bumpy	+	b	13,048
wildtype	+	+	2,018
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,978 + 12,956)}/_30,000 = ^14,934/_30,000 = 0.4978 = 49.78 cM Incorrect ^{(1,978 + 13,048)}/_30,000 = ^15,026/_30,000 = 0.5009 = 50.09 cM Incorrect ^{(1,978 + 2,018)}/_30,000 = ^3,996/_30,000 = 0.1332 = 13.32 cM Correct ^{(12,956 + 13,048)}/_30,000 = ^26,004/_30,000 = 0.8668 = 86.68 cM Incorrect ^{(2,018 + 12,956)}/_30,000 = ^14,974/_30,000 = 0.4991 = 49.91 cM Incorrect ^{(2,018 + 13,048)}/_30,000 = ^15,066/_30,000 = 0.5022 = 50.22 cM Incorrect MC

341a_7582

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is analogous to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
rusty, xanthic	r	x	73,030
rusty	r	+	46,580
xanthic	+	x	46,852
wildtype	+	+	73,538
TOTAL =			240,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(46,580 + 46,852)}/_240,000 = ^93,432/_240,000 = 0.3893 = 38.93 cM Correct ^{(46,580 + 73,030)}/_240,000 = ^119,610/_240,000 = 0.4984 = 49.84 cM Incorrect ^{(46,580 + 73,538)}/_240,000 = ^120,118/_240,000 = 0.5005 = 50.05 cM Incorrect ^{(46,852 + 73,030)}/_240,000 = ^119,882/_240,000 = 0.4995 = 49.95 cM Incorrect ^{(46,852 + 73,538)}/_240,000 = ^120,390/_240,000 = 0.5016 = 50.16 cM Incorrect ^{(73,030 + 73,538)}/_240,000 = ^146,568/_240,000 = 0.6107 = 61.07 cM Incorrect MC

6c9b_b40a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
prickly, waxy	p	w	30,439
prickly	p	+	17,199
waxy	+	w	17,172
wildtype	+	+	30,190
TOTAL =			95,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(17,172 + 17,199)}/_95,000 = ^34,371/_95,000 = 0.3618 = 36.18 cM Correct ^{(17,172 + 30,190)}/_95,000 = ^47,362/_95,000 = 0.4985 = 49.85 cM Incorrect ^{(17,172 + 30,439)}/_95,000 = ^47,611/_95,000 = 0.5012 = 50.12 cM Incorrect ^{(17,199 + 30,190)}/_95,000 = ^47,389/_95,000 = 0.4988 = 49.88 cM Incorrect ^{(17,199 + 30,439)}/_95,000 = ^47,638/_95,000 = 0.5015 = 50.15 cM Incorrect ^{(30,190 + 30,439)}/_95,000 = ^60,629/_95,000 = 0.6382 = 63.82 cM Incorrect MC

7280_0484

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
chummy, tipsy	c	t	8,272
chummy	c	+	21,679
tipsy	+	t	21,869
wildtype	+	+	8,180
TOTAL =			60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(21,679 + 21,869)}/_60,000 = ^43,548/_60,000 = 0.7258 = 72.58 cM Incorrect ^{(8,180 + 21,679)}/_60,000 = ^29,859/_60,000 = 0.4976 = 49.77 cM Incorrect ^{(8,180 + 21,869)}/_60,000 = ^30,049/_60,000 = 0.5008 = 50.08 cM Incorrect ^{(8,180 + 8,272)}/_60,000 = ^16,452/_60,000 = 0.2742 = 27.42 cM Correct ^{(8,272 + 21,679)}/_60,000 = ^29,951/_60,000 = 0.4992 = 49.92 cM Incorrect ^{(8,272 + 21,869)}/_60,000 = ^30,141/_60,000 = 0.5023 = 50.23 cM Incorrect MC

410f_dac0

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
jerky, rusty	j	r	86,860
jerky	j	+	18,256
rusty	+	r	18,347
wildtype	+	+	86,537
TOTAL =			210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(18,256 + 18,347)}/_210,000 = ^36,603/_210,000 = 0.1743 = 17.43 cM Correct ^{(18,256 + 86,537)}/_210,000 = ^104,793/_210,000 = 0.4990 = 49.90 cM Incorrect ^{(18,256 + 86,860)}/_210,000 = ^105,116/_210,000 = 0.5006 = 50.06 cM Incorrect ^{(18,347 + 86,537)}/_210,000 = ^104,884/_210,000 = 0.4994 = 49.94 cM Incorrect ^{(18,347 + 86,860)}/_210,000 = ^105,207/_210,000 = 0.5010 = 50.10 cM Incorrect ^{(86,537 + 86,860)}/_210,000 = ^173,397/_210,000 = 0.8257 = 82.57 cM Incorrect MC

b994_c07e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
eery, jerky	e	j	57,910
eery	e	+	22,114
jerky	+	j	22,094
wildtype	+	+	57,882
TOTAL =			160,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,094 + 22,114)}/_160,000 = ^44,208/_160,000 = 0.2763 = 27.63 cM Correct ^{(22,094 + 57,882)}/_160,000 = ^79,976/_160,000 = 0.4999 = 49.98 cM Incorrect ^{(22,094 + 57,910)}/_160,000 = ^80,004/_160,000 = 0.5000 = 50.00 cM Incorrect ^{(22,114 + 57,882)}/_160,000 = ^79,996/_160,000 = 0.5000 = 50.00 cM Incorrect ^{(22,114 + 57,910)}/_160,000 = ^80,024/_160,000 = 0.5001 = 50.02 cM Incorrect ^{(57,882 + 57,910)}/_160,000 = ^115,792/_160,000 = 0.7237 = 72.37 cM Incorrect MC

1049_54a2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is related to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
horsey, mushy	h	m	673
horsey	h	+	2,838
mushy	+	m	2,839
wildtype	+	+	650
TOTAL =			7,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,838 + 2,839)}/_7,000 = ^5,677/_7,000 = 0.8110 = 81.10 cM Incorrect ^{(650 + 2,838)}/_7,000 = ^3,488/_7,000 = 0.4983 = 49.83 cM Incorrect ^{(650 + 2,839)}/_7,000 = ^3,489/_7,000 = 0.4984 = 49.84 cM Incorrect ^{(650 + 673)}/_7,000 = ^1,323/_7,000 = 0.1890 = 18.90 cM Correct ^{(673 + 2,838)}/_7,000 = ^3,511/_7,000 = 0.5016 = 50.16 cM Incorrect ^{(673 + 2,839)}/_7,000 = ^3,512/_7,000 = 0.5017 = 50.17 cM Incorrect MC

0ed6_d66c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
horsey, jerky	h	j	4,131
horsey	h	+	20,966
jerky	+	j	20,764
wildtype	+	+	4,139
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(20,764 + 20,966)}/_50,000 = ^41,730/_50,000 = 0.8346 = 83.46 cM Incorrect ^{(4,131 + 20,764)}/_50,000 = ^24,895/_50,000 = 0.4979 = 49.79 cM Incorrect ^{(4,131 + 20,966)}/_50,000 = ^25,097/_50,000 = 0.5019 = 50.19 cM Incorrect ^{(4,131 + 4,139)}/_50,000 = ^8,270/_50,000 = 0.1654 = 16.54 cM Correct ^{(4,139 + 20,764)}/_50,000 = ^24,903/_50,000 = 0.4981 = 49.81 cM Incorrect ^{(4,139 + 20,966)}/_50,000 = ^25,105/_50,000 = 0.5021 = 50.21 cM Incorrect MC

84b2_2daf

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
kidney, rusty	k	r	5,648
kidney	k	+	32,050
rusty	+	r	31,655
wildtype	+	+	5,647
TOTAL =			75,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(31,655 + 32,050)}/_75,000 = ^63,705/_75,000 = 0.8494 = 84.94 cM Incorrect ^{(5,647 + 31,655)}/_75,000 = ^37,302/_75,000 = 0.4974 = 49.74 cM Incorrect ^{(5,647 + 32,050)}/_75,000 = ^37,697/_75,000 = 0.5026 = 50.26 cM Incorrect ^{(5,647 + 5,648)}/_75,000 = ^11,295/_75,000 = 0.1506 = 15.06 cM Correct ^{(5,648 + 31,655)}/_75,000 = ^37,303/_75,000 = 0.4974 = 49.74 cM Incorrect ^{(5,648 + 32,050)}/_75,000 = ^37,698/_75,000 = 0.5026 = 50.26 cM Incorrect MC

e6fc_b0fc

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene H is related to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
chummy, horsey	c	h	815
chummy	c	+	362
horsey	+	h	351
wildtype	+	+	772
TOTAL =			2,300

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(351 + 362)}/_2,300 = ⁷¹³/_2,300 = 0.3100 = 31.00 cM Correct ^{(351 + 772)}/_2,300 = ^1,123/_2,300 = 0.4883 = 48.83 cM Incorrect ^{(351 + 815)}/_2,300 = ^1,166/_2,300 = 0.5070 = 50.70 cM Incorrect ^{(362 + 772)}/_2,300 = ^1,134/_2,300 = 0.4930 = 49.30 cM Incorrect ^{(772 + 815)}/_2,300 = ^1,587/_2,300 = 0.6900 = 69.00 cM Incorrect ³⁵¹/_2,300 = ³⁵¹/_2,300 = 0.1526 = 15.26 cM Incorrect MC

2f36_7b2c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
jerky, mushy	j	m	102,566
jerky	j	+	42,181
mushy	+	m	42,006
wildtype	+	+	103,247
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(102,566 + 103,247)}/_290,000 = ^205,813/_290,000 = 0.7097 = 70.97 cM Incorrect ^{(42,006 + 102,566)}/_290,000 = ^144,572/_290,000 = 0.4985 = 49.85 cM Incorrect ^{(42,006 + 103,247)}/_290,000 = ^145,253/_290,000 = 0.5009 = 50.09 cM Incorrect ^{(42,006 + 42,181)}/_290,000 = ^84,187/_290,000 = 0.2903 = 29.03 cM Correct ^{(42,181 + 102,566)}/_290,000 = ^144,747/_290,000 = 0.4991 = 49.91 cM Incorrect ^{(42,181 + 103,247)}/_290,000 = ^145,428/_290,000 = 0.5015 = 50.15 cM Incorrect MC

ab44_fa66

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
artsy, kidney	a	k	1,680
artsy	a	+	609
kidney	+	k	610
wildtype	+	+	1,701
TOTAL =			4,600

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,680 + 1,701)}/_4,600 = ^3,381/_4,600 = 0.7350 = 73.50 cM Incorrect ^{(609 + 1,680)}/_4,600 = ^2,289/_4,600 = 0.4976 = 49.76 cM Incorrect ^{(609 + 1,701)}/_4,600 = ^2,310/_4,600 = 0.5022 = 50.22 cM Incorrect ^{(609 + 610)}/_4,600 = ^1,219/_4,600 = 0.2650 = 26.50 cM Correct ^{(610 + 1,680)}/_4,600 = ^2,290/_4,600 = 0.4978 = 49.78 cM Incorrect ^{(610 + 1,701)}/_4,600 = ^2,311/_4,600 = 0.5024 = 50.24 cM Incorrect MC

afba_9f13

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is connected with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
waxy, yucky	w	y	30,843
waxy	w	+	109,112
yucky	+	y	108,812
wildtype	+	+	31,233
TOTAL =			280,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(108,812 + 109,112)}/_280,000 = ^217,924/_280,000 = 0.7783 = 77.83 cM Incorrect ^{(30,843 + 108,812)}/_280,000 = ^139,655/_280,000 = 0.4988 = 49.88 cM Incorrect ^{(30,843 + 109,112)}/_280,000 = ^139,955/_280,000 = 0.4998 = 49.98 cM Incorrect ^{(30,843 + 31,233)}/_280,000 = ^62,076/_280,000 = 0.2217 = 22.17 cM Correct ^{(31,233 + 108,812)}/_280,000 = ^140,045/_280,000 = 0.5002 = 50.02 cM Incorrect ^{(31,233 + 109,112)}/_280,000 = ^140,345/_280,000 = 0.5012 = 50.12 cM Incorrect MC

1a9e_9eec

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
artsy, jerky	a	j	19,639
artsy	a	+	69,938
jerky	+	j	70,588
wildtype	+	+	19,835
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(19,639 + 19,835)}/_180,000 = ^39,474/_180,000 = 0.2193 = 21.93 cM Correct ^{(19,639 + 69,938)}/_180,000 = ^89,577/_180,000 = 0.4976 = 49.77 cM Incorrect ^{(19,639 + 70,588)}/_180,000 = ^90,227/_180,000 = 0.5013 = 50.13 cM Incorrect ^{(19,835 + 69,938)}/_180,000 = ^89,773/_180,000 = 0.4987 = 49.87 cM Incorrect ^{(19,835 + 70,588)}/_180,000 = ^90,423/_180,000 = 0.5023 = 50.23 cM Incorrect ^{(69,938 + 70,588)}/_180,000 = ^140,526/_180,000 = 0.7807 = 78.07 cM Incorrect MC

aff1_70e0

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is affiliated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
fuzzy, waxy	f	w	67,449
fuzzy	f	+	22,573
waxy	+	w	22,805
wildtype	+	+	67,173
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,573 + 22,805)}/_180,000 = ^45,378/_180,000 = 0.2521 = 25.21 cM Correct ^{(22,573 + 67,173)}/_180,000 = ^89,746/_180,000 = 0.4986 = 49.86 cM Incorrect ^{(22,573 + 67,449)}/_180,000 = ^90,022/_180,000 = 0.5001 = 50.01 cM Incorrect ^{(22,805 + 67,173)}/_180,000 = ^89,978/_180,000 = 0.4999 = 49.99 cM Incorrect ^{(22,805 + 67,449)}/_180,000 = ^90,254/_180,000 = 0.5014 = 50.14 cM Incorrect ^{(67,173 + 67,449)}/_180,000 = ^134,622/_180,000 = 0.7479 = 74.79 cM Incorrect MC

c623_752a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is correlated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
artsy, rusty	a	r	68,622
artsy	a	+	36,462
rusty	+	r	35,841
wildtype	+	+	69,075
TOTAL =			210,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(35,841 + 36,462)}/_210,000 = ^72,303/_210,000 = 0.3443 = 34.43 cM Correct ^{(35,841 + 68,622)}/_210,000 = ^104,463/_210,000 = 0.4974 = 49.74 cM Incorrect ^{(35,841 + 69,075)}/_210,000 = ^104,916/_210,000 = 0.4996 = 49.96 cM Incorrect ^{(36,462 + 68,622)}/_210,000 = ^105,084/_210,000 = 0.5004 = 50.04 cM Incorrect ^{(36,462 + 69,075)}/_210,000 = ^105,537/_210,000 = 0.5026 = 50.26 cM Incorrect ^{(68,622 + 69,075)}/_210,000 = ^137,697/_210,000 = 0.6557 = 65.57 cM Incorrect MC

fe89_100b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
kidney, xanthic	k	x	24,442
kidney	k	+	10,434
xanthic	+	x	10,587
wildtype	+	+	24,537
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,434 + 10,587)}/_70,000 = ^21,021/_70,000 = 0.3003 = 30.03 cM Correct ^{(10,434 + 24,442)}/_70,000 = ^34,876/_70,000 = 0.4982 = 49.82 cM Incorrect ^{(10,434 + 24,537)}/_70,000 = ^34,971/_70,000 = 0.4996 = 49.96 cM Incorrect ^{(10,587 + 24,442)}/_70,000 = ^35,029/_70,000 = 0.5004 = 50.04 cM Incorrect ^{(10,587 + 24,537)}/_70,000 = ^35,124/_70,000 = 0.5018 = 50.18 cM Incorrect ^{(24,442 + 24,537)}/_70,000 = ^48,979/_70,000 = 0.6997 = 69.97 cM Incorrect MC

b702_c4b1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
kidney, nerdy	k	n	86,209
kidney	k	+	28,776
nerdy	+	n	28,931
wildtype	+	+	86,084
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(28,776 + 28,931)}/_230,000 = ^57,707/_230,000 = 0.2509 = 25.09 cM Correct ^{(28,776 + 86,084)}/_230,000 = ^114,860/_230,000 = 0.4994 = 49.94 cM Incorrect ^{(28,776 + 86,209)}/_230,000 = ^114,985/_230,000 = 0.4999 = 49.99 cM Incorrect ^{(28,931 + 86,084)}/_230,000 = ^115,015/_230,000 = 0.5001 = 50.01 cM Incorrect ^{(28,931 + 86,209)}/_230,000 = ^115,140/_230,000 = 0.5006 = 50.06 cM Incorrect ^{(86,084 + 86,209)}/_230,000 = ^172,293/_230,000 = 0.7491 = 74.91 cM Incorrect MC

