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7: Chi Square Analysis

Statistical evaluation of genetic data, chi-square test statistic, and hypothesis testing.

LibreTexts reference: Chi Square Analysis

Chi-Square Terms and Definitions

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Match each of the following chi-square (χ²) terms with their corresponding defintions.
Note: Each choice will be used exactly once.

Your Choice Prompt
Drop Your Choice Here 1. critical value
Drop Your Choice Here 2. level of significance, α
Drop Your Choice Here 3. null hypothesis, H0
Drop Your Choice Here 4. alternative hypothesis, Ha

Drag one of the choices below:

  • A. the statistical cutoff of the result for the null hypothesis, H0 to be TRUE or false
  • B. this hypothesis makes it easier to calculate the expected values
  • C. the cutoff used to compare against the observed chi-square (χ²) test statistic
  • D. for this hypothesis, the expected values may be impossible to calculate
 

Chi-Square Terms

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Which one of the following chi-square (χ²) terms correspond to the defintion 'the cutoff used to compare against the observed chi-square (χ²) test statistic'.

 

True/False Statements About Chi-Square Tests

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Which one of the following statements is TRUE regarding chi-square (χ²) tests?

 

Chi-Square Tests for Phenotypic Ratios

Click to show Chi-Square Tests for Phenotypic Ratios example problem
Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Table 1
Phenotype Expected Observed Calculation Statistic
 Yellow Round (Y–R–) 90 96 (96-90)²⁄ 96² 0.004
 Yellow Wrinkled (Y–rr) 30 26 (26-30)²⁄ 26² 0.024
 Green Round (yyR–) 30 24 (24-30)²⁄ 24² 0.062
 Green Wrinkled (yyrr) 10 14 (14-10)²⁄ 14² 0.082
(sum) χ² =  0.172

Table 2
Phenotype Expected Observed Calculation Statistic
 Yellow Round (Y–R–) 90 96 (96-90)²⁄ 90 0.400
 Yellow Wrinkled (Y–rr) 30 26 (26-30)²⁄ 30 0.533
 Green Round (yyR–) 30 24 (24-30)²⁄ 30 1.200
 Green Wrinkled (yyrr) 10 14 (14-10)²⁄ 10 1.600
(sum) χ² =  3.733

Table 3
Phenotype Expected Observed Calculation Statistic
 Yellow Round (Y–R–) 90 96 (96-90)²⁄ 96 0.375
 Yellow Wrinkled (Y–rr) 30 26 (26-30)²⁄ 26 0.615
 Green Round (yyR–) 30 24 (24-30)²⁄ 24 1.500
 Green Wrinkled (yyrr) 10 14 (14-10)²⁄ 14 1.143
(sum) χ² =  3.633


Your lab partner is trying again (eye roll) and did another a chi-squared (χ²) test on the F2 generation in a dihybid cross based on your lab data (above). They wanted to know if the results confirm the expected phenotype ratios.
You helped them set up the null hypothesis, so you know that part is correct, but they got confused and were unsure about how to calculate the chi-squared (χ²) value. So much so that they did it three (3) different ways.
Before you ask your instructor for a new lab partner, tell them which table is correct AND whether they can accept or reject the null hypothesis using the information provided.

 

Chi-Square Tests for Goodness of Fit

Click to show Chi-Square Tests for Goodness of Fit example problem
Table of Chi-Squared (χ²) Critical Values
Degrees of Freedom Probability
0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01
1 0.00 0.02 0.10 0.45 1.32 2.71 3.84 6.63
2 0.10 0.21 0.58 1.39 2.77 4.61 5.99 9.21
3 0.35 0.58 1.21 2.37 4.11 6.25 7.81 11.34
4 0.71 1.06 1.92 3.36 5.39 7.78 9.49 13.28

Phenotype Expected Observed Calculation Statistic
 Yellow Round (Y–R–) 40 54 (54-40)²⁄ 40 4.900
 Yellow Wrinkled (Y–rr) 40 50 (50-40)²⁄ 40 2.500
 Green Round (yyR–) 40 33 (33-40)²⁄ 40 1.225
 Green Wrinkled (yyrr) 40 23 (23-40)²⁄ 40 7.225
(sum) χ² =  15.850

The final result gives the chi-squared (χ²) test value of 15.85 with 3 degrees of freedom. Consulting the Table of χ² Critical Values and a level of significance α=0.05, we obtain a critical value of 7.81.
Since the chi-squared value of 15.85 is greater than the critical value of 7.81, the null hypothesis is REJECTED.


Your lab partner completed a chi-squared (χ²) test on your lab data (above) for the F2 generation in a standard dihybrid cross. The goal was to verify if the observed results matched the expected phenotype ratios.
However, it appears they made an error. What did they do wrong?