648b_cd4e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene X is analogous to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
kidney, xanthic	k	x	80,559
kidney	k	+	34,555
xanthic	+	x	34,238
wildtype	+	+	80,648
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(34,238 + 34,555)}/_230,000 = ^68,793/_230,000 = 0.2991 = 29.91 cM Correct ^{(34,238 + 80,559)}/_230,000 = ^114,797/_230,000 = 0.4991 = 49.91 cM Incorrect ^{(34,238 + 80,648)}/_230,000 = ^114,886/_230,000 = 0.4995 = 49.95 cM Incorrect ^{(34,555 + 80,559)}/_230,000 = ^115,114/_230,000 = 0.5005 = 50.05 cM Incorrect ^{(34,555 + 80,648)}/_230,000 = ^115,203/_230,000 = 0.5009 = 50.09 cM Incorrect ^{(80,559 + 80,648)}/_230,000 = ^161,207/_230,000 = 0.7009 = 70.09 cM Incorrect MC

c4e4_26cd

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
artsy, tipsy	a	t	6,129
artsy	a	+	58,787
tipsy	+	t	59,019
wildtype	+	+	6,065
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(58,787 + 59,019)}/_130,000 = ^117,806/_130,000 = 0.9062 = 90.62 cM Incorrect ^{(6,065 + 58,787)}/_130,000 = ^64,852/_130,000 = 0.4989 = 49.89 cM Incorrect ^{(6,065 + 59,019)}/_130,000 = ^65,084/_130,000 = 0.5006 = 50.06 cM Incorrect ^{(6,065 + 6,129)}/_130,000 = ^12,194/_130,000 = 0.0938 = 9.38 cM Correct ^{(6,129 + 58,787)}/_130,000 = ^64,916/_130,000 = 0.4994 = 49.94 cM Incorrect ^{(6,129 + 59,019)}/_130,000 = ^65,148/_130,000 = 0.5011 = 50.11 cM Incorrect MC

d74e_e30b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is affiliated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene Y is correlated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
bumpy, yucky	b	y	1,249
bumpy	b	+	790
yucky	+	y	728
wildtype	+	+	1,233
TOTAL =			4,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,233 + 1,249)}/_4,000 = ^2,482/_4,000 = 0.6205 = 62.05 cM Incorrect ^{(728 + 1,233)}/_4,000 = ^1,961/_4,000 = 0.4903 = 49.02 cM Incorrect ^{(728 + 1,249)}/_4,000 = ^1,977/_4,000 = 0.4943 = 49.43 cM Incorrect ^{(728 + 790)}/_4,000 = ^1,518/_4,000 = 0.3795 = 37.95 cM Correct ^{(790 + 1,233)}/_4,000 = ^2,023/_4,000 = 0.5058 = 50.58 cM Incorrect ^{(790 + 1,249)}/_4,000 = ^2,039/_4,000 = 0.5098 = 50.98 cM Incorrect MC

6b5f_790c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
jerky, tipsy	j	t	34,367
jerky	j	+	90,376
tipsy	+	t	90,549
wildtype	+	+	34,708
TOTAL =			250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(34,367 + 34,708)}/_250,000 = ^69,075/_250,000 = 0.2763 = 27.63 cM Correct ^{(34,367 + 90,376)}/_250,000 = ^124,743/_250,000 = 0.4990 = 49.90 cM Incorrect ^{(34,367 + 90,549)}/_250,000 = ^124,916/_250,000 = 0.4997 = 49.97 cM Incorrect ^{(34,708 + 90,376)}/_250,000 = ^125,084/_250,000 = 0.5003 = 50.03 cM Incorrect ^{(34,708 + 90,549)}/_250,000 = ^125,257/_250,000 = 0.5010 = 50.10 cM Incorrect ^{(90,376 + 90,549)}/_250,000 = ^180,925/_250,000 = 0.7237 = 72.37 cM Incorrect MC

bea4_6161

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
fuzzy, prickly	f	p	27,368
fuzzy	f	+	7,800
prickly	+	p	7,509
wildtype	+	+	27,323
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(27,323 + 27,368)}/_70,000 = ^54,691/_70,000 = 0.7813 = 78.13 cM Incorrect ^{(7,509 + 27,323)}/_70,000 = ^34,832/_70,000 = 0.4976 = 49.76 cM Incorrect ^{(7,509 + 27,368)}/_70,000 = ^34,877/_70,000 = 0.4982 = 49.82 cM Incorrect ^{(7,509 + 7,800)}/_70,000 = ^15,309/_70,000 = 0.2187 = 21.87 cM Correct ^{(7,800 + 27,323)}/_70,000 = ^35,123/_70,000 = 0.5018 = 50.18 cM Incorrect ^{(7,800 + 27,368)}/_70,000 = ^35,168/_70,000 = 0.5024 = 50.24 cM Incorrect MC

e357_79c8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is analogous to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene R is analogous to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
chummy, rusty	c	r	20,590
chummy	c	+	4,287
rusty	+	r	4,258
wildtype	+	+	20,865
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(20,590 + 20,865)}/_50,000 = ^41,455/_50,000 = 0.8291 = 82.91 cM Incorrect ^{(4,258 + 20,590)}/_50,000 = ^24,848/_50,000 = 0.4970 = 49.70 cM Incorrect ^{(4,258 + 20,865)}/_50,000 = ^25,123/_50,000 = 0.5025 = 50.25 cM Incorrect ^{(4,258 + 4,287)}/_50,000 = ^8,545/_50,000 = 0.1709 = 17.09 cM Correct ^{(4,287 + 20,590)}/_50,000 = ^24,877/_50,000 = 0.4975 = 49.75 cM Incorrect ^{(4,287 + 20,865)}/_50,000 = ^25,152/_50,000 = 0.5030 = 50.30 cM Incorrect MC

156d_43a1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is associated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
chummy, eery	c	e	46,579
chummy	c	+	88,545
eery	+	e	88,116
wildtype	+	+	46,760
TOTAL =			270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(46,579 + 46,760)}/_270,000 = ^93,339/_270,000 = 0.3457 = 34.57 cM Correct ^{(46,579 + 88,116)}/_270,000 = ^134,695/_270,000 = 0.4989 = 49.89 cM Incorrect ^{(46,579 + 88,545)}/_270,000 = ^135,124/_270,000 = 0.5005 = 50.05 cM Incorrect ^{(46,760 + 88,116)}/_270,000 = ^134,876/_270,000 = 0.4995 = 49.95 cM Incorrect ^{(46,760 + 88,545)}/_270,000 = ^135,305/_270,000 = 0.5011 = 50.11 cM Incorrect ^{(88,116 + 88,545)}/_270,000 = ^176,661/_270,000 = 0.6543 = 65.43 cM Incorrect MC

b0fd_6da4

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
jerky, mushy	j	m	22,890
jerky	j	+	7,136
mushy	+	m	7,192
wildtype	+	+	22,782
TOTAL =			60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,782 + 22,890)}/_60,000 = ^45,672/_60,000 = 0.7612 = 76.12 cM Incorrect ^{(7,136 + 22,782)}/_60,000 = ^29,918/_60,000 = 0.4986 = 49.86 cM Incorrect ^{(7,136 + 22,890)}/_60,000 = ^30,026/_60,000 = 0.5004 = 50.04 cM Incorrect ^{(7,136 + 7,192)}/_60,000 = ^14,328/_60,000 = 0.2388 = 23.88 cM Correct ^{(7,192 + 22,782)}/_60,000 = ^29,974/_60,000 = 0.4996 = 49.96 cM Incorrect ^{(7,192 + 22,890)}/_60,000 = ^30,082/_60,000 = 0.5014 = 50.14 cM Incorrect MC

5350_769f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
prickly, xanthic	p	x	1,807
prickly	p	+	13,154
xanthic	+	x	13,225
wildtype	+	+	1,814
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,807 + 1,814)}/_30,000 = ^3,621/_30,000 = 0.1207 = 12.07 cM Correct ^{(1,807 + 13,154)}/_30,000 = ^14,961/_30,000 = 0.4987 = 49.87 cM Incorrect ^{(1,807 + 13,225)}/_30,000 = ^15,032/_30,000 = 0.5011 = 50.11 cM Incorrect ^{(1,814 + 13,154)}/_30,000 = ^14,968/_30,000 = 0.4989 = 49.89 cM Incorrect ^{(1,814 + 13,225)}/_30,000 = ^15,039/_30,000 = 0.5013 = 50.13 cM Incorrect ^{(13,154 + 13,225)}/_30,000 = ^26,379/_30,000 = 0.8793 = 87.93 cM Incorrect MC

1f3a_386d

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
dewy, jerky	d	j	11,040
dewy	d	+	2,607
jerky	+	j	2,640
wildtype	+	+	11,213
TOTAL =			27,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,040 + 11,213)}/_27,500 = ^22,253/_27,500 = 0.8092 = 80.92 cM Incorrect ^{(2,607 + 11,040)}/_27,500 = ^13,647/_27,500 = 0.4963 = 49.63 cM Incorrect ^{(2,607 + 11,213)}/_27,500 = ^13,820/_27,500 = 0.5025 = 50.25 cM Incorrect ^{(2,607 + 2,640)}/_27,500 = ^5,247/_27,500 = 0.1908 = 19.08 cM Correct ^{(2,640 + 11,040)}/_27,500 = ^13,680/_27,500 = 0.4975 = 49.75 cM Incorrect ^{(2,640 + 11,213)}/_27,500 = ^13,853/_27,500 = 0.5037 = 50.37 cM Incorrect MC

cb93_47b5

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is affiliated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
rusty, yucky	r	y	20,785
rusty	r	+	6,771
yucky	+	y	6,682
wildtype	+	+	20,762
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(20,762 + 20,785)}/_55,000 = ^41,547/_55,000 = 0.7554 = 75.54 cM Incorrect ^{(6,682 + 20,762)}/_55,000 = ^27,444/_55,000 = 0.4990 = 49.90 cM Incorrect ^{(6,682 + 20,785)}/_55,000 = ^27,467/_55,000 = 0.4994 = 49.94 cM Incorrect ^{(6,682 + 6,771)}/_55,000 = ^13,453/_55,000 = 0.2446 = 24.46 cM Correct ^{(6,771 + 20,762)}/_55,000 = ^27,533/_55,000 = 0.5006 = 50.06 cM Incorrect ^{(6,771 + 20,785)}/_55,000 = ^27,556/_55,000 = 0.5010 = 50.10 cM Incorrect MC

ec85_6470

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is connected with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
dewy, mushy	d	m	11,320
dewy	d	+	3,694
mushy	+	m	3,701
wildtype	+	+	11,285
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,285 + 11,320)}/_30,000 = ^22,605/_30,000 = 0.7535 = 75.35 cM Incorrect ^{(3,694 + 11,285)}/_30,000 = ^14,979/_30,000 = 0.4993 = 49.93 cM Incorrect ^{(3,694 + 11,320)}/_30,000 = ^15,014/_30,000 = 0.5005 = 50.05 cM Incorrect ^{(3,694 + 3,701)}/_30,000 = ^7,395/_30,000 = 0.2465 = 24.65 cM Correct ^{(3,701 + 11,285)}/_30,000 = ^14,986/_30,000 = 0.4995 = 49.95 cM Incorrect ^{(3,701 + 11,320)}/_30,000 = ^15,021/_30,000 = 0.5007 = 50.07 cM Incorrect MC

c9ef_9398

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
jerky, yucky	j	y	23,148
jerky	j	+	5,839
yucky	+	y	5,753
wildtype	+	+	22,760
TOTAL =			57,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,760 + 23,148)}/_57,500 = ^45,908/_57,500 = 0.7984 = 79.84 cM Incorrect ^{(5,753 + 22,760)}/_57,500 = ^28,513/_57,500 = 0.4959 = 49.59 cM Incorrect ^{(5,753 + 23,148)}/_57,500 = ^28,901/_57,500 = 0.5026 = 50.26 cM Incorrect ^{(5,753 + 5,839)}/_57,500 = ^11,592/_57,500 = 0.2016 = 20.16 cM Correct ^{(5,839 + 22,760)}/_57,500 = ^28,599/_57,500 = 0.4974 = 49.74 cM Incorrect ^{(5,839 + 23,148)}/_57,500 = ^28,987/_57,500 = 0.5041 = 50.41 cM Incorrect MC

55ae_8603

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene P is analogous to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
chummy, prickly	c	p	24,209
chummy	c	+	10,826
prickly	+	p	10,657
wildtype	+	+	24,308
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,657 + 10,826)}/_70,000 = ^21,483/_70,000 = 0.3069 = 30.69 cM Correct ^{(10,657 + 24,209)}/_70,000 = ^34,866/_70,000 = 0.4981 = 49.81 cM Incorrect ^{(10,657 + 24,308)}/_70,000 = ^34,965/_70,000 = 0.4995 = 49.95 cM Incorrect ^{(10,826 + 24,209)}/_70,000 = ^35,035/_70,000 = 0.5005 = 50.05 cM Incorrect ^{(10,826 + 24,308)}/_70,000 = ^35,134/_70,000 = 0.5019 = 50.19 cM Incorrect ^{(24,209 + 24,308)}/_70,000 = ^48,517/_70,000 = 0.6931 = 69.31 cM Incorrect MC

76cb_50c0

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
artsy, eery	a	e	79,773
artsy	a	+	35,283
eery	+	e	34,844
wildtype	+	+	80,100
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(34,844 + 35,283)}/_230,000 = ^70,127/_230,000 = 0.3049 = 30.49 cM Correct ^{(34,844 + 79,773)}/_230,000 = ^114,617/_230,000 = 0.4983 = 49.83 cM Incorrect ^{(34,844 + 80,100)}/_230,000 = ^114,944/_230,000 = 0.4998 = 49.98 cM Incorrect ^{(35,283 + 79,773)}/_230,000 = ^115,056/_230,000 = 0.5002 = 50.02 cM Incorrect ^{(35,283 + 80,100)}/_230,000 = ^115,383/_230,000 = 0.5017 = 50.17 cM Incorrect ^{(79,773 + 80,100)}/_230,000 = ^159,873/_230,000 = 0.6951 = 69.51 cM Incorrect MC

2543_05c1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is connected with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene M is related to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
horsey, mushy	h	m	3,189
horsey	h	+	11,838
mushy	+	m	11,931
wildtype	+	+	3,042
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,838 + 11,931)}/_30,000 = ^23,769/_30,000 = 0.7923 = 79.23 cM Incorrect ^{(3,042 + 11,838)}/_30,000 = ^14,880/_30,000 = 0.4960 = 49.60 cM Incorrect ^{(3,042 + 11,931)}/_30,000 = ^14,973/_30,000 = 0.4991 = 49.91 cM Incorrect ^{(3,042 + 3,189)}/_30,000 = ^6,231/_30,000 = 0.2077 = 20.77 cM Correct ^{(3,189 + 11,838)}/_30,000 = ^15,027/_30,000 = 0.5009 = 50.09 cM Incorrect ^{(3,189 + 11,931)}/_30,000 = ^15,120/_30,000 = 0.5040 = 50.40 cM Incorrect MC

03c8_54a4

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
horsey, jerky	h	j	703
horsey	h	+	6,816
jerky	+	j	6,768
wildtype	+	+	713
TOTAL =			15,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(6,768 + 6,816)}/_15,000 = ^13,584/_15,000 = 0.9056 = 90.56 cM Incorrect ^{(703 + 6,768)}/_15,000 = ^7,471/_15,000 = 0.4981 = 49.81 cM Incorrect ^{(703 + 6,816)}/_15,000 = ^7,519/_15,000 = 0.5013 = 50.13 cM Incorrect ^{(703 + 713)}/_15,000 = ^1,416/_15,000 = 0.0944 = 9.44 cM Correct ^{(713 + 6,768)}/_15,000 = ^7,481/_15,000 = 0.4987 = 49.87 cM Incorrect ^{(713 + 6,816)}/_15,000 = ^7,529/_15,000 = 0.5019 = 50.19 cM Incorrect MC

faac_8b0e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is related to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
jerky, kidney	j	k	6,430
jerky	j	+	23,581
kidney	+	k	23,411
wildtype	+	+	6,578
TOTAL =			60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(23,411 + 23,581)}/_60,000 = ^46,992/_60,000 = 0.7832 = 78.32 cM Incorrect ^{(6,430 + 23,411)}/_60,000 = ^29,841/_60,000 = 0.4974 = 49.73 cM Incorrect ^{(6,430 + 23,581)}/_60,000 = ^30,011/_60,000 = 0.5002 = 50.02 cM Incorrect ^{(6,430 + 6,578)}/_60,000 = ^13,008/_60,000 = 0.2168 = 21.68 cM Correct ^{(6,578 + 23,411)}/_60,000 = ^29,989/_60,000 = 0.4998 = 49.98 cM Incorrect ^{(6,578 + 23,581)}/_60,000 = ^30,159/_60,000 = 0.5027 = 50.27 cM Incorrect MC

a000_6dde

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is linked with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
bumpy, chummy	b	c	11,180
bumpy	b	+	23,836
chummy	+	c	23,862
wildtype	+	+	11,122
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,122 + 11,180)}/_70,000 = ^22,302/_70,000 = 0.3186 = 31.86 cM Correct ^{(11,122 + 23,836)}/_70,000 = ^34,958/_70,000 = 0.4994 = 49.94 cM Incorrect ^{(11,122 + 23,862)}/_70,000 = ^34,984/_70,000 = 0.4998 = 49.98 cM Incorrect ^{(11,180 + 23,836)}/_70,000 = ^35,016/_70,000 = 0.5002 = 50.02 cM Incorrect ^{(11,180 + 23,862)}/_70,000 = ^35,042/_70,000 = 0.5006 = 50.06 cM Incorrect ^{(23,836 + 23,862)}/_70,000 = ^47,698/_70,000 = 0.6814 = 68.14 cM Incorrect MC

a592_e20c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene W is connected with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
nerdy, waxy	n	w	9,241
nerdy	n	+	45,579
waxy	+	w	45,600
wildtype	+	+	9,580
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(45,579 + 45,600)}/_110,000 = ^91,179/_110,000 = 0.8289 = 82.89 cM Incorrect ^{(9,241 + 45,579)}/_110,000 = ^54,820/_110,000 = 0.4984 = 49.84 cM Incorrect ^{(9,241 + 45,600)}/_110,000 = ^54,841/_110,000 = 0.4986 = 49.86 cM Incorrect ^{(9,241 + 9,580)}/_110,000 = ^18,821/_110,000 = 0.1711 = 17.11 cM Correct ^{(9,580 + 45,579)}/_110,000 = ^55,159/_110,000 = 0.5014 = 50.14 cM Incorrect ^{(9,580 + 45,600)}/_110,000 = ^55,180/_110,000 = 0.5016 = 50.16 cM Incorrect MC

8794_234d

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is related to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
bumpy, fuzzy	b	f	4,501
bumpy	b	+	40,455
fuzzy	+	f	40,518
wildtype	+	+	4,526
TOTAL =			90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,501 + 4,526)}/_90,000 = ^9,027/_90,000 = 0.1003 = 10.03 cM Correct ^{(4,501 + 40,455)}/_90,000 = ^44,956/_90,000 = 0.4995 = 49.95 cM Incorrect ^{(4,501 + 40,518)}/_90,000 = ^45,019/_90,000 = 0.5002 = 50.02 cM Incorrect ^{(4,526 + 40,455)}/_90,000 = ^44,981/_90,000 = 0.4998 = 49.98 cM Incorrect ^{(4,526 + 40,518)}/_90,000 = ^45,044/_90,000 = 0.5005 = 50.05 cM Incorrect ^{(40,455 + 40,518)}/_90,000 = ^80,973/_90,000 = 0.8997 = 89.97 cM Incorrect MC

4d68_e817

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
jerky, rusty	j	r	27,925
jerky	j	+	4,675
rusty	+	r	4,802
wildtype	+	+	27,598
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(27,598 + 27,925)}/_65,000 = ^55,523/_65,000 = 0.8542 = 85.42 cM Incorrect ^{(4,675 + 27,598)}/_65,000 = ^32,273/_65,000 = 0.4965 = 49.65 cM Incorrect ^{(4,675 + 27,925)}/_65,000 = ^32,600/_65,000 = 0.5015 = 50.15 cM Incorrect ^{(4,675 + 4,802)}/_65,000 = ^9,477/_65,000 = 0.1458 = 14.58 cM Correct ^{(4,802 + 27,598)}/_65,000 = ^32,400/_65,000 = 0.4985 = 49.85 cM Incorrect ^{(4,802 + 27,925)}/_65,000 = ^32,727/_65,000 = 0.5035 = 50.35 cM Incorrect MC

4152_3184

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene Y is affiliated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
dewy, yucky	d	y	7,064
dewy	d	+	55,486
yucky	+	y	55,289
wildtype	+	+	7,161
TOTAL =			125,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(55,289 + 55,486)}/_125,000 = ^110,775/_125,000 = 0.8862 = 88.62 cM Incorrect ^{(7,064 + 55,289)}/_125,000 = ^62,353/_125,000 = 0.4988 = 49.88 cM Incorrect ^{(7,064 + 55,486)}/_125,000 = ^62,550/_125,000 = 0.5004 = 50.04 cM Incorrect ^{(7,064 + 7,161)}/_125,000 = ^14,225/_125,000 = 0.1138 = 11.38 cM Correct ^{(7,161 + 55,289)}/_125,000 = ^62,450/_125,000 = 0.4996 = 49.96 cM Incorrect ^{(7,161 + 55,486)}/_125,000 = ^62,647/_125,000 = 0.5012 = 50.12 cM Incorrect MC

4743_c3e0

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is connected with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
mushy, rusty	m	r	16,243
mushy	m	+	26,273
rusty	+	r	26,546
wildtype	+	+	15,938
TOTAL =			85,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(15,938 + 16,243)}/_85,000 = ^32,181/_85,000 = 0.3786 = 37.86 cM Correct ^{(15,938 + 26,273)}/_85,000 = ^42,211/_85,000 = 0.4966 = 49.66 cM Incorrect ^{(15,938 + 26,546)}/_85,000 = ^42,484/_85,000 = 0.4998 = 49.98 cM Incorrect ^{(16,243 + 26,273)}/_85,000 = ^42,516/_85,000 = 0.5002 = 50.02 cM Incorrect ^{(16,243 + 26,546)}/_85,000 = ^42,789/_85,000 = 0.5034 = 50.34 cM Incorrect ^{(26,273 + 26,546)}/_85,000 = ^52,819/_85,000 = 0.6214 = 62.14 cM Incorrect MC

0511_1f64

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
horsey, xanthic	h	x	58,003
horsey	h	+	87,255
xanthic	+	x	86,948
wildtype	+	+	57,794
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(57,794 + 58,003)}/_290,000 = ^115,797/_290,000 = 0.3993 = 39.93 cM Correct ^{(57,794 + 86,948)}/_290,000 = ^144,742/_290,000 = 0.4991 = 49.91 cM Incorrect ^{(57,794 + 87,255)}/_290,000 = ^145,049/_290,000 = 0.5002 = 50.02 cM Incorrect ^{(58,003 + 86,948)}/_290,000 = ^144,951/_290,000 = 0.4998 = 49.98 cM Incorrect ^{(58,003 + 87,255)}/_290,000 = ^145,258/_290,000 = 0.5009 = 50.09 cM Incorrect ^{(86,948 + 87,255)}/_290,000 = ^174,203/_290,000 = 0.6007 = 60.07 cM Incorrect MC

812d_3556

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
chummy, jerky	c	j	660
chummy	c	+	321
jerky	+	j	324
wildtype	+	+	695
TOTAL =			2,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(321 + 324)}/_2,000 = ⁶⁴⁵/_2,000 = 0.3225 = 32.25 cM Correct ^{(321 + 660)}/_2,000 = ⁹⁸¹/_2,000 = 0.4905 = 49.05 cM Incorrect ^{(321 + 695)}/_2,000 = ^1,016/_2,000 = 0.5080 = 50.80 cM Incorrect ^{(324 + 660)}/_2,000 = ⁹⁸⁴/_2,000 = 0.4920 = 49.20 cM Incorrect ^{(324 + 695)}/_2,000 = ^1,019/_2,000 = 0.5095 = 50.95 cM Incorrect ^{(660 + 695)}/_2,000 = ^1,355/_2,000 = 0.6775 = 67.75 cM Incorrect MC

0547_fc2e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
artsy, rusty	a	r	40,475
artsy	a	+	4,628
rusty	+	r	4,678
wildtype	+	+	40,219
TOTAL =			90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,628 + 4,678)}/_90,000 = ^9,306/_90,000 = 0.1034 = 10.34 cM Correct ^{(4,628 + 40,219)}/_90,000 = ^44,847/_90,000 = 0.4983 = 49.83 cM Incorrect ^{(4,628 + 40,475)}/_90,000 = ^45,103/_90,000 = 0.5011 = 50.11 cM Incorrect ^{(4,678 + 40,219)}/_90,000 = ^44,897/_90,000 = 0.4989 = 49.89 cM Incorrect ^{(4,678 + 40,475)}/_90,000 = ^45,153/_90,000 = 0.5017 = 50.17 cM Incorrect ^{(40,219 + 40,475)}/_90,000 = ^80,694/_90,000 = 0.8966 = 89.66 cM Incorrect MC

c6b0_9733

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is correlated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene F is correlated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
artsy, fuzzy	a	f	24,484
artsy	a	+	5,666
fuzzy	+	f	5,740
wildtype	+	+	24,110
TOTAL =			60,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(24,110 + 24,484)}/_60,000 = ^48,594/_60,000 = 0.8099 = 80.99 cM Incorrect ^{(5,666 + 24,110)}/_60,000 = ^29,776/_60,000 = 0.4963 = 49.63 cM Incorrect ^{(5,666 + 24,484)}/_60,000 = ^30,150/_60,000 = 0.5025 = 50.25 cM Incorrect ^{(5,666 + 5,740)}/_60,000 = ^11,406/_60,000 = 0.1901 = 19.01 cM Correct ^{(5,740 + 24,110)}/_60,000 = ^29,850/_60,000 = 0.4975 = 49.75 cM Incorrect ^{(5,740 + 24,484)}/_60,000 = ^30,224/_60,000 = 0.5037 = 50.37 cM Incorrect MC

cddc_b62c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is associated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
chummy, kidney	c	k	8,872
chummy	c	+	25,133
kidney	+	k	24,655
wildtype	+	+	8,840
TOTAL =			67,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(24,655 + 25,133)}/_67,500 = ^49,788/_67,500 = 0.7376 = 73.76 cM Incorrect ^{(8,840 + 24,655)}/_67,500 = ^33,495/_67,500 = 0.4962 = 49.62 cM Incorrect ^{(8,840 + 25,133)}/_67,500 = ^33,973/_67,500 = 0.5033 = 50.33 cM Incorrect ^{(8,840 + 8,872)}/_67,500 = ^17,712/_67,500 = 0.2624 = 26.24 cM Correct ^{(8,872 + 24,655)}/_67,500 = ^33,527/_67,500 = 0.4967 = 49.67 cM Incorrect ^{(8,872 + 25,133)}/_67,500 = ^34,005/_67,500 = 0.5038 = 50.38 cM Incorrect MC

372b_7d98

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is associated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
jerky, mushy	j	m	31,567
jerky	j	+	13,188
mushy	+	m	13,245
wildtype	+	+	32,000
TOTAL =			90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,188 + 13,245)}/_90,000 = ^26,433/_90,000 = 0.2937 = 29.37 cM Correct ^{(13,188 + 31,567)}/_90,000 = ^44,755/_90,000 = 0.4973 = 49.73 cM Incorrect ^{(13,188 + 32,000)}/_90,000 = ^45,188/_90,000 = 0.5021 = 50.21 cM Incorrect ^{(13,245 + 31,567)}/_90,000 = ^44,812/_90,000 = 0.4979 = 49.79 cM Incorrect ^{(13,245 + 32,000)}/_90,000 = ^45,245/_90,000 = 0.5027 = 50.27 cM Incorrect ^{(31,567 + 32,000)}/_90,000 = ^63,567/_90,000 = 0.7063 = 70.63 cM Incorrect MC

ace6_0679

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
artsy, waxy	a	w	121,584
artsy	a	+	18,351
waxy	+	w	18,133
wildtype	+	+	121,932
TOTAL =			280,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(121,584 + 121,932)}/_280,000 = ^243,516/_280,000 = 0.8697 = 86.97 cM Incorrect ^{(18,133 + 121,584)}/_280,000 = ^139,717/_280,000 = 0.4990 = 49.90 cM Incorrect ^{(18,133 + 121,932)}/_280,000 = ^140,065/_280,000 = 0.5002 = 50.02 cM Incorrect ^{(18,133 + 18,351)}/_280,000 = ^36,484/_280,000 = 0.1303 = 13.03 cM Correct ^{(18,351 + 121,584)}/_280,000 = ^139,935/_280,000 = 0.4998 = 49.98 cM Incorrect ^{(18,351 + 121,932)}/_280,000 = ^140,283/_280,000 = 0.5010 = 50.10 cM Incorrect MC

3738_a8bc

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
kidney, xanthic	k	x	3,189
kidney	k	+	14,249
xanthic	+	x	14,283
wildtype	+	+	3,279
TOTAL =			35,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,249 + 14,283)}/_35,000 = ^28,532/_35,000 = 0.8152 = 81.52 cM Incorrect ^{(3,189 + 14,249)}/_35,000 = ^17,438/_35,000 = 0.4982 = 49.82 cM Incorrect ^{(3,189 + 14,283)}/_35,000 = ^17,472/_35,000 = 0.4992 = 49.92 cM Incorrect ^{(3,189 + 3,279)}/_35,000 = ^6,468/_35,000 = 0.1848 = 18.48 cM Correct ^{(3,279 + 14,249)}/_35,000 = ^17,528/_35,000 = 0.5008 = 50.08 cM Incorrect ^{(3,279 + 14,283)}/_35,000 = ^17,562/_35,000 = 0.5018 = 50.18 cM Incorrect MC

6397_571c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is affiliated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
fuzzy, waxy	f	w	4,743
fuzzy	f	+	15,212
waxy	+	w	15,224
wildtype	+	+	4,821
TOTAL =			40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(15,212 + 15,224)}/_40,000 = ^30,436/_40,000 = 0.7609 = 76.09 cM Incorrect ^{(4,743 + 15,212)}/_40,000 = ^19,955/_40,000 = 0.4989 = 49.89 cM Incorrect ^{(4,743 + 15,224)}/_40,000 = ^19,967/_40,000 = 0.4992 = 49.92 cM Incorrect ^{(4,743 + 4,821)}/_40,000 = ^9,564/_40,000 = 0.2391 = 23.91 cM Correct ^{(4,821 + 15,212)}/_40,000 = ^20,033/_40,000 = 0.5008 = 50.08 cM Incorrect ^{(4,821 + 15,224)}/_40,000 = ^20,045/_40,000 = 0.5011 = 50.11 cM Incorrect MC

4c1d_1fac

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is connected with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
mushy, rusty	m	r	25,395
mushy	m	+	14,356
rusty	+	r	14,516
wildtype	+	+	25,733
TOTAL =			80,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,356 + 14,516)}/_80,000 = ^28,872/_80,000 = 0.3609 = 36.09 cM Correct ^{(14,356 + 25,395)}/_80,000 = ^39,751/_80,000 = 0.4969 = 49.69 cM Incorrect ^{(14,356 + 25,733)}/_80,000 = ^40,089/_80,000 = 0.5011 = 50.11 cM Incorrect ^{(14,516 + 25,395)}/_80,000 = ^39,911/_80,000 = 0.4989 = 49.89 cM Incorrect ^{(14,516 + 25,733)}/_80,000 = ^40,249/_80,000 = 0.5031 = 50.31 cM Incorrect ^{(25,395 + 25,733)}/_80,000 = ^51,128/_80,000 = 0.6391 = 63.91 cM Incorrect MC

46d9_e97f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
chummy, jerky	c	j	51,258
chummy	c	+	8,732
jerky	+	j	8,656
wildtype	+	+	51,354
TOTAL =			120,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(51,258 + 51,354)}/_120,000 = ^102,612/_120,000 = 0.8551 = 85.51 cM Incorrect ^{(8,656 + 51,258)}/_120,000 = ^59,914/_120,000 = 0.4993 = 49.93 cM Incorrect ^{(8,656 + 51,354)}/_120,000 = ^60,010/_120,000 = 0.5001 = 50.01 cM Incorrect ^{(8,656 + 8,732)}/_120,000 = ^17,388/_120,000 = 0.1449 = 14.49 cM Correct ^{(8,732 + 51,258)}/_120,000 = ^59,990/_120,000 = 0.4999 = 49.99 cM Incorrect ^{(8,732 + 51,354)}/_120,000 = ^60,086/_120,000 = 0.5007 = 50.07 cM Incorrect MC

8879_a74c

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is linked with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene W is related to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
jerky, waxy	j	w	17,934
jerky	j	+	51,788
waxy	+	w	52,456
wildtype	+	+	17,822
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(17,822 + 17,934)}/_140,000 = ^35,756/_140,000 = 0.2554 = 25.54 cM Correct ^{(17,822 + 51,788)}/_140,000 = ^69,610/_140,000 = 0.4972 = 49.72 cM Incorrect ^{(17,822 + 52,456)}/_140,000 = ^70,278/_140,000 = 0.5020 = 50.20 cM Incorrect ^{(17,934 + 51,788)}/_140,000 = ^69,722/_140,000 = 0.4980 = 49.80 cM Incorrect ^{(17,934 + 52,456)}/_140,000 = ^70,390/_140,000 = 0.5028 = 50.28 cM Incorrect ^{(51,788 + 52,456)}/_140,000 = ^104,244/_140,000 = 0.7446 = 74.46 cM Incorrect MC

5333_5528

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
fuzzy, nerdy	f	n	12,544
fuzzy	f	+	24,958
nerdy	+	n	25,007
wildtype	+	+	12,491
TOTAL =			75,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,491 + 12,544)}/_75,000 = ^25,035/_75,000 = 0.3338 = 33.38 cM Correct ^{(12,491 + 24,958)}/_75,000 = ^37,449/_75,000 = 0.4993 = 49.93 cM Incorrect ^{(12,491 + 25,007)}/_75,000 = ^37,498/_75,000 = 0.5000 = 50.00 cM Incorrect ^{(12,544 + 24,958)}/_75,000 = ^37,502/_75,000 = 0.5000 = 50.00 cM Incorrect ^{(12,544 + 25,007)}/_75,000 = ^37,551/_75,000 = 0.5007 = 50.07 cM Incorrect ^{(24,958 + 25,007)}/_75,000 = ^49,965/_75,000 = 0.6662 = 66.62 cM Incorrect MC

e73f_e99e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene R is related to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
chummy, rusty	c	r	122,792
chummy	c	+	22,325
rusty	+	r	22,306
wildtype	+	+	122,577
TOTAL =			290,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(122,577 + 122,792)}/_290,000 = ^245,369/_290,000 = 0.8461 = 84.61 cM Incorrect ^{(22,306 + 122,577)}/_290,000 = ^144,883/_290,000 = 0.4996 = 49.96 cM Incorrect ^{(22,306 + 122,792)}/_290,000 = ^145,098/_290,000 = 0.5003 = 50.03 cM Incorrect ^{(22,306 + 22,325)}/_290,000 = ^44,631/_290,000 = 0.1539 = 15.39 cM Correct ^{(22,325 + 122,577)}/_290,000 = ^144,902/_290,000 = 0.4997 = 49.97 cM Incorrect ^{(22,325 + 122,792)}/_290,000 = ^145,117/_290,000 = 0.5004 = 50.04 cM Incorrect MC

837e_08d9

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is analogous to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene N is related to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
artsy, nerdy	a	n	41,474
artsy	a	+	23,550
nerdy	+	n	23,731
wildtype	+	+	41,245
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(23,550 + 23,731)}/_130,000 = ^47,281/_130,000 = 0.3637 = 36.37 cM Correct ^{(23,550 + 41,245)}/_130,000 = ^64,795/_130,000 = 0.4984 = 49.84 cM Incorrect ^{(23,550 + 41,474)}/_130,000 = ^65,024/_130,000 = 0.5002 = 50.02 cM Incorrect ^{(23,731 + 41,245)}/_130,000 = ^64,976/_130,000 = 0.4998 = 49.98 cM Incorrect ^{(23,731 + 41,474)}/_130,000 = ^65,205/_130,000 = 0.5016 = 50.16 cM Incorrect ^{(41,245 + 41,474)}/_130,000 = ^82,719/_130,000 = 0.6363 = 63.63 cM Incorrect MC

a3fe_a1cd

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene R is connected with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
kidney, rusty	k	r	29,175
kidney	k	+	18,304
rusty	+	r	18,423
wildtype	+	+	29,098
TOTAL =			95,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(18,304 + 18,423)}/_95,000 = ^36,727/_95,000 = 0.3866 = 38.66 cM Correct ^{(18,304 + 29,098)}/_95,000 = ^47,402/_95,000 = 0.4990 = 49.90 cM Incorrect ^{(18,304 + 29,175)}/_95,000 = ^47,479/_95,000 = 0.4998 = 49.98 cM Incorrect ^{(18,423 + 29,098)}/_95,000 = ^47,521/_95,000 = 0.5002 = 50.02 cM Incorrect ^{(18,423 + 29,175)}/_95,000 = ^47,598/_95,000 = 0.5010 = 50.10 cM Incorrect ^{(29,098 + 29,175)}/_95,000 = ^58,273/_95,000 = 0.6134 = 61.34 cM Incorrect MC

b02b_e128

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
dewy, fuzzy	d	f	9,324
dewy	d	+	5,455
fuzzy	+	f	5,477
wildtype	+	+	9,744
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(5,455 + 5,477)}/_30,000 = ^10,932/_30,000 = 0.3644 = 36.44 cM Correct ^{(5,455 + 9,324)}/_30,000 = ^14,779/_30,000 = 0.4926 = 49.26 cM Incorrect ^{(5,455 + 9,744)}/_30,000 = ^15,199/_30,000 = 0.5066 = 50.66 cM Incorrect ^{(5,477 + 9,324)}/_30,000 = ^14,801/_30,000 = 0.4934 = 49.34 cM Incorrect ^{(5,477 + 9,744)}/_30,000 = ^15,221/_30,000 = 0.5074 = 50.74 cM Incorrect ^{(9,324 + 9,744)}/_30,000 = ^19,068/_30,000 = 0.6356 = 63.56 cM Incorrect MC

ee35_a3ae

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
waxy, xanthic	w	x	42,023
waxy	w	+	67,997
xanthic	+	x	67,985
wildtype	+	+	41,995
TOTAL =			220,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(41,995 + 42,023)}/_220,000 = ^84,018/_220,000 = 0.3819 = 38.19 cM Correct ^{(41,995 + 67,985)}/_220,000 = ^109,980/_220,000 = 0.4999 = 49.99 cM Incorrect ^{(41,995 + 67,997)}/_220,000 = ^109,992/_220,000 = 0.5000 = 50.00 cM Incorrect ^{(42,023 + 67,985)}/_220,000 = ^110,008/_220,000 = 0.5000 = 50.00 cM Incorrect ^{(42,023 + 67,997)}/_220,000 = ^110,020/_220,000 = 0.5001 = 50.01 cM Incorrect ^{(67,985 + 67,997)}/_220,000 = ^135,982/_220,000 = 0.6181 = 61.81 cM Incorrect MC

d947_e5ad

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
horsey, jerky	h	j	46,002
horsey	h	+	6,676
jerky	+	j	6,617
wildtype	+	+	45,705
TOTAL =			105,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(45,705 + 46,002)}/_105,000 = ^91,707/_105,000 = 0.8734 = 87.34 cM Incorrect ^{(6,617 + 45,705)}/_105,000 = ^52,322/_105,000 = 0.4983 = 49.83 cM Incorrect ^{(6,617 + 46,002)}/_105,000 = ^52,619/_105,000 = 0.5011 = 50.11 cM Incorrect ^{(6,617 + 6,676)}/_105,000 = ^13,293/_105,000 = 0.1266 = 12.66 cM Correct ^{(6,676 + 45,705)}/_105,000 = ^52,381/_105,000 = 0.4989 = 49.89 cM Incorrect ^{(6,676 + 46,002)}/_105,000 = ^52,678/_105,000 = 0.5017 = 50.17 cM Incorrect MC

a07d_8d11

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is related to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
prickly, waxy	p	w	824
prickly	p	+	2,386
waxy	+	w	2,334
wildtype	+	+	856
TOTAL =			6,400

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,334 + 2,386)}/_6,400 = ^4,720/_6,400 = 0.7375 = 73.75 cM Incorrect ^{(824 + 2,334)}/_6,400 = ^3,158/_6,400 = 0.4934 = 49.34 cM Incorrect ^{(824 + 2,386)}/_6,400 = ^3,210/_6,400 = 0.5016 = 50.16 cM Incorrect ^{(824 + 856)}/_6,400 = ^1,680/_6,400 = 0.2625 = 26.25 cM Correct ^{(856 + 2,334)}/_6,400 = ^3,190/_6,400 = 0.4984 = 49.84 cM Incorrect ^{(856 + 2,386)}/_6,400 = ^3,242/_6,400 = 0.5066 = 50.66 cM Incorrect MC

e516_99ea

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
jerky, waxy	j	w	17,628
jerky	j	+	9,356
waxy	+	w	9,355
wildtype	+	+	17,661
TOTAL =			54,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(17,628 + 17,661)}/_54,000 = ^35,289/_54,000 = 0.6535 = 65.35 cM Incorrect ^{(9,355 + 17,628)}/_54,000 = ^26,983/_54,000 = 0.4997 = 49.97 cM Incorrect ^{(9,355 + 17,661)}/_54,000 = ^27,016/_54,000 = 0.5003 = 50.03 cM Incorrect ^{(9,355 + 9,356)}/_54,000 = ^18,711/_54,000 = 0.3465 = 34.65 cM Correct ^{(9,356 + 17,628)}/_54,000 = ^26,984/_54,000 = 0.4997 = 49.97 cM Incorrect ^{(9,356 + 17,661)}/_54,000 = ^27,017/_54,000 = 0.5003 = 50.03 cM Incorrect MC

b600_e1e1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
kidney, waxy	k	w	5,494
kidney	k	+	29,170
waxy	+	w	29,749
wildtype	+	+	5,587
TOTAL =			70,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(29,170 + 29,749)}/_70,000 = ^58,919/_70,000 = 0.8417 = 84.17 cM Incorrect ^{(5,494 + 29,170)}/_70,000 = ^34,664/_70,000 = 0.4952 = 49.52 cM Incorrect ^{(5,494 + 29,749)}/_70,000 = ^35,243/_70,000 = 0.5035 = 50.35 cM Incorrect ^{(5,494 + 5,587)}/_70,000 = ^11,081/_70,000 = 0.1583 = 15.83 cM Correct ^{(5,587 + 29,170)}/_70,000 = ^34,757/_70,000 = 0.4965 = 49.65 cM Incorrect ^{(5,587 + 29,749)}/_70,000 = ^35,336/_70,000 = 0.5048 = 50.48 cM Incorrect MC

f80b_7ff4

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
eery, tipsy	e	t	35,725
eery	e	+	4,259
tipsy	+	t	4,373
wildtype	+	+	35,643
TOTAL =			80,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(35,643 + 35,725)}/_80,000 = ^71,368/_80,000 = 0.8921 = 89.21 cM Incorrect ^{(4,259 + 35,643)}/_80,000 = ^39,902/_80,000 = 0.4988 = 49.88 cM Incorrect ^{(4,259 + 35,725)}/_80,000 = ^39,984/_80,000 = 0.4998 = 49.98 cM Incorrect ^{(4,259 + 4,373)}/_80,000 = ^8,632/_80,000 = 0.1079 = 10.79 cM Correct ^{(4,373 + 35,643)}/_80,000 = ^40,016/_80,000 = 0.5002 = 50.02 cM Incorrect ^{(4,373 + 35,725)}/_80,000 = ^40,098/_80,000 = 0.5012 = 50.12 cM Incorrect MC

df44_07b7

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
horsey, xanthic	h	x	394
horsey	h	+	92
xanthic	+	x	84
wildtype	+	+	430
TOTAL =			1,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(394 + 430)}/_1,000 = ⁸²⁴/_1,000 = 0.8240 = 82.40 cM Incorrect ^{(84 + 394)}/_1,000 = ⁴⁷⁸/_1,000 = 0.4780 = 47.80 cM Incorrect ^{(84 + 92)}/_1,000 = ¹⁷⁶/_1,000 = 0.1760 = 17.60 cM Correct ^{(92 + 394)}/_1,000 = ⁴⁸⁶/_1,000 = 0.4860 = 48.60 cM Incorrect ⁴³⁰/_1,000 = ⁴³⁰/_1,000 = 0.4300 = 43.00 cM Incorrect ⁸⁴/_1,000 = ⁸⁴/_1,000 = 0.0840 = 8.40 cM Incorrect MC

4d40_7ded

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene N is connected with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
kidney, nerdy	k	n	4,075
kidney	k	+	881
nerdy	+	n	921
wildtype	+	+	4,123
TOTAL =			10,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,075 + 4,123)}/_10,000 = ^8,198/_10,000 = 0.8198 = 81.98 cM Incorrect ^{(881 + 4,075)}/_10,000 = ^4,956/_10,000 = 0.4956 = 49.56 cM Incorrect ^{(881 + 4,123)}/_10,000 = ^5,004/_10,000 = 0.5004 = 50.04 cM Incorrect ^{(881 + 921)}/_10,000 = ^1,802/_10,000 = 0.1802 = 18.02 cM Correct ^{(921 + 4,075)}/_10,000 = ^4,996/_10,000 = 0.4996 = 49.96 cM Incorrect ^{(921 + 4,123)}/_10,000 = ^5,044/_10,000 = 0.5044 = 50.44 cM Incorrect MC

a7a4_52d8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.

Phenotype	Genotypes		Progeny Count
artsy, chummy	a	c	1,708
artsy	a	+	3,290
chummy	+	c	3,306
wildtype	+	+	1,696
TOTAL =			10,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,696 + 1,708)}/_10,000 = ^3,404/_10,000 = 0.3404 = 34.04 cM Correct ^{(1,696 + 3,290)}/_10,000 = ^4,986/_10,000 = 0.4986 = 49.86 cM Incorrect ^{(1,696 + 3,306)}/_10,000 = ^5,002/_10,000 = 0.5002 = 50.02 cM Incorrect ^{(1,708 + 3,290)}/_10,000 = ^4,998/_10,000 = 0.4998 = 49.98 cM Incorrect ^{(1,708 + 3,306)}/_10,000 = ^5,014/_10,000 = 0.5014 = 50.14 cM Incorrect ^{(3,290 + 3,306)}/_10,000 = ^6,596/_10,000 = 0.6596 = 65.96 cM Incorrect MC

cc3e_adb2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is connected with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
chummy, mushy	c	m	4,706
chummy	c	+	7,760
mushy	+	m	7,830
wildtype	+	+	4,704
TOTAL =			25,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,704 + 4,706)}/_25,000 = ^9,410/_25,000 = 0.3764 = 37.64 cM Correct ^{(4,704 + 7,760)}/_25,000 = ^12,464/_25,000 = 0.4986 = 49.86 cM Incorrect ^{(4,704 + 7,830)}/_25,000 = ^12,534/_25,000 = 0.5014 = 50.14 cM Incorrect ^{(4,706 + 7,760)}/_25,000 = ^12,466/_25,000 = 0.4986 = 49.86 cM Incorrect ^{(4,706 + 7,830)}/_25,000 = ^12,536/_25,000 = 0.5014 = 50.14 cM Incorrect ^{(7,760 + 7,830)}/_25,000 = ^15,590/_25,000 = 0.6236 = 62.36 cM Incorrect MC

28d5_1a61

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is correlated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
eery, horsey	e	h	14,644
eery	e	+	38,201
horsey	+	h	37,798
wildtype	+	+	14,357
TOTAL =			105,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,357 + 14,644)}/_105,000 = ^29,001/_105,000 = 0.2762 = 27.62 cM Correct ^{(14,357 + 37,798)}/_105,000 = ^52,155/_105,000 = 0.4967 = 49.67 cM Incorrect ^{(14,357 + 38,201)}/_105,000 = ^52,558/_105,000 = 0.5006 = 50.06 cM Incorrect ^{(14,644 + 37,798)}/_105,000 = ^52,442/_105,000 = 0.4994 = 49.94 cM Incorrect ^{(14,644 + 38,201)}/_105,000 = ^52,845/_105,000 = 0.5033 = 50.33 cM Incorrect ^{(37,798 + 38,201)}/_105,000 = ^75,999/_105,000 = 0.7238 = 72.38 cM Incorrect MC

6412_9383

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene R is analogous to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
mushy, rusty	m	r	10,014
mushy	m	+	45,177
rusty	+	r	44,726
wildtype	+	+	10,083
TOTAL =			110,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,014 + 10,083)}/_110,000 = ^20,097/_110,000 = 0.1827 = 18.27 cM Correct ^{(10,014 + 44,726)}/_110,000 = ^54,740/_110,000 = 0.4976 = 49.76 cM Incorrect ^{(10,014 + 45,177)}/_110,000 = ^55,191/_110,000 = 0.5017 = 50.17 cM Incorrect ^{(10,083 + 44,726)}/_110,000 = ^54,809/_110,000 = 0.4983 = 49.83 cM Incorrect ^{(10,083 + 45,177)}/_110,000 = ^55,260/_110,000 = 0.5024 = 50.24 cM Incorrect ^{(44,726 + 45,177)}/_110,000 = ^89,903/_110,000 = 0.8173 = 81.73 cM Incorrect MC

5f6a_a4bb

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
prickly, tipsy	p	t	12,896
prickly	p	+	37,102
tipsy	+	t	37,228
wildtype	+	+	12,774
TOTAL =			100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,774 + 12,896)}/_100,000 = ^25,670/_100,000 = 0.2567 = 25.67 cM Correct ^{(12,774 + 37,102)}/_100,000 = ^49,876/_100,000 = 0.4988 = 49.88 cM Incorrect ^{(12,774 + 37,228)}/_100,000 = ^50,002/_100,000 = 0.5000 = 50.00 cM Incorrect ^{(12,896 + 37,102)}/_100,000 = ^49,998/_100,000 = 0.5000 = 50.00 cM Incorrect ^{(12,896 + 37,228)}/_100,000 = ^50,124/_100,000 = 0.5012 = 50.12 cM Incorrect ^{(37,102 + 37,228)}/_100,000 = ^74,330/_100,000 = 0.7433 = 74.33 cM Incorrect MC

9af2_a152

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene T is connected with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.
Gene X is correlated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
tipsy, xanthic	t	x	435
tipsy	t	+	284
xanthic	+	x	265
wildtype	+	+	516
TOTAL =			1,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(265 + 284)}/_1,500 = ⁵⁴⁹/_1,500 = 0.3660 = 36.60 cM Correct ^{(265 + 435)}/_1,500 = ⁷⁰⁰/_1,500 = 0.4667 = 46.67 cM Incorrect ^{(284 + 435)}/_1,500 = ⁷¹⁹/_1,500 = 0.4793 = 47.93 cM Incorrect ^{(435 + 516)}/_1,500 = ⁹⁵¹/_1,500 = 0.6340 = 63.40 cM Incorrect ²⁶⁵/_1,500 = ²⁶⁵/_1,500 = 0.1767 = 17.67 cM Incorrect ⁵¹⁶/_1,500 = ⁵¹⁶/_1,500 = 0.3440 = 34.40 cM Incorrect MC

47be_c21f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene W is correlated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
eery, waxy	e	w	14,225
eery	e	+	8,670
waxy	+	w	8,787
wildtype	+	+	14,318
TOTAL =			46,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,225 + 14,318)}/_46,000 = ^28,543/_46,000 = 0.6205 = 62.05 cM Incorrect ^{(8,670 + 14,225)}/_46,000 = ^22,895/_46,000 = 0.4977 = 49.77 cM Incorrect ^{(8,670 + 14,318)}/_46,000 = ^22,988/_46,000 = 0.4997 = 49.97 cM Incorrect ^{(8,670 + 8,787)}/_46,000 = ^17,457/_46,000 = 0.3795 = 37.95 cM Correct ^{(8,787 + 14,225)}/_46,000 = ^23,012/_46,000 = 0.5003 = 50.03 cM Incorrect ^{(8,787 + 14,318)}/_46,000 = ^23,105/_46,000 = 0.5023 = 50.23 cM Incorrect MC

76b3_6798

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is correlated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene K is linked with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
bumpy, kidney	b	k	6,256
bumpy	b	+	2,683
kidney	+	k	2,699
wildtype	+	+	6,362
TOTAL =			18,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,683 + 2,699)}/_18,000 = ^5,382/_18,000 = 0.2990 = 29.90 cM Correct ^{(2,683 + 6,256)}/_18,000 = ^8,939/_18,000 = 0.4966 = 49.66 cM Incorrect ^{(2,683 + 6,362)}/_18,000 = ^9,045/_18,000 = 0.5025 = 50.25 cM Incorrect ^{(2,699 + 6,256)}/_18,000 = ^8,955/_18,000 = 0.4975 = 49.75 cM Incorrect ^{(2,699 + 6,362)}/_18,000 = ^9,061/_18,000 = 0.5034 = 50.34 cM Incorrect ^{(6,256 + 6,362)}/_18,000 = ^12,618/_18,000 = 0.7010 = 70.10 cM Incorrect MC

a77d_39b1

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
dewy, fuzzy	d	f	68,078
dewy	d	+	21,713
fuzzy	+	f	21,685
wildtype	+	+	68,524
TOTAL =			180,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(21,685 + 21,713)}/_180,000 = ^43,398/_180,000 = 0.2411 = 24.11 cM Correct ^{(21,685 + 68,078)}/_180,000 = ^89,763/_180,000 = 0.4987 = 49.87 cM Incorrect ^{(21,685 + 68,524)}/_180,000 = ^90,209/_180,000 = 0.5012 = 50.12 cM Incorrect ^{(21,713 + 68,078)}/_180,000 = ^89,791/_180,000 = 0.4988 = 49.88 cM Incorrect ^{(21,713 + 68,524)}/_180,000 = ^90,237/_180,000 = 0.5013 = 50.13 cM Incorrect ^{(68,078 + 68,524)}/_180,000 = ^136,602/_180,000 = 0.7589 = 75.89 cM Incorrect MC

08d6_7473

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is correlated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
dewy, yucky	d	y	14,505
dewy	d	+	5,383
yucky	+	y	5,489
wildtype	+	+	14,623
TOTAL =			40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,505 + 14,623)}/_40,000 = ^29,128/_40,000 = 0.7282 = 72.82 cM Incorrect ^{(5,383 + 14,505)}/_40,000 = ^19,888/_40,000 = 0.4972 = 49.72 cM Incorrect ^{(5,383 + 14,623)}/_40,000 = ^20,006/_40,000 = 0.5001 = 50.02 cM Incorrect ^{(5,383 + 5,489)}/_40,000 = ^10,872/_40,000 = 0.2718 = 27.18 cM Correct ^{(5,489 + 14,505)}/_40,000 = ^19,994/_40,000 = 0.4999 = 49.98 cM Incorrect ^{(5,489 + 14,623)}/_40,000 = ^20,112/_40,000 = 0.5028 = 50.28 cM Incorrect MC

2a7c_5ded

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene H is associated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
dewy, horsey	d	h	4,330
dewy	d	+	668
horsey	+	h	568
wildtype	+	+	4,434
TOTAL =			10,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,330 + 4,434)}/_10,000 = ^8,764/_10,000 = 0.8764 = 87.64 cM Incorrect ^{(568 + 4,330)}/_10,000 = ^4,898/_10,000 = 0.4898 = 48.98 cM Incorrect ^{(568 + 4,434)}/_10,000 = ^5,002/_10,000 = 0.5002 = 50.02 cM Incorrect ^{(568 + 668)}/_10,000 = ^1,236/_10,000 = 0.1236 = 12.36 cM Correct ^{(668 + 4,330)}/_10,000 = ^4,998/_10,000 = 0.4998 = 49.98 cM Incorrect ⁵⁶⁸/_10,000 = ⁵⁶⁸/_10,000 = 0.0568 = 5.68 cM Incorrect MC

7e0c_49f2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
rusty, xanthic	r	x	5,745
rusty	r	+	19,227
xanthic	+	x	19,163
wildtype	+	+	5,865
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(19,163 + 19,227)}/_50,000 = ^38,390/_50,000 = 0.7678 = 76.78 cM Incorrect ^{(5,745 + 19,163)}/_50,000 = ^24,908/_50,000 = 0.4982 = 49.82 cM Incorrect ^{(5,745 + 19,227)}/_50,000 = ^24,972/_50,000 = 0.4994 = 49.94 cM Incorrect ^{(5,745 + 5,865)}/_50,000 = ^11,610/_50,000 = 0.2322 = 23.22 cM Correct ^{(5,865 + 19,163)}/_50,000 = ^25,028/_50,000 = 0.5006 = 50.06 cM Incorrect ^{(5,865 + 19,227)}/_50,000 = ^25,092/_50,000 = 0.5018 = 50.18 cM Incorrect MC

a381_d1e8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is related to the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene R is associated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
chummy, rusty	c	r	6,550
chummy	c	+	58,331
rusty	+	r	58,812
wildtype	+	+	6,307
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(58,331 + 58,812)}/_130,000 = ^117,143/_130,000 = 0.9011 = 90.11 cM Incorrect ^{(6,307 + 58,331)}/_130,000 = ^64,638/_130,000 = 0.4972 = 49.72 cM Incorrect ^{(6,307 + 58,812)}/_130,000 = ^65,119/_130,000 = 0.5009 = 50.09 cM Incorrect ^{(6,307 + 6,550)}/_130,000 = ^12,857/_130,000 = 0.0989 = 9.89 cM Correct ^{(6,550 + 58,331)}/_130,000 = ^64,881/_130,000 = 0.4991 = 49.91 cM Incorrect ^{(6,550 + 58,812)}/_130,000 = ^65,362/_130,000 = 0.5028 = 50.28 cM Incorrect MC

9d23_9429

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.

Phenotype	Genotypes		Progeny Count
dewy, fuzzy	d	f	74,641
dewy	d	+	40,399
fuzzy	+	f	40,354
wildtype	+	+	74,606
TOTAL =			230,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(40,354 + 40,399)}/_230,000 = ^80,753/_230,000 = 0.3511 = 35.11 cM Correct ^{(40,354 + 74,606)}/_230,000 = ^114,960/_230,000 = 0.4998 = 49.98 cM Incorrect ^{(40,354 + 74,641)}/_230,000 = ^114,995/_230,000 = 0.5000 = 50.00 cM Incorrect ^{(40,399 + 74,606)}/_230,000 = ^115,005/_230,000 = 0.5000 = 50.00 cM Incorrect ^{(40,399 + 74,641)}/_230,000 = ^115,040/_230,000 = 0.5002 = 50.02 cM Incorrect ^{(74,606 + 74,641)}/_230,000 = ^149,247/_230,000 = 0.6489 = 64.89 cM Incorrect MC

9b8a_2382

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is linked with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
nerdy, yucky	n	y	169
nerdy	n	+	1,063
yucky	+	y	1,047
wildtype	+	+	221
TOTAL =			2,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,047 + 1,063)}/_2,500 = ^2,110/_2,500 = 0.8440 = 84.40 cM Incorrect ^{(169 + 1,047)}/_2,500 = ^1,216/_2,500 = 0.4864 = 48.64 cM Incorrect ^{(169 + 1,063)}/_2,500 = ^1,232/_2,500 = 0.4928 = 49.28 cM Incorrect ^{(169 + 221)}/_2,500 = ³⁹⁰/_2,500 = 0.1560 = 15.60 cM Correct ^{(221 + 1,047)}/_2,500 = ^1,268/_2,500 = 0.5072 = 50.72 cM Incorrect ¹⁶⁹/_2,500 = ¹⁶⁹/_2,500 = 0.0676 = 6.76 cM Incorrect MC

0ae4_1908

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is connected with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene M is associated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
kidney, mushy	k	m	776
kidney	k	+	4,316
mushy	+	m	4,159
wildtype	+	+	749
TOTAL =			10,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(4,159 + 4,316)}/_10,000 = ^8,475/_10,000 = 0.8475 = 84.75 cM Incorrect ^{(749 + 4,159)}/_10,000 = ^4,908/_10,000 = 0.4908 = 49.08 cM Incorrect ^{(749 + 4,316)}/_10,000 = ^5,065/_10,000 = 0.5065 = 50.65 cM Incorrect ^{(749 + 776)}/_10,000 = ^1,525/_10,000 = 0.1525 = 15.25 cM Correct ^{(776 + 4,159)}/_10,000 = ^4,935/_10,000 = 0.4935 = 49.35 cM Incorrect ^{(776 + 4,316)}/_10,000 = ^5,092/_10,000 = 0.5092 = 50.92 cM Incorrect MC

d580_5726

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is analogous to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene J is affiliated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
fuzzy, jerky	f	j	8,777
fuzzy	f	+	27,576
jerky	+	j	27,031
wildtype	+	+	9,116
TOTAL =			72,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(27,031 + 27,576)}/_72,500 = ^54,607/_72,500 = 0.7532 = 75.32 cM Incorrect ^{(8,777 + 27,031)}/_72,500 = ^35,808/_72,500 = 0.4939 = 49.39 cM Incorrect ^{(8,777 + 27,576)}/_72,500 = ^36,353/_72,500 = 0.5014 = 50.14 cM Incorrect ^{(8,777 + 9,116)}/_72,500 = ^17,893/_72,500 = 0.2468 = 24.68 cM Correct ^{(9,116 + 27,031)}/_72,500 = ^36,147/_72,500 = 0.4986 = 49.86 cM Incorrect ^{(9,116 + 27,576)}/_72,500 = ^36,692/_72,500 = 0.5061 = 50.61 cM Incorrect MC

4b12_efc9

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is analogous to the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
nerdy, prickly	n	p	48
nerdy	n	+	104
prickly	+	p	109
wildtype	+	+	39
TOTAL =			300

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(104 + 109)}/₃₀₀ = ²¹³/₃₀₀ = 0.7100 = 71.00 cM Incorrect ^{(39 + 104)}/₃₀₀ = ¹⁴³/₃₀₀ = 0.4767 = 47.67 cM Incorrect ^{(39 + 109)}/₃₀₀ = ¹⁴⁸/₃₀₀ = 0.4933 = 49.33 cM Incorrect ^{(39 + 48)}/₃₀₀ = ⁸⁷/₃₀₀ = 0.2900 = 29.00 cM Correct ^{(48 + 104)}/₃₀₀ = ¹⁵²/₃₀₀ = 0.5067 = 50.67 cM Incorrect ³⁹/₃₀₀ = ³⁹/₃₀₀ = 0.1300 = 13.00 cM Incorrect MC

934a_90df

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is connected with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene X is connected with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
jerky, xanthic	j	x	53,313
jerky	j	+	31,398
xanthic	+	x	31,859
wildtype	+	+	53,430
TOTAL =			170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(31,398 + 31,859)}/_170,000 = ^63,257/_170,000 = 0.3721 = 37.21 cM Correct ^{(31,398 + 53,313)}/_170,000 = ^84,711/_170,000 = 0.4983 = 49.83 cM Incorrect ^{(31,398 + 53,430)}/_170,000 = ^84,828/_170,000 = 0.4990 = 49.90 cM Incorrect ^{(31,859 + 53,313)}/_170,000 = ^85,172/_170,000 = 0.5010 = 50.10 cM Incorrect ^{(31,859 + 53,430)}/_170,000 = ^85,289/_170,000 = 0.5017 = 50.17 cM Incorrect ^{(53,313 + 53,430)}/_170,000 = ^106,743/_170,000 = 0.6279 = 62.79 cM Incorrect MC

7411_6990

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene H is related to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.

Phenotype	Genotypes		Progeny Count
eery, horsey	e	h	6,325
eery	e	+	26,346
horsey	+	h	26,096
wildtype	+	+	6,233
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(26,096 + 26,346)}/_65,000 = ^52,442/_65,000 = 0.8068 = 80.68 cM Incorrect ^{(6,233 + 26,096)}/_65,000 = ^32,329/_65,000 = 0.4974 = 49.74 cM Incorrect ^{(6,233 + 26,346)}/_65,000 = ^32,579/_65,000 = 0.5012 = 50.12 cM Incorrect ^{(6,233 + 6,325)}/_65,000 = ^12,558/_65,000 = 0.1932 = 19.32 cM Correct ^{(6,325 + 26,096)}/_65,000 = ^32,421/_65,000 = 0.4988 = 49.88 cM Incorrect ^{(6,325 + 26,346)}/_65,000 = ^32,671/_65,000 = 0.5026 = 50.26 cM Incorrect MC

341f_24a4

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene M is affiliated with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
eery, mushy	e	m	1,459
eery	e	+	7,191
mushy	+	m	7,355
wildtype	+	+	1,495
TOTAL =			17,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,459 + 1,495)}/_17,500 = ^2,954/_17,500 = 0.1688 = 16.88 cM Correct ^{(1,459 + 7,191)}/_17,500 = ^8,650/_17,500 = 0.4943 = 49.43 cM Incorrect ^{(1,459 + 7,355)}/_17,500 = ^8,814/_17,500 = 0.5037 = 50.37 cM Incorrect ^{(1,495 + 7,191)}/_17,500 = ^8,686/_17,500 = 0.4963 = 49.63 cM Incorrect ^{(1,495 + 7,355)}/_17,500 = ^8,850/_17,500 = 0.5057 = 50.57 cM Incorrect ^{(7,191 + 7,355)}/_17,500 = ^14,546/_17,500 = 0.8312 = 83.12 cM Incorrect MC

5624_bad0

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is linked with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene X is affiliated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
dewy, xanthic	d	x	13,620
dewy	d	+	6,275
xanthic	+	x	6,269
wildtype	+	+	13,836
TOTAL =			40,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,620 + 13,836)}/_40,000 = ^27,456/_40,000 = 0.6864 = 68.64 cM Incorrect ^{(6,269 + 13,620)}/_40,000 = ^19,889/_40,000 = 0.4972 = 49.72 cM Incorrect ^{(6,269 + 13,836)}/_40,000 = ^20,105/_40,000 = 0.5026 = 50.26 cM Incorrect ^{(6,269 + 6,275)}/_40,000 = ^12,544/_40,000 = 0.3136 = 31.36 cM Correct ^{(6,275 + 13,620)}/_40,000 = ^19,895/_40,000 = 0.4974 = 49.74 cM Incorrect ^{(6,275 + 13,836)}/_40,000 = ^20,111/_40,000 = 0.5028 = 50.28 cM Incorrect MC

67ef_1081

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is linked with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene E is related to the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
chummy, eery	c	e	7,637
chummy	c	+	2,384
eery	+	e	2,372
wildtype	+	+	7,607
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,372 + 2,384)}/_20,000 = ^4,756/_20,000 = 0.2378 = 23.78 cM Correct ^{(2,372 + 7,607)}/_20,000 = ^9,979/_20,000 = 0.4990 = 49.90 cM Incorrect ^{(2,372 + 7,637)}/_20,000 = ^10,009/_20,000 = 0.5004 = 50.04 cM Incorrect ^{(2,384 + 7,607)}/_20,000 = ^9,991/_20,000 = 0.4995 = 49.95 cM Incorrect ^{(2,384 + 7,637)}/_20,000 = ^10,021/_20,000 = 0.5010 = 50.10 cM Incorrect ^{(7,607 + 7,637)}/_20,000 = ^15,244/_20,000 = 0.7622 = 76.22 cM Incorrect MC

f401_0c18

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is linked with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene E is associated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.

Phenotype	Genotypes		Progeny Count
artsy, eery	a	e	9,330
artsy	a	+	35,844
eery	+	e	35,445
wildtype	+	+	9,381
TOTAL =			90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(35,445 + 35,844)}/_90,000 = ^71,289/_90,000 = 0.7921 = 79.21 cM Incorrect ^{(9,330 + 35,445)}/_90,000 = ^44,775/_90,000 = 0.4975 = 49.75 cM Incorrect ^{(9,330 + 35,844)}/_90,000 = ^45,174/_90,000 = 0.5019 = 50.19 cM Incorrect ^{(9,330 + 9,381)}/_90,000 = ^18,711/_90,000 = 0.2079 = 20.79 cM Correct ^{(9,381 + 35,445)}/_90,000 = ^44,826/_90,000 = 0.4981 = 49.81 cM Incorrect ^{(9,381 + 35,844)}/_90,000 = ^45,225/_90,000 = 0.5025 = 50.25 cM Incorrect MC

7497_0742

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is linked with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene X is analogous to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
prickly, xanthic	p	x	12,812
prickly	p	+	27,304
xanthic	+	x	27,264
wildtype	+	+	12,620
TOTAL =			80,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(12,620 + 12,812)}/_80,000 = ^25,432/_80,000 = 0.3179 = 31.79 cM Correct ^{(12,620 + 27,264)}/_80,000 = ^39,884/_80,000 = 0.4985 = 49.85 cM Incorrect ^{(12,620 + 27,304)}/_80,000 = ^39,924/_80,000 = 0.4990 = 49.91 cM Incorrect ^{(12,812 + 27,264)}/_80,000 = ^40,076/_80,000 = 0.5010 = 50.09 cM Incorrect ^{(12,812 + 27,304)}/_80,000 = ^40,116/_80,000 = 0.5014 = 50.14 cM Incorrect ^{(27,264 + 27,304)}/_80,000 = ^54,568/_80,000 = 0.6821 = 68.21 cM Incorrect MC

d540_b475

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is connected with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
fuzzy, prickly	f	p	6,465
fuzzy	f	+	10,977
prickly	+	p	11,010
wildtype	+	+	6,548
TOTAL =			35,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,977 + 11,010)}/_35,000 = ^21,987/_35,000 = 0.6282 = 62.82 cM Incorrect ^{(6,465 + 10,977)}/_35,000 = ^17,442/_35,000 = 0.4983 = 49.83 cM Incorrect ^{(6,465 + 11,010)}/_35,000 = ^17,475/_35,000 = 0.4993 = 49.93 cM Incorrect ^{(6,465 + 6,548)}/_35,000 = ^13,013/_35,000 = 0.3718 = 37.18 cM Correct ^{(6,548 + 10,977)}/_35,000 = ^17,525/_35,000 = 0.5007 = 50.07 cM Incorrect ^{(6,548 + 11,010)}/_35,000 = ^17,558/_35,000 = 0.5017 = 50.17 cM Incorrect MC

e0c0_e78e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene X is associated with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.
Gene Y is linked with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
xanthic, yucky	x	y	991
xanthic	x	+	198
yucky	+	y	192
wildtype	+	+	1,019
TOTAL =			2,400

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(192 + 1,019)}/_2,400 = ^1,211/_2,400 = 0.5046 = 50.46 cM Incorrect ^{(192 + 198)}/_2,400 = ³⁹⁰/_2,400 = 0.1625 = 16.25 cM Correct ^{(192 + 991)}/_2,400 = ^1,183/_2,400 = 0.4929 = 49.29 cM Incorrect ^{(198 + 1,019)}/_2,400 = ^1,217/_2,400 = 0.5071 = 50.71 cM Incorrect ^{(198 + 991)}/_2,400 = ^1,189/_2,400 = 0.4954 = 49.54 cM Incorrect ^{(991 + 1,019)}/_2,400 = ^2,010/_2,400 = 0.8375 = 83.75 cM Incorrect MC

0239_cd79

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is correlated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene K is correlated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
fuzzy, kidney	f	k	7,913
fuzzy	f	+	15,904
kidney	+	k	15,693
wildtype	+	+	7,990
TOTAL =			47,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(15,693 + 15,904)}/_47,500 = ^31,597/_47,500 = 0.6652 = 66.52 cM Incorrect ^{(7,913 + 15,693)}/_47,500 = ^23,606/_47,500 = 0.4970 = 49.70 cM Incorrect ^{(7,913 + 15,904)}/_47,500 = ^23,817/_47,500 = 0.5014 = 50.14 cM Incorrect ^{(7,913 + 7,990)}/_47,500 = ^15,903/_47,500 = 0.3348 = 33.48 cM Correct ^{(7,990 + 15,693)}/_47,500 = ^23,683/_47,500 = 0.4986 = 49.86 cM Incorrect ^{(7,990 + 15,904)}/_47,500 = ^23,894/_47,500 = 0.5030 = 50.30 cM Incorrect MC

3422_a715

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is correlated with the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene X is related to the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
jerky, xanthic	j	x	6,670
jerky	j	+	2,219
xanthic	+	x	2,254
wildtype	+	+	6,857
TOTAL =			18,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,219 + 2,254)}/_18,000 = ^4,473/_18,000 = 0.2485 = 24.85 cM Correct ^{(2,219 + 6,670)}/_18,000 = ^8,889/_18,000 = 0.4938 = 49.38 cM Incorrect ^{(2,219 + 6,857)}/_18,000 = ^9,076/_18,000 = 0.5042 = 50.42 cM Incorrect ^{(2,254 + 6,670)}/_18,000 = ^8,924/_18,000 = 0.4958 = 49.58 cM Incorrect ^{(2,254 + 6,857)}/_18,000 = ^9,111/_18,000 = 0.5062 = 50.62 cM Incorrect ^{(6,670 + 6,857)}/_18,000 = ^13,527/_18,000 = 0.7515 = 75.15 cM Incorrect MC

3a87_6c22

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is associated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene N is associated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
bumpy, nerdy	b	n	6,900
bumpy	b	+	14,202
nerdy	+	n	14,127
wildtype	+	+	6,771
TOTAL =			42,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(14,127 + 14,202)}/_42,000 = ^28,329/_42,000 = 0.6745 = 67.45 cM Incorrect ^{(6,771 + 14,127)}/_42,000 = ^20,898/_42,000 = 0.4976 = 49.76 cM Incorrect ^{(6,771 + 14,202)}/_42,000 = ^20,973/_42,000 = 0.4994 = 49.94 cM Incorrect ^{(6,771 + 6,900)}/_42,000 = ^13,671/_42,000 = 0.3255 = 32.55 cM Correct ^{(6,900 + 14,127)}/_42,000 = ^21,027/_42,000 = 0.5006 = 50.06 cM Incorrect ^{(6,900 + 14,202)}/_42,000 = ^21,102/_42,000 = 0.5024 = 50.24 cM Incorrect MC

1bc2_58b2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is analogous to the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene T is affiliated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
mushy, tipsy	m	t	8,036
mushy	m	+	42,255
tipsy	+	t	41,635
wildtype	+	+	8,074
TOTAL =			100,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(41,635 + 42,255)}/_100,000 = ^83,890/_100,000 = 0.8389 = 83.89 cM Incorrect ^{(8,036 + 41,635)}/_100,000 = ^49,671/_100,000 = 0.4967 = 49.67 cM Incorrect ^{(8,036 + 42,255)}/_100,000 = ^50,291/_100,000 = 0.5029 = 50.29 cM Incorrect ^{(8,036 + 8,074)}/_100,000 = ^16,110/_100,000 = 0.1611 = 16.11 cM Correct ^{(8,074 + 41,635)}/_100,000 = ^49,709/_100,000 = 0.4971 = 49.71 cM Incorrect ^{(8,074 + 42,255)}/_100,000 = ^50,329/_100,000 = 0.5033 = 50.33 cM Incorrect MC

2d67_a189

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene C is correlated with the 'chummy' phenotype. A fruit fly that is homozygous recessive for Gene C shows behavior where it always maintains a close distance to other flies.
Gene K is related to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
chummy, kidney	c	k	9,854
chummy	c	+	5,107
kidney	+	k	5,138
wildtype	+	+	9,901
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(5,107 + 5,138)}/_30,000 = ^10,245/_30,000 = 0.3415 = 34.15 cM Correct ^{(5,107 + 9,854)}/_30,000 = ^14,961/_30,000 = 0.4987 = 49.87 cM Incorrect ^{(5,107 + 9,901)}/_30,000 = ^15,008/_30,000 = 0.5003 = 50.03 cM Incorrect ^{(5,138 + 9,854)}/_30,000 = ^14,992/_30,000 = 0.4997 = 49.97 cM Incorrect ^{(5,138 + 9,901)}/_30,000 = ^15,039/_30,000 = 0.5013 = 50.13 cM Incorrect ^{(9,854 + 9,901)}/_30,000 = ^19,755/_30,000 = 0.6585 = 65.85 cM Incorrect MC

746c_89ff

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene J is analogous to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
jerky, rusty	j	r	191
jerky	j	+	291
rusty	+	r	333
wildtype	+	+	185
TOTAL =			1,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(185 + 191)}/_1,000 = ³⁷⁶/_1,000 = 0.3760 = 37.60 cM Correct ^{(185 + 291)}/_1,000 = ⁴⁷⁶/_1,000 = 0.4760 = 47.60 cM Incorrect ^{(191 + 291)}/_1,000 = ⁴⁸²/_1,000 = 0.4820 = 48.20 cM Incorrect ^{(291 + 333)}/_1,000 = ⁶²⁴/_1,000 = 0.6240 = 62.40 cM Incorrect ¹⁸⁵/_1,000 = ¹⁸⁵/_1,000 = 0.1850 = 18.50 cM Incorrect ³³³/_1,000 = ³³³/_1,000 = 0.3330 = 33.30 cM Incorrect MC

86cd_c172

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is associated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene M is linked with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
bumpy, mushy	b	m	13,617
bumpy	b	+	1,418
mushy	+	m	1,426
wildtype	+	+	13,539
TOTAL =			30,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,418 + 1,426)}/_30,000 = ^2,844/_30,000 = 0.0948 = 9.48 cM Correct ^{(1,418 + 13,539)}/_30,000 = ^14,957/_30,000 = 0.4986 = 49.86 cM Incorrect ^{(1,418 + 13,617)}/_30,000 = ^15,035/_30,000 = 0.5012 = 50.12 cM Incorrect ^{(1,426 + 13,539)}/_30,000 = ^14,965/_30,000 = 0.4988 = 49.88 cM Incorrect ^{(1,426 + 13,617)}/_30,000 = ^15,043/_30,000 = 0.5014 = 50.14 cM Incorrect ^{(13,539 + 13,617)}/_30,000 = ^27,156/_30,000 = 0.9052 = 90.52 cM Incorrect MC

e353_fa71

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is connected with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene N is correlated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.

Phenotype	Genotypes		Progeny Count
artsy, nerdy	a	n	27,424
artsy	a	+	5,000
nerdy	+	n	4,971
wildtype	+	+	27,605
TOTAL =			65,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(27,424 + 27,605)}/_65,000 = ^55,029/_65,000 = 0.8466 = 84.66 cM Incorrect ^{(4,971 + 27,424)}/_65,000 = ^32,395/_65,000 = 0.4984 = 49.84 cM Incorrect ^{(4,971 + 27,605)}/_65,000 = ^32,576/_65,000 = 0.5012 = 50.12 cM Incorrect ^{(4,971 + 5,000)}/_65,000 = ^9,971/_65,000 = 0.1534 = 15.34 cM Correct ^{(5,000 + 27,424)}/_65,000 = ^32,424/_65,000 = 0.4988 = 49.88 cM Incorrect ^{(5,000 + 27,605)}/_65,000 = ^32,605/_65,000 = 0.5016 = 50.16 cM Incorrect MC

d07d_158a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is affiliated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene R is linked with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
prickly, rusty	p	r	103,365
prickly	p	+	21,579
rusty	+	r	21,596
wildtype	+	+	103,460
TOTAL =			250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(103,365 + 103,460)}/_250,000 = ^206,825/_250,000 = 0.8273 = 82.73 cM Incorrect ^{(21,579 + 103,365)}/_250,000 = ^124,944/_250,000 = 0.4998 = 49.98 cM Incorrect ^{(21,579 + 103,460)}/_250,000 = ^125,039/_250,000 = 0.5002 = 50.02 cM Incorrect ^{(21,579 + 21,596)}/_250,000 = ^43,175/_250,000 = 0.1727 = 17.27 cM Correct ^{(21,596 + 103,365)}/_250,000 = ^124,961/_250,000 = 0.4998 = 49.98 cM Incorrect ^{(21,596 + 103,460)}/_250,000 = ^125,056/_250,000 = 0.5002 = 50.02 cM Incorrect MC

f879_3fa5

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene Y is related to the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
dewy, yucky	d	y	234
dewy	d	+	742
yucky	+	y	758
wildtype	+	+	266
TOTAL =			2,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(234 + 266)}/_2,000 = ⁵⁰⁰/_2,000 = 0.2500 = 25.00 cM Correct ^{(234 + 742)}/_2,000 = ⁹⁷⁶/_2,000 = 0.4880 = 48.80 cM Incorrect ^{(234 + 758)}/_2,000 = ⁹⁹²/_2,000 = 0.4960 = 49.60 cM Incorrect ^{(266 + 742)}/_2,000 = ^1,008/_2,000 = 0.5040 = 50.40 cM Incorrect ^{(742 + 758)}/_2,000 = ^1,500/_2,000 = 0.7500 = 75.00 cM Incorrect ²³⁴/_2,000 = ²³⁴/_2,000 = 0.1170 = 11.70 cM Incorrect MC

6845_5958

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is analogous to the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene R is correlated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
horsey, rusty	h	r	5,769
horsey	h	+	19,281
rusty	+	r	19,174
wildtype	+	+	5,776
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(19,174 + 19,281)}/_50,000 = ^38,455/_50,000 = 0.7691 = 76.91 cM Incorrect ^{(5,769 + 19,174)}/_50,000 = ^24,943/_50,000 = 0.4989 = 49.89 cM Incorrect ^{(5,769 + 19,281)}/_50,000 = ^25,050/_50,000 = 0.5010 = 50.10 cM Incorrect ^{(5,769 + 5,776)}/_50,000 = ^11,545/_50,000 = 0.2309 = 23.09 cM Correct ^{(5,776 + 19,174)}/_50,000 = ^24,950/_50,000 = 0.4990 = 49.90 cM Incorrect ^{(5,776 + 19,281)}/_50,000 = ^25,057/_50,000 = 0.5011 = 50.11 cM Incorrect MC

538e_96ae

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is affiliated with the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene W is affiliated with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
bumpy, waxy	b	w	24,724
bumpy	b	+	3,022
waxy	+	w	3,050
wildtype	+	+	24,204
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(24,204 + 24,724)}/_55,000 = ^48,928/_55,000 = 0.8896 = 88.96 cM Incorrect ^{(3,022 + 24,204)}/_55,000 = ^27,226/_55,000 = 0.4950 = 49.50 cM Incorrect ^{(3,022 + 24,724)}/_55,000 = ^27,746/_55,000 = 0.5045 = 50.45 cM Incorrect ^{(3,022 + 3,050)}/_55,000 = ^6,072/_55,000 = 0.1104 = 11.04 cM Correct ^{(3,050 + 24,204)}/_55,000 = ^27,254/_55,000 = 0.4955 = 49.55 cM Incorrect ^{(3,050 + 24,724)}/_55,000 = ^27,774/_55,000 = 0.5050 = 50.50 cM Incorrect MC

7c52_e6de

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene K is analogous to the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.
Gene X is linked with the 'xanthic' phenotype. A fruit fly that is homozygous recessive for Gene X has a fluorescent bright yellow coloring.

Phenotype	Genotypes		Progeny Count
kidney, xanthic	k	x	24,400
kidney	k	+	45,653
xanthic	+	x	45,613
wildtype	+	+	24,334
TOTAL =			140,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(24,334 + 24,400)}/_140,000 = ^48,734/_140,000 = 0.3481 = 34.81 cM Correct ^{(24,334 + 45,613)}/_140,000 = ^69,947/_140,000 = 0.4996 = 49.96 cM Incorrect ^{(24,334 + 45,653)}/_140,000 = ^69,987/_140,000 = 0.4999 = 49.99 cM Incorrect ^{(24,400 + 45,613)}/_140,000 = ^70,013/_140,000 = 0.5001 = 50.01 cM Incorrect ^{(24,400 + 45,653)}/_140,000 = ^70,053/_140,000 = 0.5004 = 50.04 cM Incorrect ^{(45,613 + 45,653)}/_140,000 = ^91,266/_140,000 = 0.6519 = 65.19 cM Incorrect MC

5e78_6dc8

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is related to the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
fuzzy, tipsy	f	t	35,100
fuzzy	f	+	22,378
tipsy	+	t	22,403
wildtype	+	+	35,119
TOTAL =			115,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(22,378 + 22,403)}/_115,000 = ^44,781/_115,000 = 0.3894 = 38.94 cM Correct ^{(22,378 + 35,100)}/_115,000 = ^57,478/_115,000 = 0.4998 = 49.98 cM Incorrect ^{(22,378 + 35,119)}/_115,000 = ^57,497/_115,000 = 0.5000 = 50.00 cM Incorrect ^{(22,403 + 35,100)}/_115,000 = ^57,503/_115,000 = 0.5000 = 50.00 cM Incorrect ^{(22,403 + 35,119)}/_115,000 = ^57,522/_115,000 = 0.5002 = 50.02 cM Incorrect ^{(35,100 + 35,119)}/_115,000 = ^70,219/_115,000 = 0.6106 = 61.06 cM Incorrect MC

7407_ed55

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is associated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene D is related to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.

Phenotype	Genotypes		Progeny Count
artsy, dewy	a	d	13,156
artsy	a	+	66,624
dewy	+	d	66,960
wildtype	+	+	13,260
TOTAL =			160,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,156 + 13,260)}/_160,000 = ^26,416/_160,000 = 0.1651 = 16.51 cM Correct ^{(13,156 + 66,624)}/_160,000 = ^79,780/_160,000 = 0.4986 = 49.86 cM Incorrect ^{(13,156 + 66,960)}/_160,000 = ^80,116/_160,000 = 0.5007 = 50.07 cM Incorrect ^{(13,260 + 66,624)}/_160,000 = ^79,884/_160,000 = 0.4993 = 49.93 cM Incorrect ^{(13,260 + 66,960)}/_160,000 = ^80,220/_160,000 = 0.5014 = 50.14 cM Incorrect ^{(66,624 + 66,960)}/_160,000 = ^133,584/_160,000 = 0.8349 = 83.49 cM Incorrect MC

d7c8_0e38

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.
Gene Y is associated with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
mushy, yucky	m	y	1,982
mushy	m	+	4,062
yucky	+	y	3,924
wildtype	+	+	2,032
TOTAL =			12,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,982 + 2,032)}/_12,000 = ^4,014/_12,000 = 0.3345 = 33.45 cM Correct ^{(1,982 + 3,924)}/_12,000 = ^5,906/_12,000 = 0.4922 = 49.22 cM Incorrect ^{(1,982 + 4,062)}/_12,000 = ^6,044/_12,000 = 0.5037 = 50.37 cM Incorrect ^{(2,032 + 3,924)}/_12,000 = ^5,956/_12,000 = 0.4963 = 49.63 cM Incorrect ^{(2,032 + 4,062)}/_12,000 = ^6,094/_12,000 = 0.5078 = 50.78 cM Incorrect ^{(3,924 + 4,062)}/_12,000 = ^7,986/_12,000 = 0.6655 = 66.55 cM Incorrect MC

5b27_3745

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is connected with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
eery, tipsy	e	t	90,447
eery	e	+	39,835
tipsy	+	t	39,543
wildtype	+	+	90,175
TOTAL =			260,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(39,543 + 39,835)}/_260,000 = ^79,378/_260,000 = 0.3053 = 30.53 cM Correct ^{(39,543 + 90,175)}/_260,000 = ^129,718/_260,000 = 0.4989 = 49.89 cM Incorrect ^{(39,543 + 90,447)}/_260,000 = ^129,990/_260,000 = 0.5000 = 50.00 cM Incorrect ^{(39,835 + 90,175)}/_260,000 = ^130,010/_260,000 = 0.5000 = 50.00 cM Incorrect ^{(39,835 + 90,447)}/_260,000 = ^130,282/_260,000 = 0.5011 = 50.11 cM Incorrect ^{(90,175 + 90,447)}/_260,000 = ^180,622/_260,000 = 0.6947 = 69.47 cM Incorrect MC

7627_1820

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene R is analogous to the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.
Gene T is linked with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
rusty, tipsy	r	t	920
rusty	r	+	2,914
tipsy	+	t	2,813
wildtype	+	+	853
TOTAL =			7,500

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,813 + 2,914)}/_7,500 = ^5,727/_7,500 = 0.7636 = 76.36 cM Incorrect ^{(853 + 2,813)}/_7,500 = ^3,666/_7,500 = 0.4888 = 48.88 cM Incorrect ^{(853 + 2,914)}/_7,500 = ^3,767/_7,500 = 0.5023 = 50.23 cM Incorrect ^{(853 + 920)}/_7,500 = ^1,773/_7,500 = 0.2364 = 23.64 cM Correct ^{(920 + 2,813)}/_7,500 = ^3,733/_7,500 = 0.4977 = 49.77 cM Incorrect ⁸⁵³/_7,500 = ⁸⁵³/_7,500 = 0.1137 = 11.37 cM Incorrect MC

64d6_199b

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is linked with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
horsey, mushy	h	m	2,246
horsey	h	+	5,190
mushy	+	m	5,355
wildtype	+	+	2,209
TOTAL =			15,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,209 + 2,246)}/_15,000 = ^4,455/_15,000 = 0.2970 = 29.70 cM Correct ^{(2,209 + 5,190)}/_15,000 = ^7,399/_15,000 = 0.4933 = 49.33 cM Incorrect ^{(2,209 + 5,355)}/_15,000 = ^7,564/_15,000 = 0.5043 = 50.43 cM Incorrect ^{(2,246 + 5,190)}/_15,000 = ^7,436/_15,000 = 0.4957 = 49.57 cM Incorrect ^{(2,246 + 5,355)}/_15,000 = ^7,601/_15,000 = 0.5067 = 50.67 cM Incorrect ^{(5,190 + 5,355)}/_15,000 = ^10,545/_15,000 = 0.7030 = 70.30 cM Incorrect MC

966e_4d15

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene W is linked with the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.
Gene Y is connected with the 'yucky' phenotype. A fruit fly that is homozygous recessive for Gene Y gives off an unpleasant odor and has a generally unappealing look.

Phenotype	Genotypes		Progeny Count
waxy, yucky	w	y	364
waxy	w	+	2,218
yucky	+	y	2,267
wildtype	+	+	351
TOTAL =			5,200

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,218 + 2,267)}/_5,200 = ^4,485/_5,200 = 0.8625 = 86.25 cM Incorrect ^{(351 + 2,218)}/_5,200 = ^2,569/_5,200 = 0.4940 = 49.40 cM Incorrect ^{(351 + 2,267)}/_5,200 = ^2,618/_5,200 = 0.5035 = 50.35 cM Incorrect ^{(351 + 364)}/_5,200 = ⁷¹⁵/_5,200 = 0.1375 = 13.75 cM Correct ^{(364 + 2,218)}/_5,200 = ^2,582/_5,200 = 0.4965 = 49.65 cM Incorrect ^{(364 + 2,267)}/_5,200 = ^2,631/_5,200 = 0.5060 = 50.60 cM Incorrect MC

778c_d63f

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene J is related to the 'jerky' phenotype. A fruit fly that is homozygous recessive for Gene J moves in rapid and sudden movements, displaying an unpredictable flight pattern.

Phenotype	Genotypes		Progeny Count
artsy, jerky	a	j	60,363
artsy	a	+	24,499
jerky	+	j	24,512
wildtype	+	+	60,626
TOTAL =			170,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(24,499 + 24,512)}/_170,000 = ^49,011/_170,000 = 0.2883 = 28.83 cM Correct ^{(24,499 + 60,363)}/_170,000 = ^84,862/_170,000 = 0.4992 = 49.92 cM Incorrect ^{(24,499 + 60,626)}/_170,000 = ^85,125/_170,000 = 0.5007 = 50.07 cM Incorrect ^{(24,512 + 60,363)}/_170,000 = ^84,875/_170,000 = 0.4993 = 49.93 cM Incorrect ^{(24,512 + 60,626)}/_170,000 = ^85,138/_170,000 = 0.5008 = 50.08 cM Incorrect ^{(60,363 + 60,626)}/_170,000 = ^120,989/_170,000 = 0.7117 = 71.17 cM Incorrect MC

bd75_b10a

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene B is analogous to the 'bumpy' phenotype. A fruit fly that is homozygous recessive for Gene B has a skin texture that is not smooth, but rough with small bumps all over.
Gene K is associated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
bumpy, kidney	b	k	11,737
bumpy	b	+	68,277
kidney	+	k	67,931
wildtype	+	+	12,055
TOTAL =			160,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(11,737 + 12,055)}/_160,000 = ^23,792/_160,000 = 0.1487 = 14.87 cM Correct ^{(11,737 + 67,931)}/_160,000 = ^79,668/_160,000 = 0.4979 = 49.79 cM Incorrect ^{(11,737 + 68,277)}/_160,000 = ^80,014/_160,000 = 0.5001 = 50.01 cM Incorrect ^{(12,055 + 67,931)}/_160,000 = ^79,986/_160,000 = 0.4999 = 49.99 cM Incorrect ^{(12,055 + 68,277)}/_160,000 = ^80,332/_160,000 = 0.5021 = 50.21 cM Incorrect ^{(67,931 + 68,277)}/_160,000 = ^136,208/_160,000 = 0.8513 = 85.13 cM Incorrect MC

a018_af84

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is analogous to the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene M is connected with the 'mushy' phenotype. A fruit fly that is homozygous recessive for Gene M feels soft to the touch and unusually squishy, unlike the usual firmness.

Phenotype	Genotypes		Progeny Count
dewy, mushy	d	m	5,141
dewy	d	+	39,720
mushy	+	m	39,894
wildtype	+	+	5,245
TOTAL =			90,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(39,720 + 39,894)}/_90,000 = ^79,614/_90,000 = 0.8846 = 88.46 cM Incorrect ^{(5,141 + 39,720)}/_90,000 = ^44,861/_90,000 = 0.4985 = 49.85 cM Incorrect ^{(5,141 + 39,894)}/_90,000 = ^45,035/_90,000 = 0.5004 = 50.04 cM Incorrect ^{(5,141 + 5,245)}/_90,000 = ^10,386/_90,000 = 0.1154 = 11.54 cM Correct ^{(5,245 + 39,720)}/_90,000 = ^44,965/_90,000 = 0.4996 = 49.96 cM Incorrect ^{(5,245 + 39,894)}/_90,000 = ^45,139/_90,000 = 0.5015 = 50.15 cM Incorrect MC

4180_c702

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene N is affiliated with the 'nerdy' phenotype. A fruit fly that is homozygous recessive for Gene N has large, prominent eyes that stand out, much like thick-rimmed glasses.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
nerdy, tipsy	n	t	100,394
nerdy	n	+	24,410
tipsy	+	t	24,765
wildtype	+	+	100,431
TOTAL =			250,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(100,394 + 100,431)}/_250,000 = ^200,825/_250,000 = 0.8033 = 80.33 cM Incorrect ^{(24,410 + 100,394)}/_250,000 = ^124,804/_250,000 = 0.4992 = 49.92 cM Incorrect ^{(24,410 + 100,431)}/_250,000 = ^124,841/_250,000 = 0.4994 = 49.94 cM Incorrect ^{(24,410 + 24,765)}/_250,000 = ^49,175/_250,000 = 0.1967 = 19.67 cM Correct ^{(24,765 + 100,394)}/_250,000 = ^125,159/_250,000 = 0.5006 = 50.06 cM Incorrect ^{(24,765 + 100,431)}/_250,000 = ^125,196/_250,000 = 0.5008 = 50.08 cM Incorrect MC

f237_4e15

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is related to the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene P is analogous to the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.

Phenotype	Genotypes		Progeny Count
artsy, prickly	a	p	10,078
artsy	a	+	17,444
prickly	+	p	17,349
wildtype	+	+	10,129
TOTAL =			55,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(10,078 + 10,129)}/_55,000 = ^20,207/_55,000 = 0.3674 = 36.74 cM Correct ^{(10,078 + 17,349)}/_55,000 = ^27,427/_55,000 = 0.4987 = 49.87 cM Incorrect ^{(10,078 + 17,444)}/_55,000 = ^27,522/_55,000 = 0.5004 = 50.04 cM Incorrect ^{(10,129 + 17,349)}/_55,000 = ^27,478/_55,000 = 0.4996 = 49.96 cM Incorrect ^{(10,129 + 17,444)}/_55,000 = ^27,573/_55,000 = 0.5013 = 50.13 cM Incorrect ^{(17,349 + 17,444)}/_55,000 = ^34,793/_55,000 = 0.6326 = 63.26 cM Incorrect MC

3057_b665

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene P is associated with the 'prickly' phenotype. A fruit fly that is homozygous recessive for Gene P is covered with sharp bristles, giving it a spiky texture.
Gene R is affiliated with the 'rusty' phenotype. A fruit fly that is homozygous recessive for Gene R has a reddish-brown color, much like rusted iron metal.

Phenotype	Genotypes		Progeny Count
prickly, rusty	p	r	121,747
prickly	p	+	13,365
rusty	+	r	13,338
wildtype	+	+	121,550
TOTAL =			270,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(121,550 + 121,747)}/_270,000 = ^243,297/_270,000 = 0.9011 = 90.11 cM Incorrect ^{(13,338 + 121,550)}/_270,000 = ^134,888/_270,000 = 0.4996 = 49.96 cM Incorrect ^{(13,338 + 121,747)}/_270,000 = ^135,085/_270,000 = 0.5003 = 50.03 cM Incorrect ^{(13,338 + 13,365)}/_270,000 = ^26,703/_270,000 = 0.0989 = 9.89 cM Correct ^{(13,365 + 121,550)}/_270,000 = ^134,915/_270,000 = 0.4997 = 49.97 cM Incorrect ^{(13,365 + 121,747)}/_270,000 = ^135,112/_270,000 = 0.5004 = 50.04 cM Incorrect MC

27c2_5e63

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is linked with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene T is associated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
fuzzy, tipsy	f	t	51,168
fuzzy	f	+	13,851
tipsy	+	t	13,826
wildtype	+	+	51,155
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(13,826 + 13,851)}/_130,000 = ^27,677/_130,000 = 0.2129 = 21.29 cM Correct ^{(13,826 + 51,155)}/_130,000 = ^64,981/_130,000 = 0.4999 = 49.99 cM Incorrect ^{(13,826 + 51,168)}/_130,000 = ^64,994/_130,000 = 0.5000 = 50.00 cM Incorrect ^{(13,851 + 51,155)}/_130,000 = ^65,006/_130,000 = 0.5000 = 50.00 cM Incorrect ^{(13,851 + 51,168)}/_130,000 = ^65,019/_130,000 = 0.5001 = 50.01 cM Incorrect ^{(51,155 + 51,168)}/_130,000 = ^102,323/_130,000 = 0.7871 = 78.71 cM Incorrect MC

535d_34b2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene F is associated with the 'fuzzy' phenotype. A fruit fly that is homozygous recessive for Gene F is covered in a dense layer of hairs, giving it a soft appearance.
Gene T is correlated with the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
fuzzy, tipsy	f	t	22,720
fuzzy	f	+	2,368
tipsy	+	t	2,237
wildtype	+	+	22,675
TOTAL =			50,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(2,237 + 2,368)}/_50,000 = ^4,605/_50,000 = 0.0921 = 9.21 cM Correct ^{(2,237 + 22,675)}/_50,000 = ^24,912/_50,000 = 0.4982 = 49.82 cM Incorrect ^{(2,237 + 22,720)}/_50,000 = ^24,957/_50,000 = 0.4991 = 49.91 cM Incorrect ^{(2,368 + 22,675)}/_50,000 = ^25,043/_50,000 = 0.5009 = 50.09 cM Incorrect ^{(2,368 + 22,720)}/_50,000 = ^25,088/_50,000 = 0.5018 = 50.18 cM Incorrect ^{(22,675 + 22,720)}/_50,000 = ^45,395/_50,000 = 0.9079 = 90.79 cM Incorrect MC

1f46_c709

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene D is associated with the 'dewy' phenotype. A fruit fly that is homozygous recessive for Gene D appears moist, with its body covered in tiny droplets of water.
Gene T is analogous to the 'tipsy' phenotype. A fruit fly that is homozygous recessive for Gene T moves in an erratic path, suggesting a lack of coordination, as if intoxicated.

Phenotype	Genotypes		Progeny Count
dewy, tipsy	d	t	44,039
dewy	d	+	20,817
tipsy	+	t	20,874
wildtype	+	+	44,270
TOTAL =			130,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(20,817 + 20,874)}/_130,000 = ^41,691/_130,000 = 0.3207 = 32.07 cM Correct ^{(20,817 + 44,039)}/_130,000 = ^64,856/_130,000 = 0.4989 = 49.89 cM Incorrect ^{(20,817 + 44,270)}/_130,000 = ^65,087/_130,000 = 0.5007 = 50.07 cM Incorrect ^{(20,874 + 44,039)}/_130,000 = ^64,913/_130,000 = 0.4993 = 49.93 cM Incorrect ^{(20,874 + 44,270)}/_130,000 = ^65,144/_130,000 = 0.5011 = 50.11 cM Incorrect ^{(44,039 + 44,270)}/_130,000 = ^88,309/_130,000 = 0.6793 = 67.93 cM Incorrect MC

6037_7354

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene A is affiliated with the 'artsy' phenotype. A fruit fly that is homozygous recessive for Gene A has wings that are colorful and distinctive patterns.
Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
artsy, kidney	a	k	1,008
artsy	a	+	2,361
kidney	+	k	2,416
wildtype	+	+	1,015
TOTAL =			6,800

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,008 + 1,015)}/_6,800 = ^2,023/_6,800 = 0.2975 = 29.75 cM Correct ^{(1,008 + 2,361)}/_6,800 = ^3,369/_6,800 = 0.4954 = 49.54 cM Incorrect ^{(1,008 + 2,416)}/_6,800 = ^3,424/_6,800 = 0.5035 = 50.35 cM Incorrect ^{(1,015 + 2,361)}/_6,800 = ^3,376/_6,800 = 0.4965 = 49.65 cM Incorrect ^{(1,015 + 2,416)}/_6,800 = ^3,431/_6,800 = 0.5046 = 50.46 cM Incorrect ^{(2,361 + 2,416)}/_6,800 = ^4,777/_6,800 = 0.7025 = 70.25 cM Incorrect MC

f099_ea6e

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene H is affiliated with the 'horsey' phenotype. A fruit fly that is homozygous recessive for Gene H is quite big and strong-looking, much larger than your typical fruit fly.
Gene K is affiliated with the 'kidney' phenotype. A fruit fly that is homozygous recessive for Gene K has a body shape that is curved, similar to a kidney bean.

Phenotype	Genotypes		Progeny Count
horsey, kidney	h	k	6,734
horsey	h	+	3,346
kidney	+	k	3,296
wildtype	+	+	6,624
TOTAL =			20,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(3,296 + 3,346)}/_20,000 = ^6,642/_20,000 = 0.3321 = 33.21 cM Correct ^{(3,296 + 6,624)}/_20,000 = ^9,920/_20,000 = 0.4960 = 49.60 cM Incorrect ^{(3,296 + 6,734)}/_20,000 = ^10,030/_20,000 = 0.5015 = 50.15 cM Incorrect ^{(3,346 + 6,624)}/_20,000 = ^9,970/_20,000 = 0.4985 = 49.85 cM Incorrect ^{(3,346 + 6,734)}/_20,000 = ^10,080/_20,000 = 0.5040 = 50.40 cM Incorrect ^{(6,624 + 6,734)}/_20,000 = ^13,358/_20,000 = 0.6679 = 66.79 cM Incorrect MC

330b_ccf2

Two-Point Test Cross Problem

A standard two-point test cross involves crossing a heterozygous organism for both genes with an organism that is homozygous recessive for both genes

For this problem, a test cross using a fruit fly (Drosophila melanogaster) heterozygous for two genes was conducted to understand their genetic interactions.

Characteristics of Recessive Phenotypes

Gene E is affiliated with the 'eery' phenotype. A fruit fly that is homozygous recessive for Gene E appears to have something off, crooked limbs and other twisted appendages.
Gene W is analogous to the 'waxy' phenotype. A fruit fly that is homozygous recessive for Gene W has a thick protective layer that is water resistant and opague.

Phenotype	Genotypes		Progeny Count
eery, waxy	e	w	1,349
eery	e	+	3,669
waxy	+	w	3,636
wildtype	+	+	1,346
TOTAL =			10,000

The resulting phenotypes are summarized in the table above.

Question

With the progeny data from the table, calculate the genetic distance between the two genes, expressing your answer in centimorgans (cM)

^{(1,346 + 1,349)}/_10,000 = ^2,695/_10,000 = 0.2695 = 26.95 cM Correct ^{(1,346 + 3,636)}/_10,000 = ^4,982/_10,000 = 0.4982 = 49.82 cM Incorrect ^{(1,346 + 3,669)}/_10,000 = ^5,015/_10,000 = 0.5015 = 50.15 cM Incorrect ^{(1,349 + 3,636)}/_10,000 = ^4,985/_10,000 = 0.4985 = 49.85 cM Incorrect ^{(1,349 + 3,669)}/_10,000 = ^5,018/_10,000 = 0.5018 = 50.18 cM Incorrect ^{(3,636 + 3,669)}/_10,000 = ^7,305/_10,000 = 0.7305 = 73.05 cM Incorrect